atomic spectra early experimental evidence for discrete energy states in atoms: observation of the...
TRANSCRIPT
Atomic Spectra• Early experimental evidence for discrete energy
states in atoms: observation of the line spectra of hydrogen (Balmer, Rydberg, Ritz, 1885 – 1890)– Experimental setup:
• Light emitted at discrete wavelengths, separated by grating• Principle behind neon signs, sodium street lamps, etc.
(From Modern Physics for scientists and engineers, Thornton and Rex, 2nd ed.)
Line Spectra of Hydrogen• Balmer, Rydberg, and Ritz deduced an empirical
formula that predicted the observed wavelengths of lines in the hydrogen emission spectrum:
– RH = Rydberg constant = 1.0973732 107 m–1
– n, k are integers– k > n (always)– Understanding this equation theoretically was a hot topic in
the early 20th Century
22
111
knRH
Bohr Model of Hydrogen• To explain these results, Niels Bohr suggested
(1913) that the electron in hydrogen moved around nucleus (proton) in circular orbits– Similar to a miniature planetary system
– Coulomb attractive force keeps the electron in orbit (analogous to gravity)
• To maintain stable orbits, Bohr also suggested that the electron’s orbital angular momentum was quantized:
• In combination with Newton’s 2nd law, this leads to discrete radii for the electron orbits
– a0 = Bohr radius = 0.0529 nm
Bohr Model of Hydrogen
...3,2,12
nnnh
vrme
...3,2,1202
22
nnaekm
nr
een
Bohr Model for Hydrogen• From conservation of energy, the model predicts the
discrete total energies of the electron in hydrogen:
• Thus the energy levels form a series of states (like steps in a ladder), with transitions that can take place between the levels– Wavelengths of transitions are in
exact agreement with empirical result!
...3,2,1eV6.131
22 222
422
nnn
ekm
r
ekE eee
22
111
ifH nn
R
Interactive Example Problem: The Bohr Model
Animation and solution details given in class.
(ActivPhysics online problem 18.1, copyright Addison Wesley, 2006)
Bohr Model for Hydrogen• Although this model predicts the energies correctly,
it has several deficiencies:– Only useful for one-electron atoms (only considers e– –
nucleus force, not e– – e– forces)– Unable to account for doublets of spectral lines in
emission spectra (2 or more very closely spaced lines)– Cannot calculate transition intensities– Violates Uncertainty Principle (for circular orbit, we would
know r and pr exactly, which is not possible)
• The correct picture of the atom includes the wave attributes of the electron– Electron’s position is “smeared out,” and we are left with
electron “clouds” surrounding the nucleus
How Lasers Work• Laser = Light Amplification by Stimulated Emission
of Radiation• Stimulated
emission:
– Note difference from spontaneous emission• To produce more stimulated-emission transitions
than absorption transitions, need more atoms in excited metastable state (“population inversion”) then probability of absorbtion probability of stimulated emission
How Lasers Work• For helium – neon laser:
• Schematic of He – Ne laser:
1.20.6 eV
Helium (He)E1
E2
1. Absorption from electric current
2.
2. He atoms collide with Ne atoms
E3
4. 1.96 eV
4. Spontaneous emission of 1.96 eV photons ( = 632.8 nm, red light) produces stimulated emission of other 1.96 eV photons
Rear
Flat mirror, 100% reflective Concave mirror, reflects 99%, transmits 1%
FrontParallel laser beam
5.
5. Spontaneous emission transitions “recycle” process
E2
E1
E4 = 20.6 eV3.
3. E4 (metastable state) in Ne is populated (pop. inversion)
Neon (Ne)
Laser tube
The Atomic Nucleus• Nuclei consist of both protons and neutrons
(collectively called nucleons)
• For a given element, there are typically several nuclear isotopes having different A but same Z
Designate nucleus by: AZXN (example: )
Z = atomic number = # protons (names the element)
N = neutron number = # neutrons
A = mass number = Z + Nproton (p)
mass = 1.0072765 ucharge = +espin = ½
neutron (n)
mass = 1.0086649 ucharge = 0spin = ½
(1 u = 1.66054 10–27 kg = 931.49 MeV / c2)
6126 C
Nuclear Sizes• Nuclear sizes can be inferred from scattering
experiments, where the “probe” must have a deBroglie wavelength on the order of the size being investigated (~ 1 fm)
• From these experiments, we learn:– Nuclear density is roughly a constant (2.3 1017 kg/m3)– Nuclear force radius Mass radius Charge radius– Can approximate nuclear radius assuming a spherical
charge distribution as R = r0 A1/3 where r0 = 1.2 fm
– 1 fm = 1 10–15 m (“femtometer” or “fermi”)
Beam of particles (e– , p, , n, etc.)
