capacity planning
TRANSCRIPT
Capacity Planning
Capacity Planning
• Capacity denotes in general the extent of availability of these resources for use by various processes
• It also denotes the maximum output of products and services one can achieve using these resources
• Capacity planning is a systematic approach to – Estimate the amount of capacity required,
– Evaluation of alternative methods of augmenting capacity
– Devise methods to use capacity effectively
• Capacity planning is important– It has a significant impact on the cost of operation of the system due to
large fixed costs associated with capacity
• Economies of scale is an concept in economics related to capacity
Economies of ScaleAn illustration
2000 units per month
5000 units per month
10,000 units per month
Units of output
Avera
ge u
nit
cost
of
ou
tpu
t
Capacity buildup Alternative modes
Units
Units
Units
TimeTime
Units
Capacity
Demand
Typical mode
Proactive modeReactive modeTime
Input measures of capacity
• Firms operating in low volume, high variety situation find it relevant – Refining capacity of BPCL refinery in Mumbai is
260,000 barrels of crude per day – Television manufacturer often measures its capacity
by millions of picture tubes that it produces – Tool room facility will measure its capacity in terms of
machine hours– A hospital will measure the capacity in terms of
number of beds.
Output measures of capacity
• When the volume of production is high and the variety is relatively low output measures are useful– Toyota Kirloskar Auto Parts measures it capacity in terms
of number of transmission gear boxes it can produce
– Tata Bearings, a division of Tata Steel, has a capacity of 25 million pieces per annum
– MICO Bosch has an installed capacity of one lakh distributor pumps at its Jaipur plant
– An automated car wash facility’s capacity can be measured in terms of number of cars serviced per day
Japanese notion of capacity
• Capacity = Work + Waste• Nine types of waste according to Canon
production system:– Waste in Operations– Waste in Startup– Waste in Equipment– Waste in Defects– Waste in Materials– Waste in Indirect Labour– Waste in Human Resources– Waste in expense
Capacity PlanningTime Horizon
Long term Medium term Short-termTime frame 2 - 5 years Typically 1 year 1 week to 3 months
Planning premiseAugmenting capacity for projected growth
Balancing demand - supply Maximising availability; Efficent use of resources
Key decisions made
Capacity Augmentation; Capital Budgeting Exercises
Adjusting demand and supply attributes to balance available capacity to requirement
Resource deployment strategies, Maintenance routines, Improvement projects to be undertaken
Tools & Techniques used
Investment planning; Break-even analysis, Discounted cash flow techniques; Decision Trees
Aggregate Production Planning; Make or Buy
Planning & Scheduling, Total Productive Maintenance, Waste elimination by continuous improvement; Simulation; Heuristics;Waiting line models
Time Horizon for planningCriterion
Capacity Planning Framework
Estimate the capacity requirements for the
planning horizon
Compute the available capacity & identify
quantum of capacity to be augmented
Identify available alternatives & select the
best one for capacity augmentation
Capacity PlanningComputational steps
• Estimate the total requirement for the planning horizon
• Estimate Labour and Machine requirements
• Compute Capacity Availability• Compare availability with Requirement• Evaluate alternative methods for capacity
augmentation
Capacity requirements
• Projected demand per unit time during the = D
planning horizon
• Standard labour hours required per unit of product = SL
• Efficiency of labour = EL
• Capacity requirements (Labour) =
• Capacity requirements (Machine) =
L
L
E
SD*
M
M
E
SD*
Capacity Availability
• System availability– Number of working days in the planning horizon: Nd
– Number of working hours per day: h
– System availability (Hours) = Nd * h
• Resource availability– Number of machines available: Nm
– Machine: Time lost in breakdowns & maintenance = b %
– Number of workers available: NL
– Labour: Absenteeism of the workers = a %
• Capacity available in the system (Hours)– Machine: Nd * h * Nm * (1 – b/100)
– Labour: Nd * h * NL * (1 – a/100)
Capacity AugmentationAlternatives
• Waste Elimination
• Multi-tasking of workforce
• Sub-contracting/Outsourcing
• De-bottlenecking
• Addition of new capacity
Problem
• A product is manufactured in a shop using a five-stage process. The first step in the process is to cut the sheet metal to required shapes and sizes using a shearing process. After the shearing process, the components are subjected to pressing operations to alter the shape of the flat sheet as per the design. In the third stage of the process welding is done to join the components. The next step in the process is a painting operation. After painting, the components are packed and kept ready for dispatch.
• The time take for each of these operations are 20, 30, 15, 12 and 6 minutes respectively.
