gp2$pap$s5$hw2$answers/ - quia · gp2-pap-s5-hw2-solutions author: david unsinger created date:...

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GP2PAPS5HW2Answers (up, down) As , and as , Note; The polynomial function has an odd degree and a negative leading coefficient. (up, up) As , and as , Note; The polynomial function has an even degree and a positive leading coefficient. (down, down) As , and as , Note; The polynomial function has an even degree and a negative leading coefficient. (down, up) As , and as , Note; The polynomial function has an odd degree and a positive leading coefficient.

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Page 1: GP2$PAP$S5$HW2$Answers/ - Quia · GP2-PAP-S5-HW2-Solutions Author: david unsinger Created Date: 11/5/2015 12:37:46 AM

GP2-­‐PAP-­‐S5-­‐HW2-­‐Answers    

 

 (up,  down)    As  𝑦 → ∞, 𝑥 → −∞    and    as  𝑦 → −∞, 𝑥 → ∞      Note;  The  polynomial  function  has  an  odd  degree  and  a  negative  leading  coefficient.  

 

 

 (up,  up)    As  𝑦 → ∞, 𝑥 → −∞    and    as  𝑦 → ∞, 𝑥 → ∞      Note;  The  polynomial  function  has  an  even  degree  and  a  positive  leading  coefficient.  

 

 

 (down,  down)    As  𝑦 → −∞, 𝑥 → −∞    and    as  𝑦 → −∞, 𝑥 → ∞      Note;  The  polynomial  function  has  an  even  degree  and  a  negative  leading  coefficient.    

 

 

 (down,  up)    As  𝑦 → −∞, 𝑥 → −∞    and    as  𝑦 → ∞, 𝑥 → ∞      Note;  The  polynomial  function  has  an  odd  degree  and  a  positive  leading  coefficient.  

       

Page 2: GP2$PAP$S5$HW2$Answers/ - Quia · GP2-PAP-S5-HW2-Solutions Author: david unsinger Created Date: 11/5/2015 12:37:46 AM

 

 

The  polynomial  function  is  not  written  in  standard  form.  The  leading  coefficient  is  !!

!  and  the  degree  is  3.  The  end  

behavior  is  (up,  down);    As  𝑦 → ∞, 𝑥 → −∞    and    as  𝑦 → −∞, 𝑥 → ∞      

 

 The  polynomial  function  is  not  written  in  standard  form.  The  leading  coefficient  is  −1  and  the  degree  is  2.  The  end  behavior  is  (down,  down);    As  𝑦 → −∞, 𝑥 → −∞    and    as  𝑦 → −∞, 𝑥 → ∞      

 

 The  polynomial  function  is  written  in  standard  form.  The  leading  coefficient  is  1  and  the  degree  is  4.  The  end  behavior  is  (up,  up);    As  𝑦 → ∞, 𝑥 → −∞    and    as  𝑦 → ∞, 𝑥 → ∞    

 

 

The  polynomial  function  is  not  written  in  standard  form.  The  leading  coefficient  is  !!

!  and  

the  degree  is  5.  The  end  behavior  is  (up,  down);    As  𝑦 → ∞, 𝑥 → −∞    and    as  𝑦 → −∞, 𝑥 → ∞  

 

  The  polynomial  function  is  not  written  in  standard  form.  The  leading  coefficient  is  −1  and  the  degree  is  1.  The  end  behavior  is  (up,  down);    As  𝑦 → ∞, 𝑥 → −∞    and    as  𝑦 → −∞, 𝑥 → ∞  

 

 The  polynomial  function  is  not  written  in  standard  form.  The  leading  coefficient  is  −1  and  the  degree  is  3.  The  end  behavior  is  (up,  down);    As  𝑦 → ∞, 𝑥 → −∞    and    as  𝑦 → −∞, 𝑥 → ∞  

 

 The  polynomial  function  is  not  written  in  standard  form.  The  leading  coefficient  is  −3  and  the  degree  is  3.  The  end  behavior  is  (up,  down);    As  𝑦 → ∞, 𝑥 → −∞    and    as  𝑦 → −∞, 𝑥 → ∞  

