เฉลยคณิต ครูพี่กอล์ฟ

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เฉลยคณิตครูพี่กอล์ฟ ม.ปลาย

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  • ..

    Vol.4 4 5 8

    (diff L' Hospital)x 1lim

    7 3x x+ 3

    10 x 8x+1=

    00

    =x 1lim

    1

    2 73x(3) 1

    2 x+3(1)

    1

    2 10x( 1) 1

    2 8x+1(8)

    =

    32

    12

    13

    83

    =23

    12k = 12 23 = 8 7 7 53

    Con x = 2 f (2) function $% : f(2) = a b

    x 2lim f (x) =

    x 2lim x

    3 3x 2x 2

    =

    x 2lim 3x

    2 31

    = 3 (4) 3 = 9

    00

    x 2+lim f (x) =

    x 2+lim x2 + ax + 1 = 4 + 2a + 1 = 2a + 5

    '() 2a + 5 = 9 a = 2

    *( a b = 9 2 b = 9 b = 7

    a2 + b2 = 22 + (7 )2 = 53

    17 13 2

    f (x) = 2x , x 02 , x < 0

    f ( 5) = 2f (3) = 2(3) = 6

    =

    1

  • 18 13 2' f (x) = d

    dxf(x) =

    h 0lim

    f (x+ h) f (x)h

    1 = d (sin x)dx h 0

    limsin (x+ h) sin x

    h

    2 = d (x+ 1)dx h 0

    lim((x+ h) + 1) (x+ 1)

    h=

    x0lim

    ((x+ x) + 1) (x+ 1)x

    3 = d (e2x)

    dx h 0lim e

    2(x+h) e2x

    h=

    x 0lim e

    2(x+ x) e2x

    x

    4 = d (2x2

    1)dx h 0

    lim(2 (x+ h)2 1) (2x2 1)

    h

    21 15 54.'/0123456278$290$2$: 4 1;( t = 0 => 2$?2%f(4) (0)

    ' f (t) = 4f (t) 3f (t) + 1 (1)

    f (t) = 4f (t) 3f (t) (2)

    f(4) (t) = 4f (t) 3f (t) (3)

    f(4) (0) = 4f (0) 3f (0) (4)

    */2 t = 0 @2 (1) , f (0) = 4f (0) 3f (0) + 1 = 4(2) 3 (1) + 1 = 6

    */2 t = 0 @2 (2) , f (0) = 4f (0) 3f (0) = 4 (6) 3 (2) = 18

    */2@2 (4) , f(4) (0) = 4 (18) 3 (6) = 54 25 17 4

    ' xy = c y = cx y = cx1 y = cx2 = cx2

    B667C'7B$6D$B> a , ca m =

    yx =

    2 25 1

    = 1

    m.>% 1;( x @G > y = c

    x2

    m.>% /3? > a , ca ca2

    * m.>% /3? a , ca = m

    c

    a2= 1 c = a2 (1)

    (1,2)(5,-2)

    (a, )ca

    y = cx

    m

    2

  • m ''7 $: (1 , 2)a , ca = m =

    ca 2

    a 1 1

    = , */2 '()ca 2 a + 1 c = a2

    = a2a 2 a + 1

    2a = 3 a = 32

    */2@2 (1) , c = 32 2

    =94

    26 17 3*'7$ y = 2x2 + 8x + 6 (1)

    y = 2x + 6 (2)

    ' (1) *( (2) , 2x2 + 8x + 6 = 2x + 6

    2x2 + 10x = 0 2x(x 5) = 0 x = 0 , 5

    */2@2 (2) , 5 x = 0 ) y = 6 , 5 x = 5 ) y = 4

    '7$ > (0 , 6) $: (5,4)@ y = f(x) = 2x2 + 8x + 6

    f (x) = 4x + 8m1 = f (0) = 8

    m2 = f (5) = 4(5) + 8 = 12

    B6K : L1 y 6 = 8(x 0) y = 8x + 6 (3)

    B6K : L2 y (4) = 12(x 5) y = 12x + 56 (4)

