ejemplo fellenius bishop 230515 (1)
TRANSCRIPT
Gamma = 20 KN/m3PHI´ = 30 °c´ = 25 KN/m2ru = 0.4
Reb b (m) h (m) alpha(°) l (m) W (KN) Wsen(a) Wcos(a)1 15 8 -6 15.08 2400 -250.9 2386.92 15 22 5 15.06 6600 575.2 6574.93 15 25 15 15.53 7500 1941.1 7244.44 15 30 32 17.69 9000 4769.3 7632.45 15 24 45 21.21 7200 5091.2 5091.26 15 16 58 28.31 4800 4070.6 2543.6
112.88 16196.6
FS = 0.631
FS=c ´ . La+ tanφ ´ . Σ(W cosα−ul )
ΣWsenα
u (KN/m2) Wcos(a)-u*l64 1421.6
176 3924.8200 4138.6240 3387.4192 1018.2128 -1079.6
12811.0
Gamma = 20 KN/m3PHI´ = 30 °c´ = 25 KN/m2ru = 0.4FS(asum) = 0.835
Reb b (m) h (m) alpha(°) W (KN) Wsen(a) (I) (II)1 15 8 -6 2400 -250.9 1206.4 1.0842 15 22 5 6600 575.2 2661.3 0.9473 15 25 15 7500 1941.1 2973.1 0.8744 15 30 32 9000 4769.3 3492.7 0.8245 15 24 45 7200 5091.2 2869.2 0.8366 15 16 58 4800 4070.6 2037.8 0.896
16196.6
(I) (II)FS = 0.835DIFER = 0.000
FS=1
ΣWsen αΣ {[ c ' b+W (1−ru ) tanφ ' ]
sec α
1+tan α tanφ '
FS }
(I) * (II)1308.02519.22597.02876.32399.31825.9
13525.8
L/H FS0.0 2.580.1 2.300.2 2.080.3 1.880.4 1.700.5 1.520.6 1.410.7 1.350.8 1.290.9 1.231.0 1.19
0.0 0.2 0.4 0.6 0.8 1.0 1.20.00
0.50
1.00
1.50
2.00
2.50
3.00
f(x) = 24.5098039216x̂ 6 - 77.3755656109x̂ 5 + 90.9690799397x̂ 4 - 48.8763197587x̂ 3 + 13.1429795695x̂ 2 - 3.7613766626x + 2.5809337721
Chart Title
0.0 0.2 0.4 0.6 0.8 1.0 1.20.00
0.50
1.00
1.50
2.00
2.50
3.00
f(x) = 24.5098039216x̂ 6 - 77.3755656109x̂ 5 + 90.9690799397x̂ 4 - 48.8763197587x̂ 3 + 13.1429795695x̂ 2 - 3.7613766626x + 2.5809337721
Chart Title