5.membrane based bioseparation-purification

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    MEMBRANEBASEDBIOSEPARATION

    Recovery & Isolation

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    DEFINITION

    A membrane is a thin semi-permeable barrier which

    can be used for the following types of separation1. Particle-liquid separation

    2. Particle-solute separation

    3. Solute-solvent separation

    4. Solute-solute separation

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    FACTORSUTILIZEDINMEMBRANEBASEDSEPARATION,

    1. Solute size

    2. Electrostatic charge

    3. Diffusivity

    4. Solute shape

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    Purification

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    MODEOF MEMBRANE SEPARATION

    Spiral Wound

    Hollow Fibre

    http://en.wikipedia.org/wiki/File:Spiral_flow_membrane_module-en.svg
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    FILTRATION MODE

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    MICROFILTRATION

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    MICROFILTRATION

    Microfiltration membranes are microporous and retainparticles by a purely sieving mechanism.

    Typical permeate flux values are higher than inultrafiltration processes even though microfiltration isoperated at much lower TMP.

    A microfiltration process can be operated either in a

    dead-end (normal flow) mode or cross-flow mode

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    APPLICATIONSOF MICROFILTRATIONINDOWNSTREAMPROCESSING

    1. Cell harvesting from bioreactors

    2. Virus removal for pharmaceutical products

    3. Clarification of fruit juice and beverages

    4. Water purification

    5. Air filtration

    6. Sterilization of products

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    TRANSPORT EQUATION

    cMV RRP

    J

    c

    M

    sc r

    A

    VrR

    c = Cake layer

    For micron sized particles

    23

    11180

    sd

    r

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    EXAMPLE

    Bacterial cells having 0.8 micron average diameter arebeing microfiltered in the cross-flow mode using amembrane having an area of 100 cm2. The steady statecake layer formed on the membrane has a thickness of10 microns and a porosity of 0.35. If the viscosity of the

    filtrate obtained is 1.4 centipoise, predict the volumetricpermeate flux at a transmembrane pressure of 50 kPa.When pure water (viscosity = 1 centipoise) was filteredthrough the same membrane at the same

    transmembrane pressure, the permeate flux obtainedwas 10-4 m/s.

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    SOLUTION

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    BATCH FILTRATION (INCOMPRESSIBLE CAKE)

    dt

    dV

    A

    Jv1

    cM RR

    P

    dt

    dV

    A

    1

    A

    VR

    oc

    o = mass of cake solids per volume of filtrate

    MAVo RP

    dtdV

    A

    1

    PR

    AV

    PVAt Mo

    2

    PA

    VR

    A

    V

    PtMo

    2

    2

    y = mx+c

    t=0, V=0

    V= total volume of filtrate

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    EXAMPLE2

    A broth containing the yeast was filtered using microfilter and its timeneeded to collect the volume of filtrate is as below

    Filtration Time (sec) Volume of filtrate (ml)

    2 20

    10 56

    25 90

    50 175

    The microfilter has a total area of 9 x 10-3 m2 and the filtrate has aviscosity of 1.15 cP. The pressure drop is 68,000 Pa and the feedcontains 0.01 kg dry cake per liter

    Determine the specific cake and membrane resistance

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    ULTRAFILTRATION

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    ULTRAFILTRATION

    UF membranes can retain macromolecular solutes.

    Solute retention is mainly determined by solutesize.

    Other factors such as solute-solute and solute-membrane interactions can affect solute retention.

    Ultrafiltration is used for:

    Concentration of solutes

    Purification of solvents

    Fractionation of solutes

    Clarification

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    ULTRAFILTRATIONINDOWNSTREAMPROCESSING

    UF is widely used for processing:

    therapeutic drugs,

    enzymes,

    hormones,

    vaccines,

    blood products

    antibodies.

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    ULTRAFILTRATION

    The major areas of application are listed below:

    Purification of proteins and nucleic acids

    Concentration of macromolecules

    Desalting, i.e. removal or salts and other low molecular

    weight compounds from solution of macromolecules

    Virus removal from therapeutic products

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    ULTRAFILTRATION

    The ability of an ultrafiltration membrane to retainmacromolecules is traditionally specified in terms ofits molecular cut-off (MWCO).

    A MWCO value of 10 kDa means that themembrane can retain from a feed solution 90% ofthe molecules having molecular weight of 10 kDa.

