13.8.4 example 3
TRANSCRIPT
![Page 1: 13.8.4 Example 3](https://reader031.vdocuments.mx/reader031/viewer/2022021815/5883e16b1a28ab62358b66ad/html5/thumbnails/1.jpg)
![Page 2: 13.8.4 Example 3](https://reader031.vdocuments.mx/reader031/viewer/2022021815/5883e16b1a28ab62358b66ad/html5/thumbnails/2.jpg)
Find the following values:(a)Determine the line voltage of the delta connected three-
phase generator: VL (Load)(b)Determine the phase voltage of the load: VP (Load)(c)Determine the phase current drawn by the load: IP (Load)(d)Determine the line current delivered to the load: IL (Gen)(e)Determine the phase current in the generator: IP (Gen)
![Page 3: 13.8.4 Example 3](https://reader031.vdocuments.mx/reader031/viewer/2022021815/5883e16b1a28ab62358b66ad/html5/thumbnails/3.jpg)
VL = VP = 210 V
![Page 4: 13.8.4 Example 3](https://reader031.vdocuments.mx/reader031/viewer/2022021815/5883e16b1a28ab62358b66ad/html5/thumbnails/4.jpg)
Determine the phase voltage of the delta connected three-phase generator: VP (Load)
![Page 5: 13.8.4 Example 3](https://reader031.vdocuments.mx/reader031/viewer/2022021815/5883e16b1a28ab62358b66ad/html5/thumbnails/5.jpg)
VLVP = √3 210 VP = 1.732 VP = 121.3V
![Page 6: 13.8.4 Example 3](https://reader031.vdocuments.mx/reader031/viewer/2022021815/5883e16b1a28ab62358b66ad/html5/thumbnails/6.jpg)
Determine the phase current drawn by the load: IP (Load)
![Page 7: 13.8.4 Example 3](https://reader031.vdocuments.mx/reader031/viewer/2022021815/5883e16b1a28ab62358b66ad/html5/thumbnails/7.jpg)
VPIP = ZP 121.3IP = 20IP = 6.07A
![Page 8: 13.8.4 Example 3](https://reader031.vdocuments.mx/reader031/viewer/2022021815/5883e16b1a28ab62358b66ad/html5/thumbnails/8.jpg)
Determine the line current delivered to the load: IL (Gen)
![Page 9: 13.8.4 Example 3](https://reader031.vdocuments.mx/reader031/viewer/2022021815/5883e16b1a28ab62358b66ad/html5/thumbnails/9.jpg)
IL = IP = 6.07A
![Page 10: 13.8.4 Example 3](https://reader031.vdocuments.mx/reader031/viewer/2022021815/5883e16b1a28ab62358b66ad/html5/thumbnails/10.jpg)
Determine the phase current in the generator: IP (Gen)
![Page 11: 13.8.4 Example 3](https://reader031.vdocuments.mx/reader031/viewer/2022021815/5883e16b1a28ab62358b66ad/html5/thumbnails/11.jpg)
IL IP = √3 6.07IP = 1.732IP = 3.5A
![Page 12: 13.8.4 Example 3](https://reader031.vdocuments.mx/reader031/viewer/2022021815/5883e16b1a28ab62358b66ad/html5/thumbnails/12.jpg)
Refer to Electrical Trade Principles p. 230 - 234 by Hampson & Hanssen