    */2 @2 (3) ) (3) (4), 0 = 20x 50 x = 52

    x = 52

    y = 8 52 + 6 = 26 (a , b) > 52, 26 a + b = 28.5

    (a,b)

    (0,6) (5,-4)

    L : m = 81 1 L : m = -122 2

    3

  • 30 19 3 @ 8./. B63?6N2.>% = A

    A = 12(20 2r)r = (10 r)r = 10r r2

    dAdr

    = 10 2r = 0

    r = 5

    = K%P2C6KAmax (10 5)(5) = 25

    32 21 6' f (x) = 3 x + 5 = 3x

    12 + 5

    f(x) = f (x)dx = (3x12 + 5)dx = 3x

    32

    32

    + 5x + c = 2x x + 5x + c

    .'/0: f(1) = 5 f(1) = 2 + 5 + c = 5 c = 2

    f(x) = 2x x + 5x 2

    x 4lim

    f(x2) 2f(x) =

    f(16) 2f(4) =

    (32 16 + 80 2) 216+ 20 2

    =20434

    = 6

    34 22 7'.'/0 ">6S$21%B2B$6D$B /3?'7 (2 , 19) /$: 19"*B% *( f(2) = 19f (2) = 19

    f (x) = f (x)dx = (6x + 4)dx = 3x2 + 4x + c f (2) = 12 + 8 + c = 19 c = 1 f (x) = 3x2 + 4x 1

    f(x) = f (x)dx = (3x2 + 4x 1)dx = x3 + 2x2 x + c f(2) = 8 + 8 2 + c = 19 c = 5 f(x) = x3 + 2x2 x + 5

    f(1) = 1 + 2 1 + 5 = 7

    2 39 22?%' a, b, c CK/3?B6 KUK3:/3: '(% a3, b3, c3

    a3 = 1 + 3 4 3

    = 1 + 3 3 4 + 3 3 16 + 4 = 5 + 3 3 4 + 3 16 b3 = 3 2 + 3 3

    3= 2 + 3 3 4 3 3 + 3 3 2 3 9 + 3 = 5 + 3 3 12 + 3 18

    r r

    20 - 2r

    4

  • 8: *2G b > a $1 4 /C4%) b3 > a3

    /3:$: c3 = 11 a3 = 5 + 3 3 4 + 3 16 1 G 2 G

    8: a > c $1 1 *( 3 /C4%) : 1 2a3 > c3

    1234@SBXK : (a + b)3 = a3 + 3a2b + 3ab2 + b3

    5 41 1

    = 27 y = 35x 9x2log3

    log2log 5

    log 4log 7

    log 6

    log3

    log4log 5

    log 6log 7

    log 8

    = = 35x (32)x2 33 log3log2

    log5

    log4log7

    log6log4

    log3log6

    log5log8

    log7

    = = 35x+ 2x2 33 log8log2

    =log23

    log2=

    3 log2

    log2= 3

    = 3 5x + 2x2 xy = 12 3

    =18

    = 02x2 + 5x 3

    = 0(2x 1)(x + 3)

    x = 12, 3

    .'/0: x R+

    7 42 1 1 ! 2Y)U132KZlogxx =

    log2

    2

    2 log x = x log 2 log x2 = log 2x

    x2 = 2x

    >Y: > x = 2 , 4 2 "# 8K(6?2Y (1 , 0) *( */2@2 U[2'KC% (9,2) y = log 1

    3

    x

    3 %&' 4 5X *2G

    y

    x

    (4,16)

    (2,4)

    y = x2

    y = 2 x

    '723463> x U[2:)68C'K;

    5

  • 15 46 3log82 + log84 + log88 + log816 + ... + log82

    n= 210

    log232 + log2322 + log232

    3 + log2324 + ... + log232

    n= 210

    13

    + 23

    + 33

    + 43

    + ... + n3

    = 210

    = 6301 + 2 + 3 + 4 + ... + n

    = 630n(n+1)2

    = n(n + 1) 1260 = 35 36

    n = 35 16 46 1

    a =n = 2

    9 log 1 1n2 = n = 2

    9 log n

    2 1n

    = n = 29 log (n 1)(n+ 1)n2

    =n = 2

    9 log n 1n n+ 1n

    a = log 12 32 + log 23 43 + log 34 54 + ... + log 89 109 a = log 12 32 23 43 34 54 ... 89 109 = log 1018 = log 59

