zeta function regularization

Upload: nicolasrobles

Post on 30-May-2018

236 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/14/2019 Zeta Function Regularization

    1/115

    Z e t a F u n c t i o n R e g u l a r i z a t i o n

    N i c o l a s M R o b l e s

    D e p a r t m e n t o f T h e o r e t i c a l P h y s i c s

    I m p e r i a l C o l l e g e L o n d o n

    F e b r u a r y 2 0 t h 2 0 0 9

    S u p e r v i o r : D r A r t t u R a j a n t i e

    S u b m i t t e d i n p a r t i a l f u l l l m e n t

    o f t h e r e q u i r e m e n t s f o r t h e d e g r e e o f M a s t e r o f S c i e n c e i n

    Q u a n t u m F i e l d s a n d F u n d a m e n t a l F o r c e s o f I m p e r i a l C o l l e g e L o n d o n

  • 8/14/2019 Zeta Function Regularization

    2/115

    A b s t r a c t

    n o z l z o n d n n m m n n d ( l d o F

    e n o d n z n o n o o l o m o n n o n o o o n

    n d m o n m o n o l l o n n m m n n d d n n n E

    o n l o n m ( l d n n o o J o n d n d m n n o

    o o n d n d ' n l d o o I E l o o o d F

    n n o o n l n v n n o 4 o o l o n o l l o n o J o d n d l n d n d o n n o n

    o m o n o l l o n ( l d o o m d n d l n d n l m o

    m F

    l n k n z n o n D k n l n d w l l n n o m l n d

    n d l n n z n d d m n o n l l z o n o n n d l l

    d d o

    4 o F

    p m o D n o m o n o n I E l o o ' v n n l o l l d F

    p n l l D g m ' n o d d F

  • 8/14/2019 Zeta Function Regularization

    3/115

    I

    o m l

    1 + 1 + 1 + 1 +

    =

    1

    2 o o m n s o m e n F

    e n o n m o

    @ F F F A t h e u s e o f t h e p r o c e d u r e o f a n a l y t i c c o n t i n u a t i o n t h r o u g h t h e z e t a f u n c t i o n r e q u i r e s a

    g o o d d e a l o f m a t h e m a t i c a l w o r k . I t i s n o s u r p r i s e t h a t [ i t ] h a s b e e n o f t e n a s s o c i a t e d w i t h

    m i s t a k e s a n d e r r o r s F

    i F i l z l d n d e F o m o

    W e m a y - p a r a p h r a s i n g t h e f a m o u s s e n t e n c e o f G e o r g e O r w e l l - s a y t h a t ' a l l m a t h e m a t i c s

    i s b e a u t i f u l , y e t s o m e i s m o r e b e a u t i f u l t h a n t h e o t h e r ' . B u t t h e m o s t b e a u t i f u l i n a l l m a t h -

    e m a t i c s i s t h e z e t a f u n c t i o n . T h e r e i s n o d o u b t a b o u t i t F

    u z z o w l n k

  • 8/14/2019 Zeta Function Regularization

    4/115

    C O N T E N T S P

    C o n t e n t s

    1 I n t r o d u c t i o n 3

    2 I n t r o d u c t i o n t o t h e R i e m a n n Z e t a F u n c t i o n 9

    P F I q m m p n o n (s) F F F F F F F F F F F F F F F F F F F F F F F F F F F W P F P r z p n o n (s, a) F F F F F F F F F F F F F F F F F F F F F F F F F F I T P F Q e n l o n n o n n d n o n l o n o (s, a) F F F F F F F F F P H P F R f n o l l n m n d l o (0) F F F F F F F F F F F F F F F F F F F F P R P F S l o (0) F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F P T P F T o l m m n o n (m)(s) F F F F F F F F F F F F F F F F F F F F F F F F P V P F U v n o

    (s) n o n F F F F F F F F F F F F F F F F F F F F F F F P W P F V g o n l d n m k o n d o n o m n m n d z o o

    (s) Q H

    3 Z e t a R e g u l a r i z a t i o n i n Q u a n t u m M e c h a n i c s 3 7

    Q F I n l o m o n o l l o F F F F F F F F F F F F F F F F F F F F Q U

    Q F P o l o n o l F F F F F F F F F F F F F F F F F F F F F F F F F F F Q W

    Q F Q o o n o n n o n F F F F F F F F F F F F F F F F F F F F F F F F F R I

    Q F R l z o n o l o n o o o n o n n o n F F F F F F F F R Q

    Q F S e l n o l o n F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F R S

    Q F T p m o n o n n o n F F F F F F F F F F F F F F F F F F F F F F F F R S

    Q F U l z o n o l o n o m o n o n n o n F F F F F F F R V

    4 D i m e n s i o n a l R e g u l a r i z a t i o n 5 1

    R F I q n n n o n l n d o l m l d n n o o J S I

    R F P p n o n l n D o n n d o n l n d l l ( l d

    cl(x) F F F F S R R F Q h o n o

    4 o n l

    cl(x) F F F F F F F F F F F F F F F F F F F F F F F S W R F R E l o n o d m n o n l l o o n l F F F F F F F F F F F F F F F F F F F T S R F S i n o n o Z n i l n m F F F F F F F F F F F F F F F F F F F F F T V

    5 Z e t a R e g u l a r i z a t i o n i n F i e l d T h e o r y 7 1

    S F I r k n l n d w l l n n o m F F F F F F F F F F F F F F F F F F F F F F F U I

    S F P h o n o

    4 o n l

    cl n l z o n F F F F F F F F F F F F U Q S F Q g o l n o n n F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F U T

    S F R o n n o n n ( l d o F F F F F F F F F F F F F F F F F F F F F F F F U V

    S F S r m l m F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F V Q

    S F T i l n o n d d m n o n l l z o n n 4 o F F F F F F F F V V

    6 C a s i m i r E e c t 9 4

    T F I i m n l F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F W R

    T F P

    l o F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F W R

    T F Q i m n l d n F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F W T

    7 C o n c l u s i o n 9 7

    A A p p e n d i x 1 0 1

    e F I q n l z d q n n l F F F F F F F F F F F F F F F F F F F F F F F F F I H I

    e F P q m n x m F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F I H Q

    e F Q w l l n n o m n d n o n o log (s + 1) F F F F F F F F I H U

  • 8/14/2019 Zeta Function Regularization

    5/115

    C O N T E N T S Q

    B R e f e r e n c e s 1 1 2

    f F I f o o k F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F I I P

    f F P F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F I I P

    f F Q s n n e l F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F I I P

  • 8/14/2019 Zeta Function Regularization

    6/115

    1 I N T R O D U C T I O N R

    1 I n t r o d u c t i o n

    l n o n n o n n l n d m l l n m m l n d o l

    o o s n d n F

    s n d d D d o o l l d l n o n X h D v n d D

    f l D r n k l D r m n o n E o n m E n d n n n d o m o

    m o d n o n F m o o m n n o n n E n m m

    n o n n d o o l o n o d ' n l o n m o d l l m F

    m n n z n o n d ( n d o o m l l s V

    (s) :=n=1

    1

    ns=p

    1

    1 ps

    o d ( n o n l d o (s) > 1 n d n n l l l o n n d o o l o m l l n s = 1 m l o l d I F s l l o n o d n o l l m p F

