example 3

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EXAMPLE 3 Rewrite a linear equation Solve 9x – 4y = 7 for y. Then find the value of y when x = –5. SOLUTION Solve the equation for y. STEP 1 9x – 4y = 7 –4y = 7 – 9x y = 9 4 7 4 + x Write original equation. Subtract 9x from each side. Divide each side by –4.

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Solve the equation for y. STEP 1. x. y =. +. –. 9. 7. 4. 4. EXAMPLE 3. Rewrite a linear equation. Solve 9 x – 4 y = 7 for y . Then find the value of y when x = –5. SOLUTION. 9 x – 4 y = 7. Write original equation. –4 y = 7 – 9 x. Subtract 9 x from each side. - PowerPoint PPT Presentation

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Page 1: EXAMPLE 3

EXAMPLE 3 Rewrite a linear equation

Solve 9x – 4y = 7 for y. Then find the value of y when x = –5.

SOLUTION

Solve the equation for y.STEP 1

9x – 4y = 7

–4y = 7 – 9x

y = 94

74

– + x

Write original equation.

Subtract 9x from each side.

Divide each side by –4.

Page 2: EXAMPLE 3

EXAMPLE 3 Rewrite a linear equation

Substitute the given value into the rewritten equation.

STEP 2

y = 94

74

– + (–5)

y = 454

74

– –

y = –13

CHECK

9x – 4y = 7

9(–5) – 4(–13) 7=?

7 = 7

Substitute –5 for x.

Multiply.

Simplify.

Write original equation.

Substitute –5 for x and –13 for y.

Solution checks.

Page 3: EXAMPLE 3

EXAMPLE 4 Rewrite a nonlinear equation

Solve 2y + xy = 6 for y. Then find the value of y when x = –3.

SOLUTION

Solve the equation for y.STEP 1

2y + x y = 6

(2+ x) y = 6

y = 62 + x

Write original equation.

Distributive property

Divide each side by (2 + x).

Page 4: EXAMPLE 3

EXAMPLE 4 Rewrite a nonlinear equation

Substitute the given value into the rewritten equation.

STEP 2

y = 62 + (–3)

y = – 6

Substitute –3 for x.

Simplify.

Page 5: EXAMPLE 3

GUIDED PRACTICE for Examples 3 and 4

Solve the equation for y. Then find the value of y when x = 2.

8. y – 6x = 7

y = 7 + 6x

y = 19

ANSWER

9. 5y – x = 13

y = x5

135 +

y = 5

ANSWER

10. 3x + 2y = 12

y = – 3x2 + 6

ANSWER

y = 3

Page 6: EXAMPLE 3

GUIDED PRACTICE for Examples 3 and 4

Solve the equation for y. Then find the value of y when x = 2.

11. 2x + 5y = –1 12. 3 = 2xy – x 13. 4y – xy = 28

y = 14

284 – xy =

ANSWER

y = 1

41

3 +x 2xy =

ANSWER

2x5

–15 –

y = –1

y =

ANSWER