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Application Note
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The Future of Analog IC Technology
THE MP2905 HYSTERESIS VOLTAGE CONTROLLERBy Zhen Li
Application Engineer
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ABSTRACT
The Hysteretic Voltage Control can provide fast transient response without additional loopcompensation. With the benefits of low cost and ease of implementation, its very popular forpower supplies of microprocessors and other high-slew-rate transition loads.
The MP2905 is a synchronous PWM buck controller with the hysteretic voltage-mode control.This application note introduces the principle of hysteretic voltage control and several differentmethods to design sufficient ripple voltage for stable operation of the synchronous Buck basedon MP2905, and at last, the 25A application design with MP2905.
1. INTRODUCTION OF THE PRINCIPLE OF HYSTERETIC VOLTAGECONTROL
High reference
Low reference
HysteresisWindow
FB Voltage Ripple
High Side
Gate
Low Side
Gate
Figure 1 Principle of hysteretic voltage control
Compared with the fixed-frequency PWM control method, hysteretic voltage control doesnthave an oscillator and the error amplifier. There is only a hysteresis window with tworeferences, high reference and low reference as figure 1 shown. The output voltage is fed backto keep tracking references within the hysteretic window. Both references determine the turn-on and turn-off of the transistor to control the output voltage.
When FB is higher than the high reference, high side switch turns off, low side switch turns on,the output voltage falls down, FB falls down, too.
When FB drops to a lower level than the low reference, high side switch turns on, low sideswitch turns off, and the output voltage rises up, and FB rise up, too.
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It can react on the load current transient in the same switching cycle that the transient occurs.The key factor of hysteretic voltage control is to generate a sufficient amount ripple voltage onFB-pin to compare with the references.
MPS offers a hysteretic voltage-mode control, synchronous PWM buck controller - MP2905.This application note introduces several methods to generate the ripple voltage on FB and the
application example based on MP2905.
2. METHODS TO GENERATE THE RIPPLE VOLTAGE ON FB
There are several methods to generate the ripple voltage on FB. This chapter shows threemethods one by one.
2.1 Ripple Voltage from output Cap ESR.It is known that the voltage ripple determined by ESR is the sawtooth waveform. So weconsider to feed back the ripple voltage on ESR of output capacitor directly to FB as shown infigure 2.
MP2905
FB
SS
REF
GND
LG BST
SW
HG
IN
ILIM
VIN
VOUT
R1
R2
Cout
L
Cin
R3
C1
C2C3
Q1
Q2
Figure 2 Method One - Feedback ripple from output cap ESR to FB
Take MP2905 as an example, the required sawtooth signal level is approximately 10 mV at thecomparing point (FB-pin). This determines the Vripple at the output node like this,Vripple=VOUTx10mV/VFB, otherwise the circuit may be unstable. Ceramic capacitor is notsuitable due to the very low ESR here. Electrolytic capacitors and tantalum capacitors are
good choices, because of their larger ESR.
The operating frequency of this schematic depends on the ESR of output cap, capacitance,inductance, VIN, VOUT and the voltage-divided resistances.
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Figure 3 Equivalent circuit when High-side MOSFET on
VIN
L
ESR
Cout
R1
R2
VOUT
FB
iL
When the high side MOS is on, the circuit performs as figure 3 indicates. Assume the turn on
period of the high side MOS is INOUT V/VD,TD where , T is the operating period. The ripple of
the output voltage is mainly determined by the ESR, so:
ESR*iV LPPripple (2.1)
Li can be calculated by:
,VVTD
iL OUTIN
L
fLV
)VV(Vi
IN
OUTINOUTL
(2.2)
Where f is the operating frequency.The ripple voltage at FB:
PPrippleV2R1R
2RV
(2.3)
Combining the formula (2.1), (2.2), and (2.3), we get:
fLV)VV(VESR
2R1R2RV
IN
OUTINOUT
VLV
ESR)VV(V
2R1R
2Rf
IN
OUTINOUT
(2.4)
Actually, the V is not only due to the Hysteresis windows. It is influenced by the delay in thecircuit, such as driving signal propagation delay. Especially at higher frequency and higher VIN,the delay and noise impact frequency. As a result, the frequency calculated given by (2.4) maybe inaccurate.
Moreover, the frequency is variable with load, because the inductance isnt constant. Its
variable with load and temperature. Figure 4 shows an example that inductance drops asoutput current increasing. In this curve, the inductance @ 0A is 0.82uH, and drops to0.65uH@25A. Suppose the frequency is 500kHz@0A, according to formula (2.4), thefrequency@25A should be (5000.82)/0.65=630kHz. Besides inductance variation, the outputripple is also influenced by some parasitics such as ESL of output capacitor. This brings alarger frequency variation with load. This method is not recommended for higher currentapplication.
