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UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONSInternational General Certificate of Secondary Education

1 K_o_rk_' ft_ltS_w_tr 1

[[llJJ CANDIDATE IIInNUMBER LLLU

CANDIDATENAME

CENTRENUMBER

PHYSICS

Paper 3 Extended

Candidates answer on the Question Paper.

No Additional Materials are required.

0625/31October/November 2012

1 hour 15 minutes

READ THESE INSTRUCTIONS FIRST

Write your Centre number, candidate number and name on all the work you hand in.Write in dark blue or black pen.You may use a pencil for any diagrams or graphs.Do not use staples, paper clips, highlighters, glue or correction fluid.DO NOT WRITE IN ANY BARCODES.

Answer all questions.You may lose marks if you do not show your working or if you do not useappropriate units.Take the weight of 1 kg to be 10 N (i .e. acceleration of free fall = 10m / S2).

At the end of the examination, fasten all your work securely together.The number of marks is given in brackets [ 1 at the end of each question or partquestion.

For Examiner's Use

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Total

DC (AC/SW) 49515/3© UCLES 2012

This document consists of 16 printed pages .

• UNIVERSITYu/CAMBRIDGE': :::; International Examinations [Turn over

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1 Fig. 1.1 shows the graph of speed v against time t for a train as it travels from one station to I Forthe next. Examiner's

Use

\'6

vm/s

10

Fig. 1.1

o o \0 20 60 100 120 Ilc 140 ISO 160tis

8040

(a) Use Fig. 1.1 to calculate

(i) the distance between the two stations,

d. :~+Q~CL = aft'" U~~ arfh= L1 + \_\ + ts,:(1' ~tS'X'fO) 4- (~" \r) + (.t X 'iX~)

~0 + 2 Ib0 ~ ,\'0--distance = ~.~ ..'3..0 m............ [4]

(ii) the acceleration of the train in the first 10 s.

I~ -0:LO -- i.S'v-u

t0: --

acceleration = i.~.g mls~ [2]

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(b) The mass of the train is 1.1 x 105 kg.

Calculate the resultant force acting on the train in the first 10 s.

resultant force = t.9.S' X.J.O? N..[2]

(c) The force generated by the engine of the train is called the driving force.

Write down, in words, an equation relating the driving force to any other forces acting onthe train during the period t = 10 s to t = 130 s.

.................:.D.r..;v.i~j.E"' :;;;; ~.c...~t\.E.r..u [1]

(c:kOJ Or- ai« ve.s;sttA~ [Total: 9]

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2 (a) State the factors which completely describe a vector quantity.

...................................i..r. h.a.Ci 0 m~~.l\~.tu.dP. (.s; le.~~(~ .

.................................. ON.cJ ir he.t.!. o. di~d1o.~ [1]

(b) An aeroplane is flying towards the east in still air at 92m/s. A wind starts to blow at24m/s towards the north. - --

'12 ""'Is

wJ~ t:t,,~ tat ILt 0 w irk -eG4S+

resultant speed = g.5. ~./$ .angle between resultant and easterly direction = p.1.~ .

[5]

[Total: 6]

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5 &j rc.3 (a) A stationary body is acted upon by a number of forces. State th~/tyvo conditi s ~~ For

must apply for the body to remain at rest. CoVl OI'Ho r75 Examiner's

1 N.O.~~d.~ ..fz>r.CA ~ ~.Cb .uP ~ fiir.a.~ ~.WN ..~........... Use t2 .NO ..~,&Jt-~t...~rwt.~ ~..c..'.w. ..momef1t.~ ;;. ~.m..C~.W..m.omeJS" ~ ~

[2]

(b) Fig. 3.1 shows a device used for compressing crushed material.

, 380mm 120mm ''.. •• ' •• ••IJ~!======~/~========~4~~~!==~.~Bv~

lever arm1---- plunger

20N

-cylinderl---l...I.....---1

Fig. 3.1

The lever arm rotates about the hinge H at its right-hand end. A force of 20 N actsdownwards on the left-hand end of the lever arm. The force F of the crushed nlat8rial onthe plunger acts upwards. Ignore the weight of the lever arm.

(i) Use the clockwise and anticlockwise moments about H to calculate the upwardforce F which the crushed material exerts on the plunger. The distances are shownon Fig. 3.1.