Nucleus
Scattered particles
The Nuclear Force• The nuclear force must be strong in magnitude and
attractive to prevent Coulomb repulsion from blowing the nucleus apart (known as strong force because it’s the strongest of the known forces)
• Nucleons themselves provide the forces• The most straightforward way to probe this force is
through scattering experiments• There are n–p, p–p, and n–n forces (and potentials)
n p
p
n
V(r)
rn–p
p p
p
p
V(r)
r
p–p
The Nuclear Force and Models• Protons and neutrons experience potential wells in
nucleus, and fill discrete energy states
• However, we do not fully understand the nuclear force or how nucleons interact inside the nucleus no unified descriptive theory exists for the nucleus!
• Variety of models are used to describe nuclear behavior– Nucleons move nearly independently in a common
nuclear potential (Independent Particle Models)– Nucleons are coupled strongly together and move
collectively (Strong Interaction Models)
rr
V(r)
~ – 43 MeV~ – 37 MeV
neutrons protons
Nuclear Models• Independent Particle Models
– Nucleons move nearly independently in a common nuclear potential
– Nucleons can be thought of as exerting forces on one another through the exchange of pions (an elementary particle with rest energy of 140 MeV)
– Spherical Shell Model– Deformed Shell Model
• Strong Interaction Models – Nucleons are strongly coupled together and move
collectively– Liquid Drop Model– Rotational Model– Vibrations
(image above from Krane, Modern Physics, 2nd ed.)
Basic Research in Nuclear Physics• Nuclear structure studies
– Individual particle motion: How occupation of single-particle orbits affect shape of nucleus
– Collective motion: How rotations and vibrations affect shape of nucleus
– Interplay between individual-particle and collective motion– Deformation studies from charge-distribution/mean lifetime
measurements– Pairing between protons and neutrons
• Nuclear reaction studies– Cross section (probability) measurements– Use polarized projectiles to learn how spin affects reactions
• Nuclear Astrophysics– Origin and synthesis of the elements
Applications of Nuclear Physics
• Medicine (gamma radiation used for imaging)
• Time dating (lead and carbon dating)
• Art (determines trace elements of paints)
• Agriculture (gamma radiation kills bacteria)
• Small power systems (used in Apollo crafts)
• Fission/fusion reactors
• Knowledge of the origin of the elements (production via nuclear reactions)
Radioactive Decay• A nucleus can release three forms of radiation
– Gamma () decay• Nucleus is in an excited energy state• A series of gamma rays (high-energy photons) is released until
the nucleus reaches its lowest-energy (ground) state• Nuclear isotope remains the same (no change in Z or A)
– Alpha decay• Heavy nucleus has too large a ratio of neutrons to protons relative
to stable nuclei• Nucleus emits particle (4He nucleus)• Nucleus loses two protons and two neutrons
– Beta decay• Nucleus has too many protons or neutrons relative to stable nuclei• If too many protons, p n and a positron (e+) is emitted to
conserve charge (+ decay)• If too many neutrons, n p and an electron (e–) is emitted to
conserve charge (– decay)
Radioactive Decay• Example of + decay
– 148O6 14
7N7 + + + (14O unstable, 14N stable)– + particle is a positron
• Example of – decay
– 146C8 14
7N7 + – + (14C unstable, 14N stable)
– – particle is an electron
• Example of decay
– 23092U138 226
90Th136 + (230U unstable, 226Th unstable and will also undergo decay)
– particle is a 4He nucleus
Radioactive Decay• All three forms of radioactive decay
follow the exponential decay law– = decay constant– N = number of radioactive nuclei present at time t
– N0 = number of radioactive nuclei present at time t = 0
– e = 2.718 … = Euler’s constant
• The decay rate (or activity R) follows the same exponential decay law– R = activity at time t
– R0 = activity at time t = 0
• R and N are related by:
teNN 0
teRR 0
NR
Radioactive Decay• Plot of N (or R) vs. time:
• The time it takes for half of a given number of radioactive nuclei to decay = half life = T1/2
693.02ln
2/1 T
Radioactive Decay Experiment
Example Problem #29.36
Solution (details given in class):
9.96 103 yr
A living specimen in equilibrium with the atmosphere contains one atom of 14C (half-life = 5730 yr) for every 7.70 1011 stable carbon atoms. An archeological sample of wood (cellulose, C12H22O11) contains 21.0 mg of carbon. When the sample is placed inside a shielded beta counter with 88.0% counting efficiency, 837 counts are accumulated in one week. Assuming that the cosmic-ray flux and the Earth’s atmosphere have not changed appreciably since the sample was formed, find the age of the sample.
Example Problem #29.51
Solution (details given in class):(a) 8.97 1011
(b) 0.100 J(c) 100 rad
A patient swallows a radiopharmaceutical tagged with phosphorus–32 (32P), a – emitter with a half-life of 14.3 days. The average kinetic energy of the emitted electrons is 700 keV. If the initial activity of the sample is 1.31 MBq, determine (a) the number of electrons emitted in a 10–day period, (b) the total energy deposited in the body during the 10 days, and (c) the absorbed dose if the electrons are completely absorbed in 100 g of tissue.