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  • Example 14.16 Analyzing Classical Form first movement, …182 2 G 5:5 dolce 5 5555555555E5==: 5k$ 5E5555k$ 55555k$55 5 555555555 3 5M 555E5 G 54 p 5 =5. Title: chapter14 Author: Andrew
13
Allegro G E [Main Theme] 5 5 5 5 5 5 5 5 = cresc. 5 8 5 E 5 sf 5 M 5 M 5 M 5 5 5 = = : cresc. 5 M sf 5 M 5 M 5 M 5 M 5 5 = E 3 5 5 5 3 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 137 G E = pp 8 5 E 5 5 M 5 M 5 5 5 = = : cresc. 5 M p 5 M 5 M 5 M 5 M 5 5 5 5 5 cresc. 5 M ! 5 M 5 5 5 5 5 5 5 5 5 E 5 5 ! 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 ! 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 ! 5 5 5 5 E 5 5 5 5 5 5 5 5 5 5 5 143 G E 5 5 E 5 5 5 5 5 5 5 5 5 p 5 5 5 5 5 5 3 5 5 5 5 5 6 E 5 5 5 5 G 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 E 5 5 5 5 5 5 5 5 5 5 E 5 5 5 5 5 5 5 5 E 5 Copyright © 2013 Oxford University Press Example 14.16 Beethoven, Piano Sonata in G, Op. 14, No. 2 first movement, 131–54 1 Analyzing Classical Form

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Page 1: Example 14.16 Analyzing Classical Form first movement, …182 2 G 5:5 dolce 5 5555555555E5==: 5k$ 5E5555k$ 55555k$55 5 555555555 3 5M 555E5 G 54 p 5 =5. Title: chapter14 Author: Andrew

����

Allegro

GE[Main Theme]

5 5 5 55 5 55 =

cresc.

5�8

5E 5sf

5M 5M 5M 5 5 5� = =:cresc.

5M�sf

5M 5M 5M 5M 5 5� =�E 3 5 5 5 3 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5

137

GE =pp

8 5E 55M 5M 5 5 5� = =:cresc.

5M�p

5M 5M 5M 5M 5 5 555cresc.

5M! 5M 5� 5 5 5 55� 5� 5 5��E 5 5! 555555 55555555 5 5! 555555 555555 55 5! 555 5E 555 55555555

143

GE 5� 5E 5 5 55� 5� 5 5� 5� 5p

5� 5� 5 5� 5 5 35 5 5 5 56

�E 5 5 5 5 G5 5 5 5

5 5 5 5 5 5 5 5 5 5 5 5 5E 5 5 5 5 5 5 5 5 5 5E 5 5 5 5 5 5 5 5E 5

Copyright © 2013 Oxford University Press

Example 14.16Beethoven, Piano Sonata in G, Op. 14, No. 2first movement, 131–54

1

Analyzing Classical Form

Page 2: Example 14.16 Analyzing Classical Form first movement, …182 2 G 5:5 dolce 5 5555555555E5==: 5k$ 5E5555k$ 55555k$55 5 555555555 3 5M 555E5 G 54 p 5 =5. Title: chapter14 Author: Andrew

148

GE 5 5 3 5 5 5 5 5 5 5 3 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5E 5 5 5 5 5E 5 5� 5! 5! 5E3

GE5 5 5 5 5 5 5E 5 5 5 5 5 5 5 5E 5 5 5 5 5 5 5 5E 5 555

� = 4

152

GE[Subordinate Theme]5 5 5 5 55 :: 55EE 55 :: 55 55 :: 55!! 55 55 55 55

GE 0 � 3 5 5 3 3 553 G 3 5 5 3 4

Example 14.16, Beethoven, Piano Sonata in G, Op. 14, No. 2, first movement, 131–54 (continued)

Copyright © 2013 Oxford University Press 2

Page 3: Example 14.16 Analyzing Classical Form first movement, …182 2 G 5:5 dolce 5 5555555555E5==: 5k$ 5E5555k$ 55555k$55 5 555555555 3 5M 555E5 G 54 p 5 =5. Title: chapter14 Author: Andrew