    s n o o l o n o n l l m o d d ' n l o n I

    o m o l n o n m o n n l m n n F

    d o n l l D m n n n o n d l o n n n l n m o n d l l n d o n o m n m F e n d d m o l

    n o n l l o m l l n l m o m m n d m o l

    l d d F

    l l n d n n d n o n F l k o o o n l n o n s m l g o l l l o m o o n o d n o o l F

    o o n l l o o d ( n o n E o m E o o l n d o n l n l E

    o o o m l n l X o n n D n l o n n o n D d l l

    n d p o n d w l l n n o m F

    l m d d o n D o D o n l o n o n l l n d o o d o n n d o m m n d l o n n o n

    n n m o n d

    n o n o n l ) F

    n o n l o n o l m o n

    (s) = 2(2)s1(1 s)sins

    2

    (1 s)

    l l o m l

    (0) = 12

    , (0) = 12

    log(2)

    l l d m n d n F y o D n d n o o l ( o n F n o n n n

    (s) =1

    1 21sn=1

    (1)n+1ns

    .

    o m n o n o n F r o D n (s) < 1 r o n l o n n o n n d o o 12 s 0 n (0) = 12 n n F

    h n l o n o m F r k n R D F i l z l d D F

    y d n o n d e F o m o @ i y A Q l n d o l z o n n ( n l

  • 8/14/2019 Zeta Function Regularization

    7/115

  • 8/14/2019 Zeta Function Regularization

    8/115

    1 I N T R O D U C T I O N T

    m n m = iTFe l l m o o n o n n d d o m o n l l d r z n o n d ( n d V

    (s, a) =n=0

    1

    (n + a)s

    a = 0, 1, 2, F n m o n o d m n d n E o m m o n l o n l l n d q m n n n m n d o l l l n n d l o n l n o

    m n d d o o m o n n o n o m o n F

    m n l d n o n o o n n o n

    TreH =

    dd

    |eH| e. n d o n j q m n n n m l d S

    Z() = 2n=1

    1 +

    (2n 1)

    2

    = 2 cosh 2

    .

    s n n m m n l n l n l l k n o n o m E o n o

    A l l o m d o ( l d o l F k n o l

    A n o n o o o o n d d n o n D o n n n o o n

    boson(s) =n=1

    n

    2s=

    2s(2s).

    n m o n

    fermion(s) =

    k=1

    2(k 1/2)

    s

    =

    2s

    (s, 1/2),

    l l m k o o m l o

    (0) n d (0) o n n o n d d

    n o n l n m o m o n l l o o n n n n E

    l z o n n n m o n o o n o o m l n l D n m l

    n l o n n o n F

    f d m n n o d ' n l d o o n ( l d o o

    n l n n o o J d o d o l o l n

    o n o n F o o m l m n o p G e p o o m w F

    o n l ( l d o l l o n d 4 o m o n o n o E l z o n n l d o m o o m l ( l d o n d n o n o Q F

    l l k o n n d o d o p n m n d m n o l F

    i d l l o o l d l o d n d n o n l l o

    n o n n d n ( l d o F l l l m n o n o o m l o d n o n P D n d l o d n o n Q n d o l n d

    n o n R F p m o D l l n l o n F

    n m ( l d o o l ( l d n n o n n l o J l l

    d d F s l l o n o n n n o n l o o l m l d T

    ZE [J] = eiE[J] =

    |eiHT|

    J=

    D exp

    i

    d4x(L[] + J)

  • 8/14/2019 Zeta Function Regularization

    9/115

    1 I N T R O D U C T I O N U

    n n n i l d n m Q D U

    ZE [J] = NE exp {SEuc[(x0), J]}

    det

    ( + m2 + V[(x0)])(x1 x2)

    s l n l l d m n n n d n o m n o l d o n n d o

    n D n m l d ' n l d o o F f k n o n l o

    o

    4 o D o o o m

    AF T

    = 2 + m2 + 2

    20(x),

    s n o n o n m m n l D l n k o

    A n o n m m o o m l n d m k o k n l F o o n d o n d o n D

    o l o n o o n

    AxGA(x, y, t) = t

    GA(x, y, t)

    n l o d

    GA(x, y, t) =

    x|etA|y = n

    etnn(x)n(y).

    n n l o o o n d n o o o n l n o F o o l o n

    d4xGA(x,x,t) =n

    etn = TrGA(t)

    n d l n k A n o n o m o m w l l n n o m R

    A(s) =n

    sn =1

    (s)

    0

    dtts1TrGA(t).

    l l o k n n o o n ( o d n m o o n D o n l n

    v n n o ( l d o n o m l z d

    V(c l

    ) =

    4!4

    c l

    +24

    c l

    2562

    log

    2c l

    M2 25

    6

    c l

    l l ( l d d ( n d n m o o J n d o n d

    cl(x) = |(x)|J =

    J(x)E[J] = i

    J(x)log Z.

    l l n d o o l n o n n o l n m o l d n d n n d

    l o n n l o n ( l d o n d l m n F p m o D l l

    o U

    log Z =1

    2A(0) =

    1

    2 log(1 e).

    o n n o n o p m o n o l l o F n m o d m o

    o n

    log Z =1

    2B(0) = V

    M3

    12+

    2

    903 M

    2

    24+

    M4

    322

    + log

    4

    +

  • 8/14/2019 Zeta Function Regularization

    10/115

    1 I N T R O D U C T I O N V

    B = 2

    t2 + 22 + m2 + 2 20

    2

    n l m o m

    0 F n l l l o o o ' v n n ' d F

    e m n o k o m k n l d m l o E

    l z o n n l l d m l n m o n d d m o d

    o n E l o o n o n o F r o D l l d o n o n

    o n l n n d l l o l l o o 4 o F

    i y d o n l m o n o o o k o n g m ' F g o n n l

    n o d o n o l l o n d o n g m n l I W R H F l l o n E

    m o 9 l d 9 o F

    o n l o n o n n l ( o n o n o m o j d d n n d

    l l d ( n n o n o n l l o o n l o o o n o n n n d o n o z o o n o n D l z o n n d d m n o n l l z E o n F