~"ii C.\V MOrnfn+,:: C. 'tV rnom.f~-tt:20 N X 500 ""'" - F'"" X 1'2.0 t'tItn

(0000 120 F--force F = B.3..'..~ N [3]

(ii) The cross-sectional area A of the plunger in contact with the crushed material is0.0036m2. Calculate the pressure exerted on the crushed material by the plunger.

© UCLES 2012

'P~ F/A':. cg '3.'3 .;. 0 ·0036

pressure = .'~3....!.Q9. 'R [2]

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4 (a) State what is meant by the centre of mass of a body.

.......................~G po:,r1i: i.n. fkD lo~ af w.h\.c.h .

................................i+s ~e; eh\:···· .Of'¥'C\.r.,s ±~ fAt.t .

............................................(..to ..be balan.l4. 0J0.QIJi.) [1]

(b) Fig. 4.1 shows an athlete successfully performing a high jump.

Fig. 4.1

The height of the bar above the ground is 2.0 m. The maximum increase in gravitationalpotential energy (g.p.e.) of the athlete during the jump is calculated using the expressiong.p.e. = mgh.

Explain why the value of h used in the calculation is much less than 2.0 m.

..............h: .;,s 1iv he·tJhf fMm.~h w~~c.h .

........ tk GI1'Iv:. f MtUJ. ~ cises.... .

........................( C.,..•.l H ~.,·.te.! ~ ••.t.b k~1..~ 2~.O'..tr.\). [1]

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(c) Fig. 4.2 shows, in order, five stages of an athlete successfully performing a pole-vault.

2

s

Fig. 4.2

Describe the energy changes which take place during the performance of the pole-vault, from the original stationary position of the pole-vaulter before the run-up, to thefinal stationary position after the vault.

I . . Gtardiilq Ivts c.hem/td ..efl~. . .Z RU.~.u.~ l<ineAl~ ~ ..~ivJ .

..........................................................................................................................................

3 Po.k ~.t MJ Stm,in!efcts:Itc.. e.nef1Y .

'-I R,~s.e [6..!entia! ~.tte~ .~nJ .'5 FD4I.1.. K:.'!Vb"c.. -eMlj} ·3J:M.'rvJ .

6 0ft ..Ha.t. ~~ 111e(m41....(krJJ b1tK!Jj .

....... .( .~O.v.".d.~ .$.~f.1.7." ..elM."i:( ..e.l'I&,)1............. [6]

[Total: 8]

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© UCLES 2012

8

(a) Explain

(i) how gas molecules exert a force on a solid surface,

..........................'JorU.:..~e.m..d ~ m.QkCJt( hit .

..........lNctl{ -.~J. reholJrd., .

............................................................................................................................ [1]

(ii) the increase in pressure of a gas when its volume is decreased at constanttemperature .

.....................l.do~c~ CoaidD- (,.kit (,JtNJs .

.......................m.o~ o.+Ie.n .

.....................$.o b..~e~ ~r.C4 c~d .

............................................................................................................................ [3]

(b) A cylinder of volume 5.0 x 103cm3 contains air at a pressure of 8.0 x 105 Pa.

A leak develops so that air gradually escapes from the cylinder until the air in the cylinderis at atmospheric pressure. The pressure of the atmosphere is 1.0 x 105 Pa.

Calculate the volume of the escaped air, now at atmospheric pressure. Assume that thetemperature stays constant.

--1

V" = '"'0 000 ~

VO\\Jme. es~:; Lto bOO - ~OOU

volume = 3S QQO ern" [4]

[Total: 8]

ForExaminer's

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500D

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6 (a) Define specific latent heat of fusion.

..........................h~J. ..re9w~d h..(•.... s.mk J. .l..~ .

.........................£w, {SO.tll. i~ l.t1J~.;J.) ~~t1.e.Jli~~~ .

...................kt/~ft;.o\Jt ~.r~.~ CJ,q~~ [1]

(b) (i) A tray of area Q1.§Jn2, filled with ice to a depth of 12 mm, is removed from arefrigerator. -- +\000

ForExaminer's

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Calculate the mass of ice on the tray. The density of ice is 920kg/m3. VO\v = A)( h=. 0·2 f... 0·012.Mass = de",~;~ X. Volucnt!...

