11 x1 t05 01 permutations i (2013)

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The Basic Counting Principle

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Page 1: 11 x1 t05 01 permutations i (2013)

The Basic Counting Principle

Page 2: 11 x1 t05 01 permutations i (2013)

The Basic Counting PrincipleIf one event can happen in m different ways and after this another event can happen in n different ways, then the two events can occur in mn different ways.

Page 3: 11 x1 t05 01 permutations i (2013)

The Basic Counting PrincipleIf one event can happen in m different ways and after this another event can happen in n different ways, then the two events can occur in mn different ways.

e.g. 3 dice are rolled

Page 4: 11 x1 t05 01 permutations i (2013)

The Basic Counting PrincipleIf one event can happen in m different ways and after this another event can happen in n different ways, then the two events can occur in mn different ways.

e.g. 3 dice are rolled(i) How many ways can the three dice fall?

Page 5: 11 x1 t05 01 permutations i (2013)

The Basic Counting PrincipleIf one event can happen in m different ways and after this another event can happen in n different ways, then the two events can occur in mn different ways.

e.g. 3 dice are rolled(i) How many ways can the three dice fall?

666 Ways

Page 6: 11 x1 t05 01 permutations i (2013)

The Basic Counting PrincipleIf one event can happen in m different ways and after this another event can happen in n different ways, then the two events can occur in mn different ways.

e.g. 3 dice are rolled(i) How many ways can the three dice fall?

666 Ways

iespossibilit6has die1st the

Page 7: 11 x1 t05 01 permutations i (2013)

The Basic Counting PrincipleIf one event can happen in m different ways and after this another event can happen in n different ways, then the two events can occur in mn different ways.

e.g. 3 dice are rolled(i) How many ways can the three dice fall?

666 Ways

iespossibilit6has die1st theiespossibilit6hasdie2ndthe

Page 8: 11 x1 t05 01 permutations i (2013)

The Basic Counting PrincipleIf one event can happen in m different ways and after this another event can happen in n different ways, then the two events can occur in mn different ways.

e.g. 3 dice are rolled(i) How many ways can the three dice fall?

666 Ways

iespossibilit6has die1st theiespossibilit6hasdie2ndthe

iespossibilit6has die3rdthe

Page 9: 11 x1 t05 01 permutations i (2013)

The Basic Counting PrincipleIf one event can happen in m different ways and after this another event can happen in n different ways, then the two events can occur in mn different ways.

e.g. 3 dice are rolled(i) How many ways can the three dice fall?

666 Ways

iespossibilit6has die1st theiespossibilit6hasdie2ndthe

iespossibilit6has die3rdthe612

Page 10: 11 x1 t05 01 permutations i (2013)

(ii) How many ways can all three dice show the same number?

Page 11: 11 x1 t05 01 permutations i (2013)

(ii) How many ways can all three dice show the same number?

116 Ways

Page 12: 11 x1 t05 01 permutations i (2013)

(ii) How many ways can all three dice show the same number?

116 Ways

iespossibilit6has die1st the

Page 13: 11 x1 t05 01 permutations i (2013)

(ii) How many ways can all three dice show the same number?

116 Ways

iespossibilit6has die1st theypossibilit1only has nowdie2ndthe

Page 14: 11 x1 t05 01 permutations i (2013)

(ii) How many ways can all three dice show the same number?

116 Ways

iespossibilit6has die1st theypossibilit1only has nowdie2ndthe

ypossibilit1only has nowdie3rdthe

Page 15: 11 x1 t05 01 permutations i (2013)

(ii) How many ways can all three dice show the same number?

116 Ways

iespossibilit6has die1st theypossibilit1only has nowdie2ndthe

ypossibilit1only has nowdie3rdthe6

Page 16: 11 x1 t05 01 permutations i (2013)

(ii) How many ways can all three dice show the same number?

116 Ways

iespossibilit6has die1st theypossibilit1only has nowdie2ndthe

ypossibilit1only has nowdie3rdthe6

(iii) What is the probability that all three dice show the same number?

Page 17: 11 x1 t05 01 permutations i (2013)

(ii) How many ways can all three dice show the same number?

