bureaucratic stuffee100/su08/lecture... · ee100 summer 2008 bharathwaj muthuswamyslide 1 ee100su08...
TRANSCRIPT
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Slide 1EE100 Summer 2008 Bharathwaj Muthuswamy
EE100Su08 Lecture #11 (July 21st 2008)• Bureaucratic Stuff
– Lecture videos should be up by tonight– HW #2: Pick up from office hours today, will leave them in lab.
REGRADE DEADLINE: Monday, July 28th 2008, 5:00 pm PST, Bart’s office hours.
– HW #1: Pick up from lab.– Midterm #1: Pick up from me in OH
REGRADE DEADLINE: Wednesday, July 23rd 2008, 5:00 pm PST. Midterm: drop off in hw box with a note attached on the first page explaining your request.
• OUTLINE– QUESTIONS?– Op-amp MultiSim example– Introduction and Motivation– Arithmetic with Complex Numbers (Appendix B in your book)– Phasors as notation for Sinusoids– Complex impedances – Circuit analysis using complex impedances– Derivative/Integration as multiplication/division– Phasor Relationship for Circuit Elements– Frequency Response and Bode plots
• Reading– Chapter 9 from your book (skip 9.10, 9.11 (duh)), Appendix E* (skip second-order resonance
bode plots)– Chapter 1 from your reader (skip second-order resonance bode plots)
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Slide 2EE100 Summer 2008 Bharathwaj Muthuswamy
Op-amps: Conclusion
• Questions?
• MultiSim Example
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Slide 3EE100 Summer 2008 Bharathwaj Muthuswamy
Types of Circuit Excitation
Linear Time-InvariantCircuit
Steady-State Excitation
Linear Time-InvariantCircuit
OR
Linear Time-InvariantCircuit
DigitalPulseSource
Transient Excitation
Linear Time-InvariantCircuit
Sinusoidal (Single-Frequency) Excitation
AC Steady-State
(DC Steady-State)
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Slide 4EE100 Summer 2008 Bharathwaj Muthuswamy
Why is Single-Frequency Excitation Important?
• Some circuits are driven by a single-frequency sinusoidal source.
• Some circuits are driven by sinusoidal sources whose frequency changes slowly over time.
• You can express any periodic electrical signal as a sum of single-frequency sinusoids – so you can analyze the response of the (linear, time-invariant) circuit to each individual frequency component and then sum the responses to get the total response.
• This is known as Fourier Transform and is tremendously important to all kinds of engineering disciplines!
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Slide 5EE100 Summer 2008 Bharathwaj Muthuswamy
a b
c d
sign
al
sign
al
T i me (ms)
Frequency (Hz)
Sig
nal (
V)
Rel
ativ
e A
mpl
itude
Sig
nal (
V)
Sig
nal (
V)
Representing a Square Wave as a Sum of Sinusoids
(a)Square wave with 1-second period. (b) Fundamental component (dotted) with 1-second period, third-harmonic (solid black) with1/3-second period, and their sum (blue). (c) Sum of first ten components. (d) Spectrum with 20 terms.
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Slide 6EE100 Summer 2008 Bharathwaj Muthuswamy
Steady-State Sinusoidal Analysis• Also known as AC steady-state• Any steady state voltage or current in a linear circuit with
a sinusoidal source is a sinusoid.– This is a consequence of the nature of particular solutions for
sinusoidal forcing functions.
• All AC steady state voltages and currents have the same frequency as the source.
• In order to find a steady state voltage or current, all we need to know is its magnitude and its phase relative to the source – We already know its frequency.
• Usually, an AC steady state voltage or current is given by the particular solution to a differential equation.
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Slide 7EE100 Summer 2008 Bharathwaj Muthuswamy
Example: 1st order RC Circuit with sinusoidal excitation
R+
-CVs
t=0
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Slide 8EE100 Summer 2008 Bharathwaj Muthuswamy
Sinusoidal Sources Create Too Much Algebra
)cos()sin()( wtBwtAtxP +=
)cos()sin()()( wtFwtFdt
tdxtx BAP
P +=+τ
)cos()sin())cos()sin(())cos()sin(( wtFwtFdt
wtBwtAdwtBwtA BA +=+
++ τ
Guess a solution
Equation holds for all time and time variations are
independent and thus each time variation coefficient is
individually zero
0)cos()()sin()( =−++−− wtFABwtFBA BA ττ
0)( =−+ BFAB τ0)( =−− AFBA τ
12 ++
=τ
τ BA FFA12 +
−−=
ττ BA FFB
Two terms to be general
Phasors (vectors that rotate in the complex plane) are a clever alternative.
