general chemistry-chapter 14
TRANSCRIPT
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Chapter 14Chapter 14
SolutionsSolutions
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14.1 General properties of solutions14.1 General properties of solutionssolution a system in which one or more
substances are homogeneously mixed ordissolved in another substance
two components in a solution:solute the component that is dissolved or
is the least abundant componentsolvent the dissolving agent or
the most abundant component
the properties of a true solution:1. the mixture of two or more components is
homogeneous and have a variable composition
2. the dissolved solute is molecular or ionic in size3. it is either colored or colorless and is usually
transparent4. the solute is uniformly distributed throughout
the solution and will not settle out with time5. the solute can generally be separated from the
solvent by purely physical means
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ex. sugar solution 10 g or 20 g of sugar in 100 mL of water every portion of the solution has the same
sweet taste if no solvent is lost, the solution will taste
and appear he same a week or month later carefully evaporating water, the sugar can
be recovered ex. potassium permanganate KMnO 4 solution
the purple color disperses until it is evenlydistributed throughout the solutionsolution permanency is explained in term ofkinetic-molecular theory: both solute andsolvent particles are in constant randommotion that is energetic enough to preventthe solute particles from settling out underthe influence of gravity
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14.2 Solubility14.2 Solubilitysolubility the amount of solute that will dissolve
in a specified amount of solvent understated condition all radiations travel atthe same speed
ex. 36 g of NaCl will dissolve in 100 g of waterat 20 oC solubility of NaCl in water is
36 g/100 g H 2O at 20 oCqualitative description of solubility:
very soluble, moderately soluble,slightly soluble, insoluble
miscible liquids that are capable of mixingand forming a solution
immiscible those that do not form solution orare generally insoluble in each other
ex. oil and water are immisciblewater and ethanol are miscible
the quantitative expression for theamount of dissolved solute in a
particular quantity of solvent isknown as the concentration of asolution
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general guidelines for the solubility of commonionic compounds (salts)
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14.3 Factors related to solubility14.3 Factors related to solubilitymany variables are involved in the solubility of asubstance, some factors related to solubility areexamined 1. the nature of the solute and solvent
like dissolve like is a general rule polar or ionic substances tend to be more
compatible with other polar substances
nonpolar substances tend to be compatible withother nonpolar substances and less misciblewith polar substancesex. NaCl is more soluble in water than in ether,
hexane or benzene pentane is slightly soluble in water but is
soluble in ether or benzenesolution formation between
polar substance
NaCl dissolves in water NaCl(crystal)
Na +(aq) + Cl -(aq)
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2. the effect of temperature on solubility
for most solids dissolved in a liquid, an increasein temperature results in increased solubilitythere are some exceptionsthe solubility of a gas in water usuallydecreases with increasing temperature
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3. the effect of pressure on solubilitychanges in pressure have little effect on thesolubility of solid in liquids or liquids in liquids, but have marked effect on the solubility ofgases in liquidsthe solubility of a gas in a liquids directly
proportional to the pressure of that gas abovethe solution
ex. carbonated beverages CO 2 in water at a specific temperature there is a limit to theamount of solute that will dissolve in a givenamount of solventreaching this limit the resulting solution is said to
be saturated solutionex. adding 40 g KCl to 100 g H 2O at 20 oC34 g KCl dissolves and 6 g KCl undissolved
solute (undissolved) solute (dissolved)saturated solution contains dissolved andundissolved solute
unsaturated solution contains less solute per unitof volume than does its corresponding saturatedsolution
ex. adding 40 g KCl to 100 g H 2O at 20 oC34 g KCl dissolves and 6 g KCl undissolved if the solution heated to 50 oC, all the salt
will dissolve and the solution is unsaturated
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in some circumstances, solutions can be preparedthat contain more than needed for a saturatedsolution at a particular temperaturethese solution are said to be supersaturated
supersaturated solutions are unstabledisturbances will cause the supersaturatedsolution to return saturation releasing heatex. 14.1 will a solution made by adding 2.5 g
CuSO 4 to 10 g H 2O be saturated orunsaturated at 20 oC?