116 Ways

iespossibilit6has die1st theypossibilit1only has nowdie2ndthe

ypossibilit1only has nowdie3rdthe6

(iii) What is the probability that all three dice show the same number?

2166same the3 all P

Page 18: 11 x1 t05 01 permutations i (2013)

(ii) How many ways can all three dice show the same number?

116 Ways

iespossibilit6has die1st theypossibilit1only has nowdie2ndthe

ypossibilit1only has nowdie3rdthe6

(iii) What is the probability that all three dice show the same number?

2166same the3 all P

361

Page 19: 11 x1 t05 01 permutations i (2013)

Mice are placed in the centre of a maze which has five exits.

Each mouse is equally likely to leave the maze through any of the five exits. Thus, the probability of any given mouse leaving by a particular exit is

Four mice, A, B, C and D are put into the maze and behave independently.

(i) What is the probability that A, B, C and D all come out the same exit?

51

1996 Extension 1 HSC Q5c)

Page 20: 11 x1 t05 01 permutations i (2013)

Mice are placed in the centre of a maze which has five exits.

Each mouse is equally likely to leave the maze through any of the five exits. Thus, the probability of any given mouse leaving by a particular exit is

Four mice, A, B, C and D are put into the maze and behave independently.

(i) What is the probability that A, B, C and D all come out the same exit?

51

1996 Extension 1 HSC Q5c)

51

51

511exit same theuse all P

Page 21: 11 x1 t05 01 permutations i (2013)

Mice are placed in the centre of a maze which has five exits.

Each mouse is equally likely to leave the maze through any of the five exits. Thus, the probability of any given mouse leaving by a particular exit is

Four mice, A, B, C and D are put into the maze and behave independently.

(i) What is the probability that A, B, C and D all come out the same exit?

51

1996 Extension 1 HSC Q5c)

51

51

511exit same theuse all P

1door any through gocan mouseFirst P

Page 22: 11 x1 t05 01 permutations i (2013)

Mice are placed in the centre of a maze which has five exits.

Each mouse is equally likely to leave the maze through any of the five exits. Thus, the probability of any given mouse leaving by a particular exit is

Four mice, A, B, C and D are put into the maze and behave independently.

(i) What is the probability that A, B, C and D all come out the same exit?

51

1996 Extension 1 HSC Q5c)

51

51

511exit same theuse all P

1door any through gocan mouseFirst P

51door samethrough

gomust miceOther

P

Page 23: 11 x1 t05 01 permutations i (2013)

Mice are placed in the centre of a maze which has five exits.

Each mouse is equally likely to leave the maze through any of the five exits. Thus, the probability of any given mouse leaving by a particular exit is

Four mice, A, B, C and D are put into the maze and behave independently.

(i) What is the probability that A, B, C and D all come out the same exit?

51

1996 Extension 1 HSC Q5c)

51

51

511exit same theuse all P

1door any through gocan mouseFirst P

51door samethrough

gomust miceOther

P

1251

Page 24: 11 x1 t05 01 permutations i (2013)

(ii) What is the probability that A, B and C come out the same exit and D comes out a different exit?

Page 25: 11 x1 t05 01 permutations i (2013)

(ii) What is the probability that A, B and C come out the same exit and D comes out a different exit?

51

51

541exitdifferent uses exit, same use DABCP

Page 26: 11 x1 t05 01 permutations i (2013)

(ii) What is the probability that A, B and C come out the same exit and D comes out a different exit?

51

51

541exitdifferent uses exit, same use DABCP

1door any through gocan D P

Page 27: 11 x1 t05 01 permutations i (2013)

(ii) What is the probability that A, B and C come out the same exit and D comes out a different exit?

51

51

541exitdifferent uses exit, same use DABCP

1door any through gocan D P

54

choosetodoors4hasmouseNext

P

Page 28: 11 x1 t05 01 permutations i (2013)

(ii) What is the probability that A, B and C come out the same exit and D comes out a different exit?

51

51

541exitdifferent uses exit, same use DABCP

1door any through gocan D P

54

choosetodoors4hasmouseNext

P

51door samethrough

gomust miceOther

P

Page 29: 11 x1 t05 01 permutations i (2013)

(ii) What is the probability that A, B and C come out the same exit and D comes out a different exit?

