calculate the final molarity if 75.0 ml of a 5.0 m naoh solution were diluted to a final volume of...

43
Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Upload: roy-page

Post on 25-Dec-2015

218 views

Category:

Documents


2 download

TRANSCRIPT

Page 1: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0

mL. M1V1 = M2V2

0.58 M NaOH

Page 2: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Jared believes that equilibrium means the concentration of

reactants is equal to the concentration of products. Do you

agree or disagree? Explain your answer.

Disagree because concentrations do not have to be equal at equilibrium

Page 3: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Explain the difference between activation energy and activated complex?

Activation energy is the minimum amount of energy needed to react

Activated complex is the intermediate between reactants and products

Page 4: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Explain the following P.E. diagram using correctly the terms endothermic and exothermic processes and reactions.

Exothermic reaction

Endothermic process

Exothermic process

Page 5: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Which way would a system at equilibrium shift if products were

removed?Towards the right (products)

Page 6: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Joe believes that a reaction stops when it reaches equilibrium. Do you agree or disagree? Explain

your answer.Disagree because equilibrium is

mainly about forward and reverse rates canceling each other out

Page 7: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Which way would a system at equilibrium shift if heat were

added to an exothermic reaction?

Towards the left (reactants) because heat is like a product in exothermic

reactions (heat released)

Page 8: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Calculate the initial molarity of a Pb(NO3)2 solution if 40.0 mL were diluted to make 2.10 L of a 0.50 M

Pb(NO3)2 solution. M1V1 = M2V2

26 M Pb(NO3)2

Page 9: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Which is the more diluted solution? Explain.

Page 10: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Explain how using reactants with a smaller surface area would affect the reaction rate in terms of the

collision of particles.Smaller surface area would decrease

reaction rate because less particles are exposed for collisions to occur

Page 11: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Which part of the P.E. diagram represents change in enthalpy?

Page 12: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

What is the molar mass of Li2S? Please include units.

45.95 g/mol Li2S

Page 13: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Calculate the volume of a 6.0 M KOH solution needed to make

850.0 mL of a 1.20 M solution?M1V1 = M2V2

170 mL of 6.0 M KOH

Page 14: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Which way would a system at equilibrium shift if products were

added?Towards the left (reactants)

Page 15: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Which is the more concentrated solution? Explain.

Page 16: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Which way would a system at equilibrium shift if reactants were

added?Towards the right (products)

Page 17: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

How many grams of MgSO4 are required to prepare 350.0 mL of a

1.50 M solution?M = mol/L

63.2 g MgSO4

Page 18: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Explain how decreasing the concentration of reactants would

affect the reaction rate in terms of the collision of particles.

Decreasing concentration would decrease reaction rate because less

particles would be available to collide

Page 19: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

What is the molar mass of KOH? Please include units.

56.11 g/mol KOH

Page 20: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Will this reaction be hot or cold to the touch? Explain.

Hot because energy from the reaction is released to your hand

Page 21: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Which is the solvent in this solution?

Page 22: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Which way would a system at equilibrium shift if heat were

removed from an endothermic reaction?

Towards the left (reactants) because heat is like a reactant in endothermic

reactions (heat absorbed)

Page 23: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Which way would a system at equilibrium shift if heat were

added to an endothermic reaction?

Towards the right (products) because heat acts like a reactant in

endothermic reactions (absorbed)

Page 24: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Calculate the final volume in milliliters of a NH4Cl solution if

125.0 mL of a 7.0 M solution were diluted to 0.15 M.

M1V1 = M2V2

5800 mL NH4Cl

Page 25: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Is the reaction endothermic or exothermic? Explain.

Exothermic because energy of products is less than energy of

reactants

Page 26: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

What is the molar mass of HC2H3O2? Please include units.

60.06 g/mol HC2H3O2

Page 27: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Which way would a system at equilibrium shift if heat were removed from an exothermic

reaction?Towards the right (products) because heat is like a product in exothermic

reactions (heat released)

Page 28: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Which is the solute in this solution?

Page 29: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Which way would a system at equilibrium shift if reactants were

removed?Towards the left (reactants)

Page 30: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

What is the molarity of a solution containing 28.0 g of magnesium

chloride in enough water to make 1.50 L of solution?

M = mol/L0.196 M MgCl2

Page 31: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Calculate the final molarity if 15.0 mL of a 3.0 M NaOH solution were diluted to a final volume of 450.0

mL. M1V1 = M2V2

0.10 M NaOH

Page 32: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Calculate the initial molarity of a Pb(NO3)2 solution if 200.0 mL were diluted to make 1.00 L of a 0.30 M

Pb(NO3)2 solution. M1V1 = M2V2

1.5 M Pb(NO3)2

Page 33: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

What is the molar mass of sodium hydroxide? Please include units.

40.00 g/mol NaOH

Page 34: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Calculate the volume of a 2.0 M KOH solution needed to make

150.0 mL of a 0.50 M solution?M1V1 = M2V2

38 mL of 2.0 M KOH

Page 35: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

How many grams of sodium chloride are required to prepare 150.0 mL of a 2.50 M solution?

M = mol/L21.9 g NaCl

Page 36: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

What is the molar mass of HCl? Please include units.

36.46 g/mol HCl

Page 37: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Calculate the final volume in milliliters of a CaCl2 solution if 25.0

mL of a 6.0 M solution were diluted to 0.10 M.

M1V1 = M2V2

1500 mL CaCl2

Page 38: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

What is the molar mass of C6H12O6? Please include units.

180.18 g/mol C6H12O6

Page 39: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Explain the difference between activation energy and activated complex?

Activation energy is the minimum amount of energy needed to react

Activated complex is the intermediate between reactants and products

Page 40: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Explain the following P.E. diagram using correctly the terms endothermic and exothermic processes and reactions.

Endothermic reaction

Endothermic process

Exothermic process

Page 41: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Which part of the P.E. diagram represents change in enthalpy?

Page 42: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Is the reaction endothermic or exothermic? Explain.

Endothermic because energy of products is greater than energy of

reactants

Page 43: Calculate the final molarity if 75.0 mL of a 5.0 M NaOH solution were diluted to a final volume of 650.0 mL. M 1 V 1 = M 2 V 2 0.58 M NaOH

Will this reaction be hot or cold to the touch? Explain.

Cold because energy from your hand is absorbed in the reaction