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Slide 9EE100 Summer 2008 Bharathwaj Muthuswamy
Complex Numbers (1)• x is the real part• y is the imaginary part• z is the magnitude• θ is the phase
( 1)j = −
θ
z
x
y
real axis
imaginary axis
• Rectangular Coordinates Z = x + jy
• Polar Coordinates: Z = z ∠ θ
• Exponential Form:
θcoszx = θsinzy =
22 yxz +=xy1tan−=θ
(cos sin )z jθ θ= +Z
j je zeθ θ= =Z Z
0
2
1 1 1 0
1 1 90
j
j
e
j eπ
= = ∠ °
= = ∠ °
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Slide 10EE100 Summer 2008 Bharathwaj Muthuswamy
Complex Numbers (2)
2 2
cos2
sin2
cos sin
cos sin 1
j j
j j
j
j
e e
e ej
e j
e
θ θ
θ θ
θ
θ
θ
θ
θ θ
θ θ
−
−
+=
−=
= +
= + =
j je ze zθ θ θ= = = ∠Z Z
Euler’s Identities
Exponential Form of a complex number
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Slide 11EE100 Summer 2008 Bharathwaj Muthuswamy
Arithmetic With Complex Numbers• To compute phasor voltages and currents, we
need to be able to perform computation with complex numbers.– Addition– Subtraction– Multiplication– Division
• Later use multiplication by jω to replace:– Differentiation– Integration
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Slide 12EE100 Summer 2008 Bharathwaj Muthuswamy
Addition
• Addition is most easily performed in rectangular coordinates:
A = x + jyB = z + jw
A + B = (x + z) + j(y + w)
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Slide 13EE100 Summer 2008 Bharathwaj Muthuswamy
Addition
Real Axis
Imaginary Axis
AB
A + B
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Slide 14EE100 Summer 2008 Bharathwaj Muthuswamy
Subtraction
• Subtraction is most easily performed in rectangular coordinates:
A = x + jyB = z + jw
A - B = (x - z) + j(y - w)
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Slide 15EE100 Summer 2008 Bharathwaj Muthuswamy
Subtraction
Real Axis
Imaginary Axis
AB
A - B
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Slide 16EE100 Summer 2008 Bharathwaj Muthuswamy
Multiplication
• Multiplication is most easily performed in polar coordinates:
A = AM ∠ θB = BM ∠ φ
A × B = (AM × BM) ∠ (θ + φ)
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Slide 17EE100 Summer 2008 Bharathwaj Muthuswamy
Multiplication
Real Axis
Imaginary Axis
A
BA × B
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Slide 18EE100 Summer 2008 Bharathwaj Muthuswamy
Division
• Division is most easily performed in polar coordinates:
A = AM ∠ θB = BM ∠ φ
A / B = (AM / BM) ∠ (θ − φ)
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Slide 19EE100 Summer 2008 Bharathwaj Muthuswamy
Division
Real Axis
Imaginary Axis
A
B
A / B
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Slide 20EE100 Summer 2008 Bharathwaj Muthuswamy
Arithmetic Operations of Complex Numbers
• Add and Subtract: it is easiest to do this in rectangular format– Add/subtract the real and imaginary parts separately
• Multiply and Divide: it is easiest to do this in exponential/polar format– Multiply (divide) the magnitudes– Add (subtract) the phases
1
2
1 2
1 1 1 1 1 1 1
2 2 2 2 2 2 2 2
2 1 1 2 2 1 1 2 2
2 1 1 2 2 1 1 2 2( )
2 1 2 1 2 1 2
2 1 2
cos sin
cos sin( cos cos ) ( sin sin )( cos cos ) ( sin sin )
( ) ( ) ( )
/ ( / )
j
j
j
z e z z jz
z e z z jzz z j z zz z j z z
z z e z z
z z e
θ
θ
θ θ
θ θ θ
θ θ θθ θ θ θθ θ θ θ
θ θ+
= = ∠ = +
= = ∠ = ++ = + + +− = − + −
× = × = × ∠ +
=
1
1
1
1
1
Z
ZZ ZZ Z
Z Z
Z Z 1 2( )1 2 1 2( / ) ( )j z zθ θ θ θ− = ∠ −
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Slide 21EE100 Summer 2008 Bharathwaj Muthuswamy
Phasors• Assuming a source voltage is a sinusoid time-
varying functionv(t) = V cos (ωt + θ)
• We can write:
• Similarly, if the function is v(t) = V sin (ωt + θ)
( ) ( )( ) cos( ) Re Rej t j t
j
v t V t V e Ve
Define Phasor as Ve V
ω θ ω θ
θ
ω θ
θ
+ +⎡ ⎤ ⎡ ⎤= + = =⎣ ⎦ ⎣ ⎦= ∠
( )
( )2
2
( ) sin( ) cos( ) Re2
j tv t V t V t Ve
Phasor V
πω θ
πθ
πω θ ω θ+ −
−
⎡ ⎤= + = + − = ⎢ ⎥
⎣ ⎦
= ∠
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Slide 22EE100 Summer 2008 Bharathwaj Muthuswamy
Phasor: Rotating Complex Vector
Real Axis
Imaginary Axis
V
{ } )( tjjwtj eeVetVtv ωφφω VReRe)cos()( ==+=
Rotates at uniform angular velocity ωt
cos(ωt+φ)
The head start angle is φ.