solubility of CuSO 4 at 20o
C: 21 g/100 g H 2Othat is, 2.1 g/10 g H 2Oso, this is a saturated solution
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14.4 Rates of dissolving solids14.4 Rates of dissolving solidsthe rate at which a solid dissolve is governed by1. the size of the solute particles
a solid can dissolve only at the surfacethe surface-to volume ratio increases as sizedecreases, small crystals dissolve faster thanlarge one
2. the temperaturethe rate of dissolving of a solid increases withtemperature
the solvent molecules move more rapidly athigher temperatures and strike the solid surfacesmore often and harder, causing the rate ofdissolving increases
3. the concentration of the solutionas the concentration of the solution increases and
the solution becomes more nearly saturated with
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the solute, the rate of dissolving decreasesgreatly
4. agitation or stirring
stirring distributes the dissolved solute rapidlythrough the solution, and more solvent is broughtinto contact with the solid, causing it to dissolvemore rapidly
17 g
25 g
27 g29 g 30 g
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14.5 Solutions: a reaction medium14.5 Solutions: a reaction mediummany solids must be put into solution to undergoappreciable chemical reaction
ex. NaCl + AgNO 3 AgCl + NaNO 3mixing solid NaCl and solid AgNO 3if any reaction occurs, it is slow and virtually undetctableif dissolving NaCl and AgNO
3separately in
water and mixing two solutions, white AgCl precipitate immediately forms
NaCl (aq) + AgNO 3(aq)AgCl(aq) + Na NO 3(aq)
the mixture of the two solutions provides a
medium or space in which Ag+
and Cl-
reactsolutions also function as diluting agents inreactions in which the undiluted reactants wouldcombine with each other too violently
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14.6 Concentration of solutions14.6 Concentration of solutionsthe concentration of a solution expresses theamount of solute dissolved in a given quantity ofsolvent or solution qualitative expression
dilute solution a solution that contains arelatively small amount of dissolved solute
concentrated solution contains a relativelylarge amount of dissolved solute mass percent solution
ex. 10% NaOH solutiong solute
mass percent = 100g solution
g solute= 100
g solute + g solvent
g soluteparts per million = 1,000,000
(ppm) g solutionex. 14.2 what is the mass percent of NaOH in a
solution made by dissolving 8 g NaOHin 50 g H 2O?
8 100 = 13.8% NaOH solution
50 + 8
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ex. 14.3 what mass of KCl and H 2O are needed to make 250 g of 5% solution?
(250 g) 5% = 12.5 g KCl250 - 12.5 = 237.5 g H 2O
ex. 14.4 a 34% H 2SO 4 solution has a density of 1.25 g/mL, how many g of H 2SO 4 arecontained in 1 L of this solution?
1000 mL
1.25 g/mL = 1250 g solution1250 34% = 425 g H 2SO 4 mass/volume percent (m/V)
gram of solute per 100 mL of solutiong solute
mass/volume percent = 100mL solution
ex. 14.5 a 3% H 2O2 solution, what volume ofthis solution will contain 10 g of H 2O2?
(10 g) / (0.03 g/mL) = 333 mL volume percent
volume of liquid in questionvolume percent = 100
total volume of solution
volume percent is used to express theconcentration of alcohol in beverages
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molarity1000 g of 10% NaOH solution 100 g NaOH1000 g of 10% KOH solution 100 g KOH
mol NaOH = 100/40.0 = 2.50 molmol KOH = 100/56.11 = 1.78 mol
mass percent does not express the number ofmoles of solute
molarity the number of moles of solute per literof solutionnumber of moles of solute
molarity = M = liter of solution
ex. preparation of a 1 M solution
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molarities of concentrated acids commonly usedin the laboratory:
HCl 12 M HC 2H5O2 17 MHNO 3 16 M H2SO 4 18 M
ex. 14.6 what is the molarity of a solutioncontaining 1.4 mol of acetic acid in250 mL of solution?
1.4 mol/0.25 L = 5.6 M ex. 14.7 what is the molarity of a solution made
by dissolving 2.0 g of KClO 3 in water to make 150 mL of solution?
