18-cones and pyramids

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    The ConeA Cone is a three dimensional solidwith a circular base and a curved

    surface that gradually narrows to avertex.

    Volume of a Cone

    =

    + + =

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    Find the volume of a cylinder with a radiusr=1 m and height h=2 m. Find the volumeof a cone with a radius r=1 m and height

    h=1 m

    Volume of a Cylinder= base x height= r 2h

    = 3.14(1) 2 (2)

    = 6.28 m 3

    Exercise #1

    Volume of a Cone =(1/3) r 2h

    = (1/3)(3.14)(1)2

    (2)= 2.09 m 3

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    Find the area of a cone with aradius r=3 m and height h=4 m.

    Use the PythagoreanTheorem to find l

    l 2 = r2 + h2l 2 = (3) 2 + (4) 2

    l 2 = 25

    l = 5

    Surface Areaof a Cone

    Surface Area of a Cone

    = r 2 + rl

    = 3.14(3) 2 + 3.14(3)(5)

    = 75.36 m 2

    r = the radius h = the height l = the slant height

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    Cones PracticeQuestions

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    A Pyramid is a three dimensional figure with aregular polygon as its base and lateral facesare identical isosceles triangles meeting at a

    point.

    Pyramids

    base = quadrilateral base = pentagon base = heptagon

    Identical isoscelestriangles

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    Volume of a Pyramid: V = (1/3) Area of the base x heightV = (1/3) Ah

    Volume of a Pyramid = 1/3 x Volume of a Prism

    Volume of Pyramids

    + + =

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    Surface Area= area of base+ 5 (area of one lateral face)

    Area of Pyramids

    Find the surface area of thepyramid.height h = 8 m apothem a = 4 m side s = 6 m

    h

    as

    Area of a pentagonl

    What shape is the base?

    = Pa= (5)(6)(4)= 60 m2

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    Area of Pyramids

    Find the surface area of thepyramid.height h = 8 m apothem a = 4 m side s = 6 m

    h

    as

    Area of a triangle= base (height)

    l

    What shape are the lateral sides?

    l 2 = h2 + a2 = 82 + 42 = 80 m2

    l = 8.9 m

    Attention! the height of thetriangle is the slant height l

    = (6)(8.9)= 26.7 m2

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    Cones PracticeQuestions