aceleracion metodo analitico

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2 2 3 5 4 6 A O2 B C Calcule la aceleracin en el nodo C y B, por el mtodo analtico. NOMBREMEDIDA ESLABON 22.4 m ESLABON 35.8 m ESLABON 57.2 m 2 62.83 rad/s 3 23.013rad/s 5 10.9507rad/s ANGULO DE ENTRADA 30 O2 A aA 2 ( )2 22 22( ) (62.83)(2.4)9474.26AAma OAsmase = == O2 B A 230138.0611.94OABZ =Z=Z= aB aA A B A B aA aB /nBAa/tBAaB BA At nA Ba a a a + + =aA /nBAa/tBAaaB 78.06 168.06 30 aA aB /nBAa/tBAa78.06 168.06 210 180B BA At nA Ba a a a < + < + < = < 23 30 210 ( ) 168.06 78.06A AB ABasen r sen r sen e o = + +23 3cos180 cos 210 ( ) cos168.06 cos 78.06B A AB ABa a r r e o = + +210342.82 /Ba m s = O2 A C 230103.22116.778OACZ =Z=Z=C aC aA aA C A /nCAa/tCAaC A aA /nCAa/tCAaaC / /n tCA CA A Ca a a a + + =aA /nBAa/tBAaaC 17 287 210 270C CA At nA Ca a a a < + < + < = < 25 5270 210 ( ) 287 17C A AC ACasen asen r sen r sen e o = + +25 50 cos 210 ( ) cos 287 17A AC ACa r r sen e o = + +23131.4849 /Ca m s =177330