= Q20 )( (D·2SY 0.012)

mass = 2.~.1.b k9 [2]

(ii) Thermal energy from the Sun is falling on the ice at a rate of 250 W/m2. The iceabsorbs ~ of this energy.

Calculate the energy absorbed in 1.0 s by the 0.25 m2 area of ice on the tray.- -'0 f. of 2.50 W/rnz = ISO W ImZheaf 4bforb~ ir'l t s:: 15'"0 X 0.25 =. '31Z. 5 J

'3-=7.5 Jenergy = [2]

(iii) The ice is at its melting temperature.

Calculate the time taken for all the ice to melt. The specific latent heat of fusion ofice is 3.3 x 105 J/kg.

Q = ~L ---"YV\:. 1.· S! 3. '3 X\0;

= 0·000 1136 K~

\;""e tAke" = 2. -=1-6O· 00011 L.t

time = 2~ ...3.00 S [3]

Qm--- L,,,,S

[Total: 8]

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7 (a) Explain why a liquid cools when evaporation takes place from its surface.

.......................~ra.stty ..(mDrt. ..~~ ..m1)(ecJ.v escape .

..........fv.om ..su.c.h.rtz ~ ..So. £ le.f:f: ..m.p.(eu1t~ w.lll ~tg,. .

.........................(f).wer. t{.~~ ....5peld. ..((.~1J...s? ..¥ ckc~ [2]

(b) Fig. 7.1 shows five vessels each made of the same metal and containing water.

Fig. 7.1

Vessels A, 8, e and 0 are identical in size and shape. Vessel E is shallower and wider.The temperature of the air surrounding each vessel is 20oe.

A 8 e o E

The table shows details about each vessel and their contents.

vessel outer surface volume of initial temperaturewater/crn'' ofwater/oe

A dull 200 808 shiny 200 80e dull 200 950 dull 100 80E dull 200 80

The following questions are about the time taken for the temperature of the water in thevessels to fall by 10"C from the initial temperature. .

(i) Explain why the water in 8 takes longer to cool than the water in A .

...............D"Jl .rurfa~ i.$ he.~ m~~ator.: .

..........(.!.hi(.)1" fu5 5{Q.w. (1b.w) ~'di:tba [1]

(ii) Explain why the water in e cools more quickly than the water in A.

.................C hQife.~ tkn 4. .

........................(.~aJi.r #...~.~!.~.r.~ j.~ ~) [1]

(iii) Explain why the water in 0 cools more quickly than the water in A.

.......................l{.$$. h~~ \~ 1) .

............................(¥fJ.~~~~r-'.N-d.i(l AJ. : [1]

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(iv) Suggest two reasons why the water in E cools more quickly than the water in A.

[2]

1 ~ h#.> -9~ S ..~.A..~ .................( ;?h.(j.f.o.~r...~~ ...~ ....d...l.\?U I...~ ~.&'ff.~

2 7::>w.. ~ v.c::ta(,.~ .

ForExaminer's

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[Total: 7]

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8 (a) A ray of light in air travels across a flat boundary into glass. The angle of incidence is51°. The angle of refraction is 29°.

(i) In the space below, draw a labelled diagram to illustrate this information. [3]

"51

(ii) Calculate the refractive index of the glass.

r=,bSiV'l Jh=Sj", r

refractive index = ..I.~.6.03 [2]

(b) A ray of light in glass travels towards a flat boundary with air. The angle of incidence is51°. This ray does not emerge into the air.

State and explain what happens to this ray.

~J';. fbWy';"fcrrIaf"'Htr~~c:kJ..............~~ i.\ be..C.C.~~ ~ ~ ..-J ..iI1Gtc1~Vl is .

........................~o.r.c. ~.n. -t£...,. Crih~ ..4?..1..8.~rr .

.................................................................................................................................... [2]

[Total: 7]

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9 Fig. 9.1 shows a thin, straight rod XY placed in the magnetic field between the poles of amagnet. The wires from the ends of XY are connected to a centre-zero voltmeter.

Fig. 9.1

(a) When XY is moved slowly upwards the needle of the voltmeter shows a small deflection.

(i) State how XY must be moved to produce a larger deflection in the oppositedirection. -- - -

.......................rnD.d J)Dwn.~rd.~ .