����

Allegro

G�[Main Theme]5 4 5 5 4

f5E 5 : 5 5 5 5 5 5 5 5

sf

5E 5 55L 5 5 5 5 : 5 5sf

5 5 5 5E 5 : 5 5 5 5 5 5E��

554 555 55 4

55EE 555 5 5 5 5 5 5 5 5 5 5

555555E 4 55

5555E 4

159

G� 5 : 555 55 5 55sf

5L 5 5 5 5555!� :::: 55sf

5� 555 5� : 55 5� 55 5! 5 : 5� 55 55 5� 555L 5 5 5�� 5 5

5 5 5 5 5 5 5 5 5 555

5555!� 4 555555!� 4 5� 5 5 5 5 5 5� 5 5 5 5 5

165

G�sf

5555�!� :::: 5 5�sf

5� 555 5� : 5 5� 5� 555 5 5555 5� 555 5 5� 555 4 5! 55555555�� 5�

5555!�� 4 5�5555�� 4 5� 5 5 5 5 5 5� 5 5 5 5 5 5 5 5! 5 5 5

Copyright © 2013 Oxford University Press

Example 14.17Mozart, Piano Sonata in F, K. 332first movement, 153–76

1

Analyzing Classical Form

Page 4: Example 14.16 Analyzing Classical Form first movement, …182 2 G 5:5 dolce 5 5555555555E5==: 5k$ 5E5555k$ 55555k$55 5 555555555 3 5M 555E5 G 54 p 5 =5. Title: chapter14 Author: Andrew

170

G� 5 5 5 5 5 4 5� 5 5 5 5 5! 5 5 5 5 5 5 5 5� 5 5 5! 5 B 5� 5� 5 5

�� 5 5 5 5 5 5 5! 5 5� 5 5 5 5! 5 5� 5 5 5 5 5! 5 5 5 5�

174

G�B 5� 5� 5 5 5 : 5� 5 5 5� 5 5 5L 5K 4

�� 5 5 5 5 5 5� 5 : 5� 5 5 5� 5 5 555

4

Example 14.17, Mozart, Piano Sonata in F, K. 332, first movement, 153–76 (continued)

Copyright © 2013 Oxford University Press 2

Page 5: Example 14.16 Analyzing Classical Form first movement, …182 2 G 5:5 dolce 5 5555555555E5==: 5k$ 5E5555k$ 55555k$55 5 555555555 3 5M 555E5 G 54 p 5 =5. Title: chapter14 Author: Andrew

��

��

Allegro

G���[Main Theme]

4pp5! 55555 5M 4 4 4

5 55555 5M4 4 4

ff5 5! 5555 5M

4 4 0 0 4 5B 5� �� BB : 5 5B :5 5�3 33 3 3 3

���� 4 4 5555! 555M 4 4 4 4 555 555M 4 4 4 455M 55M

4 4 0fp

B� : BB� :: BB :: BB� ::

195

G��� �5B : 5! 5 4 5B5� �� BB :5 5B :5 5� �5B : 5! 5 4 !5B5 BB :5 5B : 5� 5 5B :5 5� !5B :55 5B :5 5! 5B 555

����BB�� :: G BB�� :: BB :: BB� :: BB�� :: BB :: BB� :: BB :: BB� :: BB� :: BB! :: B! : �

207

G���p

!55 4 4 4 5� 5 5� 54 4 5 5 5 5! 4 = 5 5E 5 5! 5 = 5! 5! 5 55 = 5� 5! 5 55 B! : 5 : 5�5

���� B :5 55 5B : 55 5B : 5! 5 5B :5 5! 5B : 5 5! 5B : 5E 5 !5B : 5! 5! 5B : 5 5! 5 5 5! 555 5 555 5! 5

Copyright © 2013 Oxford University Press

Example 14.18Beethoven, Piano Sonata in C minor, Op. 10, No. 1first movement, 184–247 (R=2N)

1

Analyzing Classical Form

Page 6: Example 14.16 Analyzing Classical Form first movement, …182 2 G 5:5 dolce 5 5555555555E5==: 5k$ 5E5555k$ 55555k$55 5 555555555 3 5M 555E5 G 54 p 5 =5. Title: chapter14 Author: Andrew

217

G��� B : 5! 4 4 B : �!5 : 5!�5� B : 5! 4 4 5M! 5M 5M 5M 5M! 5M 5

M 5M! 5M 5M 5M 5M!

