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    RR

    ActuatorsActuators

    Instructor: Dr. Hong Zhang

    Mechanical Engineering

    Rowan University

    ME ROWANME ROWAN 22

    RR Homework 1Homework 1

    Chapter 2:

    Problem 1, 10, 14, 17, 18

    Chapter 3:

    Problem 9

    Due: March 2, 2004

    ME ROWANME ROWAN 33

    RR ActuatorsActuators

    Actuators are the elements that transformthe control inputs to actions of a machine.

    The common types of actuators:

    Electric motors

    DC & AC motors

    Stepper motors

    Servo motors

    Hydraulic & Pneumatic actuators

    Shape memory metal actuators

    Others

    ME ROWANME ROWAN 44

    RR Mechanical Actuation SystemsMechanical Actuation Systems

    Mechanisms: Devices that transform motionfrom one form to some other required form.

    Mechanical elements: Linkage, cam, gear,rack-and-pinion, chain, belt drive, etc.

    Functions:

    Force amplification

    Change of speed

    Transfer rotation between axis Others

    ME ROWANME ROWAN 55

    RR Four Bar LinkFour Bar Link

    1

    4

    3

    2

    1

    4 3

    2

    14 3

    2

    Double-lever

    2143 llll +>+ 2143 llll +

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    ME ROWANME ROWAN 77

    RR Gear TrainGear Train

    A

    B

    B

    A

    n

    n=

    C

    D

    A

    B

    C

    D

    A

    B

    D

    A

    n

    n

    n

    n

    n

    n

    n

    n=

    =

    A C DB

    A B

    ME ROWANME ROWAN 88

    RR Planetary Gear TrainPlanetary Gear Train

    SunRing Gear

    Planet

    Arm

    armF

    arm

    gearsdrivenonteethofnumberofproduct

    gearsdriveronteethofnumberofproduct

    = L

    ME ROWANME ROWAN 99

    RR

    The sun has 40 teeth, the planet 20 teeth,and the ring gear 80 teeth. The arm is inputand the sun is output. The ring gear is heldstationary. Find the train ratio of sun/arm.

    ratio of sun/arm =3

    ME ROWANME ROWAN 1010

    RR

    Build a remotely controlled mouse:

    Basic parts: a mouse set & a joystick set

    Other material: anything you can buy within the limit ofthe allowance (which you can keep it as secret), andanything you find from machine shop and other places(which you need to inform the entire class and getapproval).

    Tool: machines and tools available in machine shop

    and electric lab, you can also use your own tool Allowance: $10 (dept.) + $10 (self), keep receipts for

    peer examination prior competition

    Project 1: Mouse HouseProject 1: Mouse House

    ME ROWANME ROWAN 1111

    RR

    Date: March 10, 2004

    Mouse soccer tournament Time: 5 minutes each game for 3 games

    You can design and install any ball handling tool

    Sumouse triangle: Time: 2 minutes

    Push or trick the others out of the boundary.

    Point = 10 # of stepping out down time (every 5s)

    You can add any attachment to enhance your chance

    CompetitionCompetition

    ME ROWANME ROWAN 1212

    RR Characteristics of ActuatorsCharacteristics of Actuators

    Weight

    Power-to-weight ratio

    Stiffness: The resistance of a materialagainst deformation.

    Stiff vs.Compliant

    Accuracy vs. Flexibility

    Reduction gears

    Reduce speed, increase torque

    Increased cost, number of parts, backlash, etc.

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    ME ROWANME ROWAN 1313

    RR Bucket ScienceBucket Science

    You have a 5L and a 3L bucket and unlimitedsupply of water. How to use these twobuckets to measure any amount of water

    from 1L to 8L.