• Presently, each stage has only one machine for operation. • Map the process and analyse the capacity with respect to the following scenarios:
– If the shop works for an 8-hour shift with an effective available time of 450 minutes, what is the production capacity of the shop?
– Where is the bottleneck in the system? If we want to add one machine, where should we make the investment?
– Identify the additional capacity required for a daily production target of 25 units. Compute the utilisation of the machines as per the revised capacity calculations.
Shearing (20 minutes)
Pressing (30 minutes)
Welding (15 minutes)
Painting (12 minutes)
Packing (6 minutes)
The production capacities are:
– Shearing: 450/20 = 22.50 Pressing: 450/30 = 15.00
– Welding: 450/15 = 30.00 Painting: 450/12 = 37.50
– Packing: 450/6 = 75.00
• The smallest number in the above calculation limits the production capacity for the shop. Therefore, the current production capacity is 15 units per day.
Shearing (20 minutes)
Pressing (30 minutes)
Welding (15 minutes)
Painting (12 minutes)
Packing (6 minutes)
Bottleneck
The production capacities are:
– Shearing: 450/20 = 22.50 Pressing: 450/30 = 15.00
– Welding: 450/15 = 30.00 Painting: 450/12 = 37.50
– Packing: 450/6 = 75.00
• The smallest number in the above calculation limits the production capacity for the shop. Therefore, the current production capacity is 15 units per day.
Shearing (20 minutes)
Pressing (30 minutes)
Welding (15 minutes)
Painting (12 minutes)
Packing (6 minutes)
Shearing (20 minutes)
Pressing (30 minutes)
Welding (15 minutes)
Painting (12 minutes)
Packing (6 minutes)
Pressing (30 minutes) Bottleneck
• The production target is 25 per day now. Since a day has 450 minutes, the maximum time that the process can take in each stage is 18 minutes. – Packing, Painting and Welding sections have timings less than 18.
Therefore, they do not need any more investment in capacity.
– By adding one more machine at the pressing stage, the effective time will be less than 18 minutes.
– Similarly, by adding one more machine at the shearing stage, the effective time will be 10 minutes.
– Utilisation of Shearing =
– Utilisation of Pressing =
– Utilisation of Welding =
– Utilisation of Painting = 66.67% Utilisation of Packing = 33.33%
%56.55450*2
20*25
*
*
timeavailablemachinesofnumber
timeprocessproductionDaily
%33.83450*2
30*25
%33.83450*1
15*25
Bottleneck & Capacity Analysis The Wandering Bottleneck
Shearing (20 minutes)
Pressing (30 minutes)
Welding (15 minutes)
Painting (12 minutes)
Packing (6 minutes)
Shearing (20 minutes)
Pressing (30 minutes)
Welding (15 minutes)
Painting (12 minutes)
Packing (6 minutes)
Pressing (30 minutes)
Hierarchies in capacity estimation
First operation
Fabrication Shop
Paint Shop
Electrical & Wiring
Assembly & Testing
Shearing Unit
Pressing Unit
Welding Unit
CNC Turret Press
Hydraulic Press
NC Press Brake
63 Tonne ECC Press
Denotes bottleneck in the process
Capacity Planning under uncertaintyUse of waiting line models
• Often demand placed on resources is uncertain making capacity requirement estimation difficult
• In such cases, waiting line models – make use of queueing theory fundamentals
– to analyse the impact of alternative capacity choices
– on important operational measures such as queue length, waiting time and utilisation of resources
• In service systems, waiting time is an important operational measure that determines the service quality – Computerised passenger reservation facility of Indian Railways
– Banking system or BSNL’s bill payment counters
Components of Queuing System
ArrivalsServer Served
customersWaiting
Line
Calling Populatio
n
Components of Queuing Systems
Calling Population
Arrival Parameters
System Structure & Parameters
Service Parameters
Infinite
Finite
Rate
Pattern
Markovian, General Distbn., Deterministic
Single, Bulk, Special group
Servers
Stages
Routing
Capacity
Single, Multiple
Single, Multiple
Single, Serial, Network
Finite, Infinite
Markovian, General Distbn., Deterministic
Performance Metrics
Queue length, Waiting time, Utilisation, Cost based
Queue Parameters
FCFS, LCFS, Random, Balk, Renege, Jog
Single-Channel Structures
Servers
Waiting line
Single-server, multiple stages
Waiting line Server
Single-server, single-stage
Multi-Channel Structures
Servers
Servers
Waiting line
Multiple-servers, single stage
Multiple-servers, multiple-stages
Single Server QueueFormulae for Lq
Lq =
Single server Queue
(Exponential service time)
Ls Average number of customers in the system (waiting to be served)
Lq Average number of customers in the waiting line
Ws Average time a customer spends in the system (waiting and being served)
Wq Average time a customer spends waiting in line
mean arrival rate
mean service rate
S Number of servers in a multi-server queue
Performance MetricsRelationships
Ws =Ls
Wq =
Average time customerspends in system
Average time customer spends in queue
Lq
Ls = Lq +
Average number of customers in system
Little’s Formula
S
Server utilisation
In the case of single server:
In the case of multiple servers:
In the case of a Single Server
Problem• The teller facility of a bank has a one-man operation at present.