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Figure 4 A inductor curve- Inductance vs Current
If we use ceramic cap with lower ESR, the frequency will be very low based on the formula(2.4). Due to the low frequency and the resultant large output voltage ripple, ceramic caps
cannot be used with this design method. If a ceramic is needed, the next method canovercome these problems.
2.2 Ripple Voltage from DCR of inductorIn the Buck circuit, the ripple on the DCR of inductor is a sawtooth waveform. So we can feedback the DCR voltage instead of the ESR ripple of the output cap, as shown in figure 5. R1and C5 forms a lossless sensing circuit to get the voltage across the DCR of the inductor. R4and the ceramic cap C4 filter the output ripple for C5. With this filter, the noise on the feedbackripple of the output voltage can be greatly decreased.
This section will introduce this DCR feedback method based on the MP2905.
MP2905
FB
SS
REF
GND
LG BST
SW
HG
IN
ILIM
VIN
VOUT
Cin
Cout
L
C1
C2
R2
C4C5
R1
C3
R4
R3
Figure 5 Method Two - Feedback ripple from inductors DCR to FB
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2.2.1 Setting frequency
Figure 6 shows the equivalent circuit when low side switch is on. Assuming R4=0 and no C4,the current going through C5 is:
)1(1//255
D
fVC
dt
dvC
RR
Vi FBc
(2.5)
Figure 6 Equivalent circuit when Low-side MOSFET on
VOUT
Cout
L
R2
C5
R1
FB
ic
)V
V1(
V
V
C
1
R
1f
IN
OUTFB
5FB
(2.6)
Where21
212//1
RR
RRRRRFB
.
Assuming that V is equal to the hysteresis of the comparing window, it is obvious that thefrequency is variable with VIN. The higher input voltage, the higher frequency will be. We haveto also consider the circuit delay when calculating the voltage ripple on FB as Figure 7 shows.
The Delay consists of the FB propagation delay, dead time, driving circuit delay, etc. Forsimple calculation, only the hysteresis and FB propagation delay are considered and V isrevised as:
DELAYHY VVV (2.7)
Where VHY is hysteresis of the comparing window, VDELAY is the voltage caused by delay. Tocalculate the voltage caused by delay, VDELAY, we need to get the rising and falling slope of FBripple.
When high side switch turns on, FB is rising, figure 8 shows the Equivalent circuit. The currentgoing through C5 is:
FB
FBINFBFBIN5C
R
V
1R
V
2R
V
1R
VV
dt
dvCi
Hysteresis
Window
FB
ripple
?V
Caused by delay
Caused by delay
FB
propagationdelay
SW
falls
FB
propagationdelay
SW rise
and Dead
time
SW
Figure 7 Delay Time influence on FB ripple
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VOUT
Cout
L
R2
C5
R1VIN
FB
ic
Figure 8 Equivalent circuit of high side MOS on at DCR ripple
The FB rising speed is:
)R
V
1R
V(
C
1
C
i
dt
dv
FB
FBIN
55
CpeRising_slo (2.8)
The falling slope of FB can be calculated from the formula (2.5),
FB
FBC
R
V
5C
1
5C
iopeFalling_sl (2.9)
Table 1 lists the MP2905 FB propagation and dead time. The data are also listed in theDatasheet of MP2905.
Table 1 FB propagation and dead timeFBPropagationDelay
FB Falling to LG Falling 50ns
FB Rising to HG Falling 70ns
Dead timeHG low to LG high 40ns
LG low to HG high 40ns
The voltage caused by FB propagation:
)R
Vns20
1R
Vns70(
C
1
ns50slope_Fallingns70slope_gsinRiV
FB
FBIN
5
1DELAY
(2.10)
During the time SW falls and rises, and the dead time, the FB doesnt fall linearly because it isaffected by the driving circuit. Its difficult to calculate it accurately. We estimate it by 20ns oflinear falling slope.
1R
Vns20
C
1
R
V
C
1ns20)
R
V
1R
V(
C
1ns20
)ns20slope_Fallingns20slope_gsinRiV
IN
5
FB
FB
5FB
FBIN
5
2DELAY
(2.11)
Then,
)201
90(1
5
21
FB
FBIN
DELAYDELAYDELAY
R
Vns
R
Vns
C
VVV
(2.12)
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Combining formula (2.6), (2.7) and (2.12), the more accurate frequency can be obtained:
)V
V1(
)R
Vns20
1R
Vns90(
C
1V
V
C
1
R
1f
IN
OUT
FB
FBIN
5
HY
FB
5FB
(2.13)
Where VHY is 22mV, VFB is 590mV, and
21
21
RR
RRRFB
.
According to formula (2.13), frequency is variable with VOUT, VIN, C5 and Voltage-dividedresistors R1 and R2. As a result, the variation between frequency and input voltage isnonlinear, a higher VIN doesnt mean a higher frequency.