    5L 3L

    ME ROWANME ROWAN 1414

    RR Hydraulic ActuatorsHydraulic Actuators

    High power- to- weight ratio (depending on whetherthe pump & reservoir are included)

    Large forces at low speeds (linear or rotary)

    Compatible with microprocessor and electronic

    control No reduction gears required

    Tolerance of extreme hazardous environments

    May leak

    Expensive and noisy, requires maintenance

    Depends on the properties of oil (dirt, temp., etc)

    ME ROWANME ROWAN 1515

    RR ApplicationsApplications

    Dump Truck

    Car Brakes

    Shovel

    ME ROWANME ROWAN 1616

    RR Principle of Hydraulic SystemsPrinciple of Hydraulic Systems

    F F

    Oil

    Pistons have equal areasF F

    Oil

    Pistons with different areas

    F=F

    21

    '

    A

    F

    A

    F=

    FA

    AF

    1

    2'=

    A1 A2

    ME ROWANME ROWAN 1717

    RR Common ComponentsCommon Components

    Power source

    Hydraulic linear or rotary cylinders and rams

    Hydraulic switches and other controllers

    Connecting hoses

    Safety valves and other mechanisms

    Sensors

    ME ROWANME ROWAN 1818

    RR Schematic of a Hydraulic SystemSchematic of a Hydraulic System

    Sensors Controller

    HydraulicPowerSource

    Switch

    Return

    Source

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    ME ROWANME ROWAN 1919

    RR Power SourcePower Source

    Reservoir

    Hydraulic pump operated by a motor or an

    engine Cooling system (for pneumatic system)

    ME ROWANME ROWAN 2020

    RR Power SourcePower Source

    Return

    Oil Reservoir

    Pump

    Motor

    None-return

    valve

    Pressure

    relieve valveAccumulator

    To system

    ME ROWANME ROWAN 2121

    RR Hydraulic CylindersHydraulic Cylinders

    Hydraulic cylinder

    Telescope cylinderSchematic drawing

    ME ROWANME ROWAN 2222

    RR Directional Control ValvesDirectional Control Valves

    Port 1Port 3 Port 2

    Spool

    Port 3 Port 1Port 2

    One-way valve

    ME ROWANME ROWAN 2323

    RR Valve SymbolsValve Symbols

    Flow path Flow shut-off InitialConditions

    Push-buttonSpring-button

    RollerSolenoid Pneumatic Lever Pedal

    ME ROWANME ROWAN 2424

    RR Example: Poppet ValveExample: Poppet Valve

    Poppet valve

    2 port 2 position (2/2) poppet valve

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    ME ROWANME ROWAN 2525

    RR More ExamplesMore Examples

    3/2 valve 4/2 valve

    Lift system

    Vent

    Pressure supply

    ME ROWANME ROWAN 2626

    RR 22--Actuator Sequential OperationActuator Sequential Operation

    5

    6

    7

    b+b-Cylinder BLimit switches

    a-

    a+

    Start1

    4

    3

    2

    a+a-Cylinder ALimit switches

    b-b+

    ME ROWANME ROWAN 2727

    RR Brain SugarBrain Sugar

    Use 1, 5, 6, 7 and any combination of +, -, *and / to obtain 24 and 21.

    2465*)17( =

    21)7/51/(6 =

    ME ROWANME ROWAN 2828

    RR Electric MotorsElectric Motors

    Most popular motor

    Types:

    DC motor

    AC motor

    Brushless motor

    Step motor

    Servo motor

    Linear motor

    Applications:

    ME ROWANME ROWAN 2929

    RR Basic Principles of Electromagnetic MotorsBasic Principles of Electromagnetic Motors

    N

    S

    B

    1. A magnetic field B is generated by a pair of magnets.

    2. A conductor with no current will not disturb the field B.

    x

    3. When a conductor carries an electrical current, aconcentric magnetic field is produced along theconductors length.

    4. Combined action between the two magnetic fieldscreate a mutual repulsive force forcing thewire downwards.

    F

    x B

    BilFrr

    =

    ME ROWANME ROWAN 3030

    RR

    When there is a loop of conductor carrying current inthe magnetic field, a torque will be generated.

    Electromagnetic MotorElectromagnetic Motor

    Current

    N S

    B

    F

    F

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    ME ROWANME ROWAN 3131

    RR Brushes and CommutatorBrushes and Commutator

    For continuous operation, a pair of brushes andcommutator are used to change the direction of current

    ME ROWANME ROWAN 3232

    RR Direction Changing w/ BrushesDirection Changing w/ Brushes

    (a) (b)Armature

    ME ROWANME ROWAN 3333

    RR A Simple MotorA Simple Motor

    ME ROWANME ROWAN 3434

    RR Inside a DC MotorInside a DC Motor

    Field magnet

    DC motor

    Armature

    Commutator

    ContactBrushes

    ME ROWANME ROWAN 3535

    RR DiscussionDiscussion

    How does this worlds simplest motor work?