51

51

541exitdifferent uses exit, same use DABCP

1door any through gocan D P

54

choosetodoors4hasmouseNext

P

1254

51door samethrough

gomust miceOther

P

Page 30: 11 x1 t05 01 permutations i (2013)

(iii) What is the probability that any of the four mice come out the same exit and the other comes out a different exit?

Page 31: 11 x1 t05 01 permutations i (2013)

(iii) What is the probability that any of the four mice come out the same exit and the other comes out a different exit?

125

4exitdifferent uses DP

Page 32: 11 x1 t05 01 permutations i (2013)

(iii) What is the probability that any of the four mice come out the same exit and the other comes out a different exit?

125

4exitdifferent uses DP

125

4exitdifferent uses AP

Page 33: 11 x1 t05 01 permutations i (2013)

(iii) What is the probability that any of the four mice come out the same exit and the other comes out a different exit?

125

4exitdifferent uses DP

125

4exitdifferent uses AP

125

4exitdifferent uses BP

Page 34: 11 x1 t05 01 permutations i (2013)

(iii) What is the probability that any of the four mice come out the same exit and the other comes out a different exit?

125

4exitdifferent uses DP

125

4exitdifferent uses AP

125

4exitdifferent uses BP

125

4exitdifferent uses CP

Page 35: 11 x1 t05 01 permutations i (2013)

(iii) What is the probability that any of the four mice come out the same exit and the other comes out a different exit?

125

4exitdifferent uses DP

125

4exitdifferent uses AP

125

4exitdifferent uses BP

125

4exitdifferent uses CP

125

44exitdifferent uses mouseany P

Page 36: 11 x1 t05 01 permutations i (2013)

(iii) What is the probability that any of the four mice come out the same exit and the other comes out a different exit?

125

4exitdifferent uses DP

125

4exitdifferent uses AP

125

4exitdifferent uses BP

125

4exitdifferent uses CP

125

44exitdifferent uses mouseany P

12516

Page 37: 11 x1 t05 01 permutations i (2013)

(iv) What is the probability that no more than two mice come out the same exit?

Page 38: 11 x1 t05 01 permutations i (2013)

(iv) What is the probability that no more than two mice come out the same exit?

sameuse3sameall1exitsameuse2 than moreno PPP

Page 39: 11 x1 t05 01 permutations i (2013)

(iv) What is the probability that no more than two mice come out the same exit?

sameuse3sameall1exitsameuse2 than moreno PPP

12516

12511

Page 40: 11 x1 t05 01 permutations i (2013)

(iv) What is the probability that no more than two mice come out the same exit?

sameuse3sameall1exitsameuse2 than moreno PPP

12516

12511

125108

Page 41: 11 x1 t05 01 permutations i (2013)

Permutations

Page 42: 11 x1 t05 01 permutations i (2013)

PermutationsA permutation is an ordered set of objects

Page 43: 11 x1 t05 01 permutations i (2013)

PermutationsA permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such Objects

Page 44: 11 x1 t05 01 permutations i (2013)

PermutationsA permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such Objects

(i.e. use all of the objects)

Page 45: 11 x1 t05 01 permutations i (2013)

PermutationsA permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such Objects

If we arrange n different objects in a line, the number of ways we could arrange them are;

(i.e. use all of the objects)

Page 46: 11 x1 t05 01 permutations i (2013)

PermutationsA permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such Objects

If we arrange n different objects in a line, the number of ways we could arrange them are;

ntsArrangemen ofNumber 1object for

iespossibilit

(i.e. use all of the objects)

Page 47: 11 x1 t05 01 permutations i (2013)

PermutationsA permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such Objects

If we arrange n different objects in a line, the number of ways we could arrange them are;

ntsArrangemen ofNumber 1object for

iespossibilit

(i.e. use all of the objects)

1 n

2object for iespossibilit

Page 48: 11 x1 t05 01 permutations i (2013)

PermutationsA permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such Objects

If we arrange n different objects in a line, the number of ways we could arrange them are;

ntsArrangemen ofNumber 1object for

iespossibilit

(i.e. use all of the objects)

1 n 2 n

2object for iespossibilit

3object for iespossibilit

Page 49: 11 x1 t05 01 permutations i (2013)

PermutationsA permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such Objects