    n d o n n o m o m l d d n o ( n n o n n d m k

    o l d o n l m o l E o n n d F n n o d d n n d d l

    D n l d n m n d n l o d F y l l D l

    o n

    l z o n F m n o o d o n n q o n d

    n D u l n D m o n d n d i l z l d D y d n o D n d o m o F

    s n m o k n o l d o D o n l E o m o m ( l d o

    o n o o p G e p o m w n p p p F

    s n n o j o o l o m d ' n o n n l D

    l n o o n d n o n o m l n d l o n l d

    o o n d o n n o m l F

    p n l l D m k s n o n l o ( n d n l n o m d

    o n n n o n l l o n n n o n n d m l o l m n E l F h ' n n o n o m n o l n n m m n o m n o n n o n F e d o D m n n (s) n o n d n o o n E o n n o n D r z (s, a) n o n n d d o m o n o n n o n F

    m n n n o n o o n r z n o n m o n

    s o l d n n n j o o n o n o n o o o n d n l D n d k n d o k n o l d n o

    l n l n o n F p o n n D o o n n o d n o n D n d o n n o n n o m d n k n o n o

    n o n D o n o

    n d D k n o n o o o n m n l ( o n o o o

    n o n F

    l d m n n o l m l l n o n l z o o m n n

    n o n o o m ( 12 + it) t l F e n o o o n s n o n l

  • 8/14/2019 Zeta Function Regularization

    11/115

    1 I N T R O D U C T I O N W

    o ( n d o l d o o n d n o o n n o n o o m ( 12 + it) n d n o o n o n o o o F o l d m n 9 n l o n 9 o m n n o n d d o l n o n F

    i p i x g i

    E I t F f n g o n T h e R i e m a n n H y p o t h e s i s

    E P r F f F q F g m n d h F o l d T h e I n u e n c e o f R e t a r d a t i o n o n t h e L o n d o n - v a n d e r

    W a a l s F o r c e s

    E Q i l z l d D y d n o D o m o D f n k n d n Z e t a R e g u l a r i z a t i o n T e c h n i q u e s w i t h

    A p p l i c a t i o n s

    E R n r k n Z e t a F u n c t i o n R e g u l a r i z a t i o n o f P a t h I n t e g r a l s i n C u r v e d S p a c e t i m e

    E S r n u l n I n t e g r a l s i n Q u a n t u m M e c h a n i c s , S t a t i s t i c s , P o l y m e r P h y s i c s a n d

    F i n a n c i a l M a r k e t s

    E T w l i F k n n d h n l F o d A n I n t r o d u c t i o n t o Q u a n t u m F i e l d T h e o r y

    E U m o n d D F i e l d T h e o r y : A M o d e r n P r e m i e r

    E V i d d m T h e T h e o r y o f t h e R i e m a n n Z e t a F u n c t i o n

    E W n n T h e Q u a n t u m T h e o r y o f F i e l d s

  • 8/14/2019 Zeta Function Regularization

    12/115

    2 I N T R O D U C T I O N T O T H E R I E M A N N Z E T A F U N C T I O N I H

    2 I n t r o d u c t i o n t o t h e R i e m a n n Z e t a F u n c t i o n

    2 . 1 T h e G a m m a F u n c t i o n

    (s)y n n m m D m o n l o d ( n n o n n m o n n l d E

    n d n o n m n o o F n o n o n F d o n l l D n o d o d o m E d n d n

    n l F o o n o n o d n o n o l l o o m o n o m l n l d l d p n d m P D l l m T n d

    k n d o n U F

    d o n o o n s = + it n o d d m n n n I V S W n d o m n d d n l o n o n F v ( d ( n i l n o n F

    D e n i t i o n 1 n l

    (s) :=

    0

    dtts1et@ P F I A

    l l d ( n d n d d ( n o l o m o n o n n l o m l l n D

    Re(s) = > 0F

    ( l m m n l o l n o n o l l o

    L e m m a 1 p o n n N (n) = (n 1)!FP r o o f F x o (1) :=

    0

    dtet n d n o n

    (s + 1) =

    0

    dttset = tset|0 + s

    0

    dtts1et = s(s)

    o n s n l E l n F x o D o n o n n D

    (n) = (n 1)(n 1) = (n 1)!(1) = (n 1)! @ P F P A o l o d F

    s n o d o o m l o n o n n d o n d o m o m o E n o n n o l o m l l n F

    L e m m a 2 v cn n Z+ n o o m l n m m n=0 |cn| o n F p m o D l S = {n|n Z+ n d cn = 0} F n

    f(s) =

    n=0

    cns + n

    o n o l l o s CS n d n o m l o n o n d d o CSF n o n f m o m o n o n o n C m l o l o n n S n d d

    n s=nf(s) = cn o n n SFP r o o f F v ( n d n o n d F s |s| < RD n |s + n| |n R| o l l n RF o D |s + n|1 (n R)1 o |s| < R n d n RF p o m n d d o

    n0 > R

    n=n0

    cns + n

    n=n0

    |cn||s + n|

    n=n0

    |cn|n R

    1

    n R

    n=n0

    |cn|.

  • 8/14/2019 Zeta Function Regularization

    13/115

    2 I N T R O D U C T I O N T O T H E R I E M A N N Z E T A F U N C T I O N I I

    e

    n>R cn/(s + n) o n o l l n d n o m l o n d k |s| < R

    n d d ( n o l o m o n o n F s o l l o n=0 cn/(s + n) m o m o n o n o n d k m l o l o n o S o n d k |s| < R F D

    n=0 cn/(s + n) m o m o n o n m l o l o n n S n d o n n S n

    f(s) =cn

    s + n+

    kS{n}

    cks + k

    =cn

    s + n+ g(s),

    g o l o m o nF p o m d n d d s=nf(s) = cn F o n l d o o F

    i d l m m n o o n o n d n o n n d F

    T h e o r e m 1 n o n n d o m o m o n o n o n o m l l n F s m l o l 0, 1, 2, 3, F d o n

    ress=k

    (s) =(1)k

    k!, @ P F Q A

    o n k Z+ FP r o o f . v l n o n

    (s) =

    10

    dtts1et +

    1

    dtts1et,

    o n d n l o n o n o m l s n d n n n o n F v n d

    o n n l n o n n ( n l

    10

    dtts1et =

    10

    dtts1k=0

    (1)kk!

    tk =k=0

    (1)kk!

    10

    dttk+s1 =k=0

    (1)kk!

    1

    s + k,

    o o n l d o

    s C o n n l n o n n n d o n n o m l o n o m o o m l l n F n o n n n o n n o m v m m P n d D F F

    (s) =

    1

    dtts1et +k=0

    (1)kk!