    Ultrafiltration separates solutes in the molecularweight range of 5 kDa to 500 kDa. UF membranes

    have pores ranging from 1 to 20 nm in diameter.

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    TRANSPORT EQUATIONS

    The solvent flow is proportional to the applied force

    (solvent velocity) (force on solvent)

    PLj pv Lp is the solvent permeability

    Include the osmotic pressure

    PLj pv

    PLj pv

    For solute leak through the membrane

    is the reflection coefficient, 0 <

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    is osmotic pressure which can be determined from its solutionconcentration

    RTC

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    GOVERNINGLAWSDARCYLAW

    Darcy's law is a simple proportional relationship

    between the instantaneous discharge ratethrough a porous medium, the viscosity of thefluid and the pressure drop over a given distance.

    The total discharge, Q(units of volume per time, e.g., m3/s) isequal to the product of the permeability of the medium, k(m2),the cross-sectional area to flow, A (units of area, e.g., m2), andthe pressure drop (Pa), all divided by the viscosity, (Pa.s)

    and the length the pressure drop is taking place over.

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    MODEL-POISEUILLEFLOW

    The flow of a solvent through ultrafiltrationmembranes can be described in terms of a poreflow model which assumes ideal cylindrical poresaligned normal to the membrane surface:

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    TRANSMEMBRANE PRESSURE

    The transmembrane pressure in cross-flow UF isgiven by:

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    CONCENTRATIONPOLARIZATION

    the retained macromolecules accumulate near themembrane surface caused concentrationpolarization.

    At steady state, a stable concentration gradient

    exists near the membrane owing to back diffusionof solute from the membrane surface.

    offers extra hydraulic resistance to the flow ofsolvent

    development of osmotic pressure which actsagainst the applied transmembrane pressure

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    MODEL

    As most ultrafiltration membranes can not bevisualized as having parallel cylindrical pores, aparameter, the membrane hydraulic resistance isused for calculating permeate flux:

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    If the solute build-up is extensive, a gel layer maybe formed on top of the membrane

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    LIMITINGFLUX

    At lower values of transmembrane pressure, thepermeate flux increases linearly with increase inpressure

    However, as the pressure is further increased, there

    is deviation from the solvent profile, this being dueto concentration polarization.

    At very high transmembrane pressures, thepermeate flux usually plateaus off, clearly

    suggesting the formation of a gel layer.

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    LIMITING FLUX

    Beyond this point, increasing the transmembranepressure has a negligible effect on the permeateflux

    This value of permeate flux being referred to as thelimiting flux (Jlim).

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    CROSSFLOWFILTRATION

    The fluid in crossflow filtration flows parallel to themembrane surface, resulting in constant permeateflux at steady state

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    MODEL

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    CONCENTRATIONPOLARIZATIONMODEL

    At steady state, a material balance of solutemolecules in a control volume within theconcentration polarization layer yields the followingdifferential equation:

    Integrating this with boundary conditions (C= Cwatx= 0; C= Cbat x= b), we get

    k(= mass transfer coefficient) = D/b

    0dx

    dCDCJCJ pvv

    pb

    pw

    vCC

    CCkJ ln

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    CONCENTRATIONPOLARIZATIONMODEL

    For total solute rejection, i.e., when Cp = 0, theequation reduces to

    b

    w

    vCCkJ ln

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    ULTRAFILTRATION-EXAMPLE 1

    A protein solution (concentration = 4.4 g/1) is being

    ultrafiltered using a spiral wound membrane module,which totally retains the protein. At a certaintransmembrane pressure the permeate flux is 1.3 x10-5 m/s. The diffusivity of the protein is 9.5 x 10-11

    m2

    /s while the wall concentration at this operatingcondition is estimated to be 10 g/1. Predict thethickness of the boundary layer. If the permeate fluxis increased to 2.6 x 10-5 m/s while maintaining thesame hydrodynamic conditions within the membrane

    module, what is the new wall concentration?

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    ULTRAFILTRATION-MODEL-SOLUTEMASSTRANSFERCOEFFICIENT

    The solute mass transfer coefficient (k) is a

    measure of thehydrodynamic conditions within amembrane module.