If we arrange n different objects in a line, the number of ways we could arrange them are;

ntsArrangemen ofNumber 1object for

iespossibilit

(i.e. use all of the objects)

1 n 2 n 1

2object for iespossibilit

3object for iespossibilit

objectlast for iespossibilit

Page 50: 11 x1 t05 01 permutations i (2013)

PermutationsA permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such Objects

If we arrange n different objects in a line, the number of ways we could arrange them are;

ntsArrangemen ofNumber 1object for

iespossibilit

!n

(i.e. use all of the objects)

1 n 2 n 1

2object for iespossibilit

3object for iespossibilit

objectlast for iespossibilit

Page 51: 11 x1 t05 01 permutations i (2013)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line if;

(i) there are no restrictions?

Page 52: 11 x1 t05 01 permutations i (2013)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line if;

(i) there are no restrictions?

!9tsArrangemen

Page 53: 11 x1 t05 01 permutations i (2013)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line if;

(i) there are no restrictions?

!9tsArrangemen With no restrictions, arrange 9 peoplegender does not matter

Page 54: 11 x1 t05 01 permutations i (2013)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line if;

(i) there are no restrictions?

!9tsArrangemen With no restrictions, arrange 9 peoplegender does not matter 362880

Page 55: 11 x1 t05 01 permutations i (2013)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line if;

(i) there are no restrictions?

!9tsArrangemen With no restrictions, arrange 9 peoplegender does not matter 362880

(ii) boys and girls alternate?

Page 56: 11 x1 t05 01 permutations i (2013)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line if;

(i) there are no restrictions?

!9tsArrangemen With no restrictions, arrange 9 peoplegender does not matter 362880

(ii) boys and girls alternate? (ALWAYS look after any restrictions first)

Page 57: 11 x1 t05 01 permutations i (2013)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line if;

(i) there are no restrictions?

!9tsArrangemen With no restrictions, arrange 9 peoplegender does not matter 362880

(ii) boys and girls alternate?

1tsArrangemen

boy a beMUSTperson first

(ALWAYS look after any restrictions first)

Page 58: 11 x1 t05 01 permutations i (2013)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line if;

(i) there are no restrictions?

!9tsArrangemen With no restrictions, arrange 9 peoplegender does not matter 362880

(ii) boys and girls alternate?

1tsArrangemen

boy a beMUSTperson first

(ALWAYS look after any restrictions first)

!5

boys thearrangingof waysofnumber

Page 59: 11 x1 t05 01 permutations i (2013)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line if;

(i) there are no restrictions?

!9tsArrangemen With no restrictions, arrange 9 peoplegender does not matter 362880

(ii) boys and girls alternate?

1tsArrangemen

boy a beMUSTperson first

(ALWAYS look after any restrictions first)

!5 !4

boys thearrangingof waysofnumber

girls thearrangingofwaysofnumber

Page 60: 11 x1 t05 01 permutations i (2013)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line if;

(i) there are no restrictions?

!9tsArrangemen With no restrictions, arrange 9 peoplegender does not matter 362880

(ii) boys and girls alternate?

1tsArrangemen

boy a beMUSTperson first

(ALWAYS look after any restrictions first)

!5 !4

boys thearrangingof waysofnumber

girls thearrangingofwaysofnumber

2880

Page 61: 11 x1 t05 01 permutations i (2013)

(iii) What is the probability of the boys and girls alternating?

Page 62: 11 x1 t05 01 permutations i (2013)

(iii) What is the probability of the boys and girls alternating?

362880

2880alternate girls & boys P

Page 63: 11 x1 t05 01 permutations i (2013)

(iii) What is the probability of the boys and girls alternating?

362880

2880alternate girls & boys P

1261

Page 64: 11 x1 t05 01 permutations i (2013)

(iii) What is the probability of the boys and girls alternating?

362880

2880alternate girls & boys P

1261

(iv) Two girls wish to be together?

Page 65: 11 x1 t05 01 permutations i (2013)

(iii) What is the probability of the boys and girls alternating?

362880

2880alternate girls & boys P

1261

(iv) Two girls wish to be together?

!2tsArrangemen

arranged becan girlsthewaysofnumber the

Page 66: 11 x1 t05 01 permutations i (2013)

(iii) What is the probability of the boys and girls alternating?