    1

    s + k, @ P F R A

    o n s n l E l n F f v m m P D r d ( n m o m o n o n

    o n o m l l n m l o l 0,

    1,

    2,

    3,

    F d n

    d l o n o l m m F

    T h e o r e m 2 p o s C n

    (s + 1) = s(s). @ P F S A

    P r o o f . o l l o d l o m v m m I n d o m I F

    E d m n o n l n o n o n o n l o o k l k e n o m o n n o n l d o n o n D n d l o d o d i l D

  • 8/14/2019 Zeta Function Regularization

    14/115

    2 I N T R O D U C T I O N T O T H E R I E M A N N Z E T A F U N C T I O N I P

    p P F I X |(x + iy)| o 5 x 3 n d 1 y 1

    f n o n o d o d l o o l l o F v (p), (q) > 0 n d n n l d ( n n o n D m k n o l t = u2 o o n

    (p) =

    0

    dttp1et = 2

    0

    duu2p1eu2

    .

    s n n n l o o o m

    (q) = 2

    0

    dvv2q1ev2

    w l l n o o

    (p)(q) = 4

    0

    0

    dudve(u2+v2)u2p1v2q1,

    n d n o o l o o d n u = r cos , v = r sin , dudv = rdrd

    (p)(q) = 4

    0

    /20

    drd er2

    r2(p+q)1 cos2p1 sin2q1

    =

    2

    0

    dr er2

    r2(p+q)1

    2

    /20

    d cos2p1 sin2q1

  • 8/14/2019 Zeta Function Regularization

    15/115

    2 I N T R O D U C T I O N T O T H E R I E M A N N Z E T A F U N C T I O N I Q

    = 2(p + q)

    /2

    0

    d cos2p1 sin2q1

    n l n m l ( d n z = sin2

    2

    /20

    d cos2p1 sin2q1 =

    10

    dz zq1(1 z)p1.

    x d ( n

    B(p,q) :=

    10

    dz zp1(1 z)q1

    o Re(p), Re(q) > 0, n d d n

    B(p,q) = B(q, p) =(p)(q)

    (p + q).

    d n o B f n o n F w o o D 0 < x < 1

    (x)(1 x) = (x)(1 x)(1)

    = B(x, 1 x) =1

    0

    dz zx1(1 z)x.

    l l l n l n o o n o D ( n d o m k o n

    l n z = u/(u + 1) l d

    1

    0

    dz zx1(1

    z)x =

    0

    du

    (u + 1)2

    ux1

    (u + 1)x1 1

    u

    u + 1x

    =

    0

    duux1

    1 + u

    .

    L e m m a 3 p o 0 < y < 1 @ I F I H A

    0

    duuy

    1 + u=

    sin y.

    @ P F T A

    P r o o f . v k o l o n o D o m l d n o m l l n

    l o n o l F y n o n d ( n n o n

    f(s) =sy

    1 + s

    m n o sy l o H o n d o F p m o D n o n f ( o d o l s = 1 d eiy F p P F P l o F n o o n n o n l o n d d n p P F P X o

    l o n d o o m > 0 o R D n l o n l CR o d R n d o n D n l o n d o o m R o

    n d n d o n d o n

    l

    C o d l o n d o n F e n l o n o g d o m

    2ieiy =

    R

    duuy

    1 + u+

    CR

    dzzy

    1 + z e2iy

    R

    duuy

    1 + uC

    dzzy

    1 + z.

  • 8/14/2019 Zeta Function Regularization

    16/115

    2 I N T R O D U C T I O N T O T H E R I E M A N N Z E T A F U N C T I O N I R

    p P F P X C = CR C [, R] [R, ]

    n d o n l o n d o m F x o o

    o l l o n

    |zy| = |ey log z| = eyRe(log z) = ey log |z| = |z|y, zy1 + z |z|y|1 + z| |z|

    y

    |1 |z|| ,

    n d n l n m d

    CR

    dzzy

    1 + z

    2R1y

    R 1 R0,C

    dzzy

    1 + z

    21y

    1 0 0;

    o l

    (1 e2iy)0

    duuy

    1 + u= 2ieiy .

    m E o o n ( n l l

    (eiy

    eiy)

    0

    duuy

    1 + u

    = 2i

    0

    duuy

    1 + u

    =

    sin y

    .

    o l m o l m m F

    v n o m k o n l d n m k F

    T h e o r e m 3 @ i l ) o n p o m l A p o l l

    s C o n

    (s)(1 s) = sin s

    . @ P F U A

  • 8/14/2019 Zeta Function Regularization

    17/115

    2 I N T R O D U C T I O N T O T H E R I E M A N N Z E T A F U N C T I O N I S

    P r o o f . l m m j o d n n

    (x)(1 x) = sin (1 x) = sin x ,

    o 0 < x < 1 F r o D o d o o n o m o m o D n o d o m F

    C o r o l l a r y 1 y n

    1

    2

    =

    0

    dtt1/2et =

    dtet2

    =

    .@ P F V A

    P r o o f F o l l o n s = 1/2 n i l ) o n o m l @ P F U A F

    T h e o r e m 4 n o n n o z o F P r o o f . n s sin(s) n n n o n D r o o m Q n o z o D o (s) = 0 o n l n s (1 s) o l F r o D d o D o l o 0, 1, 2, 3, o o l l o (1 s) m o l 1, 2, 3, F f o l o m l D (n + 1) = n! = 0 n d o n o z o F

    s n n l l o n n d o n o n i l o n n F v ( d ( n n d o n F

    L e m m a 4 s sn := 1 +12 + + 1n log n, n limn sn F l m l l d

    i l o n n F P r o o f . g o n d tn = 1 +

    12 + + 1n1 log n o m l l D n o

    n 1 o n n m n n m n d l o n1 dx x1 F o tn n n F n tn =

    n1k=1

    1

    k log k + 1

    k

    , limntn =

    k=1

    1

    k log

    1 +

    1

    k

    .

    o n o n o o o n n n

    0 1 o n n n ( n o d n z o o n l o n o o n z o F v 1, 2, z o o (s) F s o l l o o m n o n l o n (s) n o z o o < 0 o l o n F n n o n l o n @ P F P P A (1 s)

  • 8/14/2019 Zeta Function Regularization

    36/115

    2 I N T R O D U C T I O N T O T H E R I E M A N N Z E T A F U N C T I O N Q R

    n o z o o < 0 D n d sin(s/2) m l z o s = 2, 4, n d (1 s) n o z o F

    l D l z o o (s) d o n o o o n d o z o o (s) n n l l d o l o (s/2)F o D o l l o (s) n o z o o < 0 n d o > 1 F z o 1, 2, l n 0 1 F r o D z o o (s) l o n s(s 1)(s/2) n o z o n o n s = 1 n l l d m l o l o (s) F o