         

Page 3: GP2$PAP$S5$HW2$Answers/ - Quia · GP2-PAP-S5-HW2-Solutions Author: david unsinger Created Date: 11/5/2015 12:37:46 AM

 The  polynomial  function  is  written  in  standard  form.  The  leading  coefficient  is  1  and  the  degree  is  4.  The  end  behavior  is  (up,  up);    As  𝑦 → ∞, 𝑥 → −∞    and    as  𝑦 → ∞, 𝑥 → ∞  

 

 

 To  find  the  y-­‐intercept,  let  x  =  0  𝑓 0 = 0,  so  the  𝑦-­‐intercept  is  𝑦 = 0    To  find  the  x-­‐intercept(s),  let  y  =  0  0 = 𝑥! 𝑥 − 1 ! 3𝑥 − 4    Zeros  (x-­‐intercepts)  

Multiplicity   Cross  or  Touch-­‐n-­‐turn  

𝑥 = 0   3   cross  𝑥 = 1   2   Touch-­‐n-­‐turn  

𝑥 =43  

1   cross  

                       

 𝑓 𝑥 = 𝑥 − 2 ! 𝑥 + 2 ! 𝑥 + 2 𝑥 − 2  

𝑓 𝑥 = 𝑥 − 2 ! 𝑥 + 2 !      

To  find  the  y-­‐intercept,  let  x  =  0  𝑓 0 = 0− 2 ! 0+ 2 ! 0! − 4 = −256    To  find  the  x-­‐intercept(s),  let  y  =  0    Zeros  (x-­‐intercepts)  

Multiplicity   Cross  or  Touch-­‐n-­‐turn  

𝑥 = 2   5   cross  𝑥 = −2   3   cross                        

   

 𝑓 𝑥 = 𝑥 − 6 𝑥 + 2 𝑥 + 2 𝑥 + 5    𝑓 𝑥 = 𝑥 + 2 ! 𝑥 − 6 𝑥 + 5    

To  find  the  y-­‐intercept,  let  x  =  0  𝑓 0 = −12 10 = −120    To  find  the  x-­‐intercept(s),  let  y  =  0    Zeros  (x-­‐intercepts)  

Multiplicity   Cross  or  Touch-­‐n-­‐turn  

𝑥 = −2   2   Touch-­‐n-­‐turn  𝑥 = 6   1   cross  𝑥 = −5   1   cross                      

         

Page 4: GP2$PAP$S5$HW2$Answers/ - Quia · GP2-PAP-S5-HW2-Solutions Author: david unsinger Created Date: 11/5/2015 12:37:46 AM

 𝑓 𝑥 = 𝑥! + 9 𝑥! − 9  

𝑓 𝑥 = 𝑥! + 9 𝑥 + 3 𝑥 − 3    

To  find  the  y-­‐intercept,  let  x  =  0  𝑓 0 = 81    To  find  the  x-­‐intercept(s),  let  y  =  0    Zeros  (x-­‐intercepts)  

Multiplicity   Cross  or  Touch-­‐n-­‐turn  

𝑥 = −3   1   cross  𝑥 = 3   1   cross                      

   

 𝑓 𝑥 = 7𝑥! 3𝑥 − 5 3𝑥 + 7 2𝑥 3𝑥! + 𝑥 − 10  

𝑓 𝑥 =  14𝑥! 3𝑥 − 5 3𝑥 + 7 3𝑥 − 5 𝑥 + 2  

𝑓 𝑥 = 14𝑥! 3𝑥 − 5 ! 3𝑥 + 7 𝑥 + 2      

To  find  the  y-­‐intercept,  let  x  =  0  𝑓 0 = 0    To  find  the  x-­‐intercept(s),  let  y  =  0    Zeros  (x-­‐intercepts)  

Multiplicity   Cross  or  Touch-­‐n-­‐turn  

𝑥 = 0   4   Touch-­‐n-­‐turn  

𝑥 =53  

2   Touch-­‐n-­‐turn  

𝑥 =−73  

1   cross  

𝑥 = −2   1   cross