..................... l't1ovt.d. ~.sft,.r::: [2]

(ii) XY is now rotated about its central point by raising X and lowering Y. Explain whyno deflection is observed .

......................No. Y.1?~?.(.t).~Cu.r~f:) .ia:lu.tu1 .····X y a~ ~ 1.1.4. cv.z,( ./~ DfPO'Si ..J: di.~doo..r. .

..............................(Off!'k ~ao'(J7&;r.) ~ [2]

(b) The effect of moving XY can be seen if the wires are connected to the terminals of acathode-ray oscilloscope instead of the voltmeter.

(i) State the parts inside the oscilloscope tube to which these terminals are connected .

....................................y"'"' pltiJiJ [1]

(ii) The spot on the oscilloscope screen moves up and down repeatedly. State how XYis being moved .

......................()p fM.rA d.DVJn ~d.'t [1]

(iii) State the setting of the time-base of the oscilloscope during the process describedin (ii) .

.................O.f+.. I.z~r.o. : [1]

[Total: 7]

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10 (a) State the electrical quantity that has the same value for each of two resistors connectedto a battery

(i) when they are in series, G;.,rr.nt .(ii) when they are in parallel. Po.f., c(ifF (.VQ~) .

[1]

ForExaminer's

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(b) Fig. 10.1 shows a circuit with a 1.2 kQ resistor and a thermistor in series. There is nocurrent in the voltmeter.

1.2kQ-,-

9.0V II

Fig. 10.1

Calculate the voltmeter reading when the resistance of the thermistor is 3.6 kQ.

0) 1<. = 'R r + R'l.= 1.2 + 3.6 = L.. C( k.n.. = ~.IiOD

I :.V /R ~I. ~+S ')(\0- A::. q.o I '-t)~OO -

).~7S v \~J X 3'00voltmeter reading = 6..•.15 V [3]

v= I.R~

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(c) Fig. 10.2 shows a fire-alarm circuit. The circuit is designed to close switch S and ringbell B if there is a fire.

9.0V

B

Fig. 10.2

Explain the operation of the circuit.

. k; 1;,~' hi L.............. J.n ~re... ·....•......·'l"····\~········!1'~""""""""""""""""""""""""".................1011p J- 1he.r:miS'b: n$~ .

.................R.~.S..i~·~\(\·~··1\k. ..· d.«..~ .

....................CU.v:.r.e.,r.d~ y-.ises ( ..H~w.Y. .

....................HC{ ~ fi~·(J·····1··~···cJ()~S.lAO+~ .

............................o.eU r..'''' .~ .

.................................................................................................................................... [3]

[Total: 7]

Question 11 is on the next page.

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11 (a) A radioactive source emits U-, r~-and y-radiation.

Which of these radiations

(i) has the shortest range in air, .a.fpha. .....b.ekJ. .(ii) has a negative charge,

(iii) is not deflected in a magnetic field? 3Q·/fIm.(l .[2]

(b)~u.~.r~h

In a famous experiment, carried out in a vacuum, a very thin sheet of gold was placed inthe path of alpha particles.

It was found that a large number of the alpha particles passed through the sheet withlittle or no deflection from their original path. A very small number of the alpha particleswere reflected back towards the source.

(i) Explain, in terms of the force acting, why the direction of motion of an alpha particlechanges when it comes close to the nucleus of a gold atom .

..................tt~uJsj~ fO.r.U ........«.~..-f~r..tid.ts ~ .jIJJd .nucltMs..( w.~ +~.cAtt.rrJ .

............................................................................................................................ [2]

(ii) State two conclusions, about the nuclei of atoms, that were made from the resultsof this experiment.

1 I1.u.~ i.$. ~ Sm4II.. ~ .......... ...(mo.Jt ..'>.I:. ~~ ~t; r~fR.) .

2 J1u.dw.I i.s. p~~;-b..~ .

[Total: 6]

Permission to reproduce items where third-party owned material protected by copyright is included has been sought and cleared where possible. Everyreasonable effort has been made by the publisher (UCLES) to trace copyright holders, but if any items requiring clearance have unwittingly been included, thepublisher will be pleased to make amends at the earliest possible opportunity.

University of Cambridge International Examinations is part of the Cambridge Assessment Group. Cambridge Assessment is the brand name of University ofCambridge Local Examinations Syndicate (UCLES), which is itself a department of the University of Cambridge. .

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