362880

2880alternate girls & boys P

1261

(iv) Two girls wish to be together?

!2tsArrangemen

arranged becan girlsthewaysofnumber the

!8 others 7 girls) (2objects 8 arranging

ofwaysofnumber

Page 67: 11 x1 t05 01 permutations i (2013)

(iii) What is the probability of the boys and girls alternating?

362880

2880alternate girls & boys P

1261

(iv) Two girls wish to be together?

!2tsArrangemen

arranged becan girlsthewaysofnumber the

!8 others 7 girls) (2objects 8 arranging

ofwaysofnumber

80640

Page 68: 11 x1 t05 01 permutations i (2013)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such Objects (k < n)

Page 69: 11 x1 t05 01 permutations i (2013)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such Objects (k < n)

(i.e. use some of the objects)

Page 70: 11 x1 t05 01 permutations i (2013)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such Objects (k < n)

If we have n different objects in a line, but only want to arrange k of them, the number of ways we could arrange them are;

(i.e. use some of the objects)

Page 71: 11 x1 t05 01 permutations i (2013)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such Objects (k < n)

If we have n different objects in a line, but only want to arrange k of them, the number of ways we could arrange them are;

ntsArrangemen ofNumber 1object for

iespossibilit

(i.e. use some of the objects)

Page 72: 11 x1 t05 01 permutations i (2013)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such Objects (k < n)

If we have n different objects in a line, but only want to arrange k of them, the number of ways we could arrange them are;

ntsArrangemen ofNumber 1object for

iespossibilit

(i.e. use some of the objects)

1 n

2object for iespossibilit

Page 73: 11 x1 t05 01 permutations i (2013)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such Objects (k < n)

If we have n different objects in a line, but only want to arrange k of them, the number of ways we could arrange them are;

ntsArrangemen ofNumber 1object for

iespossibilit

(i.e. use some of the objects)

1 n 2 n

2object for iespossibilit

3object for iespossibilit

Page 74: 11 x1 t05 01 permutations i (2013)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such Objects (k < n)

If we have n different objects in a line, but only want to arrange k of them, the number of ways we could arrange them are;

ntsArrangemen ofNumber 1object for

iespossibilit

(i.e. use some of the objects)

1 n 2 n 1 kn

2object for iespossibilit

3object for iespossibilit

kobject for iespossibilit

Page 75: 11 x1 t05 01 permutations i (2013)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such Objects (k < n)

If we have n different objects in a line, but only want to arrange k of them, the number of ways we could arrange them are;

ntsArrangemen ofNumber 1object for

iespossibilit

1231

1231121

knknknknknnnn

(i.e. use some of the objects)

1 n 2 n 1 kn

2object for iespossibilit

3object for iespossibilit

kobject for iespossibilit

Page 76: 11 x1 t05 01 permutations i (2013)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such Objects (k < n)

If we have n different objects in a line, but only want to arrange k of them, the number of ways we could arrange them are;

ntsArrangemen ofNumber 1object for

iespossibilit

1231

1231121

knknknknknnnn

(i.e. use some of the objects)

1 n 2 n 1 kn

2object for iespossibilit

3object for iespossibilit

kobject for iespossibilit

!! kn

n

Page 77: 11 x1 t05 01 permutations i (2013)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such Objects (k < n)

If we have n different objects in a line, but only want to arrange k of them, the number of ways we could arrange them are;

ntsArrangemen ofNumber 1object for

iespossibilit

1231

1231121

knknknknknnnn

(i.e. use some of the objects)

1 n 2 n 1 kn

2object for iespossibilit

3object for iespossibilit

kobject for iespossibilit

!! kn

n

knP

Page 78: 11 x1 t05 01 permutations i (2013)

e.g. (i) From the letters of the word PROBLEMS how many 5 letter words are possible if;

a) there are no restrictions?

Page 79: 11 x1 t05 01 permutations i (2013)

e.g. (i) From the letters of the word PROBLEMS how many 5 letter words are possible if;

a) there are no restrictions?

58 Words P

Page 80: 11 x1 t05 01 permutations i (2013)

e.g. (i) From the letters of the word PROBLEMS how many 5 letter words are possible if;

a) there are no restrictions?