2 g/122.6 g/mol = 0.109 M
150/1000 Lex. 14.8 how many grams of KOH are required
to prepare 600 mL of 0.45 M KOHsolution0.45 M 0.6 L 56.11g/mol = 15.1 g
ex. 14.9 calculate the number of moles ofHNO 3 in 325 mL of 16 M HNO 3solution16 M 0.325 L = 5.2 mol
ex. 14.10 what volume of 0.25 M solution can be prepared from 16g of K 2CO 3
16/138.2 = 0.116 mol0.116 mol /0.25 M = 0.463 L
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ex. 14.13 how many grams of AgCl will be precipitated by adding sufficient AgNO 3 to
react with 1500 mL of 0.4 M BaCl 2 solution?2AgNO 3 + BaCl 2 2AgCl + Ba(NO 3)21.5 L 0.4 M = 0.6 mol BaCl 20.6 mol 2 143.4 g/mol = 172 g AgCl
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14.714.7 ColligativeColligative properties of solutionsproperties of solutionstwo solutions 1 mole urea and 1 mole sucrose in1 Kg water, both have a freezing point of -1.86 oC,not 0 oCin fact, dissolving 1 mole of any nonionizablesolute in 1 Kg of water, the freezing point is-1.86 oCfreezing point depression is a general property ofsolutions, each solvent shows a characteristicfreezing point depression constant
the solution formed by addition of a nonvolatilesolute to a solvent has a lower freezing point , ahigher boiling point , a lower vapor pressure thanthat of pure solventcolligative proerties the properties that depend
only on the number of solute particles in asolution and not on the nature of those particles
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vapor pressure curve of pure water and watersolution
boiling point elevation freezing point depression
some particular applications involving colligative properties:1. use of salt-ice mixture to provide low freezing
temperatures for homemade ice cream2. use of NaCl or CaCl 2 to melt ice from street
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3. use of ethylene glycol-water mixtures asantifreeze in automobile radiators
molality (m) the number of moles of solute perkilogram of solvent
mole of solute m =
Kg solventthe colligative properties
t f = m K f t b = m K bm: molality t f : freezing point depression tb: boiling point elevation
f : freezing point depression constant b : boiling point elevation constant
ex. 14.14 what is the molality of a solution prepared by dissolving 2.7 g CH 3OH in25 g H 2O?
2.7 / 32.04 = 0.084 mol CH 3OH0.084 mol / 0.025 kg = 3.37 m
ex. 14.15 a solution is made by dissolving 100 gethylene glycol in 200 g H 2O, what isthe freezing point of the solution?
100 / 62.07 = 1.61 mol C 2H6O21.61 mol / 0.2 kg = 8.05 m1.86 8.05 = 15 oCfreezing point is -15 oC
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ex. 14.16 a solution is made by dissolving4.71 g of a compound of unknown
molar mass in 100 g H 2O has afreezing point of -1.46 oC, what isthe molar mass of the compound?
t f = 1.46 oC1.46 / 1.86 = 0.785 m0.78 m 0.1 kg = 0.0785 mol
4.71 / 0.0785 = 60.0 g/mol
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14.8 Osmosis and osmotic pressure14.8 Osmosis and osmotic pressurethe red blood cells are enclosed in semipermeablemembranes , they behave differently in the solutionsof different salt concentrations
(a) in an isotonic solution (b) in a hypertonic solution (c) in a hypotonic solution(0.9% saline) (1.6% saline) (0.2% saline)
* 0.9% (0.15 M) NaCl solution is known as physiological saline solution which isisotonic with the blood plasma
a semipermeable membrane allows the passage ofwater (solvent) molecules through it in eitherdirection but prevents the passage of larger solutemolecules or ions
when two solutions of different concentrations areseparated by a semipermeable membrane, waterdiffuses through the membrane from the solution oflower concentration to higher concentrationthis phenomenon is called osmosisall solutions exhibit osmotic pressure which is a
colligative property
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the osmotic pressure can be measured bydetermining the amount of counterpressureneeded to prevent osmosisthe osmotic pressure of a solution containing 1mol of solute particles in 1 kg of water is about22.4 atmdemonstration of osmosis