    (s) n n ( n n m o z o 1, 2, n 0 1 n d n

    (1 21s)(s) =n=1

    (1)n+1ns

    > 0

    o 0 < s < 1 n d (0) = 1/2 = 0 n (s) n o z o o n l n H n d I D F F z o 1, 2, l l o m l F r o m l o o n F z o o m n o n j X n (s) l o n l n d z o o 1 n o n l o n n o 1 F s = + i n 1 = 1 + iF g o n n l z o l o n = 1/2 o o n m m l o l n F

    p P F W X |(x + iy)|1 o 2 x 2 n d 0 y 50X z o o m o l

    m n n k o o o o o m o n o n m N(T) o z o o 0 < t < T

    N(T) =T

    2log

    T

    2 T

    2+ O(log T). @ P F S I A

  • 8/14/2019 Zeta Function Regularization

    37/115

    2 I N T R O D U C T I O N T O T H E R I E M A N N Z E T A F U N C T I O N Q S

    n l o d o n w n o l d F o n m o m o

    o o ' v n n I E l o o o d @ o n S F T i o n @ S F I V W A A F

    m n n n n n d o n j d l l z o o n l n Re(s) = 12 Fs n I W I R r d o d n n ( n n m o z o o n l l n Re(s) = 12 d o n o m n a l l z o l o d F

    m n n 9 m n o m l m n o I V S W n l o n n o n o n o n n d o o @ o A o n o n l o n F p m o D o

    n n n o p o n o m o d

    log (s) = s

    2

    du(u)

    u(us 1)

    n l d m o o o l l o n m k l l o d n l o m l o (x)

    (x) = R(x) 12

    R(x1/2) 13

    R(x1/3) 15

    R(x1/5) + 16

    R(x1/6) + =n=1

    (n)n

    R(x1/n)

    (n) w o n o n d ( n d H n d l m D I n o d o n n n m o d n m n d 1 n o d o n o d d n m o d n m n d

    R(x) = Li(x)

    :()=0

    Li(x) log 2 +x

    dt

    t(t2 1) log t ,

    m d 9 n 9 D F F 1 o

    Li(x

    ) =

    Im>0 Li(x

    ) + Li(x

    1

    ).

    s n I V W T r d m d n d d l l l o n o d D n d n d n l n d l m o m l n E

    o l D m n m o m o n l n o

    (1 + it) = 0 D F F n o z o o n Re(s) = 1 F m n n 9 r o l n o

    (x) x

    2

    dt

    log t= O(x1/2 log x)

    x Fp n l l D r d m d l o o d o d n o n d @ o l d o o A

    m n n

    (s) =eHs

    2(s 1) s2 + 1

    :()=0

    1 s

    es/

    @ P F S P A

    H = log 2 1 /2 F (s) n o n l o d m o d n o n

    (s) =1

    2

    1 s

    .

  • 8/14/2019 Zeta Function Regularization

    38/115

    2 I N T R O D U C T I O N T O T H E R I E M A N N Z E T A F U N C T I O N Q T

    v E d ( n o n o (s)

    (s) = s

    2

    (s 1)s/2(s) m n n 9 n o o n o d n o n

    (s 1) := (s). l o m d o (s) o n o n n d

    d

    dslog

    1 s

    =

    1

    s

    n d o n o n d

    d

    dslog

    s

    2 1

    2log +

    1

    s

    1

    +(s)

    (s).

    i l n o o n s = 0 l d

    1

    =

    1

    2+

    1

    2log + 1 log2

    o Im>0

    1

    +

    1

    1

    =1

    2[2 + log4] @ P F S Q A

    n (0) = (1) = F x o log4 m m l o n n l l o n l n n o m l z o n D n d n n o l n k n n m o n d

    z o o

    n o n F o m l n d o o m z o

    F o m o

    ( z o = 12 + iti

    p P F I H X |( 12 + it)| o 0 t 50

    D

    t1 = 14.134725t2 = 21.022040t3 = 25.010858t4 = 30.424878t5 = 32.935057

  • 8/14/2019 Zeta Function Regularization

    39/115

    2 I N T R O D U C T I O N T O T H E R I E M A N N Z E T A F U N C T I O N Q U

    i p i i x g i

    r o l l o d o o m

    E I o m e o o l 9 I n t r o d u c t i o n t o A n a l y t i c N u m b e r T h e o r y o n o n o n o n n d n l o n n o n F e o o l n n o l l o

    E Q D i s t r i b u t i o n o f P r i m e N u m b e r s s n m F

    o n o n o n o l l o o m o @ n d A o n E P C o m p l e x A n a l y s i s p n d f m D m 9 T h e o r y o f F u n c t i o n s T n d

    k n d o n 9 M o d e r n A n a l y s i s U F

    m n o o d l o m n o m n n

    n o n F m o o m E

    n o n

    E R s 9 R i e m a n n ' s Z e t a F u n c t i o n D n d E S i F g F m @ d h F F r E

    f o n A T h e T h e o r y o f t h e R i e m a n n Z e t a F u n c t i o n F

  • 8/14/2019 Zeta Function Regularization

    40/115

    3 Z E T A R E G U L A R I Z A T I O N I N Q U A N T U M M E C H A N I C S Q V

    3 Z e t a R e g u l a r i z a t i o n i n Q u a n t u m M e c h a n i c s

    3 . 1 P a t h i n t e g r a l o f t h e h a r m o n i c o s c i l l a t o r

    y n o ( n n m n n n o n o n n m n n l d l o m n o m o n o l l o Y ( l l k l n

    o m n o n n o n o m o m o n o l l o F

    l l o l l o i W F P Q I P o m k n n d o d P n d n l

    d l o m n o m g P o u l n I F o n o o n E d m n o n l m o n

    o l l o n

    S =

    tfti

    dtL, @ Q F I A

    v n n

    L =1

    2mx2 1

    2m2x2. @ Q F P A

    e k n o o m n o n l o o n m m n D n o n m l d

    n o n l n l

    xf, tf|xi, ti =

    DxeiS[x(t)]. @ Q F Q A

    m m o S D xc(t) D (

    S[x]

    x x=xc(t)

    = 0. @ Q F R A

    n o o d o n d o n o n d xc(t)F n d xc(t) l l j o o n n n o E m o n o m l d n d o (

    i l E v n o n

    xc + 2xc = 0. @ Q F S A

    o l o n o o n o o n d o n xc(ti) = xi n d xc(tf) = xf

    xc(t) = (sin T)1[xf sin (t ti) + xi sin (tf t)], @ Q F T A

    T = tf ti F n l o l o n n o o n S

    Sc := S[xc] =m

    2sin T [(x2f + x2i )cos T 2xfxi]. @ Q F U A

    e n n d d o n l l D n o n d

    S[x] o n d x = xc o o n

    S[xc + z] = S[xc] +

    dtz(t)

    S[x]

    x(t)

    x=xc

    +1

    2!

    dt1dt2z(t1)z(t2)

