cheat sheet

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Experiment A-1(a) Diameter of small spherical body OBSERATIONS-: Length of smallest division on main scale S=1mm || 10VSD=9MSD|| 1V=9/10S || VC=1S-1V = 1S-(9/10)S=(1/10s) || S=1mm || VC=1/10*1mm=0.1mm=0.01cm|| FOR ZERO ERROR-: i)-----cm ii)--------cm iii)-------cm || mean zero error(e)=----cm|| mean zero correction(-e)=----cm||CALCULATION-: Mean corrected dia D=(D 1 +D 2 +D 3 )/3=---cm RESULT-:The diameter of given marble is----cm. Experiment A-1(b) Volume and Hieght All same-:except CALCULATIONS-: volume=(π*d 2 )/4 || Result -: the volume of given calorimeter =----cm. Experiment no. A-2(a) Diameter of a given wire using screw guage. (same for thickness of sheet) OBSERVATION-: no.of complete rotation of circular scale y=--- || Distance moed by screw X-----mm || pitch(p)----(x/y)mm Total no.of division on circular scale N----- || Least count(p/N)---mm || ZERO ERROR CALC. SAME AS ABOVE || Mean dia d 0 =(d 1 +d 2 +d 3 )/3=----mm || mean observed dia(d 0 )=-----mm|| Mean corrected dia =(d 0 +zero correction)|| RESULT SAME Experiment no. B-2(a) To find the spr. Const. of a helical spring from load extension graph. Theory-: Spring constant of a spring is the restoring force per unit extension in spring. K=Restoring force(newton)/Ext.(mtrs) OBSERV-: Original length of the helical spring =----cm || least count of the vertical scale: || Distance b/w two long closest marks=---L 0 cm ||no. of div b/w them=---(n) || least count LC=----(L 0 /n) ||Mass of hanger of slotted weights -----gm || Mass of each slotted weights----gm || CALC.-: choose 2 suitable pts. L and M wide apart on thr graph from point M drop perp lr MN on x axis and from point L draw a dotted per lr to y axis meeting MN at point N || Slope=f/l=MN/LN || since spring factor K=f/l hence value of MN/LN=K=-----Kg wt/m=-----Nm -1 . Experiment no.B-5(viscocity) Theory- According to strokes law when a sphere of radius r is allowed to fall freely in aliquid of viscocity η, it aqquires a term. Velocity|| viscous Force= 6πrηv||according to archi..Principle the up. Buyount force = weight of the vol. of water displ. By sphere so, F=4/3πr 3 ρg-4/3πr 3 σg. Hence 6ηπrv=4/3πr 3 (ρ-σ)g||v=(2/9)r 2 /η(ρ-σ)g||by this find η. ||| OBSERATION-: 1. Least count of screw guage---cm 2. Length of wide bore tube=---cm 3. Least count of stopwatch=-----sec 4. Temp of Glycerine---- 0 C 5. Density og gyl.----gcm -3 6. Density of

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Page 1: Cheat Sheet

Experiment A-1(a) Diameter of small spherical bodyOBSERATIONS-: Length of smallest division on main scale S=1mm || 10VSD=9MSD|| 1V=9/10S || VC=1S-1V = 1S-(9/10)S=(1/10s) || S=1mm || VC=1/10*1mm=0.1mm=0.01cm|| FOR ZERO ERROR-: i)-----cm ii)--------cm iii)-------cm || mean zero error(e)=----cm|| mean zero correction(-e)=----cm||CALCULATION-: Mean corrected dia D=(D1+D2+D3)/3=---cmRESULT-:The diameter of given marble is----cm.Experiment A-1(b) Volume and HieghtAll same-:except CALCULATIONS-: volume=(π*d2)/4 || Result -: the volume of given calorimeter =----cm.Experiment no. A-2(a) Diameter of a given wire using screw guage. (same for thickness of sheet)OBSERVATION-: no.of complete rotation of circular scale y=--- || Distance moed by screw X-----mm || pitch(p)----(x/y)mmTotal no.of division on circular scale N----- || Least count(p/N)---mm || ZERO ERROR CALC. SAME AS ABOVE|| Mean dia d0=(d1+d2+d3)/3=----mm || mean observed dia(d0)=-----mm|| Mean corrected dia =(d0+zero correction)||RESULT SAMEExperiment no. B-2(a) To find the spr. Const. of a helical spring from load extension graph.Theory-: Spring constant of a spring is the restoring force per unit extension in spring. K=Restoring force(newton)/Ext.(mtrs)OBSERV-: Original length of the helical spring =----cm || least count of the vertical scale: || Distance b/w two long closest marks=---L0 cm ||no. of div b/w them=---(n) || least count LC=----(L0/n) ||Mass of hanger of slotted weights -----gm ||Mass of each slotted weights----gm || CALC.-: choose 2 suitable pts. L and M wide apart on thr graph from point M drop perplr MN on x axis and from point L draw a dotted perlr to y axis meeting MN at point N || Slope=f/l=MN/LN || since spring factor K=f/l hence value of MN/LN=K=-----Kg wt/m=-----Nm-