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Slide 23EE100 Summer 2008 Bharathwaj Muthuswamy
Complex Exponentials• We represent a real-valued sinusoid as the real
part of a complex exponential after multiplying by .
• Complex exponentials – provide the link between time functions and phasors.– Allow derivatives and integrals to be replaced by
multiplying or dividing by jω– make solving for AC steady state simple algebra with
complex numbers.• Phasors allow us to express current-voltage
relationships for inductors and capacitors much like we express the current-voltage relationship for a resistor.
tje ω
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Slide 24EE100 Summer 2008 Bharathwaj Muthuswamy
I-V Relationship for a Capacitor
Suppose that v(t) is a sinusoid:v(t) = Re{Vej(ωt+θ)}
Find i(t).
C v(t)
+
-
i(t)
dttdvCti )()( =
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Slide 25EE100 Summer 2008 Bharathwaj Muthuswamy
Capacitor Impedance (1)
C v(t)
+
-
i(t)dt
tdvCti )()( =
( ) ( )
( ) ( ) ( ) ( )
( ) ( )
( ) cos( )2
( )( )2 2
sin( ) cos( )2 2
(
2
j t j t
j t j t j t j t
j t j t
c
Vv t V t e e
dv t CV d CVi t C e e j e edt dt
CV e e CV t CV tj
V VZCVI
ω θ ω θ
ω θ ω θ ω θ ω θ
ω θ ω θ
ω θ
ω
ω πω ω θ ω ω θ
θ θ θπ ωθ
+ − +
+ − + + − +
+ − +
⎡ ⎤= + = +⎣ ⎦
⎡ ⎤ ⎡ ⎤= = + = −⎣ ⎦ ⎣ ⎦
− ⎡ ⎤= − = − + = + +⎣ ⎦
∠= = = ∠ −
⎛ ⎞∠ +⎜ ⎟⎝ ⎠
VI
1 1 1) ( )2 2
jC C j C
π πω ω ω
− = ∠ − = − =
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Slide 26EE100 Summer 2008 Bharathwaj Muthuswamy
Capacitor Impedance (2)
C v(t)
+
-
i(t)dt
tdvCti )()( =
( )
( )( )
( ) cos( ) Re
( )( ) Re Re
1( )
j t
j tj t
c
v t V t Ve V
dv t dei t C CV j CVe Idt dtV VZI j CV j C
ω θ
ω θω θ
ω θ θ
ω θ
θ θ θθ ω ω
+
++
⇒
⇒
⎡ ⎤= + = = ∠⎣ ⎦⎡ ⎤
⎡ ⎤= = = = ∠⎢ ⎥ ⎣ ⎦⎣ ⎦
∠= = = ∠ − =
∠
V
I
VI
Phasor definition
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Slide 27EE100 Summer 2008 Bharathwaj Muthuswamy
Example
v(t) = 120V cos(377t + 30°)C = 2µF
• What is V?• What is I?
• What is i(t)?
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Slide 28EE100 Summer 2008 Bharathwaj Muthuswamy
Computing the Current
ωjdtd
⇒
Note: The differentiation and integration operations become algebraic operations
ωjdt 1
⇒∫
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Slide 29EE100 Summer 2008 Bharathwaj Muthuswamy
Inductor Impedance
V = jωL I
L v(t)
+
-
i(t)
dttdiLtv )()( =
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Slide 30EE100 Summer 2008 Bharathwaj Muthuswamy
Example
i(t) = 1µA cos(2π 9.15 107t + 30°)L = 1µH
• What is I?• What is V?
• What is v(t)?
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Slide 31EE100 Summer 2008 Bharathwaj Muthuswamy
-8
-6
-4
2
4
6
8
-2
00 0.01 0.02 0.03 0.04 0.05
Phase
7sin( ) 7cos( ) 72 2
t t π πω ω ⎛ ⎞= − = ∠ −⎜ ⎟⎝ ⎠
7cos( ) 7 0tω = ∠ °
7sin( ) 7cos( ) 72 2
t t π πω ω ⎛ ⎞− = + = ∠ +⎜ ⎟⎝ ⎠
capacitor current
inductor currentVoltage
Behind
t
lead
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Slide 32EE100 Summer 2008 Bharathwaj Muthuswamy
Phasor Diagrams
• A phasor diagram is just a graph of several phasors on the complex plane (using real and imaginary axes).
• A phasor diagram helps to visualize the relationships between currents and voltages.
• Capacitor: I leads V by 90o
• Inductor: V leads I by 90o
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Slide 33EE100 Summer 2008 Bharathwaj Muthuswamy
Impedance
• AC steady-state analysis using phasorsallows us to express the relationship between current and voltage using a formula that looks likes Ohm’s law:
V = I Z• Z is called impedance.
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Slide 34EE100 Summer 2008 Bharathwaj Muthuswamy
Some Thoughts on Impedance
• Impedance depends on the frequency ω.• Impedance is (often) a complex number.• Impedance allows us to use the same
solution techniques for AC steady state as we use for DC steady state.