58 Words P6720

Page 81: 11 x1 t05 01 permutations i (2013)

e.g. (i) From the letters of the word PROBLEMS how many 5 letter words are possible if;

a) there are no restrictions?

58 Words P6720

b) they must begin with P?

Page 82: 11 x1 t05 01 permutations i (2013)

e.g. (i) From the letters of the word PROBLEMS how many 5 letter words are possible if;

a) there are no restrictions?

58 Words P6720

b) they must begin with P?

1Words

first placed becan Pwaysofnumber the

Page 83: 11 x1 t05 01 permutations i (2013)

e.g. (i) From the letters of the word PROBLEMS how many 5 letter words are possible if;

a) there are no restrictions?

58 Words P6720

b) they must begin with P?

1Words

first placed becan Pwaysofnumber the

47 P ROBLEMS

dsletter wor 4many howbecomesnowQuestion

Page 84: 11 x1 t05 01 permutations i (2013)

e.g. (i) From the letters of the word PROBLEMS how many 5 letter words are possible if;

a) there are no restrictions?

58 Words P6720

b) they must begin with P?

1Words

first placed becan Pwaysofnumber the

47 P ROBLEMS

dsletter wor 4many howbecomesnowQuestion

840

Page 85: 11 x1 t05 01 permutations i (2013)

c) P is included, but not at the beginning, and M is excluded?

Page 86: 11 x1 t05 01 permutations i (2013)

c) P is included, but not at the beginning, and M is excluded?

4Words

in placed becan Ppositionsofnumber the

Page 87: 11 x1 t05 01 permutations i (2013)

c) P is included, but not at the beginning, and M is excluded?

4Words

in placed becan Ppositionsofnumber the

46 P ROBLES

dsletter wor 4many howbecomesnowQuestion

Page 88: 11 x1 t05 01 permutations i (2013)

c) P is included, but not at the beginning, and M is excluded?

4Words

in placed becan Ppositionsofnumber the

46 P ROBLES

dsletter wor 4many howbecomesnowQuestion

1440

Page 89: 11 x1 t05 01 permutations i (2013)

c) P is included, but not at the beginning, and M is excluded?

4Words

in placed becan Ppositionsofnumber the

46 P ROBLES

dsletter wor 4many howbecomesnowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.What is the probability that Bill and Ted are on the left side and Greg is on the right?

Page 90: 11 x1 t05 01 permutations i (2013)

c) P is included, but not at the beginning, and M is excluded?

4Words

in placed becan Ppositionsofnumber the

46 P ROBLES

dsletter wor 4many howbecomesnowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.What is the probability that Bill and Ted are on the left side and Greg is on the right?

68 ns)restrictio (no Ways P

Page 91: 11 x1 t05 01 permutations i (2013)

c) P is included, but not at the beginning, and M is excluded?

4Words

in placed becan Ppositionsofnumber the

46 P ROBLES

dsletter wor 4many howbecomesnowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.What is the probability that Bill and Ted are on the left side and Greg is on the right?

68 ns)restrictio (no Ways P20160

Page 92: 11 x1 t05 01 permutations i (2013)

c) P is included, but not at the beginning, and M is excluded?

4Words

in placed becan Ppositionsofnumber the

46 P ROBLES

dsletter wor 4many howbecomesnowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.What is the probability that Bill and Ted are on the left side and Greg is on the right?

68 ns)restrictio (no Ways P20160

24 ons)(restricti Ways P

gocan Ted & BillWays

Page 93: 11 x1 t05 01 permutations i (2013)

c) P is included, but not at the beginning, and M is excluded?

4Words

in placed becan Ppositionsofnumber the

46 P ROBLES

dsletter wor 4many howbecomesnowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.What is the probability that Bill and Ted are on the left side and Greg is on the right?

68 ns)restrictio (no Ways P20160

24 ons)(restricti Ways P

gocan Ted & BillWays

14P

gocan GregWays

Page 94: 11 x1 t05 01 permutations i (2013)

c) P is included, but not at the beginning, and M is excluded?

4Words

in placed becan Ppositionsofnumber the

46 P ROBLES

dsletter wor 4many howbecomesnowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.What is the probability that Bill and Ted are on the left side and Greg is on the right?