2.2.2 Setting Output voltageIn this method, the Feedback point is at the SW node, so the voltage regulated is the DCcomponent of SW. It is equal to VOUT plus VDCR(inductor series resistance)
DCRFBOUT VV2R
2R1RV
(2.14)
Since VDCR is variable with load, then VOUT is also variable with load, which results in bad load
regulation at the output terminal. Choosing an inductor with smaller DCR (several milliohms)can improve the load regulation.
2.2.3 Transient ResponseBecause the circuit feeds back the DC component of SW instead of the real V OUT, there is adroop caused by the DCR of inductor in steady state, which benefits the transientperformance. Transient response is highly sensitive to the inductor, the sensing capacitor C5and the voltage divided resistors R1 and R2. The time constant of the sensing network is(R1C5), the inductors time constant is (L/DCR). If the time constant of the sensing networkC5 and R1 is the same as the inductor L and DCR, the transient response can be improved.The formula below shows the relation.
DCRLCR 51 (2.15)
If the formula (2.15) is satisfied, the voltage spike during the load transient can be minimized,below is an example.
Test condition: VIN=12V, VOUT=1.8V, IOUT=0~5A, slew rate=1A/us,Setting frequency=350KHz,Selecting C5=10nF, R1=12.7k, R4=1, C4=4.4uF.
The time constant of C5 and R1 is:
s101275C1RRC_6
Choose an inductor L=2.2uH with DCR=10.2m.
The time constant of inductor is:RC_s10216DCR/LLR_
6
Figure 9 is the test result. Its not good. There is a spike when load stepping.
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Figure 9 Transient response at R5C1>L/DCR
Select another inductor with L=2.2uH, DCR=14m. The time constant of this inductor is:
s10157DCR/LLR_ 6
.
Its near the time constant of R1 and C5. Figure 10 shows the transient response. There is no
spike when load stepping, the transient performance is improved a lot.
Figure 10 Transient Response at R5C1L/DCR
If one chose an inductor L=2.2uH, DCR=21m, then the time constant of inductor is:
RC_s10041DCR/LLR_ 6
Figure 11 shows the transient response. There isnt a spike during the load transfer, buttransient response time is a little longer, and the voltage droop is bigger than figure 8 andfigure 9 because of the larger DCR.
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Figure 11 Transient response at R5C1
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Figure 13 FB ripple at no load condition with insufficient filter
Figure 14 shows waveforms at 5A load. The noise is bigger at 5A load, therefore the waveformat point B is not a DC value. The influence of the increased ripple on the FB(point A) causesthe frequency to increase from 300kHz up to about 400kHz.
Figure 14 FB ripple at 5A load with insufficient filter
When we set R4=10, C4=4.7uF, the bandwidth is reduced and the influence from noise iseliminated.
FB ripple at no load condition FB ripple at 5A load
Figure 15 FB ripple with sufficient filter
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In figure15, FB ripple is not influenced by VOUT ripple. Point B is very clean, and the frequencydrifts little under different load condition: 340KHz under no load condition and 364KHz under5A condition. However, this doesnt mean that the lower corner frequency of the filter thebetter. Too low corner of a frequency in the filter will worsen the transient response. So, thereis a tradeoff between frequency variation and transient response. Based on the test result, it isrecommended to set R4=1, C4=4.4uF. It also has some relationship with layout. Its better to
keep the wire from VOUT to point B as short as possible, and point B should be close to chip.Then a smaller filter may be enough.
For the other parameters design, please refer to MP2905 datasheet.
Although we can use ceramic caps at the output in this method, there are some additionaldisadvantages, such as bad load regulation, variable frequency with load current, and a morecomplex design. The third method may be better than the present one with respect to theseissues.
2.3 Ripple Voltage from external circuit
In this method, we use three external components to generate ripple.
MP2905
FB
SS
REF
GND
LG BST
SW
HG
IN
ILIM
VIN
VOUT
Cin
Cout
L
C1
C2
R1
C3
R3R2
C5
C4
R4
Figure16 Method Three - Feedback ripple from external circuitry to FB
Figure 16 shows a simplified diagram based on MP2905. The voltage divider R1 and R2 feeds
back the output voltage. C4, R4, and C5 circuitry form an additional ramp signal generator. C4is a DC-blocking capacitor. Its used to block the SWs DC component. Only the ACcomponent is sent to the filter R4 and C5 to generate the ripple voltage for comparison with thehysteresis. The two components are summed together at FB. Because the DC component atFB is only decided by VOUT, so there is no droop.
The VOUT can be decided by the reference voltage and the R-divider:
FBOUT V)2R
1R1(V (2.16)
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By proper selection of R4 and C5, we can get the amplitude of the additional ramp signalgenerator which is much higher than the output ripple. As a result, the output ripple can beignored, the switching frequency mainly depends on R4, C5 values. It is impacted little byoutput filter characteristics including inductance, the DCR of inductor, ESR, ESL and thecapacitance of the output capacitor.