    The mass transfer coefficient can be estimated from

    correlations involving the: Sherwood number (Sh),

    Reynolds number (Re), and

    Schmidt number (Sc):

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    These correlations are based on heat and mass

    transfer analogy. In the case of fully developed laminar flow, the

    Graetz-Leveque correlation can be used:

    For turbulent flow (i.e. Re > 2000), the Dittus-Boelter correlation can be used:

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    MEMBRANEPERFORMANCE - RETENTION

    If a solute is not totally retained (or rejected), theamount of solute going through the membrane canbe quantified in terms of the membrane intrinsicrejection coefficient (R,) or intrinsic sieving

    coefficient (S,):

    More practical parameters such as the apparent

    rejection coefficient (Ra) or the apparentsievingcoefficient (Sa) are frequently preferred:

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    A correlation between the intrinsic sieving coefficient andthe apparent sieving coefficient can be obtained as:

    If the intrinsic sieving coefficient could be considered aconstant, above equation provides a way by which themass transfer coefficient and the intrinsic sievingcoefficient could be determined by plotting experimentaldata

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    EXAMPLE

    The intrinsic and apparent rejection coefficients fora solute in an ultrafiltration process were found tobe 0.95 and 0.63 respectively at a permeate fluxvalue of 6 x 10-3 cm/s. What is the solute mass

    transfer coefficient?

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    MEMBRANE PERFORMANCE - FLUX

    The permeate flux in an ultrafiltration processdetermines its productivity

    The permeate flux depends on:

    properties of the membrane

    Properties of the feed solution.

    transmembrane pressure

    the solute mass transfer coefficient (which affects theconcentration polarization).

    membrane fouling

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    ENHANCINGPERMEATEFLUX

    By increasing the cross-flow rate

    By creating pulsatile or oscillatory flow on the feedside

    By back flushing the membrane

    By creating turbulence on the feed side usinginserts and baffles

    By sparging gas bubbles into the feed

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    MEMBRANEPERFORMANCE - RETENTION

    The retention of a solute by a membrane primarilydepends of on

    the solute diameter to pore diameter ratio.

    the solute shape,

    solute charge,

    solute compressibility,

    solute-membrane interactions (which depend on thesolution conditions)

    operating conditions (such as cross-flow velocity andtransmembrane pressure).

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    NANOFILTRATION

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    NANOFILTRATION

    Nanofiltration (NF) membranes allow salts andother small molecules to pass through but retainlarger molecules such as peptides, hormones andsugars.

    The transmembrane pressure in NF ranges from 40to 200 psig.

    ST

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    GOVERNINGLAWS - FICKS 1STLAW

    Fick's first law relates the diffusive flux to the

    concentration field, by postulating that the flux goesfrom regions of high concentration to regions of lowconcentration,

    where

    J is the diffusion flux in dimensions of [(amount of substance)length2 time1]

    D is the diffusion coefficient or diffusivity in dimensions of[length2 time1] (for ideal mixtures)

    is the concentration in dimensions of [(amount of substance)length3],

    x is the position [length],

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    GOVERNINGLAWS - FICKS 2NDLAW

    Fick's second law predicts how diffusion causes

    the concentration field to change with time (derivedfrom Fick's First law and the mass balance):

    Where

    is the concentration in dimensions of [(amount of substance)length3],

    t is time [s]

    D is the diffusion coefficient in dimensions of [length2 time1],

    x is the position [length]

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    The extended Nernst-Planck equation proposed bySchlogl and Dresner forms the basis of thedescription of ion transport through the membranes.

    The equation can be expressed as

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    REVERSE OSMOSIS

    Reverse osmosis (RO) membranes allow water togo through but retain all dissolved species presentin the feed.

    In osmosis water travels from the lower solute

    concentration side to the higher soluteconcentration side of the membrane.

    In RO the reverse takes place due to theapplication of transmembrane pressure.

    The normal transmembrane pressure range in ROis from 200 to 300 psig.

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    ASSIGNMENT 3

    A protein solution at a concentration of 0.5 g/liter andvolume of 1000 liters must be concentrated on acrossflow ultrafilter to a concentration of 10 g/L. Theultrafiltration has an area of 100 m2 and operates at 5oC

    with an inlet pressure of 14.0 bar, and back pressure onthe permeate of 1.4 bar. The protein has a molecularweight of 20,000 Da and will not pass through theultrafiltration membranes. The feed has a viscosity of1.2 cp. The membrane resistance (Rm) of the ultrafilter

    has been determined to be 2 x 1013

    cm-1

    . The Reynoldsnumber for flow within the ultrafilter is large enough torender concentration polarization negligible. Determinethe time required to perform the ultrafiltration.

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    SOLUTION

    cpMV

    RR

    PJ

    RTC