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Linear Equations in Two Variables

Digital Lesson

Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 2

Equations of the form ax + by = c are called linear equations in two variables.

The point (0,4) is the y-intercept.

The point (6,0) is the x-intercept.

x

y

2-2

This is the graph of the equation 2x + 3y = 12.

(0,4)

(6,0)


y

x2-2

The slope of a line is a number, m, which measures its steepness.

m = 0

m = 2m is undefined

m =1

2

m = -1

4


x

y

x2 – x1

y2 – y1

change in y

change in x

The slope of the line passing through the two points (x1, y1) and (x2, y2) is given by the formula

The slope is the change in y divided by the change in x as we move along the line from (x1, y1) to (x2, y2).

y2 – y1

x2 – x1

m = , (x1 ≠ x2 ).

(x1, y1)

(x2, y2)


Example: Find the slope of the line passing through the points (2, 3) and (4, 5).

Use the slope formula with x1= 2, y1 = 3, x2 = 4, and y2 = 5.

y2 – y1

x2 – x1

m = 5 – 3

4 – 2= =

22

= 1

2

2(2, 3)

(4, 5)

x

y


A linear equation written in the form y = mx + b is in slope-intercept form.

To graph an equation in slope-intercept form:

1. Write the equation in the form y = mx + b. Identify m and b.

The slope is m and the y-intercept is (0, b).

2. Plot the y-intercept (0, b).

3. Starting at the y-intercept, find another point on the line using the slope.

4. Draw the line through (0, b) and the point located using the slope.


1

Example: Graph the line y = 2x – 4.

2. Plot the y-intercept, (0, - 4).

1. The equation y = 2x – 4 is in the slope-intercept form. So, m = 2 and b = - 4.

3. The slope is 2.

The point (1, -2) is also on the line.

1= change in y

change in xm = 2

4. Start at the point (0, 4). Count 1 unit to the right and 2 units up to locate a second point on the line.

2

x

y

5. Draw the line through (0, 4) and (1, -2).

(0, - 4)

(1, -2)


A linear equation written in the form y – y1 = m(x – x1) is in point-slope form.

The graph of this equation is a line with slope m passing through the point (x1, y1).

Example:

The graph of the equation

y – 3 = - (x – 4) is a line

of slope m = - passing

through the point (4, 3).

1

2 1

2

(4, 3)

m = -1

2

x

y

4

4

8

8


Example: Write the slope-intercept form for the equation of the line through the point (-2, 5) with a slope of 3.

Use the point-slope form, y – y1 = m(x – x1), with m = 3 and (x1, y1) = (-2, 5).

y – y1 = m(x – x1) Point-slope form

y – y1 = 3(x – x1) Let m = 3.

y – 5 = 3(x – (-2)) Let (x1, y1) = (-2, 5).

y – 5 = 3(x + 2) Simplify.

y = 3x + 11 Slope-intercept form


Example: Write the slope-intercept form for the equation of the line through the points (4, 3) and (-2, 5).

y – y1 = m(x – x1) Point-slope form

Slope-intercept formy = - x + 13

31

3

2 1 5 – 3 -2 – 4

= - 6

= - 3

Calculate the slope.m =

Use m = - and the point (4, 3).y – 3 = - (x – 4)1

3 3

1


Two lines are parallel if they have the same slope.

If the lines have slopes m1 and m2, then the lines are parallel whenever m1 = m2.

Example: The lines y = 2x – 3 and y = 2x + 4 have slopes m1 = 2 and m2 = 2.

The lines are parallel.

x

y

y = 2x + 4

(0, 4)

y = 2x – 3

(0, -3)


Two lines are perpendicular if their slopes are negative reciprocals of each other.If two lines have slopes m1 and m2, then the lines are

perpendicular whenever

The lines are perpendicular.

1m1

m2= - or m1m2 = -1. y = 3x – 1

x

y

(0, 4)

(0, -1)

y = - x + 41

3Example:

The lines y = 3x – 1 and

y = - x + 4 have slopes

m1 = 3 and m2 = - .

1

3 1

3

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