Ngy son:5/1/2009

LUYN TP V KIM LOI KIM V HP CHT CA KIM LOI KIMA. Mc tiu: - Cng c v khc su kin thc : T/c ha hc, iu ch cc kim loi kim v hp cht ca chng- Rn k nng vit ptpu, nhn bit , gii cc loi bi tp v kim loi kim v h/cht.

B. Phng php: Hi p tho lun m thoi din ging C. T chc hot ng:Hot ng ca thy Hot ng 1: n tp cc kin thc c bn: - YC hs nu v tr, cu to ng.t v kh nng hot ng ha hc ca KLK - Xc nh cu hnh nguyn t v ion: 3s1, [Ar]4s1, [Ne], 3s23p6 l ca ng.t, ion M+ no? - Na, K t/dng vi nhng cht no sau: Cl2, O2, dd HCl, H2O, dd CuSO4, . - Hp cht NaOH, NaHCO3, Na2CO3 c nhng t/c ha hc g? - T dd NaCl, dd NaOH lm th no /ch Na - Nhn bit:Na, NaOH, NaCl, Na2O Hot ng ca tr Nhm IA, ns1 , M M+ + 1e ( Trong cc h/c KLK lun c s OXH +1) Na, K, Na+, K+ -HS Vit ptpu -HS Vit ptpu -HS vit ptpu in phn nng chy - dng nc, qu tm, AgNO3, nc 1) Vit ptpu Tnh mKOH theo p/ Tnh m dd = mK + m H2O mH2 C% = mKOH/m dd 2) Vit ptpu T V kh n kh n kim loi ( theo p/) Tm M = m/n kim loi Na 3)Vit ptpu CaCO3 + HCl Tnh V CO2( nCO2) Lp t s n NaOH/nCO2

Hot ng 2: Bi tpBi1)Ha tan 78 g K vo 724 g H2O c nng % dd =? Bi 2) in phn mui clorua mt kim loi kim nng chy thu c 0,448 lt kh(kc) anot v 0,92 g catot. Tm kim loi? Bi 3) Cho 50 g CaCO3 t/d vi dd HCl thu c V lt CO2. Sc ton b CO2 vo dd c cha 30g NaOH. Tnh lng mui thu c?

p/

Bi 4)Nung 148g hh NaHCO3 v Na2CO3 n khi lng khng i c 132,5 g cht rn. Xc nh % m mi cht trong hh ban u? Hd hs vit ptp/, t tnh theo ptp/

Vi 1< n NaOH/nCO2 < 2 c 2 p/ to 2 mui t lp h pt tnh c s mol 2 mui khi lng 4) Na2CO3 khng b nhit phn 2NaHCO3 Na2CO3 + CO2 + H2O Lp h pt: 106 x + 84y = 148 106x + 106y/2 = 132,5 gii c x,y v % mui

T CHN 12 CB

HK II

Ngy son: 7/1/2009 Tun 20

LUYN TP V KIM LOI KIM Th V HP CHT CA KIM LOI KIM ThA. Mc tiu: - Cng c v khc su kin thc : T/c ha hc, iu ch cc kim loi kim th v hp cht ca chng- Nc cng v cch lm mm nc cng - Rn k nng vit ptpu, nhn bit , gii cc loi bi tp v kim loi kim th v h/cht. B. Phng php: Hi p tho lun m thoi din ging C. T chc hot ng: Hot ng ca thy Hot ng ca tr I. Nhm IIA, ns2 , M M2+ + 2e I.Hot ng 1: n tp cc kin thc c bn: ( Trong cc h/c KLK lun c s OXH +2) - YC hs nu v tr, cu to ng.t v kh nng hot ng ha hc ca KLK Na, Mg, Mg2+, Ca2+. - Xc nh cu hnh nguyn t v ion: 3s1, 3s2, [Ar]4s2, [Ne], 3s23p6 l ca ng.t, ion M2 no? -HS Vit ptpu - Mg, Ca t/dng vi nhng cht no sau: Cl2, O2, dd HCl, H2O, dd CuSO4, . -HS Vit ptpu - Hp cht CaO, Ca(HCO3)2, CaCO3, Ca(OH)2. C nhng t/c ha hc g? - T dd CaCl2, dd Ca(OH)2, CaCO3. lm th no -HS vit ptpu in phn nng chy /ch Ca Mui halogen - dng nc, qu tm, CO2, Na2CO3, nc - Nhn bit:Ca, Ca(OH)2, CaCl2, CaO

II.Hot ng 2: Bi tpBi 1)Cho 14,2 g hh CaCO3 v MgCO3 t/d ht vi dd HCl thu c 3,36 lt kh CO2 (kc) Tnh % klg mui hh ban u? Bi 2) Cho 10g KL IIA t/ ht vi dd HCl to ra 27,75 g mui clorua. Tm kim loi Hd hs vit ptp/, t tnh theo ptp/

Bi 3)Cho 28 g CaO vo H2O d thu c dd A . Sc 16,8 lt CO2 (kc) vo dd A a) Tnh khi lg kt ta b) Khi un nng thu thm bao nhiu g kt ta? Hd hs vit ptp/, t tnh theo ptp/

II. 1)Vit 2 ptp/ Lp h pt ton theo s mol l gii c 100x + 84y = 14,2 x+ y = 0,15 2) Vit ptp/ M +2HCl MCl2 + H2 M M+71 10 27,75 Lp t s M C th gii theo pp tng gim klg 3) a) Ptp/ CaO + H2O Ca(OH)2 0,5 mol 0,5 mol Lp t s mol CO2/Ca(OH)2 100ppm l t b nhim. Trong cc mu t nghin cu sau 1) Mu t gia cnh ng :125,4ppm ; (2)Mu t ni nu ch :387,6ppm ; (3)Mu t gn ni nu ch :2911,4ppm ; (4)Mu bn thi nc acquy :2166,0ppm. Mu b nhim ch l : A.1,4. B.2,3. C.3,4. D.1,2,3,4 Hot ng 3 : Cng c. Dn d K duyt: Ngy..thng. nm 2009 Bi 1 : B

Bi 2 : D.

Bi 3 : D

Bi 4 : D

T CHN 12 CB

HK II