welcome to jeopardy! ap calculus contestants!. call 911! we need a parametric. too hip to be...

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Welcome to Jeopardy!

AP Calculus Contestants!

Call 911! We Need a

Parametric.

Too hip to be squared.

Can You Function in

the Morning?

Opposites Attract

I Saw the Sine.

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Graph the curve and determine the initial and terminal points, if any.

And the Answer Is:

Back to the Board.

π‘°π’π’Šπ’•π’Šπ’‚π’ π’‚π’π’…π‘»π’†π’“π’Žπ’Šπ’π’‚π’ π‘·π’π’Šπ’π’•π’” :(𝟎 ,πŸ“)8

6

4

2

-2

-4

-6

-8

-10 -5 5 10

Find a Cartesian equation for a curve that contains the parametrized

curve. What portion of the graph of the Cartesian equation is traced

by the parametrized curve?

And the Answer Is:

Back to the Board.

All

Find the values of t that produce the graph in Quadrant IV.

And the Answer Is:

Back to the Board.

βˆ’πŸ‘<𝒕<𝟏

Find a parametrization for the part of the graph that

lies in Quadrant I.

Possible Answers Include:

Back to the Board.

Find a parametrization for the left half of

the parabola

Back to the Board.

Possible Answers Include:

Rewrite the following

expression to have base 3:

Back to the Board.

And the Answer Is:

πŸ‘βˆ’πŸ‘π’™

Determine how much time is required for an investment to triple in

value if interest is earned at the rate of 5.75% compounded

daily.

Back to the Board.

And the Answer Is:

If John invests $2300 in a savings account with

a 6% interest rate compounded annually,

how long will it take until John’s account has a balance of $4150?

And the Answer Is:

Back to the Board.

β‰ˆπŸπŸŽ .πŸπŸπŸ—π’šπ’†π’‚π’“π’”

The half life of a certain radioactive substance is 12

hours. There are 8 grams present initially.

a) Express the amount of substance remaining as a function of time.

b) When will there be 1 gram remaining?

And the Answer Is:

Back to the Board.

a) Amount =

b) After 36 hours

The population of Glenbrook is 375,999 and is increasing at the rate of 2.25% per year. Predict when the population will

be 1 million.

Back to the Board.

And the Answer Is:

After about 44.081 years

Write an equation for the lines parallel and

perpendicular to the line and contains the point .

And the Answer Is:

Back to the Board.

Find the domain and range of the following

function:

Back to the Board.

And the Answer Is:

Determine if the following function is

even or odd:

And the Answer Is:

Back to the Board.

Odd function

Find the formula of the piecewise function displayed on the following graph:

And the Answer Is:

Back to the Board.

𝒇 (𝒙 )={πŸ‘βˆ’ 𝒙 , π’™β‰€πŸπŸ 𝒙 ,𝟏<𝒙

Find the composition of functions , , , and when

and

Back to the Board.

And the Answer Is:

Is the function one-to-one?

Explain why or why not.

And the Answer Is:

Back to the Board.

No because not every output has only one

input. (Does not pass the horizontal line

test.)

Does the function have an inverse?

If yes, find If not, explain why.

Back to the Board.

1f

And the Answer Is:

Back to the Board.

Yes, 1( )f x

Find the inverse of the following function

and verify that :

And the Answer Is:

Back to the Board.

𝒇 βˆ’πŸ (𝒙 )=βˆšπ’™βˆ’πŸ

Solve the following equation

algebraically and support your answer

graphically.

And the Answer Is:

Back to the Board.

Graph and on the

same screen.

What do you notice?

And the Answer Is:

Back to the Board.

8

6

4

2

-2

-4

-6

-8

-10 -5 5 10

𝒇 βˆ’πŸ (𝒙 ) π’Šπ’” π’‚π’“π’†π’‡π’π’†π’„π’•π’Šπ’π’π’π’‡ 𝒇 (𝒙 )𝒐𝒗𝒆𝒓 𝒕𝒉𝒆 π’π’Šπ’π’†π’š=𝒙

Determine the period and amplitude and

draw the graph of the following function:

π’š=πŸ‘πœπ¬πœ (πŸ‘ 𝒙+𝝅 )βˆ’πŸ

And the Answer Is:

Back to the Board.

Period: Amplitude: 3 6

5

4

3

2

1

-1

-2

-3

-4

-5

-6

-7

-10 -8 -6 -4 -2 2 4 6 8 10

Find the value of the six trigonometric

functions at given that

And the Answer Is:

Back to the Board.

Evaluate the following expression:

And the Answer Is:

Back to the Board.

𝐬𝐒𝐧(πœπ¨π­βˆ’πŸ(πŸπŸπŸ“ ))= πŸ“πŸπŸ‘

Show that is an odd function of x.

Using this, show that the reciprocal of an odd function is also odd.

And the Answer Is:

Back to the Board.

𝐜𝐬𝐜(βˆ’πœ½ ΒΏ)= π’“βˆ’π’š

=βˆ’( π’“π’š )=βˆ’πœπ¬πœπœ½ ΒΏ

The reciprocal of cosecant is the sine function:

Solve the following equation in the

specified interval:

And the Answer Is:

Back to the Board.

𝒙=π…πŸ”πšπ§π

πŸ“π…πŸ”

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