���� 55 5! 555 55 5! 555 5! 55555 5! 55 5 5 5 5 555 5! 5 5 555 5! 5 55 5! 5 55 5 5 5! 5 5 5

225

G���sf

B : 5!4 4 5M 5M 5M! 5M 5M 5M! sf

5M 5M 5M 5M! 5M 5M B� : 5 5 5 B� : � 5 5 5���� 5

55555 5 55555 5! 5 555 5 5! 55 555 5 555 5� 5 5 55555 5 5� 5 555 55 5! 555

233

G���fBB :: 55 :: 55�

55 BB:: 55

M!! 4 4 BB :: 55 :: 55�

55 BB :: 55M4 4

���� 5 55555 5 555 5 5 5 55555 5 55555 5! 55555 5! 55 5 5 5 5 55555 5 55555

241

G��� 5 5 5 5 5 5 5 5 5 5 5 5 B : 5! 4 45 5! 5 5 5 5 5 5 5! 5 5 5 5

cresc.

4sf

5

���� 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5! 5 5 5 5 5 5! 5 5 5 5 5 = 5 5! 5 5 5

Example 14.18, Beethoven, Piano Sonata in C minor, Op. 10, No. 1, first movement, 184–247 (R=2N) (continued)

Copyright © 2013 Oxford University Press 2

Page 7: Example 14.16 Analyzing Classical Form first movement, …182 2 G 5:5 dolce 5 5555555555E5==: 5k$ 5E5555k$ 55555k$55 5 555555555 3 5M 555E5 G 54 p 5 =5. Title: chapter14 Author: Andrew

����

Allegro

G�p

[DEVELOPMENT]

3555

pp

5555 355E 55555 4 =� EE

p55M� 555M =

35 5E 5 5M = 55M� 55M =

35 5E 5 5M = 5� 5 :55 5���

554

554 4 =� EE55M�

55M 4 4 = 55M�55M 4 0 555 5555

123

GEE 5� 5 5� 5� 5 55 5 5 48 555� 5 5 5 555 5 5 5 :55 :5 5 5 5 :55 :5 5 4 4 =

pp55M� 55M� = 35� 5 5!

�EE555 555 G 5555! 5555 555 4 555 555E 555 �

555 555 555 55 4 4 �= 55M�

55M 4

132

GEE 5M� = 55M�

�55M� =

pp

5� 5 5! 5M� = 5 55! 5M� 5 5 5! 5M 5 5 5 5� = �

p

5� 5 :55 5� 5� 5 5� 5� 5 5 53 3

�EE 4 = 55M�

55M!! 4 0 0 4 = � = G

555 555 555 5555 555 5555�

Copyright © 2013 Oxford University Press

Example 14.19Beethoven, Piano Sonata in F, Op. 10, No. 2first movement, 115–73

1

Analyzing Classical Form

Page 8: Example 14.16 Analyzing Classical Form first movement, …182 2 G 5:5 dolce 5 5555555555E5==: 5k$ 5E5555k$ 55555k$55 5 555555555 3 5M 555E5 G 54 p 5 =5. Title: chapter14 Author: Andrew

140

G�5 5 4

8 555� 5 5 5 55 5 5 5 5 :55 :5 5 5 5 :55 :5 5cresc.