    10a = 59

    18 47 10@ '() logxy + logyx = 103 A = logxy ,

    1A

    = logyx

    A + 1A

    =103

    3A2 + 3 = 10A 3A2 10A + 3 = 0 (3A 1)(A 3) = 0

    A = 13, 3 logxy =

    13, 3 y = x

    13 , x3

    () 1 , ' y = x13 xy = 16 x x

    13 = 16 x

    43 = 16

    (x43 )

    34 = (16)

    34 x = (24)

    34 = 23 = 8 y = x

    13 = 8

    13 = 2

    $%2$42 x + y = 8 + 2 = 10

    () 2 ' x = 2y = x3, xy = 16 x x3 = 16 x4 = 16

    y = x3 = 23 = 8 x + y = 2 + 8 = 10

    6

  • 20 48 f1(x) = 12log x1x1

    y = f(x) = 10x 10x10x + 10x

    =

    10x 110x

    10x + 110x

    =

    102x 1

    10x

    102x +110x

    =102x 1

    102x + 1

    inverse U3?2 x U[2 y , U3?2 y U[2 x '()x = 10

    2y 1

    102y +1 x(102y + 1) = 102y 1 x(102y) + x 102y = 1

    102y(x 1) = x 1 102y = x 1x 1

    2y = log x 1x 1 y = 1

    2log x 1x 1 f1(x) = 12 log x 1x 1

    22 49 2logc+ ba + logc ba = x(logc+ ba)(logc ba)

    log a

    log (c+ b) +log a

    log (c b) =x log a

    log (c+ b) log a

    log (c b)

    2Y >X;/78'20@2B6K log (c + b) log (c b)

    log (c b) + log (c + b) = x log a

    *(.'/0: log(c2 b2) = log ax a2 + b2 = c2

    log a2 = log ax

    x = 2 25 51 > a )66

    1234U[21B:.> 6.S. P\?%.'/02'(DC8K('.'/0 log a = 2 log( x 2 + x + 2 ) log x

    log a = log( x 2 + x + 2 )2 log x

    log a = log

    ( x 2 + x+ 2 )2x

    a = ( x 2 + x+ 2 )2

    x (1)

    '%?2)1$% % > 0 *( /Y@ log 1 x 2

    %*/2 x 'Y22=6/3? @2 (1) 2*/2 @S)6) a %U[2'Y22KK(x = 2 : a = (0+ 2)

    2

    2= 2

    .... ........

    7

  • */2 x = 3 : a = (1+ 5 )2

    2=

    6+ 2 5

    3

    */2 x = 4 : a = ( 2 + 6 )2

    4=

    8+ 2 12

    4= 2 + 3

    */2 x = 5 : a = ( 3 + 7 )2

    5=

    10+ 2 21

    5

    8:5K*/2 x 'Y22=6)UK?G '()> a 66> 1 63 544

    B66C>K:>K$/3? 1 : >K:>K$/3? 2 : A,B, a, b M,N, m, n 8, *6 X 8, *6 X

    '$8, *6 /$4% 2 >K:>K$2$?%2 *2YXG 1B3:() 1 : A, B XK%16

    - M, N B$:$2) 2! C93- X>K:>K$/3? 1 1B3:@2/3?% 4 S%) C934 3- X>K:>K$/3? 2 1B3:@2/3?% 4 S%) (1S%3$:>K:>K$*K))

    /Y) C934 3

    K;3/3? 1 /Y) C932! (4 3) (4 3) = 288

    () 2 : A, B C$2

    A

    B

    M N

    LOCK

    A

    M

    N B

    LOCK1 2

    34

    8

  • - B XPK11% A /Y) 2 C93- B$: M, N ) 2! C93- X>K:>K$/3? 1 1B3:) 2 *:: >

    S% 1, 2, 3 - >2(S% /Y) C93 S%/3?3 2

    K6 8 C93- S%3$2 /Y) 2 C93

    S% 2 /2$42*(B$: a, b ) 2 C93- X>K:>K$/3? 2 /Y62>K:>K$*K /Y) 8 C93

    K;3/3? 2 /Y) C932 2! 8 8 = 256

    K6 2 K;3) C93288 + 256 = 544 4 64 3

    __ __ __ __ __ __ __

    x ) 7 $' 3 9 B$: 4 $

    () 1 x )6@S 0, 1, 2 /Y) C937 4! = 168

    () 2 x U[2 0, 1 K 2 /Y) C933 4!2!