Figure17 shows the process of getting ramp signals. SW is a square waveform including DCand AC components. After the DC blocking capacitor C4, the DC component is decoupled.The waveform at point D is a square wave without DC component, its high level is (V IN-VOUT),low level is (-VOUT). Across the filter R4 and C5, the square wave is integrated to the sawtoothripple.
VOUT
Cout
L
R1C4
R4
SW
FB
DC COMPONENT ofSW = VOUT+VDCR Vout
t
VVin
0
t
VVin-Vout
0
Vout
V
t
FBs ripple
DR2C5
Figure17 Waveform of ripple generation.
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2.3.1 Setting frequencyFigure 18 shows the equivalent circuit of high side MOS on.
VOUT
CoutL
R1C4
R4
Vin
FB
C5R2
D
Vin-Vout
iR4iC5
iR1
iR2
Figure 18 Equivalent circuit of high side MOS on
According to Kirchhoffs electric current law (KCL), we can get:
1425 RRRC iiii (2.17)
Consider VFB as a stable DC voltage, the currents through R1 and R2 are:
1
1
2
2 ,R
VVi
R
Vi FBOUTR
FBR
substituting VOUT by (2.16), 221 /RVii FBRR , therefore,
4R5C ii (2.18)
These formulas show that DC component goes through the voltage divider formed by R1 andR2. AC component goes through R4 and C5. FB can be considered as zero, when analyzingthe AC signal. Therefore:
4
4
R
VVi OUTINR
(2.19)
Combining (2.17) and (2.18) yields:
DT
VC
dt
dvC
R
VVii OUTINRC
55
4
45 (2.20)
VRCV
VVVf
IN
OUTINOUT
45
)((2.21)
In the same way, V consists of a hysteresis window and a delay component as in formula(2.7). The delay is the same as that described in figure 6. First, calculate the rising and fallingslope of FB.
According to formula (2.20), FB ripple rising slope is:
4R5CVV
5Ci
dtdv OUTIN5C
SlopeRising (2.22)
Figure 19 shows the equivalent circuit of low side MOS on.
44
455
)(0
R
V
R
Vi
dt
dvCi OUTOUTRC
(2.23)
FB ripple falling slope is:
455SlopeFalling 5
RC
V
C
i
dt
dv OUTC
(2.24)
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CoutL
R1C4
R4
FB
C5R2
D
-Vout
iR4iC5
Figure 19 Equivalent circuit of low side MOS on at external ripple
Calculate the FB propagation delay voltage as in formula (2.10),
)ns20Vns70V(RC
1
ns50RC
Vns70
RC
VV
ns50slope_Fallingns70slope_RisingV
OUTIN
45
45
OUT
45
OUTIN
1DELAY
(2.25)
Estimate the dead time and driving circuit delay voltage as in formula (2.11),
45
IN
45
OUT
45
OUTIN
2DELAY
RC
V
ns20
RC
Vns20
RC
VVns20
ns20slope_Fallingns20slope_RisingV
(2.26)
The total delay voltages are:
)2090(1
45
21 OUTINDELAYDELAYDELAY VnsVnsRC
VVV
(2.27)
Combining (2.7), (2.27) and (2.21):
)2090
(
)(
)(
45
45
45
RC
VnsVnsVRCV
VVV
VRCV
VVVf
OUTINHYIN
OUTINOUT
IN
OUTINOUT
(2.28)
Where VFB is 590mV
Frequency is influenced by VOUT, VIN, C5 and R4. Assuming VOUT, VIN are constant, we caneasily set the frequency by C5 and R4. And frequency also has nonlinear variation with inputvoltage.
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Note: If the time constant of C5 and R4 is too large, and the duty cycle is large, such asgreater than 30%. The frequency calculated by formula 2.28 is not accurate, because the FBripple doesnt rise and fall linearly. Usually, we recommend selecting R4 10%~30% less thanthe calculation.
2.3.2 Transient Response
In this configuration, there is a cap C5 paralleled with the low side voltage divided resistor.Obviously, it could worsen the transient response because of the delay. In order to minimizethe effect on the transient, the capacitance of C5 should be small. However, too small of a C5may influence the stability of FB ripple and introduce noise on FB. Capacitance between 2nFand 10nF is recommended for C5. Since frequency is set by C5 and R4, so its better to use asmaller C5 and bigger R4 to set the frequency.Besides decreasing C5s value, voltage divided resistances R1 and R2 should be smallenough, too. Small R1, R2 and C5 means short time constants, so that the time delay fromVOUT to FB pin is short. When the output changes with load stepping, the Vo will be feedbackto FB pin with little delay. So the circuit responds to the Vo quickly. However, the no loadpower consumption is higher with smaller voltage divided resistances.