=55�

5555 55555555:::: 5555�

G� 555 4 555 555! 555 555 555 555� = � 555 5555 5 555 5555 5 555 5555 5

147

G�sf

5555�5555 5555�

5555 5555� =5555 cresc. 555

5 5555:::: 55

�sf

55�55 55�

55 55� =�� 555 55555 555 5E 5 555 555 5E 5555 555 5E 5555 555 5E 5555 55 5! 5E 555 5�

153

G�p5 5� 555555 5 5� 5 55555 5 5� 555555 55 5� 5E 5555 55 5� 5E 5555 55 5� 5E 5555

�� B4 5 �55 ::5 : 55� 55� 55 55 55 555� 4 B�4 5 55 ::5 : 55��

159

G� 5 5 5� 5E 5 5 5 5 5� 5 5� 5 5! 5 5! 5 5 5 5 5 5! 5 5 5 5 =5M�

5 5= !5�

5�

��55� 55 55 55 55� 5� 5! 5�

5 !555555 5555555 55555555555555

Example 14.19, Beethoven, Piano Sonata in F, Op. 10, No. 2, first movement, 115–73 (continued)

Copyright © 2013 Oxford University Press 2

Page 9: Example 14.16 Analyzing Classical Form first movement, …182 2 G 5:5 dolce 5 5555555555E5==: 5k$ 5E5555k$ 55555k$55 5 555555555 3 5M 555E5 G 54 p 5 =5. Title: chapter14 Author: Andrew

164

G�5

=sf

5M�

5 5 5 5=

sf

!5 5 5�5� 5

=sf

!5 5 5 5 5�5� 5

=sf

!5 5 5 5 5�5�

�� 56

!5 5 5 5 5 5 56

5 5 5 5 5 5 55 5 5 5 5 5 55 5 5 5 5 5 55 5 5 5 5 5 55 5 5 5 5 5 55 5 5 5 5 5 55 5 5 5 5 5

168

G�55 5 5 5 5! 5 5 5

p

5 5 5E 5 �5 5� 5M 5�5 5 5M 5 555M

� = 555M� = 555M

5! 5 5 5

�� 555 4 0 �5 5 5 555 5M5M

5 5 55M� = 555M� = 555M

55 5M5M

Example 14.19, Beethoven, Piano Sonata in F, Op. 10, No. 2, first movement, 115–73 (continued)

Copyright © 2013 Oxford University Press 3

Page 10: Example 14.16 Analyzing Classical Form first movement, …182 2 G 5:5 dolce 5 5555555555E5==: 5k$ 5E5555k$ 55555k$55 5 555555555 3 5M 555E5 G 54 p 5 =5. Title: chapter14 Author: Andrew

����

Allegro

G���[Trans.]

5� =[Subordinate Theme]

5 5 5 5 5 5 5 5 5 5 5L 5K 5K 5E 5 5 5! 5 5 5 5 5 5 5 5 5L 5K 5K���� 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5

162

G��� 5E 5 5 5! 5 5 5 5 5� 5 5 : �!5�5 : 5 5 85! : 5 5 �!5 : 5 5 3 5 5 3 5�

���� 55 5 5 5 5 5 5 5 5 5 5 5� 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5� 5 5 5

166

G��� 5 85 : 555 55 5! 555555 5 5� 55555555 5 55 5! 5 5� 5 5! 555 5! 5 5! 5 5 5! 5 :5 5 5� 53

���� 55555555 5555 5 4 455 4 4 0 G

Copyright © 2013 Oxford University Press

Example 14.20Haydn, Piano Sonata in E-flat, H. 49first movement, 158–90

1

Analyzing Classical Form

Page 11: Example 14.16 Analyzing Classical Form first movement, …182 2 G 5:5 dolce 5 5555555555E5==: 5k$ 5E5555k$ 55555k$55 5 555555555 3 5M 555E5 G 54 p 5 =5. Title: chapter14 Author: Andrew

171

G��� 5 : �5� 55 5 5 = 5 55 5 5 5 : 555 5 5 35555 5 5 5 5555555555G��� BB : 5 � 555555555555 555555555555 555555555555 5 4 4