    = 36

    x ' 0, 1, 2 B$:*::63PY4 1 >X

    C93/$4%6 C93= 168 + 36 = 204

    7 66 3521 1 - 10 1( 4 >(*22, 1 11 - 20 1( 1 >(*22 K6 50 >(*22%K/Y) 45 >(*22 *U /YDC 5 >(*22() 1 DC1 4 >(*22 1 1, 1 1 >(*22 1 1

    /Y) C93 101 101 = 100() 2 DC1 1 >(*22 5 1 /Y) C93 105 = 252 C93/$4%6 C93= 100 + 252 = 352

    3 9 2

    1 C93 0, 1, 2, x

    9

  • 14 69 7' /7 *B% *( f(x) x x A f(1) 1 f(2) 2

    A B () 1 1 /&0 2 *( 2 /&0 1, 3, 41 1 1 C93 3 C93 = 3 C932 2 $@$2\?%/3? 1 )6

    3 () 2 1 /&0 3, 4 *( 2 /&0 1, 3, 44 2 C93 2 C93 = 4 C93

    C93/$4%6 C93= 3 + 4 = 7 16 70 0.7

    n(s) = 53 = 10E : D:U[2'Y22>XKD>X;U[2'Y22>3? 63 2 K;3

    K;3/3? 1 : >X, >3?, >3? 63 C93 21 32 = 6 K6 C937

    K;3/3? 2 : >3?, >3?, >3? 63 C93 33 = 1 P(E) = n(E)

    n(S) =710

    = 0.7

    17 71 1n(s) = 104 = 210E : () 1 : 63 C93+,+,+, 53 51 = 50

    K6 C93100

    63 C93+,,, 51 53 = 50 P(E) = n(E)

    n(S) =100210

    =1021

    19 72 2n(s) = 72 = 21E : C:)6)B3Y *U %C:'B3*% + 1/2$42 P\?%63 5 X

    n(E) = 52 = 10 P(E) = 1021

    10

  • 21 73 196 49pi196

    n(s) = 8./. = 14 14n(s) = 8./. *K% = 14 14 pi(72)

    P(E) = 196 49pi196

    24 74 3n(s) = 6 6 = 36E : (1, 6) (6, 1) (2, 5) (5, 2) (4, 3) (3, 4) (6, 2) (2, 6)

    P(E) = n(E)n(S) =

    836

    =29

    29 77 0.55 P((A B) ) = 0.55

    7

    7

    7 7

    7

    7

    77

    A B

    0.15 0.15 0.15

    0.55

    11

  • 30 77 1S : 2Y a, b, c, d, e, f 6B$:/3?)U6 C93n(s) = 6! = 720E : *U $*K)6@S a *( b *($B7/)6@SBK(A B

    __ __ __ __ __ __ c, d, e, f CBK( b, c, d, f

    8:$*K*($B7/ 63 c, d, f /3?@SK6$2'\%%*K;34!

    () 1 /Y) C931 __ __ __ __ 4 1 4! 4 = 96 K6

    4! 312 C93() 2 /Y) C933 __ __ __ __ 3 3 4! 3 = 216

    P(E) = 312720

    =1330

    32 78 2' =Tr+ 1 nr an r br

    = 10r 2x3 10 r

    x3

    y2

    r

    = 10r 210 r x30+ r (x3)r

    y2r

    = x

    6

    y12r = 6

    B.U.B. 1% > x6y12

    106 210 6 = 3, 360 2 93 3

    u = 4a + 2b c = 4 21 + 2 32 10 = 18 >6S$21% u = mu = 8

    1= 8

    Vector /3?$4%j$: %63>6S$2 u = 18

    '$/$4% 4 8: 6313/3? >1 3m = 18

    3 94 10' a + b 2 = a 2 + 2a b + b 2

    132 = 102 + 2a b + 72 a b = 10

    e

    c, d, f

    b, c, d, f

    b, c, d, f /3?)6PY4$:$*K

    12

  • 12 98 1' a b a b = 0 3x + 2y = 0 y = 3

    2x (1)