The inductor also influences the transient response. Small inductance will have better transientresponse, but higher current ripple, so, there is a tradeoff.
2.4 SUMMARY
Method one is the simplest way to generate the ripple voltage for hysteresis voltage controller.But, it needs a large ripple on ESR to guarantee the stability and set the frequency. It is wellknown that ESR of capacitor cant be designed by application. So the frequency setting has todepend on the existing ESR parameter. Generally, the higher the frequency, the lower thevoltage ripple for a given output capacitance will be. So if the ESR is not big enough, circuitmay be unstable at higher frequencies.
Method two can use ceramic caps at the output. The frequency is set by R1, R2 and thesensing capacitor C5 (see figure 4). However, the load regulation characteristics make thedesign not suitable for higher current applications.
Method three seems to be a good solution for any current and any frequency application.Frequency is easy to be set with three additional components, which are independent of theoutput inductor and the output capacitor. The load regulation and transient response are goodas well.
3. MP2905 DESIGN EXAMPLE FOR 25A APPLICATION
Compared to the other two, method three is a good choice for 25A application. The 25Aapplication circuit is shown in figure20. The spec is VIN=12V (typ.), VOUT=1.8V, and IOUT=25A.The parameter design of the 25A circuit is detailed introduced as follows.
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MP2905
FB
SS
REF
GND
LG BST
SW
HG
IN
ILIM
VIN
VOUT
Cin
Cout
L
C1
C2
R1
C3
R3R2
C5
C4
R4
Figure20 Method Three - Feedback ripple from external circuitry to FB
C6
3.1 Setting frequency
With higher switching frequency, the transient can be better, and small output LC filter can beused, but power dissipation is higher. Considering these factors, the frequency is set at 300kHz.
First, choose C5. As chapter 2.3.2 described, a 2.2nF is recommended.Second, calculate R4 as in formula (2.28). Substitute in the known parameters,
k8.83VCV
)Vns20Vns90(Vf
)VV(V
RHY5IN
OUTININOUTINout
4
Choose R4=82k.
3.2 Setting the output voltageExternal voltage divider resistors (R1 and R2 in figure20) are used to set the output voltage.Per the chapter 2.3.2 description, voltage divider resistances should be small enough to getgood transient performance. So, set R2s value to be 1k, R1 is determined by:
)1V
V(2R1R
FB
OUT (2.29)
Where VFB=0.59V, VOUT=1.8V, R2=1k. Therefore,
k05.2)159.0
8.1(1000
)1V
V(2R1R
FB
OUT
Choosing a typical value 2.1k for R1
3.3 Selecting the inductorThe inductor is required to supply constant current to the output load while being driven by thesquare input voltage. A larger value inductor is favorable to reduce ripple current and loweroutput ripple voltage. However, the larger value inductor will have a larger physical size, higherseries DC resistance, and/or lower saturation current. Furthermore, the transient performance
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may be poor. A good rule for selecting the inductance is to allow the peak-to-peak ripplecurrent in the inductor to be approximately 30% of the maximum output current. Also, makesure that the peak inductor current is below the maximum switch current limit. The inductancevalue can be calculated by:
)1(
IN
OUT
LS
OUT
V
V
If
VL
(2.29)
Where VIN is the input voltage, VOUT is the output voltage, fS is the switching frequency, and ILis the peak-to-peak inductor ripple current, recommended to be 30% of the maximum outputcurrent. Substitute all the known parameters,
uH68.0)12
8.11(
253.010300
8.1
)V
V1(
If
VL
3
IN
OUT
LS
OUT
The DC current rating of the inductor must be higher than the maximum output current to keepthe temperature rise within the desired range. The inductor also needs to have a low DCR toachieve good efficiency, as well as enough room above peak inductor current beforesaturation. The peak inductor current can be estimated as follows:
)1(2 IN
OUT
S
OUTLOADLP
V
V
Lf
VII
(2.30)
The maximum inductor peak current can by calculated from formula (2.30), as 28.1A.
A1.28)12
8.11(
1082.0103002
8.125
)V
V1(
Lf2
VII
63
IN
OUT
S
OUTLOADLP
Considering all above factors, select such an inductor: 0.82uH with 0.9m DCR, 27A currentrating, and 35A saturated current which is higher than 28.1A.