    2S[x]

    x(t1)x(t2)

    x=xc

    @ Q F V A

    z(t) ( o n d o n d o n

    z(ti) = z(tf) = 0. @ Q F W A

  • 8/14/2019 Zeta Function Regularization

    41/115

  • 8/14/2019 Zeta Function Regularization

    42/115

    3 Z E T A R E G U L A R I Z A T I O N I N Q U A N T U M M E C H A N I C S R H

    o ( @ Q F W A F n l n o n n l

    T0

    dt(z2 2z2) = T2

    n=1

    a2n

    nT

    2 2

    . @ Q F I V A

    s n o d o l l E d ( n d n o m o n m k n m o l

    m o n d n o m o n F s n d d D p o n o m o n o m

    y(t) o an m o o n o l n n o n F o k D k n m o m l o

    N + 1 D n l d n o t = 0 n d t = TD o

    N 1 n d n d n zk l F o D m an = 0 o l l n > N 1 Fx D o m o o n d n t o n F h n o

    tk k m l n n l [0, T] l n o N n ( n m l D n

    JN = detzk

    an= detsin ntk

    T . @ Q F I W A

    l t o n o o l D o l F

    o D l m k d o n o l o m n o n d o l m l d F

    3 . 2 S o l u t i o n o f t h e f r e e p a r t i c l e

    p o l D v n n L = 12 mx2

    F g l l d d o l o n o

    l n o n d n g P o u l n I l l n g Q o q o n d

    n R F m l d o m d ( n o n r m l o n n n

    H = px L = p2

    2m, @ Q F P H A

    o

    xf, tf | xi, ti =

    xf|eiHT| xi

    =

    dp

    xf| exp(iHT)|p

    p| xi

    =

    dp

    2eip(xfxi)eiTp

    2/(2m) =

    m

    2iTexp

    im(xf xi)2

    2T

    @ Q F P I A

    T = tf ti n o d o n d d n o d z o n o m = T /NF m l l o o o n o n l n o n m l d

    xf, tf | xi, ti = limn

    m2i

    n/2 dx1 dxn1 exp

    i

    nk=1

    m

    2

    xk xk1

    2. @ Q F P P A

    n o n o o d n o zk

    = (m/(2))1/2xk

    o m l d o m

    xf, tf | xi, ti = limn

    m2i

    n/2 2m

    (n1)/2 dz1 dzn1 exp

    i

    nk=1

    (zk zk1)2

    .

    @ Q F P Q A

    s n n d D o n d o n

    dz1 dzn1 exp

    i

    nk=1

    (zk zk1)2

    =

    (i)n1

    n

    1/2ei(znz0)

    2/n. @ Q F P R A

  • 8/14/2019 Zeta Function Regularization

    43/115

    3 Z E T A R E G U L A R I Z A T I O N I N Q U A N T U M M E C H A N I C S R I

    o n d o

    xf, tf | xi, ti = limn

    m

    2i

    n/2

    2im

    (n1)/21n

    eim(xfx0)2/(2n)

    =

    m

    2iTexp

    im

    2T(xf xi)2

    .

    @ Q F P S A

    k n @ Q F P S A n o o n

    xf, T | xi, 0 =

    1

    2iT

    1/2exp

    im

    2T(xf xi)2

    =

    1

    2iT

    1/2eiS[xc]. @ Q F P T A

    n n m o n l o n

    eiS[xc] z(0)=z(T)=0

    Dz expim

    2

    tf

    ti

    dtz2. @ Q F P U A x o D o m @ Q F I V A

    m

    2

    T0

    dtz2 mN

    n=1

    a2nn22

    4T@ Q F P V A

    n d n o m o n l o n o n l

    1

    2iT

    1/2=

    z(0)=z(T)=0

    Dz exp

    i m

    2

    tfti

    dtz2

    = limN

    JN

    12i1/2

    da1 . . . d aN1 exp

    im

    N1n=1

    a

    2

    nn

    2

    2

    4T

    . @ Q F P W A

    x o o m o o l n q n n l 1

    2iT

    1/2= lim

    NJN

    1

    2i

    N/2 N1n=1

    1

    n

    4iT

    2

    1/2

    = limN

    JN

    1

    2i

    N/21

    (N 1)!

    4iT

    2

    (N1)/2@ Q F Q H A

    n d o m o n o m l o t o n

    JN = 2(N1)/2NN/2N/1(N 1)!

    N @ Q F Q I A

    t o n d n D d n n o l n JN o m n d o d n o F

    v n o n o o n l o l m o o l m l d o m o n

    o l l o F m l d

    xf, T | xi, 0 = limN

    JN

    1

    2iT

    N/2eiS[xc]

    da1 . . . d aN1 exp

    i

    mT

    4

    N1n=1

    a2n

    nT

    2 2

    . @ Q F Q P A

  • 8/14/2019 Zeta Function Regularization

    44/115

    3 Z E T A R E G U L A R I Z A T I O N I N Q U A N T U M M E C H A N I C S R P

    e d d l D o o m o n o q n n l

    n o m l

    dan exp

    imT

    4a2n

    nT

    2 2

    =

    4iT

    n2

    1/2 1

    T

    n

    21/2. @ Q F Q Q A

    k m l d @ Q F Q P A n o m l l

    xf, tf | xi, ti = limN

    JN

    N

    2iT

    N/2eiS[xc]

    N1k=1

    1

    k

    4iT

    1/2N1n=1

    1

    T

    n

    21/2

    = limN

    1

    2iT

    1/2eiS[xc]

    N1n=1

    1

    T

    n

    21/2. @ Q F Q R A

    s n o n o d l o

    limN

    Nn=1

    1

    T

    n

    2=

    sin T

    T. @ Q F Q S A

    d n o Jn n l d n o o m n d o l ( n l o n ( m n d o o n n n l n o J F n n l o o d ( n l l @ P F Q T A

    xf, tf | xi, ti =

    2i sin T

    1/2eiS[xc]

    =

    2i sin T

    1/2

    expi

    2sin T(x2f + x2i )cos T

    2xixf . @ Q F Q T A 3 . 3 T h e b o s o n i c p a r t i t i o n f u n c t i o n

    s r m l o n n H o m o n d d o m l o n D d d n o o n n o r m l o n n D n m k H o d ( n D F F

    spec(H) = {0 < E0 E1 En } . @ Q F Q U A

    e l o m o n d n o d n F l d o m o o n o

    eiHt

    eiHt =

    neiEnt |n n| @ Q F Q V A

    n d d o m o o n n l n l o l E l n o t D H|n = En |n Fe d o n n l n q n n l n o d k o o n

    t = i l n d o D x = idx/d n d eiHt = eH o

    i

    tfti

    dt

    1

    2mx2 V(x)

    = i(i)

    fi

    dt

    1

    2m

    dx

    d

    2 V(x)

    =

    fi

    dt

    1

    2m

    dx

    d

    2+ V(x)

    @ Q F Q W A

  • 8/14/2019 Zeta Function Regularization

    45/115

    3 Z E T A R E G U L A R I Z A T I O N I N Q U A N T U M M E C H A N I C S R Q

    g o n n l D n l o m

    xf, tf | xi, ti = xf, tf |e H(fi)| xi, ti=

    Dx exp

    fi

    d

    1

    2m

    dx

    d

    2+ V(x)