    ' a = 4 x2 + y2 = 4 x2 + y2 = 16 (2)

    */2 @2 (2), y = 32x x2 + 32x

    2= 16 x2 + 9

    4x2 = 16 13x

    2

    4= 16

    */2@2 (1) 8?> y13x2 = 64 x2 = 6413

    x = 813

    5 x = 813

    y = 32

    813

    = 1213

    5 x = 813

    y = 32

    813

    = 1213

    *(.'/0: a c > 0 2x + 3y > 0 2x > 3y

    K;3 )6'KC%x = 813

    , y = 1213

    2 813

    > 3

    1213

    K;3 'KC%x = 813

    , y = 1213

    2 813

    > 3

    1213

    x y = 813

    12

    13=

    20

    13

    14 99 1U[2B6:$C12\?%1% vector 3 6CC

    17 101 1.5@ AB = u , AD = v

    AM = AB + BM = u + 13v

    AN = AD + DN = v + 13u

    AM + AN = u + 13v + v + 1

    3u

    AM + AN = 43(u + v) = 4

    3(AC)

    AC = 34(AM) + 3

    4(AN)

    '() = 34, = 3

    4 + = 3

    4+ 34

    =32

    = 1.5

    A

    D C

    B

    1

    2

    21

    u

    v

    N

    M

    13

  • 4 111 31 3 DC S2 A = {1, 2} B = {1} C = {2}

    P(A) = {, {1}, {2}, {1, 2}}

    P(B) = {, {1}}

    P(C) = {, {2}}P(B) P(C) = {, {1}, {2}}8: P(A) P(B) P(C)

    6 112 4' set B : x2 4x + 3 = 0 (x 3)(x 1) = 0 x = 3, 1

    B = {3, 1} , C = {1, 2, 3, .....}

    A C = {4,3,2,1, 0}

    63'Y22B6SC 7 $(A C) B = {4,3,2,1, 0, 1, 3}

    7 113 2'.'/0 *B%C A B

    1 1 (C A) (C B) C1 2 (A C) (B C)

    = (A B) C = C1 3 (A C) (B C)

    = (A B) C C1 4 (A B C) (A B)

    10 114 9'B6SC 1, 2, 3, ....., 10 8: P\?%K 5 %$1 + 2 + 3 + ..... + 10 = 55

    $%2$42 KB6SC6 8 $ * DK6$%>%K 5 %$'\%62$:KB6SC 2 $ ' 10 $ .

    D:1% 2 $2$42%K 5 %$S2$2 '() B6SC 2 $/3?) 63$%234

    K6 9 C93(1, 4) (1, 9) (2, 3) (2, 8) (3, 7) (4, 6) (5, 10) (6, 9) (7, 8)

    A B

    C

    14

  • 11 115 48C'K;B6SC *($@2 8: *($'(63/%A B = {1, 2, 3, 4} A B

    3 %> )UX@2P A %3, )UX@2P B %3K)UX@2P A *( B /$4%B%P (*'()6X@2 A K B )6)) '(BK%) C933 3 3 3 = 81*@2 81 C93/3?)%$ 2 C93 >

    1. 1, 2, 3, 4 )UX@2 A 6 B '(U[2 2. 1, 2, 3, 4 )UX@2 B 6 A '(U[2

    C93KBK% A *( B > C9381 2 = 79 14 116 26

    n(UUUU) = 66 2$K32/3?B:)CS3 = 6 x + y + z = 6' n(UUUU) = 66(x + y + z) + 10 + 11 + 17 + 13 + m = 66 m = 9

    'Y22>2/3?B:)CS$%mn*(>;C >2= 17 + 9 = 26

    ******************************

    )/ $%mn

    >;C

    x

    z

    y1017

    11 m

    13

    15