3.4 Selecting Power MOSFETsThe MOSFETs are the key points for circuit efficiency. The major parameters we shouldconsider are:1) On-resistance, RDS_ON: the lower, the better it is.2) Continuous Drain Current (@10sec), IDS: it should be higher than the peak current under fullload condition. Pay attention to the variation of IDS with temperature.3) Maximum drain-to-source voltage, VDS(MAX): it should be at least 20% higher than the input supplyrail.4) Total gate charge, Qg: the lower, the better it is.For high-side MOSFET, the main power loss consists of conduction loss, switching loss, and driving
loss.The high-side MOSFET conduction loss can be calculated by:
DRIP DSON_HS2
LOADconduction_HS (2.31)
Where D is the duty cycle, its defined by INOUT V/VD
High-side MOSFET switching loss is estimated by:
SfrLOADINswitching_HS f)tt(IV2
1P (2.32)
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Where tr is the rise time of the high-side MOSFET driving signal Vgs, t f is the fall time of thehigh-side MOSFET driving signal Vgs, fS is the switching frequency.High-side MOSFET driving loss is calculated by:
driveSHS_gdrive_HS VfQP (2.33)
Where Vdrive is the high-side MOSFET driving voltage. The value in MP2905 is 5V.
For low-side MOSFET, there isnt switching loss, conduction loss is the main loss. We choosea MOSFET with lower RDS_ON. The low-side MOSFET loss consists of conduction loss, drivingloss and body diode conduction loss.The Low-side MOSFET conduction loss is calculated by:
)D1(RIP DSON_LS2
LOADconduction_LS (2.34)
Low-side MOS driving loss is calculated by:
driveSLS_gdrive_LS VfQP (2.35)
Body diode conduction loss is calculated by:
SdeadtimeLOADFbodydiode ftIV2P (2.36)
Where VF is body diode forward voltage drop, tdeadtime is the transition time between high-sideMOSFET and low-side MOFETS.Except for the losses above, there is output cap loss in both the high side MOSFET and thelow side MOSFET. Output cap loss is defined by:
S
2
DSDSCds fVC2
1P (2.37)
where CDS is the equivalent output cap of MOSFET.
For the spec: VIN=12V, VOUT=1.8V, IOUT=25A, the duty cycle is very small, then conduction loss
in the high side MOS is limited. Switching loss accounts for the main part. So when selectingthe high side MOS, we should first consider tr and tf of MOS.
For the low side MOS, the main loss is conduction loss, so the Rds-on should be as small aspossible. We can even parallel two MOSFETs at low side to minimize the Rds-on. However,we should pay attention to the driving loss. The Qg is very large if two MOSFETs areparalleled on the low side. The driving loss will cause the temperature to rise in MP2905.
Below is an example for MOS selection, use one MOS at high side, two MOS at low side.Table 2 shows several MOSFETs.
The tr and tf of MOS1 and MOS2 are small, so they are used as high side MOS. MOS3 andMOS4 are fit for low side MOS because of their low RDS_ON. Estimate the power loss in eachMOS.
Table 2 MOSFET for selectionPart Number Rds-
on(m)Qg(nC) Tr(nS) Tf(nS) VF(V)
1 AP3R303GMT-HF 5 13.3 5.5 17 -
2 AP0603GM 10.5 9 4.5 10.5 -
3 Si7658ADP 2.8 34 - - 1.1
4 AP2R403GMT-HF 3.6 20.5 - - 1.3
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According to loss analysis table3, the loss of MOS1 is lower, it is a good choice for high sideMOS at the spec because of its lower tr, tf and lower Rds-on. MOS2s loss is higher becauseof its higher Rds-on, but its switching loss is very small, so at higher frequency or higher VINspec, MOS2 may have the better performance than MOS1.
Table3 loss analysis M1 and M2 (Vin=12V, Vo=1.8V, Io=25A, fs=300kHz)MOS1 MOS2
Conduction loss 0.47W 0.98W
Switching loss 1.01W 0.675W
Driving loss 0.02W 0.014W
Total loss(neglect output cap loss)
1.5W 1.669W
According to loss analysis table4, the loss of MOS3 is much lower than MOS 4, but the Qg anddriving loss is much higher. MP2905s driving signal is generated by internal LDO. If the LDOsefficiency is not high enough, then larger Qg and higher driving loss could cause highertemperature rise at chip. The junction to ambient thermal resistance of MP2905 is 150oC/W.0.1W driving loss causes 15oC temperature rise. Considering the loss of the MP2905 internal
LDO, the temperature rise may be higher than 30oC. As a tradeoff, MOS4 with higher total lossbut lower driving loss is a more reasonable choice.
Table4 loss analysis M3 and M4 (Vin=12V, Vo=1.8V,Io=25A,fs=300kHz)MOS3 MOS4
Conduction loss 0.74W 0.96W
Body diode conduction loss 0.66W 0.78W
Driving loss 0.1W 0.06W
Total loss(neglect output cap loss)
1.5W 1.8W
For the driving circuit of the MOS, its better to slow down the high side and low side MOS turnon speed. It reduces the noise caused by switching, and insures enough dead time to avoidshoot through. We recommend placing series driving resistor to slow down the turn on speed.The resistance shouldnt be too large(less than 10 is ok), otherwise the switching loss willincrease. Part of the driving loss is now in the driving resistors which are outside the chip.Therefore, the temperature rise of chip can be lower. An anti-parallel diode is recommended,so that the turn-off speed is not reduced.
