advanced mechanics of silids worksheet#02

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  • 8/16/2019 Advanced Mechanics of Silids Worksheet#02

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    01: Sutherland’s viscosity law is used to represent the variation of gas viscosity with

    temperature,

    µ

    µ˳  =

    T  ¿3

    2(T  ˳ S)

    ¿¿¿

     

    where μ is the dynamic viscosity, T is the absolute temperature, μo

    and To

    are reference values

    of μ and T, respectively, and S is a constant with units of temperature!that depends on the gas"

    #or air, To

    = $%& ', μo

    =1 "%1 (10)*

    +g m -s!, and S =110 ". '

    /rite a script m)file that evaluates μair

    at &0o" n your e2pression for μ, use variables, not the

    numerical constants, for , T , and S"μ ˳

    Solution:

    T=&03T = T4$%&3

    To = $%&3

    uo= 1"%151e)*3S = 110".3

    u= TTo6&$!5To5S!!T4S!!5uo

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    $" onvert the script written in the preceding e2ercise to a function" The function should have one

    input parameter, T, and one output parameter, μ"

     Solution:function u = viscosityt!T = T4$%&3

    To = $%&3uo = 1"%151e)*3

    S = 110".3

    u = TTo!6&$!5To5S!!T4S!!5uo3

    &" 7odify the function from the preceding e2ercise so that it accepts a vector of T values as well

    as a scalar T values"

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    Solution:

    function u = viscosityt!T = T4$%&3

    To = $%&3

    uo =1"%151e)*3T =110".3

    u = T"To!"6&$!"5To5S!!"T4S!!"5uo3

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    4. Write a function that evaluates μair

    in the range 0 ≤ T ≤ 230o

    C using the

    function written in the preceding exercise. Plot the utherland !odel data

    against the shown "elow.

    0 1"%$0e)*

    $0 1"81%e)*.0 1"911e)*

    0 $"00$e)*

    80 $"091e)*100 $"1%%e)*

    1$% $"$9.e)*

    1%% $".9&e)*  $$% $"%01e)*

    Solution:

    function u = plotviscosityT,Tv,uv!T = T4$%&3

    To =$%&3

    uo =1"%151e)*3

    S =110".3u = T"To!"6&$!"5To5S!!"T4S!!"5uo3

     plot T,u,;));!3hold on3

     plotTv,uv,;);!3

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    *" ? that can be used to:

    a! #ind the principal stresses for the given state of stress"

    b! #ind absolute ma2imum shear stress for the given state of stress"

    c! #ind octahedral shear stress for the given state of stress"

    d! #ind the principal strains for the given state of stress"e!

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    % exy,eyz,ezx are s$earin& strains

    ex = (sx-(v.sy)-(v.sz))E'

    ey = (sy-(v.sx)-(v.sz))E'

    ez = (sz-(v.sx)-(v.sy))E'

    exy = sxy(2"/.4)'

    eyz = syz(2"/.4)'

    ezx = szx(2"/.4)'

    es = zeros(3,3)'

    % es is t$e strain tensor

    es(1,1) = ex'

    es(2,2) = ey'

    es(3,3) = ez'

    es(1,2) = exy'

    es(2,1) = exy'

    es(2,3) = eyz'

    es(3,2) = eyz'

    es(1,3) = ezx'

    es(3,1) = ezx'

    % e is t$e Ei&en strain vector

    % e1, e2, e3 as t$e rincia! strains

    e = ei&(es)'e1 = max(e)'

    e3 = min(e)'

    % f condition is used to find t$e e2

    if (e(1)e3 ** e(1)+e1)

    e2 = e(1)'

    e!seif (e(2)e3 ** e(2)+e1)

    e2 = e(2)'

    e!se

      e2 = e(3)'

    end

     

    % 678 989:E 68 #;8E##% r12 = radius of circ!e

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    !ot(x2,y2)'

    x!aorma! stress)

    y!a

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    s1 =*0

    s$ =$*s& = )%*

    tma2 = $"*000

    toct =*."00$e1 = 0"00&0

    e$ = 0"001*

    e& = )0"00.*