beth baguley - learning objective - feb 22nd - lo4
TRANSCRIPT
![Page 1: Beth Baguley - Learning Objective - Feb 22nd - LO4](https://reader035.vdocuments.mx/reader035/viewer/2022062515/55cf66debb61ebba1d8b4794/html5/thumbnails/1.jpg)
Power and Intensity
![Page 2: Beth Baguley - Learning Objective - Feb 22nd - LO4](https://reader035.vdocuments.mx/reader035/viewer/2022062515/55cf66debb61ebba1d8b4794/html5/thumbnails/2.jpg)
How do Power and Intensity relate?
Power is energy per time unit while Intensity is power per area unit.
![Page 3: Beth Baguley - Learning Objective - Feb 22nd - LO4](https://reader035.vdocuments.mx/reader035/viewer/2022062515/55cf66debb61ebba1d8b4794/html5/thumbnails/3.jpg)
What variables do Power and
Intensity depend on?
Power or Intensity
depending on which equation you are using
¼ or 4 a constant used
in both equations
1/π or Π another
constant used in both
equations
1/r^2 or r^2 this takes the
size of the object
(particularly the radius) into consideration
![Page 4: Beth Baguley - Learning Objective - Feb 22nd - LO4](https://reader035.vdocuments.mx/reader035/viewer/2022062515/55cf66debb61ebba1d8b4794/html5/thumbnails/4.jpg)
Equations
Using the variables we discovered in the previous slide, we can equate the equations needed for Power and Intensity.
Power = I4πr^2
Intensity = P(1/(4πr^2))
![Page 5: Beth Baguley - Learning Objective - Feb 22nd - LO4](https://reader035.vdocuments.mx/reader035/viewer/2022062515/55cf66debb61ebba1d8b4794/html5/thumbnails/5.jpg)
Inverse Square Law explained
Intensity
The intensity of a sound source that radiates equally in all directions, then is evenly radiated outward from a point sources in which it reflects off. The surface area of a sphere (4πr^2) is proportional to the square of the radius therefore as the intensity of the sound get radiated off the point source, it is spreading over and area that is increasing in proportion to the square distance from the source.
![Page 6: Beth Baguley - Learning Objective - Feb 22nd - LO4](https://reader035.vdocuments.mx/reader035/viewer/2022062515/55cf66debb61ebba1d8b4794/html5/thumbnails/6.jpg)
Sample Question
A canon from a ship explodes. Suppose person A is sitting on a boat 2 km from where the canon is blown and person B is scuba diving 500 m below water. Which person hears the canon explode first? And at what intensity do each of them hear it at?
![Page 7: Beth Baguley - Learning Objective - Feb 22nd - LO4](https://reader035.vdocuments.mx/reader035/viewer/2022062515/55cf66debb61ebba1d8b4794/html5/thumbnails/7.jpg)
Sample Question Solution
We will used the inverse square law for intensity in this problem, I=(1/r^2).
For person A, the intensity equates to I=1/(2000m)^2, I=2.5e-7.
For person B, the intensity equates to I=1/(500m)^2, I=4e-6.
Therefore, Person B has a high intensity and will be able to hear the explosion first, at intensity 2.5e-7, compared to Person A who will hear it second at intensity 4e-6. The difference in intensities is related to the distance the person is located from the canon when it explodes.
![Page 8: Beth Baguley - Learning Objective - Feb 22nd - LO4](https://reader035.vdocuments.mx/reader035/viewer/2022062515/55cf66debb61ebba1d8b4794/html5/thumbnails/8.jpg)
Thanks for watching!
Work Cited
- Physics 101 Textbook - equations
- Webassign Reading Assignment 6 – sample question
- http://en.wikipedia.org/wiki/Inverse-square_law