3.5 Current Limit settingMP2905 current limit can be set by an external resistor (R3 in figure 16) which is connectedbetween ILIM pin and the drain of the high side MOSFET. An internal 50uA sink current sets a
voltage drop on the resistor. The voltage drop compares to the high-side MOSFET voltagedrop (VDS) to set the peak current limit threshold. Below is the diagram of the current limitfunction:
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--
+
--
+
+--
ILIM RILIMVIN
Rdson_max
High Side
SwitchOC COM
SW
Ids
SW
V+
V-
Figure 21Current Limit Functional Diagram
The voltage drop on the high side MOSFET is:
(max)R(max)I(max)V ON_DSDSON_DS (2.38)Where IDS(max) equals the max peak inductor current ILP (max).Then, RILIM can be calculated using the VDS_ON(MAX) with the following formula:
)(50
(max)_
uA
VR
ONDS
ILIM (2.39)
RILIM should be kept in the range of 1k~ 8k.
The RDS_ON is variable with temperature. At higher temperature, RDS_ON is higher, and then thecurrent limit will be lower than the calculation. We have to consider the temperature coefficientof RDS_ON. Usually, the temperature coefficient kth is 1.2@75
oC, 1.3@90
oC, and for more exact
value, please refer to the DS of the MOS you select.Then the formula 2.39 can be corrected as:
)(50
(max) _
uA
kthRIR
ONDSDS
ILIM(2.40)
Design example: suppose we choose a high side MOS with 5m RDS_ON, 1.3 kth and 0.82uHinductor as above. Then the peak to peak value of inductor current is 6.2A. Set the max DCcurrent at 27A, then the peak current of inductor is:
AILP 1.30)2/2.6(27
Therefore:
VDS_ON(max)=30.1A5m1.3=195.7mV.
RILIM=195.7mV/50uA=3.91k.
The oscillation at SW when the high side MOS is on, the distribution of RDS_ON, the currentsense program current source and the temperature drift of the current sense program caninfluence the precision of the current limit. To ensure the circuit can always work at 25A, itsbetter to set the RILIM to be 15%~20% higher than the theoretic calculation. In the example, wecan set RILIM at 4.5k.
A small parallel capacitor (C6 in figure 20) is necessary to filter the noise on R3. 10nF isrecommended. Figure22 shows the noise waveform on R3, with C6 and without C6.
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Figure22. Noise Waveform on R3 with C6 and without C6.
3.6 Setting Input CapacitorThe input current to the step-down converter is pulsating, therefore a capacitor is required tosupply the AC current to the step-down converter while maintaining the DC input voltage. Uselow ESR capacitors for the best performance. Ceramic capacitors with X5R or X7R dielectricsare highly recommended because of their low ESR and small temperature coefficients. Theeffect of electrolytic capacitors is limited, because the electrolytic capacitor is not fit to work athigher frequency.
Since the input capacitor (Cin) absorbs the input switching current, it requires an adequateripple current rating. The RMS current in the input capacitor can be estimated by:
)1(IN
OUT
IN
OUTLOADCin
V
V
V
VII
The worse case condition occurs at VIN = 2VOUT, where ICin = ILOAD/2.
For simplification, choose the input capacitor whose RMS current rating greater than half of themaximum load current.
Make sure that capacitance is enough to provide sufficient charge to prevent excessive voltageripple at input. The input voltage ripple can be estimated by:
(1 )LOAD OUT OUTIN
S in IN IN
I V VV
f C V V
Big input ripple worsens efficiency and causes higher temperature rise in capacitors, andimpacts the stability of the circuit.
3.7 Selecting Output CapacitorThe output capacitor (Cout) is required to maintain the DC output voltage. Ceramic, tantalum,or low ESR electrolytic capacitors are recommended. A low ESR capacitor is preferred to keepthe output voltage ripple low. The output voltage ripple can be estimated by:
1(1 ) ( )
8
OUT OUT OUT ESR
S IN S OUT
V VV R
f L V f C
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Where L is the output inductance and RESR is the equivalent series resistance (ESR) of theoutput capacitor.
In the case of a ceramic capacitor, the impedance at the switching frequency is dominated bythe capacitance. The output voltage ripple is mainly caused by the capacitance. The outputvoltage ripple can be simplified:
2(1 )
8
OUT OUT OUT
S OUT IN
V VV
f L C V
In the case of tantalum or electrolytic capacitors, the ESR dominates the impedance at theswitching frequency. For simplification, the output ripple is approximated to:
(1 )OUT OUT OUT ESRS IN
V VV R
f L V
In method three, the output ripple will influence the FB ripple. The system will be unstable withlarge output ripple. So, we should minimize the output ripple with a big capacitance and lowESR. A POSCAP is recommended at the output for its large capacitance and low ESR.
