© 2013 pearson education, inc. chapter 8, section 5 1 learning check what is the molarity (m) of a...

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© 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH to 60.0 mL?

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Page 1: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 1

Learning Check

What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH to 60.0 mL?

Page 2: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 2

Solution

What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH to 60.0 mL?

Step 1 Prepare a table of the concentrations and volumes of the solutions.

Analyze the Problem.

Page 3: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 3

What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH to 60.0 mL?

Step 2 Rearrange the dilution expression to solve for the unknown quantity.

Step 3 Substitute the known quantities into the dilution expression and calculate.

Solution

Page 4: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 4

Guide to Calculations Involving Solutions in Chemical Reactions

Page 5: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 5

Learning Check

How many liters of 3.00 M HCl are needed to completelyreact with 4.85 g of CaCO3?

Page 6: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 6

Solution

How many liters of 3.00 M HCl are needed to completelyreact with 4.85 g of CaCO3?

Step 1 State the given and needed quantities.

Analyze the Problem.

Page 7: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 7

Solution

How many liters of 3.00 M HCl are needed to completelyreact with 4.85 g of CaCO3?

Step 2 Write a plan to calculate the needed quantity or concentration.

mass molar moles mole–mole moles molarity litersof CaCO3 mass of CaCO3 factor of HCl HCl of HCl

Page 8: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 8

Solution

How many liters of 3.00 M HCl are needed to completelyreact with 4.85 g of CaCO3?

Step 3 Write equalities and conversion factors including mole–mole and concentration.

Page 9: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 9

Solution

How many liters of 3.00 M HCl are needed to completelyreact with 4.85 g of CaCO3?

Step 3 Write equalities and conversion factors including mole–mole and concentration.

Page 10: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 10

Solution

How many liters of 3.00 M HCl are needed to completelyreact with 4.85 g of CaCO3?

Step 4 Set up the problem to calculate the needed quantity or concentration.

Page 11: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 11

Learning Check

If 22 mL of 0.10 M MgCl2 is needed to completely react 15 mL of AgNO3 solution, what is the molarity of AgNO3?

Page 12: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 12

Solution

If 22 mL of 0.10 M MgCl2 is needed to completely react15 mL of AgNO3 solution, what is the molarity of AgNO3?

Step 1 State the given and needed quantities. Analyze the Problem.

Page 13: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 13

Solution

If 22 mL of 0.10 M MgCl2 is needed to completely react15 mL of AgNO3 solution, what is the molarity of AgNO3?

Step 2 Write a plan to calculate the needed quantity or concentration.

volume molarity moles mole–mole moles of MgCl2 MgCl2 of MgCl2 factor of AgNO3

Page 14: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 14

Solution

If 22 mL of 0.10 M MgCl2 is needed to completely react15 mL of AgNO3 solution, what is the molarity of AgNO3?

Step 3 Write equalities and conversion factors including mole–mole and concentration.

Page 15: © 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH

© 2013 Pearson Education, Inc. Chapter 8, Section 5 15

Solution

If 22 mL of 0.10 M MgCl2 is needed to completely react15 mL of AgNO3 solution, what is the molarity of AgNO3?

Step 4 Set up the problem to calculate the needed quantity or concentration.