2012 ppt spiderman

Download 2012 ppt spiderman

Post on 27-Jun-2015

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  • 1. T2 T 1 = 400 N573075 kg.

2. yT2T1 400N 5730 x Fg -735N 3. T1x = T1 COS T1x = (400N) (COS 30)T1x = 346.4N 4. T1y = T1 SIN T1y = (400 N) SIN 30T1y = 200 N 5. yT2yxT1y 200 N T2xT1x 346.4 N 6. If you used the x direction T1x = T2346.4 N = (T2)(cos 57)346.4 N/(cos 57) = T2636 N = T2 7. If you used the y direction Fy net = Fs + Fgsubstitute Ty net = T1y + T2y + Fg 0 = 200 N + T2y + -735 N T2y = 535 N THEN 8. If you used the y directionFy = mayT1y + T2y + Fg = (75 kg)(0 m/s2)T1y + T2y + Fg = 0 (T2) (sin 57) = T2y(T2) (sin 57*) = 535 NT2 = 535N/(sin 57)T2 = 637 N