3.8 PCB layout guidelinePCB layout is very important to achieve stable operation. Follow these guidelines:
1) Keep the path of switching current short and minimize the loop area formed by the inputcap, high-side MOSFET and low-side MOSFET.2) IC bypass ceramic capacitors are suggested to be put close to the IN Pin.3) Ensure all feedback connections are short and direct. Place the feedback resistors as closeto the chip as possible.4) Route SW away from sensitive analog areas such as FB.5) Connect IN, SW, and especially GND respectively to a large copper area to improve chipthermal performance and long term reliability.
6) It is suggested to add a snubber circuit across the high side MOSFET (IN pin and SW pin)so as to reduce the SW spike.7) The signal GND and power GND should be connected by a single point. This will ensure aclean control signal.8) For 25A application, four-layer or even a six-layer PCB is recommended. If we use a fourlayers PCB, make sure the copper area is big enough to create a low thermal resistance andkeep the temperature rise small. If the size of the PCB is limited, another heat sink should beused.
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MP2905
FB
SS
REF
GND
LG BST
SW
HG
IN
ILIM
Vin
Vo
Cin
Cout
L
C1
C2
R1
C3
R3R2
C5
C4
R4
Figure23 Method Three - Feedback ripple from external circuitry to FB
C6
3.9 25A demo board SCH, BOM, PCB
Figure 24Demo Board SCH
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Table5 Demo Board BOM
RefDes Value Description Package Manufacturer
C1A,C1B 22uF Ceramic Cap,25V,X5R 1210 Murata
C2A 22uF Ceramic Cap,10V,X7R 1210 Murata
C2B 100uF Ceramic Cap,6.3V,X5R 1210 MurataC2C 330uF Poscap, 6.3V Poscap Sanyo
C3,C5 10nF Ceramic Cap,50V,X7R 0603 TDK
C4 4.7uF Ceramic Cap,10V,X5R 0805 TDK
C6 1uF Ceramic Cap,50V,X7R 0805 Murata
C7 100nF Ceramic Cap,50V,X7R 0603 TDK
C8 3.9nF Ceramic Cap,50V,X7R 0603 Murata
C9,C11 2.2uF Ceramic Cap,10V,X7R 0603 Murata
C10 2.2nF Ceramic Cap,50V,X7R 0603 TDK
R1 2.1K Film Res,1% 0603 Yageo
R2 1K Film Res,1% 0603 Yageo
R3 4.99K Film Res,1% 0603 Yageo
R4 2.49 Film Res,1%
R5 82K Film Res,1% 0603 Yageo
R6 NS
R7 0 Film Res,5% 0603
R8 2 Film Res,5% 0603
R11 4.99 Film Res,1% 0603 Yageo
D1 B0530-W, 30V0.5A SOD-123 Diodes
D2 B0530-Ws-7-F,30V,0.5A SOD-323 Diodes
Q1 AP3R303GMT-HF, 30V,105A,[email protected],Qg=13.3nC,tr=5.5ns,tf=17ns@10Vgen
PowerPAKSO-8
Apec
Q2,Q3 AP2R403GMTHF,30V,130A,[email protected], Qg=20.5nC
PowerPAKSO-8
Apec
Q4 NSL1 0.82uH Inductor, Rated current=27A,Saturation
current=35A,DCR=0.9m,
SMT Wurth
U1 MP2905 MSOP10 MPS
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Top layer IN1
IN2 BOT
Figure 25Demo Board Layout
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3.10 Demo board test result1. FB RippleTest condition: Vin=12V, Vout=1.8V
No load 25A load
Figure 26FB Voltage Ripple
2. Output RippleTest condition: Vin=12V, Vout=1.8V
No load 25A load
Figure 27Output Voltage Ripple
SW
FBAC Coupling
SW
FBAC Coupling
Vo
SWSW
Vo
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3. TransientTest condition: Vin=12V, Vout=1.8V,0~25A,2.5A/us
Figure 28Transient Response
4. EfficiencyTest condition: Vin=12V, Vout=1.8V
Figure 29Efficiency Curve
0%
10%
20%
30%
40%
50%
60%
70%
80%
90%
100%
0 5 10 15 20 25 30
Io(A)
Efficiency
Vo
SW
Vo
SW
Vo
SW
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4. CONCLUSION
We compared three different methods to do hysteresis control based on the MP2905. Methodthree can fulfill any request especially with respect to the high output current case. For method3, ceramic capacitors can be used as the output capacitors. Ceramic caps keep the outputripple lower and the physical size very compact. The frequency is independent of output filter
characteristics and parasitics. The transient response of this hysteresis control is excellent withthe careful design of the feedback loop.