db make it more simpler

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    Training material for Engineers

    dBmake it more simpler

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    Goals

    ! Electromagnetic waves carry power measured inmilliwatts.

    ! Decibels (dB) use a relative logarithmic relationship toreduce multiplication to simple addition.

    ! You can simplify common radio calculations by usingdBm instead of mW, and dB to represent variations of

    power.

    ! It is simpler to solve dBcalculations in your head byusing dB.

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    Power

    !

    Any electromagnetic wave carries energy - we can feel thatwhen we enjoy (or suffer from) the warmth of the sun. Theamount of energy received in a certain amount of time iscalledpower.

    !The electric field is measured in V/m (volts per meter), thepower contained within it is proportional to the square ofthe electric field:

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    ! The unit of power is the watt(W). For wireless work, themilliwatt(mW) is usually a more convenient unit.

    P ~ E2

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    Gain & Loss

    ! If the amplitude of an electromagnetic wave increases, itspower increases. This increase in power is called again.

    ! If the amplitude decreases, its power decreases. This decreasein power is called a loss.

    ! When designing communication links, you try to maximize the

    gains while minimizing any losses.

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    Intro to dB

    ! Decibels are a relativemeasurement unit unlike theabsolute measurement of milliwatts.

    ! The decibel(dB) is 10 times the decimal logarithm of the

    ratio between two values of a variable. The calculation ofdecibels uses a logarithm to allow very large or very smallrelations to be represented with a conveniently smallnumber.

    ! On the logarithmic scale, the reference cannot be zerobecause the log of zero does not exist!

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    Why do we use dB?

    ! Power does not fade in a linear manner, but inversely as thesquare of the distance.

    !You move by xand the signal decreases by 1/x2; hence, theinverse square law.

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    1 meter away "some amount of power

    2 meters away "1/4 power at one meter

    4 meters away "1/16 power at one meter

    8 meters away "1/64 power at one meter

    !The fact that exponential relationships are involved in signalstrength measurement is one reason why we use a logarithmicscale.

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    A quick review of logarithms

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    ! If x=10y, then y=log10(x)

    ! Logarithms reduce multiplication to simple addition,

    because log(a!b)=log(a)+log(b)

    The logarithmof anumber in base 10 isthe exponent to whichten must be raised inorder to produce thenumber.

    0 1 2 3 4 5 6 7 8 910

    -5

    -4

    -3

    -2

    -1

    0

    1

    2

    log(1)=0

    log(0)=undefined

    log(10)=1

    it is called the logarithm in base 10of x

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    Definition of dB

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    ! The definition of the decibel uses a logarithm to allowvery large or very small relationsto be represented with aconveniently small number.

    ! Let assume we are interested in the ratio between twovalues a and b.

    ! ratio= a/b

    ! In dB the ratio is defined as:

    ! ratio[dB]= 10 log10(a/b)

    ! It is a dimensionless, relative measure (a relative to b)

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    Definition of dB

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    ! ratio= 10 log10(a/b)

    ! What if we now use a value of athat is 10 times bigger?

    ! newratio= 10 log10(10a/b)

    = 10 [log10(10) + log10(a/b)]= 10 log10(10) + 10 log10(a/b)

    = 10 + ratio! The new value (in dB) is simply 10 plus the old value, so

    the multiplication by ten is now expressed by

    a simple addition of 10 units.

    Rememberlog(a!b)=log(a)+log(b)

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    dBm and mW

    ! What if we want to measure an absolute power with dB?We have to define a reference.

    ! The reference point that relates the logarithmic dB scale tothe linear watt scale may be for example this:

    1 mW "0 dBm

    ! The new min dBm refers to the fact that the reference isone mW, and therefore a dBmmeasurement is ameasurement of absolute power with reference to 1 mW.

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    dBm and mW

    ! To convert power in mW to dBm:

    PdBm= 10 log10PmW

    ! To convert power in dBm to mW:

    PmW= 10PdBm/10 10 to the power of( Power in dBm

    divided by 10 )

    10 times the logarithm in base 10ofthe Power in mW

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    dBm and mW

    ! Example: mW to dBm

    Radio power: 100mW

    PdBm= 10 log10(100)

    100mW"20dBm

    Signal measurement: 17dBm

    PmW= 1017/10

    17dBm "50 mW

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    ! Example: dBm to mW

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    !

    When using dB, gains and losses are additive.

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    15

    -40

    dBm

    -30

    dBm

    -20

    dBm

    -10

    dBm

    0

    dBm

    +10

    dBm

    +20

    dBm

    +30

    dBm

    +40

    dBm

    100

    nW

    1

    W

    10

    W

    100

    W

    1

    mW

    10

    mW

    100

    mW

    1

    W

    10

    W

    -12

    dBm

    -9

    dBm

    -6

    dBm

    -3

    dBm

    0

    dBm

    +3

    dBm

    +6

    dBm

    +9

    dBm

    +12

    dBm

    62.5

    W

    125

    W

    250

    W

    500

    W

    1

    mW

    2

    mW

    4

    mW

    8

    mW

    16

    mW

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    dB and milliwatts

    It is easy to use dB to simplify the addition of gains andlosses, then convert back to milliwatts when you need torefer to the absolute power.

    1 mW = 0 dBm

    2 mW = 3 dBm 4 mW = 6 dBm 8 mW = 9 dBm 10 mW = 10 dBm20 mW = 13 dBm

    50 mW = 17 dBm100 mW = 20 dBm200 mW = 23 dBm500 mW = 27 dBm1000 mW (1W) = 30 dBm

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    Simple dB math

    How much power is 43 dBm?

    ! +43 dBm is 43 dB relative to 1 mW

    ! 43 dB = 10 dB + 10 dB + 10 dB + 10 dB + 3 dB

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    1 mW x 10 = 10 mW

    x 10 = 100 mW

    x 10 = 1000 mW

    x 10 = 10 000 mW

    x 2 = 20 000 mW= 20 W

    ! Therefore, +43 dBm = 20 W

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    What about negative values?

    Negative doesnt mean bad. ;-)

    How much power is -26 dBm?

    ! -26 dBm is 1mW (0dBm) minus 26 dB

    ! -26 dB = -10 dB - 10 dB - 3 dB - 3 dB

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    1 mW / 10 = 100 "W

    / 10 = 10 "W

    / 2 = 5 "W / 2 = 2.5 "W (2.5*10-6W)

    ! Therefore, -26 dBm = 2.5 W

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    Conclusions

    ! Using decibels (dB) provides an easier way to make calculationson wireless links.

    ! The main advantage of using dB is that gains and losses areadditive.

    ! It is simple to solve dBcalculations in your head by usingdB instead of using milliwatts.

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    Thank You!