    , @ Q F R H A Dx n o n m n m n m F i o n @ Q F R H A o o n n o n n n o n l o n d l m n F

    v n o d ( n o n n o n I D P D R D S o r m l o n n H

    Z() = TreH, @ Q F R I A

    o o n n n d o r l o d HF o n n n n m o n o n {|En}

    H|En = En |En , Em| En = mn. @ Q F R P A s n

    Z() =n

    En|eH| En

    =n

    En|eEn | En

    =n

    eEn , @ Q F R Q A

    o n m o n o |x o o o n o o xD

    Z() =

    dx

    x|eH| x

    .@ Q F R R A

    s n l l d n o = iT ( n d

    xf|eiHT| xi

    =

    xf|eH| xi

    , @ Q F R S A

    n d o m n l o n o o n n o n

    Z() =

    dz

    x(0)=x()=z

    Dx exp

    0

    d

    1

    2mx2 + V(x)

    =

    periodic

    Dx exp

    0

    d

    1

    2mx2 + V(x)

    , @ Q F R T A o d n l n d n l o l l o d

    n n l [0, ] F n l o m o n o l l o D o n n o n m l

    TreH =

    n=0

    e(n+1/2). @ Q F R U A

    e l o n m o o l n o n n o n D o o

    o n o l z o n l l d F o d o l l o F m n m = iT o o n n l z(0)=z(T)=0

    Dz exp

    i

    2

    dtz

    d

    2

    dt2 2

    z

    z(0)=z()=0

    Dz exp

    1

    2

    d z

    d

    2

    dt2+ 2

    z

    ,

    @ Q F R V A

  • 8/14/2019 Zeta Function Regularization

    46/115

    3 Z E T A R E G U L A R I Z A T I O N I N Q U A N T U M M E C H A N I C S R R

    n Dz n d n o n m m n m F o n n

    n r m n m M o E d ( n n l k 1

    k

    n

    n o n n d @ j n Q A

    nk=1

    dxk

    exp

    1

    2

    p,q

    xpMpqxq

    = n/2

    nk=1

    1k

    =n/2

    detM.

    @ Q F R W A

    m n l z o n o l q n n l

    dx exp

    1

    2x2

    =

    2

    , > 0.

    n k o d ( n d m n n o n o o O n ( n o d o

    n l

    kF o m l d n

    DetO =

    k kF x o h l

    d d n o d m n n o n o o D m l l d d n o d m n n

    o m D m l o n d F

    3 . 4 Z e t a r e g u l a r i z a t i o n s o l u t i o n o f t h e b o s o n i c p a r t i t i o n f u n c t i o n

    n n n n l o m n m

    z(0)=z()=0

    Dz exp

    1

    2

    d z

    d

    2

    dt2+ 2

    z

    =

    DetD

    d

    2

    d2+ 2

    1/2@ Q F S H A

    D d n o h l o n d o n d o n z(0) = z() = 0F m l l o d d @ Q F I V A n l o l o n

    z() =1

    n=1

    zn sinn

    . @ Q F S I A

    d o n o 0 n zn l z l n o n F n o n o o n o o m l o n F u n o n n l o n o n

    sin(n/) n = (n/)2 + 2 m d m n n o o o

    DetD

    d

    2

    d2+ 2

    =

    n=1

    n =n=1

    n

    2+ 2

    =

    n=1

    n

    2 m=1

    1 +

    m

    2.

    @ Q F S P A

    s n o m o d n ( n ( n o d n o n l d m n n D F F

    DetD

    d

    2

    d2

    n=1

    n

    2. @ Q F S Q A

    r n o n o m n o l F o O n o o o E d ( n n l n F p o l l o n I D R D S n D k l o

    log DetO = logn

    n = Tr log O =n

    log n. @ Q F S R A

  • 8/14/2019 Zeta Function Regularization

    47/115

    3 Z E T A R E G U L A R I Z A T I O N I N Q U A N T U M M E C H A N I C S R S

    x o d ( n l n o n

    O(s) :=n

    sn . @ Q F S S A

    m o n o 0 n l l @ s A n d

    O(s) n l n s n o n F e d d o n l l D n n l l l o n n d o o l s l n o l

    ( n n m o o n F d o l n o n l n k d o n o n l d m n n

    dO(s)

    ds

    s=0

    = n

    log n. @ Q F S T A

    e n d o o n o DetO

    DetO = exp dO(s)ds s=0 . @ Q F S U A

    o o n d n O = d2/d2 o l d

    d2/d2(s) =n=1

    n

    2s=

    2s(2s). @ Q F S V A

    e o d n g I D n o n n l o o l o m l s l n m l o l s = 1 F l @ P F Q H A n d @ P F Q Q A

    (0) = 12

    (0) = 12

    log(2)

    l o l l d D n d n m n o o o n

    d2/d2(0) = 2 log

    (0) + 2(0) = log(2). @ Q F S W A

    n n o o n o d m n n h l o n d o n

    DetD

    d

    2

    d2

    = elog(2) = 2 @ Q F T H A

    n d ( n l l

    DetD d2

    d2+ 2 = 2

    p=11 +

    p 2

    . @ Q F T I A x o o n ( n o d n o o m ( n d o (0) n d (0)Fv o k o o n n o n

    TreH =n=0

    e(n+1/2) =

    2

    p=1

    1 +

    p

    21/2

    tanh(/2)

    1/2

    =

    2

    sinh

    1/2

    tanh(/2)

    1/2=

    1

    2 sinh(/2).

    @ Q F T P A

  • 8/14/2019 Zeta Function Regularization

    48/115

  • 8/14/2019 Zeta Function Regularization

    49/115

  • 8/14/2019 Zeta Function Regularization

    50/115

    3 Z E T A R E G U L A R I Z A T I O N I N Q U A N T U M M E C H A N I C S R V

    g o n n l

    Z() =n

    dd(1 )

    0|eH| n n | 0 1|eH| n n | 1 + 0|eH| n n | 1 + 1|eH| n n | 0 .@ Q F U R A

    x o n o l m o n n d d o n o o n o n l n d o

    m o m l

    Z() =n

    dd(1 )

    0|eH| n n | 0 1|eH| n n | 1 + 0|eH| n n | 1 1|eH| n n | 0=

    dde

    |eH|

    . @ Q F U S A

    n l k o o n D o m o n n E o d o n d o [0, ] n n q m n n l

    n

    = 0 n d n = Ff n o k n o n

    eH = limN

    (1 H/N)N @ Q F U T A n d n n o m l n l o n @ e F T H A o n o l l o n o n

    o o n n o n

    Z() = limN

    dde

    |(1 H/N)N|

    = limN

    dd

    N1

    k=1dkdk exp

    N1

    n=1nn

    |(1 H)| N1 N1| | 1 1|(1 H)|

    = limN

    Nk=1

    dkdk exp

    Nn=1

    nn

    N|(1 H)| N1 N1| | 1 1|(1 H)| N , @ Q F U U A l o n n o n n d n n l l l o n

    = /N and = N = 0, =

    N =

    0 . @ Q F U V A

    w l m n l d @ o ( o d A

    k|(1 H)| k1 = k| k1

    1 k|H| k1k| k1

    = k| k1 exp( k|H| k1 / k|k1)= e

    kk1e(

    kk11/2) = e/2e(1)

    kk1 .