    How to reverse the direction of rotation?

    ME ROWANME ROWAN 3636

    RR Field CoilsField Coils

    Practical motors have several loops on anarmature to provide a more uniform torqueand the magnetic field is produced by anelectromagnet arrangement called the fieldcoils.

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    ME ROWANME ROWAN 3737

    RR Arrangement of Field CoilsArrangement of Field Coils

    Field coil

    Armature coil

    Series wound motor

    Field coil

    Armaturecoil

    Shunt wound motor

    Field coil

    Armaturecoil

    Field coil

    Compound motor

    Armaturecoil

    Field coil

    Separately wound motor

    ME ROWANME ROWAN 3838

    RR Torque with Permanent MagnetTorque with Permanent Magnet

    Force generated by oneconductor

    BilF=

    i

    B

    F

    F

    l

    b

    Torque generatedbBilT =

    iknbBliT t ==

    Total torque

    ME ROWANME ROWAN 3939

    RR Torque with Field CoilTorque with Field Coil

    For motor with field coil, we just need tochangeB toKfIstator.

    ikliIbKnT tstatorf ==

    ME ROWANME ROWAN 4040

    RR Back ElectroBack Electro--Magnetic FieldMagnetic Field

    Rotating armature coil in magnetic field willinduce back e.m.f. vb

    vb kv =

    V

    R L

    Vb

    A DC motor can be considered as anequivalent circuit

    RkV

    RvVi vb

    =

    =i

    ME ROWANME ROWAN 4141

    RR Torque and SpeedTorque and Speed

    Ignoring the inductance of armature, the torque is

    Where R is the armature resistance, V is theapplied voltage, and the rotational speed.

    R

    kVkikT vtt

    )( ==

    Torque

    Rotational speed

    V1

    V2

    V3

    ME ROWANME ROWAN 4242

    RR Torque Characteristics of a MotorTorque Characteristics of a Motor

    Rotation rate (rpm)

    Torque

    (Nm)

    10 60504030200

    0.1

    0.5

    0.4

    0.3

    0.2

    0.8

    0.7

    0.6

    A 12V DC motor

    A 24V DC motor

    Stall

    No load

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    ME ROWANME ROWAN 4343

    RR Brain SugarBrain Sugar

    Add following lines together

    4100

    1000

    20

    1030

    1020

    20

    +) 1010

    ME ROWANME ROWAN 4444

    RR

    Connect all 9 dots with 4 connected straight lines

    ME ROWANME ROWAN 4545

    RR Design ProblemDesign Problem

    Known: Total mass m= 5 kg. We have 10 AA NiCd batterieswith 1.2V, 500mAh, and a DC motor with normal runningcurrent 0.15A at 12V. Suppose transmission ratio 1:10 and

    stall torque of the motor is 300 oz.in.Check: 1. Whether the car can reach acceleration a=0.1g?

    2. How long will the battery last?

    Body

    Wheel (r=4cm)

    MotorBattery

    Transmission

    ME ROWANME ROWAN 4646

    RR CalculationCalculation

    Acceleration: a = 0.1 x 9.8 =0.98 m/s2

    Force: F = ma = 5 x 0.981 = 4.9 N

    Wheel torque:

    Tw= Fr = 4.9 x 0.04 = 0.196 Nm

    Minimum torque required from the motor:

    Tm= Tw*10 = 1.96 Nm

    = 141.61*1.96 oz.in = 278 oz.in

    Stall torque of the motor is 300 oz.in300 oz.in > 278 oz.in

    ME ROWANME ROWAN 4747

    RR CalculationCalculation

    Running power of the motor:P=VI= 12 x0.15 = 1.8 w

    Running time: 500mAh = 0.5 Ah

    0.5 / 0.15 = 3.3 hr

    Note: You need to consider other factors inreal design, such as friction in transmission,uneven surface, etc.