Customers arrive at the bank at the rate of one every 4 minutes to use the teller facility. The service time varies randomly across customers on account of some parameters. However, based on the observations in the past, it has been found that the teller takes on an average 3 minutes to serve an arriving customer. The arrivals follow Poisson distribution and the service times follow exponential distribution.
– What is the probability that there are at most three customers in front of the teller counter?
– Assess the various operational performance measures for the teller facility.
– Of late the bank officials notice that the arrival rate has increased to one every three and a half minutes. What is the impact of this change in the arrival rate? Do you have any observation to make?
Solution to Problem
• Arrival rate at the bank: = = 15 per hour• Service rate at the teller: = = 20 per hour
• Utilisation of teller facility:
• Probability of at most three customers in the system =
• Using equation, we compute Pn for values of n = 0 to 3P0 = (1- ) = 0.25; P1 = 0.25*0.751 = 0.1875; P2 = 0.25*0.752 = 0.1406; P3 = 0.25*0.753 = 0.1055.
• Probability of at most 3 customers =0.25 + 0.1875 + 0.1406 + 0.1055 = 0.6836
75.020
15
3
0
n
nnP
Operational Performance Measures
Avg. No. of customers in the waiting line:
Avg. No. of customers in the system:
Avg. time a customer spends waiting in line:
Avg. time a customer spends in the system:
)(
2
qL
qs LL
q
q
LW
s
s
LW
Operational Performance Measures
Avg. No. of customers in the waiting line:
Avg. No. of customers in the system:
Avg. time a customer spends waiting in line:
Avg. time a customer spends in the system:
25.2)1520(20
15
)(
22
qL
00.320
1525.2
qs LL
min915.015
25.2 Hr
LW qq
min1220.015
00.3 Hr
LW ss
Impact of Arrival Rate
Arrival rate = 15 per hour
Arrival rate = 17.143 per hour
Utilisation of the teller facility 75% 85.7%
Avg. number of customers in waiting line
2.25 5.14
Avg. number of customers in the system
3.00 6.00
Average time a customer spends waiting in line
9 minutes 18 minutes
Average time a customer spends in the system
12 minutes 21 minutes
Capacity Design issue Flexibility/Utilization Trade-
off
Utilization () 100%0 Op
era
tional Perf
orm
an
ce
Measu
res
High utilizationLow cost of operationPoor service
Low utilizationHigh cost of operationGood service
Cost Relationship in QueuingE
xpe
cte
d c
ost
s
Level of service
Total cost
Service cost
Waiting Costs
Formulae For Lq
Three types of Queuing systems
Lq =
Single server QueueExponential service time
Lq =
Single server QueueGeneral service time
Lq =
=
=
Single server QueueDeterministic service time
Multi-Server QueuesApproximation for Lq based
on dataXa_ Mean Inter-Arrival Time
(IAT)Xs
_
Mean Service Time (ST)Sa Standard deviation of inter-arrival
timeSs Standard deviation of service timeCa Coefficient of variation of IATCs Coefficient of variation of ST
=_
Mean arrival rate = Xa
_1/
=Ss/Xs
_
Utilisation of the ‘s’ servers = S Mean service rate Xs
_
1/=
2*
)1(
22)1(2sa
S
qCC
L
Sa/Xa
Source: Chase, R.B, F.R. Jacobs, and N. J. Aquilano, (2003), “Operations Management for competitive advantage”, Tata McGraw Hill, 10th Edition, pp 261 – 262.
_
Capacity ManagementServices
Peak HourPeak Hour• Assemble to order• Service Portfolio
(narrow)• Demand Mgmt.
– Reservations
• Exploiting – Multi-skill labour– Flexible work force
Non-Peak HourNon-Peak Hour• Made to order• Service Portfolio
(wide)• Demand Mgmt.
– Special Tariffs, offers