1.Experiment no.B-5(viscocity)Theory- According to strokes law when a sphere of radius r is allowed to fall freely in aliquid of viscocity η, it aqquires a term. Velocity|| viscous Force= 6πrηv||according to archi..Principle the up. Buyount force = weight of the vol. of water displ. By sphere so, F=4/3πr3ρg-4/3πr3σg. Hence 6ηπrv=4/3πr3(ρ-σ)g||v=(2/9)r2/η(ρ-σ)g||by this find η. ||| OBSERATION-: 1. Least count of screw guage---cm2. Length of wide bore tube=---cm 3. Least count of stopwatch=-----sec 4. Temp of Glycerine----0C 5. Density og gyl.----gcm-3 6. Density of material of steel bal=----gcm-3 7. Least count od screw guage -----cm 9. Mean internal dia of wide bore tube=----cm || Distance b/w A and B =-----cm || B and C=----cm ||g=980cm/s2 || CALC. slope =BC/CA also, v/r2=(2/9)g(ρ-σ)/η=m=slope find η ----poiseEXPERIMENT no.(RESONANCE)Theory-: If l1 and l2 are the lengths of the air column for the first and the second position of resonance so, we get l1=x+λ/4 and l2 = x+ 3λ/4 where x is the end correction. Subtracting 1 from 2 we have l2-l1=λ/2 or λ=2(l2-l1) or V= vλ where V and v are velocity and freq. of sound resp.|| OBS-: 1. Frequency of 1st tuning fork -480Hz 2. Freq of 2nd tuning fork 512Hz 3. Room temp in beginning ----0C 4. Room temp at end ---0C 5. Position of upper end A of the resonance tube r1=----cm|| CALC. 1. V1=2v1(l2-l1)=-------m/s 2. Similarly calc. V2 and vt=(v1+v2)/2 3. Mean room temp---(t1+t2)/2 4. Velocity of sound at 00C - v0=(vt-0.61t)=---m/s

Page 2: Cheat Sheet

ExperimentNo.(Viscocity)No.of obs Dia(d1) Dia(d2) Mean

diameterMean.Radius R2 L(dis b/w

bands)Timetaken from A->B

T.T from B->C

Mean Time

Velocity

1 2.08 2.09 4.16 2.08 4.3264

Experiment No.(Spring)

No.of Obs Load suspended (W)Gm wt.

Load increasing(x cm)

Load Decreasing(y cm)

Mean(x+y)/2=r Extension for load wL cm

1 0 0 0.5 R0=0.25 0.52 20 0.5 1.1 R1=0.8 0.63 40 104 2.5 R3=2.0 1.14 60 2.4 3. R4=2.7 0.65 80 3.3 3.9 R5=3.6 0.66 100 4.2 4.6 R6=4.4 0.47 120 5.1 5.5 5.3 0.48 140 5.7 6.1 5.9 0.49 160 7 7 7 0Experiment(Vernier calliper)

S.no Main scale(M)(cm)

Vernier Division(n)coincinding with Main.Scale

V.S.R(n)X(V.C)(cm)=y

Obsereved Dia(M+y)

123Instead of y use x incase of depth and use h instead of D.

S.no Pitch Scale Reading(M) cm

Circular scale div in line with main scale

Diamter=M+n X (LC) Mean dia

123Instead of dia use thickness.

Freq of fork Resonance No.of obs Water is falling

Water is rising

Mean r2 MeanR2-r1

480 1st 1.2.

2nd 1.2.

512 1st 1.2.

2nd 1.2.