    ME ROWANME ROWAN 4848

    RR DiodeDiode

    Diode

    Cathode

    AnodeV

    I

    Forwardbiased

    Reversebiased

    0

    Diode characteristic

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    ME ROWANME ROWAN 4949

    RR Bipolar TransistorBipolar Transistor

    BFEcIhI =

    Ic Ic

    Base current

    Ic

    Base current

    Ic

    Emitter

    Base

    Collector

    NPN

    Collector

    Emitter

    Base

    PNP

    ME ROWANME ROWAN 5050

    RR Darlington PairsDarlington Pairs

    NPN PNP

    IcIc

    Base current

    Ic

    Base current

    IcIc Ic

    ME ROWANME ROWAN 5151

    RR H Circuit DC Motor ControllerH Circuit DC Motor Controller

    V+

    High

    Low

    ME ROWANME ROWAN 5252

    RR H Circuit DC Motor ControllerH Circuit DC Motor Controller

    V+

    High

    Low

    ME ROWANME ROWAN 5353

    RR MOSFETMOSFET

    Drain

    Source

    Gate

    Drain

    Source

    Gate

    12V

    12V

    GND

    Output portof micro-

    processor

    N-channel P-channel

    1.High frequencyswitching

    2.Easy interfacing tomicroprocessor

    ME ROWANME ROWAN 5454

    RR Electronic Speed ControllerElectronic Speed Controller

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    ME ROWANME ROWAN 5555

    RR Commercial ESCCommercial ESC

    ME ROWANME ROWAN 5656

    RR Mirror TimeMirror Time

    There are times when hour and minutereadings are same, such as 1:01, 2:02, 3:03,etc. What is the shortest possible timebetween two different readings of this mirrortime?

    49min, 12:12 1:01

    ME ROWANME ROWAN 5757

    RR Who is lying?Who is lying?

    Four friends Andrew, Barbara, Cindy, andDaniel were shown a number. Here is whatthey had to say about that number:

    Andrew: It has two digits

    Barbara: It goes evenly into 150

    Cindy: It is not 150

    Daniel: It is divisible by 25

    It turns out that one and only one of the fourfriends is lying. Which one is it?

    D

    ME ROWANME ROWAN 5858

    RR Stepper MotorsStepper Motors

    A motor produces rotation through equalangles, the so-called steps, for each digitalpulse supplied to its input.

    NS

    N S

    N

    S

    N

    S

    ME ROWANME ROWAN 5959

    RR Obtain Smaller StepsObtain Smaller Steps

    A stepper motor with 4 teeth rotor and 6 teeth stator willobtain minimum step of 15

    (A)

    1

    23

    4

    5 6

    a

    b

    c

    d

    (C)

    1

    23

    4

    5 6

    ab

    cd

    (B)

    1

    23

    4

    5 6

    a

    b

    c

    d

    Develop a control scheme for a stepper motor with 8teeth rotor and 6 teeth stator

    Given a 50 teeth rotor and 40 teeth stator, what isthe minimum step?

    ME ROWANME ROWAN 6060

    RR MicroMicro--SteppingStepping

    In micro- stepping, the

    power- on or power- off for each coil is donegradually by dividingthe changes intosmaller divisions.

    N

    S

    N

    S

    N

    S

    Half stepping

    Pro and Cons.

    Smaller stepping angles

    Smoother rotation

    Complex controller

    Develop half stepping scheme for the previous 4/6 example

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    ME ROWANME ROWAN 6161

    RR Servo MotorServo Motor

    A servomotor is any motor with feedback that canbe controlled to move at a desired speed (andconsequently, torque), for a desired angle ofrotation.

