# 11X1 T05 05 perpendicular distance (2010)

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TRANSCRIPT

• Perpendicular Distance Formula

• Perpendicular Distance Formula

The shortest distance from a point to a line is the perpendicular distance.

• Perpendicular Distance Formula

The shortest distance from a point to a line is the perpendicular distance. 1 1,x y

• Perpendicular Distance Formula

The shortest distance from a point to a line is the perpendicular distance.

Ax + By + C = 0

1 1,x y

• Perpendicular Distance Formula

The shortest distance from a point to a line is the perpendicular distance.

Ax + By + C = 0

d 1 1,x y

• Perpendicular Distance Formula

1 12 2

Ax By CdA B

The shortest distance from a point to a line is the perpendicular distance.

Ax + By + C = 0

d 1 1,x y

• Perpendicular Distance Formula

1 12 2

Ax By CdA B

e.g. Find the equation of the circle with tangent 3x 4y 12 = 0 and centre (1,4).

The shortest distance from a point to a line is the perpendicular distance.

Ax + By + C = 0

d 1 1,x y

• Perpendicular Distance Formula

1 12 2

Ax By CdA B

e.g. Find the equation of the circle with tangent 3x 4y 12 = 0 and centre (1,4).

The shortest distance from a point to a line is the perpendicular distance.

Ax + By + C = 0

d 1 1,x y

1,4

• Perpendicular Distance Formula

1 12 2

Ax By CdA B

e.g. Find the equation of the circle with tangent 3x 4y 12 = 0 and centre (1,4).

The shortest distance from a point to a line is the perpendicular distance.

Ax + By + C = 0

d 1 1,x y

1,43x 4y 12 = 0

• Perpendicular Distance Formula

1 12 2

Ax By CdA B

e.g. Find the equation of the circle with tangent 3x 4y 12 = 0 and centre (1,4).

The shortest distance from a point to a line is the perpendicular distance.

Ax + By + C = 0

d 1 1,x y

1,43x 4y 12 = 0

r

• Perpendicular Distance Formula

1 12 2

Ax By CdA B

e.g. Find the equation of the circle with tangent 3x 4y 12 = 0 and centre (1,4).

The shortest distance from a point to a line is the perpendicular distance.

Ax + By + C = 0

d 1 1,x y

1,43x 4y 12 = 0

r

22

3 1 4 4 12

3 4r

• Perpendicular Distance Formula

1 12 2

Ax By CdA B

e.g. Find the equation of the circle with tangent 3x 4y 12 = 0 and centre (1,4).

2525

The shortest distance from a point to a line is the perpendicular distance.

Ax + By + C = 0

d 1 1,x y

1,43x 4y 12 = 0

r

22

3 1 4 4 12

3 4r

• Perpendicular Distance Formula

1 12 2

Ax By CdA B

e.g. Find the equation of the circle with tangent 3x 4y 12 = 0 and centre (1,4).

2525

5 units

The shortest distance from a point to a line is the perpendicular distance.

Ax + By + C = 0

d 1 1,x y

1,43x 4y 12 = 0

r

22

3 1 4 4 12

3 4r

• Perpendicular Distance Formula

1 12 2

Ax By CdA B

e.g. Find the equation of the circle with tangent 3x 4y 12 = 0 and centre (1,4).

2525

5 units

The shortest distance from a point to a line is the perpendicular distance.

Ax + By + C = 0

d 1 1,x y

1,43x 4y 12 = 0

r

22

3 1 4 4 12

3 4r

2 2the circle is

1 4 25x y

• If has different signs for different points, they are on different sides of the line. 1 1Ax By C

• If has different signs for different points, they are on different sides of the line. 1 1Ax By C

Ax + By + C = 0

• If has different signs for different points, they are on different sides of the line. 1 1Ax By C

Ax + By + C = 0

Ax + By + C > 0

• If has different signs for different points, they are on different sides of the line. 1 1Ax By C

Ax + By + C = 0

Ax + By + C > 0Ax + By + C < 0

• If has different signs for different points, they are on different sides of the line. 1 1Ax By C

Exercise 5E; 1b, 2cf, 5a, 6a, 7bd, 8b, 9abc, 10, 13, 14, 18*

Ax + By + C = 0

Ax + By + C > 0Ax + By + C < 0

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