176

G��� 5� =5 5 5�5� = 5�5

� =�5� =5� 5�5� = 5�5

� = 5�5� 4 4 4 =

p

5 5 5 B :5 5 5 B : 5 :5 : 5$ 5$ 5$5 5 5 B :5 5 5 B :���� 5� =

5� = 5� = 5� = 5� =55!� = 5�� = 4 4 0 4 = 5� 5 5 B� 4 4 =

f

5$ 5$ 5$5� 5 5

183

G��� BBf

555!� 555! ::: 555555 5 : 5 5 5!p

5 5 5 5 5 5� 5! 5� 5! 5 5! 5 5 5 5 5K�f

5 5 5 5 5 55 5 5 5 5 5 4 555 555

���� 5� 5 5� BBB ::: BBB ::: B := 5 5 5! 5 5! B :5 5� 5� 5 5 5 5� = 4 4f

55 55!! 55�� 55 5555 555�

Example 14.20, Haydn, Piano Sonata in E-flat, H. 49, first movement, 158–90 (continued)

Copyright © 2013 Oxford University Press 2

Page 12: Example 14.16 Analyzing Classical Form first movement, …182 2 G 5:5 dolce 5 5555555555E5==: 5k$ 5E5555k$ 55555k$55 5 555555555 3 5M 555E5 G 54 p 5 =5. Title: chapter14 Author: Andrew

��������

Andante edInnocentemente1

2

G�fz

5 : 55555p fz

5 5M 5M 5M 5 : 55555p fz

5 5M 5M 5M 5 55555 5 5 5E 5� 5 5M 5M5 55555 5

G�f55M� =

p5M 5M 5M� = 4

f55ME� =

p5M 5M 5M

� = 4 0f

5 5555 5ME 5M 5 4

��f

5M� =p

5M 5M 5M� = 4f

55ME� =p

5M 5M 5M� = 4fz

555 5 5555 5 5 5 5fz

5555 555 5 5555

��f5 4 0

f5 4 0

fz

B 5 4fzB

731

2

G� 5 5E 5� 5fz

5 5 5 55555M 5 5! 5 555555 5 5E� 3p

5� 5M�35�5M�35� 5�=4cresc.

5 5! 5 :55555 5E : 5�G�

f

5 5555fz

5ME 5M B 5 5 5 55 5 5� 3p

5� 5M�35�5M�35� 5E�=4cresc.5 5E B 5 : 55555

�� 5 5 5 5fz

5555 5 5 5� = = 5! � 5 4 0 0 4cresc.

5� B 5! : 5E 5555�� 5 4

fz

B 5 : 5E� 5 5� = =p5� = 05� 4

cresc.

5 B B

Copyright © 2013 Oxford University Press

Example 14.21Haydn, String Quartet in D minor, Op. 42first movement, 66–96

1

Analyzing Classical Form

Page 13: Example 14.16 Analyzing Classical Form first movement, …182 2 G 5:5 dolce 5 5555555555E5==: 5k$ 5E5555k$ 55555k$55 5 555555555 3 5M 555E5 G 54 p 5 =5. Title: chapter14 Author: Andrew

821

2

G� 5 :5dolce

5555 55555555 5 5E = =: k5$5�k5$5 5E 55 k5$5555 5 5= =: 5� 5 5 5 5 5 5 5 5 553 5

M� 555 5E

G� 5 4p5� = 5� = 5!� = 4 5� = 5� = 5� = 4 5 : 5� 5� = 4

�� 5E 4p

5� = 5� = 5� = 4 5� = 5� = 5E� = 4 5E 5 5 5� 3 5M�� 555 5�� 5 4 0 =:

fz

5�� 0555M =:fz

5�� 0555M =:p

5M� 555 5

891

2

G� 5E 55 5!cresc.

5555 5 :5 5 5 5 5E 5E 5 5 5 5 5 55 5E 5 5 5 5 5 5 5 5E 5!f

555 5 5 5E 555 5� =

G� 0 5E :5 5 5 5 5 5 5 5 5 5 5E 55 5 5 5 5 5 5! 5 5! 5!f

5� 5 BE 5 5! 5555 5� =�� 555 5

cresc.

5 5! 5! :5 5 5 5 5 5 5E 5 5 5 5 55 5 5E 5 5 5 5 5 5 5 5Ef

555 5 55555 355M

�� 555 5cresc.

cresc.5 5E B B B BfB B 355M

Example 14.21, Haydn, String Quartet in D minor, Op. 42, first movement, 66–96 (continued)

Copyright © 2013 Oxford University Press 2


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