    MotorDynamics Load

    Differentiate

    Feedback

    Desiredposition &velocity +

    _Position

    Velocity

    Error

    ME ROWANME ROWAN 6262

    RR Anatomy of a Servo MotorAnatomy of a Servo Motor

    ME ROWANME ROWAN 6363

    RR Angle ControlAngle Control

    ME ROWANME ROWAN 6464

    RR Digital Control of a MotorDigital Control of a Motor

    The speed of the motor is controlled byvarying voltage

    Control signal from computer is digital, henceneed conduct digital-to-analog converters(DAC)

    The resolution of the control is determined bythe number of ports or bits (2n)

    ME ROWANME ROWAN 6565

    RR Servo Motor ControllerServo Motor Controller

    PIC16C73 based

    SV203 Servo

    Motor Controller

    PRINT #1,"BD";ID$;"SV";Servo$;"M";Position$

    ME ROWANME ROWAN 6666

    RR Pulse Width Modulation (PWM)Pulse Width Modulation (PWM)

    The voltage is sent as pulse with constant voltage

    The average voltage is determined by the width ofthe pulse

    Time

    V

    tT

    Vcc

    Vout

    T

    tVV ccout

    =

    T 4T3T2T 5T0

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    ME ROWANME ROWAN 6767

    RR Industrial AC MotorIndustrial AC Motor

    1000 HP1 HP

    ME ROWANME ROWAN 6868

    RR AC Induction MotorAC Induction Motor

    Same theory of DC motor to turn the rotor

    No wiring required for rotor

    3-phase AC to induct rotating electro-

    magnetic field.

    ME ROWANME ROWAN 6969

    RR Component of an AC MotorComponent of an AC Motor

    Stator Rotor

    ME ROWANME ROWAN 7070

    RR 3 Phase Alternating Current (AC)3 Phase Alternating Current (AC)

    ME ROWANME ROWAN 7171

    RR 3 Phase AC Wiring3 Phase AC Wiring

    iA

    iC

    iBD2

    D1

    D3

    D5D4

    D6

    Y (Star) wiring

    (Triangle) wiring

    ME ROWANME ROWAN 7272

    RR

    D3

    D6

    D1

    D4

    D5

    D2

    iA D1

    iC

    iBD2

    D3

    D5 D4

    D6

    iA

    iB

    iC

    V

    t

    0

    t1 t2 t3 t4 t5 t6

    t= 0x

    x

    N

    S

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    ME ROWANME ROWAN 7373

    RR Turning ElectroTurning Electro--Magnetic FieldMagnetic Field

    D3

    D6

    D1

    D4

    D5

    D2

    iA D1

    iC

    iBD2

    D3

    D5 D4

    D6

    iA iBiCV

    t

    0

    t1 t2 t3 t4 t5 t6

    t= t1, t2,?

    ???

    ME ROWANME ROWAN 7474

    RR

    D3

    D6

    D1

    D4

    D5

    D2

    x

    x

    x

    D3

    D6

    D1

    D4

    D5

    D2

    x

    x

    t= t1t= t2

    t= t3

    t= t4

    D3

    D6

    D1

    D4

    D5

    D2x

    x

    x

    D3

    D6

    D1

    D4

    D5

    D2

    x

    x

    x

    D3

    D6

    D1

    D4

    D5

    D2x

    x

    x

    t= t5 t= t6

    D3

    D6

    D1

    D4

    D5

    D2x

    x

    x

    ME ROWANME ROWAN 7575

    RR Use of Reduction GearsUse of Reduction Gears

    In most motor powered system, we use reductiongears or other mechanics to reduce speed andincrease torque.

    Inertia of loadIl, Inertia of motorIm, Gear ratio N,viscous friction of load and motor are IlandIm

    Motor

    Gears

    Loadm& L

    &

    Tm

    ME ROWANME ROWAN 7676

    RR Dynamic EquationsDynamic Equations

    mNl && 1= mNl

    &&&& 1=and

    lN

    m

    l TT1=

    mlNmmlNm

    llllNmmmm

    lNmmmmm

    bbII

    bIbI

    TbIT

    &&&

    &&&&&&

    &&&

    )()(

    )(

    22

    11

    1

    1

    +++=

    +++=

    ++=

    Total inertia Total friction

    ME ROWANME ROWAN 7777

    RR ExerciseExercise

    A motor withIm=0.015 kgm2 and maximum torque of 8Nm is

    connected to a uniformly distributed arm with aconcentrated mass at its end. Ignoring the inertia felt by themotor and viscous friction in the system, calculate the totalinertia felt by the motor and the maximum angularacceleration it can develop if the gear ratio is (a) N=3 and(b) N=30.

    Motor

    m& L

    &

    0.5m

    3kg

    2kg