68 ns)restrictio (no Ways P20160

24 ons)(restricti Ways P

gocan Ted & BillWays

14P 3

5P

gocan GregWays

gocan peopleremainingWays

Page 95: 11 x1 t05 01 permutations i (2013)

c) P is included, but not at the beginning, and M is excluded?

4Words

in placed becan Ppositionsofnumber the

46 P ROBLES

dsletter wor 4many howbecomesnowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.What is the probability that Bill and Ted are on the left side and Greg is on the right?

68 ns)restrictio (no Ways P20160

24 ons)(restricti Ways P

gocan Ted & BillWays

14P 3

5P

gocan GregWays

gocan peopleremainingWays

2880

Page 96: 11 x1 t05 01 permutations i (2013)

c) P is included, but not at the beginning, and M is excluded?

4Words

in placed becan Ppositionsofnumber the

46 P ROBLES

dsletter wor 4many howbecomesnowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.What is the probability that Bill and Ted are on the left side and Greg is on the right?

68 ns)restrictio (no Ways P20160

24 ons)(restricti Ways P

gocan Ted & BillWays

14P 3

5P

gocan GregWays

gocan peopleremainingWays

2880

201602880rightG left, T&B P

Page 97: 11 x1 t05 01 permutations i (2013)

c) P is included, but not at the beginning, and M is excluded?

4Words

in placed becan Ppositionsofnumber the

46 P ROBLES

dsletter wor 4many howbecomesnowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.What is the probability that Bill and Ted are on the left side and Greg is on the right?

68 ns)restrictio (no Ways P20160

24 ons)(restricti Ways P

gocan Ted & BillWays

14P 3

5P

gocan GregWays

gocan peopleremainingWays

2880

201602880rightG left, T&B P

71

Page 98: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

Page 99: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are three blocks high?

Page 100: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are three blocks high?

35 Towers P

Page 101: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are three blocks high?

35 Towers P60

Page 102: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are three blocks high?

35 Towers P60

(ii) How many different towers can she form in total?

Page 103: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are three blocks high?

35 Towers P60

(ii) How many different towers can she form in total?

25 Towersblock 2 P

Page 104: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are three blocks high?

35 Towers P60

(ii) How many different towers can she form in total?

25 Towersblock 2 P 20

Page 105: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are three blocks high?

35 Towers P60

(ii) How many different towers can she form in total?

25 Towersblock 2 P

35 Towersblock 3 P

20

Page 106: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are three blocks high?

35 Towers P60

(ii) How many different towers can she form in total?

25 Towersblock 2 P

35 Towersblock 3 P

20

60

Page 107: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are three blocks high?

35 Towers P60

(ii) How many different towers can she form in total?

25 Towersblock 2 P

35 Towersblock 3 P

20

60

45 Towersblock 4 P

Page 108: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are three blocks high?

35 Towers P60

(ii) How many different towers can she form in total?

25 Towersblock 2 P

35 Towersblock 3 P

20

60

45 Towersblock 4 P 120

Page 109: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are three blocks high?

35 Towers P60

(ii) How many different towers can she form in total?

25 Towersblock 2 P

35 Towersblock 3 P

20

60

45 Towersblock 4 P 120

55 Towersblock 5 P

Page 110: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are three blocks high?

35 Towers P60

(ii) How many different towers can she form in total?

25 Towersblock 2 P

35 Towersblock 3 P

20

60

45 Towersblock 4 P 120

55 Towersblock 5 P 120

Page 111: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are three blocks high?

35 Towers P60

(ii) How many different towers can she form in total?

25 Towersblock 2 P

35 Towersblock 3 P

20

60

45 Towersblock 4 P 120

55 Towersblock 5 P 120

320Towersofnumber Total

Page 112: 11 x1 t05 01 permutations i (2013)

Sophia has five coloured blocks: one red, one blue, one green, one yellow and one white.

She stacks two, three, four or five blocks on top of one another to form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are three blocks high?

35 Towers P60

(ii) How many different towers can she form in total?

25 Towersblock 2 P

35 Towersblock 3 P

20

60

45 Towersblock 4 P 120

55 Towersblock 5 P 120

320Towersofnumber Total

Exercise 10E; odd (not 39)