surface area of pyramids and cones

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Surface Area of Pyramids and Cones Geometry

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Surface Area of Pyramids and Cones. Geometry. A regular pyramid has a regular polygon for a base and its height meets the base at its center. The altitude or height of a pyramid is the perpendicular distance between the base and the vertex. - PowerPoint PPT Presentation

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Page 1: Surface Area of Pyramids and Cones

Surface Area of Pyramids and Cones

Geometry

Page 2: Surface Area of Pyramids and Cones

pyramids

• A regular pyramid has a regular polygon for a base and its height meets the base at its center. The altitude or height of a pyramid is the perpendicular distance between the base and the vertex.

• The slant height of a regular pyramid is the altitude of any lateral face.

Page 3: Surface Area of Pyramids and Cones

Pyramid Arena

Page 4: Surface Area of Pyramids and Cones

Ex. 1: Finding the Area of a Lateral Face• Architecture. The lateral faces of the

Pyramid Arena in Memphis, Tennessee, are covered with steel panels. Use the diagram of the arena to find the area of each lateral face of this regular pyramid.

Page 5: Surface Area of Pyramids and Cones
Page 6: Surface Area of Pyramids and Cones

Hexagonal Pyramids

• A regular hexagonal pyramid and its net are shown at the right. Let b represent the length of a base edge, and let l represent the slant height of the pyramid. The area of each lateral face is 1/2bl and the perimeter of the base is P = 6b. So the surface area is as follows:

Page 7: Surface Area of Pyramids and Cones

Hexagonal pyramid

S = (Area of base) + 6(Area of lateral face)

S = B + 6( ½ bl)

S = B + (6b)l

S = B + Pl

Substitute

Rewrite 6( ½ bl) as ½ (6b)l.

Substitute P for 6b

Surface Area of a Regular Pyramid

The surface area S of a regular pyramid is:

S = B + ½ Pl, where B is the area of the base, P is the perimeter of the base, and l is the slant height.

Page 8: Surface Area of Pyramids and Cones

Ex. 2: Finding the surface area of a pyramid• To find the surface area

of the regular pyramid shown, start by finding the area of the base.

• Use the formula for the area of a regular polygon,

½ (apothem)(perimeter). A diagram of the base is shown to the right.

Page 9: Surface Area of Pyramids and Cones

Ex. 2: Finding the surface area of a pyramidAfter substituting, the

area of the base is ½ (3 )(6• 6), or

54 square meters.

3

3

Page 10: Surface Area of Pyramids and Cones

Surface area

• Now you can find the surface area by using 54 for the area of the base, B.3

Page 11: Surface Area of Pyramids and Cones

Finding the Surface Area of a Cone• The altitude, or height, is the

perpendicular distance between the vertex and the base. In a right cone, the height meets the base at its center and the slant height is the distance between the vertex and a point on the base edge.

Page 12: Surface Area of Pyramids and Cones

Finding the Surface Area of a Cone• The lateral surface of a

cone consists of all segments that connect the vertex with points on the base edge. When you cut along the slant height and like the cone flat, you get the net shown at the right. In the net, the circular base has an area of r2 and the lateral surface area is the sector of a circle.

Page 13: Surface Area of Pyramids and Cones

More on cones . . . • You can find the area of this sector by

using a proportion, as shown below.

Area of sectorArea of circle =

Arc lengthCircumference Set up proportion

Area of sectorl2 =

2r

2lSubstitute

Area of sector = l2 •2r

2lMultiply each side by l2

Area of sector = rl Simplify

The surface area of a cone is the sum of the base area and the lateral area, rl.

Page 14: Surface Area of Pyramids and Cones

Theorem

• Surface Area of a Right Cone

The surface area S of a right cone is S = r2 + rl, where r is the radius of the base and l is the slant height

Page 15: Surface Area of Pyramids and Cones

Ex. 3: Finding the surface area of a cone• To find the surface area

of the right cone shown, use the formula for the surface area.

S = r2 + rl Write formula

S = 42 + (4)(6) Substitute

S = 16 + 24 Simplify

S = 40 SimplifyThe surface area is 40 square inches or about 125.7 square inches.