    @ Q F U W A

    s n m o n l o n n o n o m @ P F I I Q A

    Z() = limN

    e/2N

    k=1

    dkdk exp

    Nn=1

    nn

    exp

    (1 )

    Nn=1

    nn

    = e/2 limN

    Nk=1

    dkdk exp

    Nn=1

    {n(n n1) + nn1}

    ,

  • 8/14/2019 Zeta Function Regularization

    51/115

    3 Z E T A R E G U L A R I Z A T I O N I N Q U A N T U M M E C H A N I C S R W

    n d o n m l ( o n o o n n l I

    Z() = e/2 limN

    Nk=1

    dkdk exp(

    B ), @ Q F V H A

    o l l o n o n d m l m n

    =

    1F

    F

    F

    N

    , = 1 N , BN =

    1 0 0 yy 1 0 00 y 1 0

    F

    F

    F

    F

    F

    F

    F

    F

    F

    F

    F

    F

    F

    F

    F

    0 0 y 1

    , @ Q F V I A

    y = 1 + F o m o n n d d l l n o m d ( n o n o q m n n q n

    n l o n d

    Z() = e/2 limN

    det BN = e/2 lim

    N

    1 + (1 /N)N = e/2(1 + e) = 2 cosh

    2.

    @ Q F V P A

    e o o n o n n o n D n o m l n

    n o n

    @ n l z o n o A D n d l l o l l F

    l l o d

    Z() = e/2 limN

    Nk=1

    dkdk exp(

    B )

    = e/2 Dk

    Dk

    exp

    0

    d (1 )d

    d+

    = e/2Det()=(0)

    (1 ) d

    d+

    . @ Q F V Q A

    () = (0) n d n l o l d l d o o l o n o n E o d o n d o n d o n

    () = (0)Fp D n d o

    () n p o m o d F n m o d n d o o n d n n l

    exp

    i(2n + 1)

    , (1 ) i(2n + 1)

    + , @ Q F V R A

    n n n = 0, 1, 2, F n m o d o d o m N(= /) o o n @ o A o m l F n

    n o o l l o n o

    n ( n o n o n o n l ( n F

    3 . 7 Z e t a r e g u l a r i z a t i o n s o l u t i o n o f t h e f e r m i o n i c p a r t i t i o n f u n c t i o n

    n o n o m l l o l d o d o m D n d o n o d

    N/4 k N/4 F p o l l o n o n D o n

    Z() = e/2 limN

    N/4k=N/4

    i(1 ) (2n 1)

    +

  • 8/14/2019 Zeta Function Regularization

    52/115

    3 Z E T A R E G U L A R I Z A T I O N I N Q U A N T U M M E C H A N I C S S H

    = e/2e/2

    k=1

    2(n 1/2)

    2

    + 2=

    k=1

    (2k 1)

    2 n=1

    1 +

    (2n 1)2

    @ Q F V S A

    o l o m o m ( n ( n o d D D d n n d n n d o l o o m ( n F n o m l d o l l o

    log = 2k=1

    log

    2(k 1/2)

    ,

    @ Q F V T A

    n d d ( n o o n d n n o n @ r z n o n A

    fermion(s) =

    k=1

    2(k 1/2)

    s=

    2s

    (s, 1/2), @ Q F V U A

    @ g P D i P F I I A

    (s, a) =k=0

    (k + a)s,

    0 < a < 1F

    = exp(2fermion(0)). @ Q F V V A

    o n o l o d ' n n fermion n o n s = 0 d o n o l l o I

    fermion(0) = log

    2

    (0, 1/2) + (0, 1/2) = 1

    2log2, @ Q F V W A

    n o d n g P @ o m I H A

    (0, 12 ) = 0, (0, 12 ) = 12 log2.

    n l l o o D o n n l

    = exp(2fermion(0)) = elog 2 = 2. @ Q F W H A

    l n d n d n d n o o n l z o n o m d F p n l l D o n n o n l d n l l

    Z() = 2n=1

    1 +

    (2n 1)2

    = 2 cosh

    2, @ Q F W I A

    o o m l

    n=1

    1 +

    x

    (2n 1)2

    = coshx

    2. @ Q F W P A

  • 8/14/2019 Zeta Function Regularization

    53/115

    3 Z E T A R E G U L A R I Z A T I O N I N Q U A N T U M M E C H A N I C S S I

    x o m l n @ Q F Q S A n d @ Q F W P A l l @ Q F T P A n d @ Q F W I A o o o n

    n d m o n l F

    d p n m n n d o o n o l o n o k n o n o l m n n k n o n o E

    l m D o n m 9 T h e s a m e e q u a t i o n s h a v e t h e s a m e s o l u t i o n s 9 F o n l n d

    m n o n o l m m l o l m D n E o l o n n n o

    l o n F p n m n k l l d n n o m n o l m n o o n o l d

    o l F l d o n n F n o @ Q F W P A n

    n l F

    i p i i x g i

    d o n o o l o n o n n n m m n n d z n o n E l z o n l n d n o n d k o

    E I r n u l n 9 P a t h I n t e g r a l s i n Q u a n t u m M e c h a n i c s V I o V Q D I T I o I T Q n d

    T H H o T I R

    E P k n n d o d P W W o Q H I n d

    E Q A d v a n c e d Q u a n t u m F i e l d T h e o r y o j n o d l o m n o q m n n

    n m F

    s l o o m l m n d o m

    E R g F q o n d p F n H a n d b o o k o f F e y n m a n P a t h I n t e g r a l s Q U o R R D S S o

    S W o m o n n d

    E S i y 9 T S o T U o m o n F

  • 8/14/2019 Zeta Function Regularization

    54/115

    4 D I M E N S I O N A L R E G U L A R I Z A T I O N S P

    4 D i m e n s i o n a l R e g u l a r i z a t i o n

    4 . 1 G e n e r a t i n g f u n c t i o n a l a n d p r o b a b i l i t y a m p l i t u d e s i n t h e p r e s -

    e n c e o f a s o u r c e J

    p o m n m m n l n l d n l z o n l d o

    d o m X ( l d o F l l l l d l 4, (x) l l ( l d F v m m z n d d l o m ( l d o o m k n n d o d P l l

    j n Q F o n l o m v n n

    S =

    dxL((x), (x)), @ R F I A

    n d o o d L v n n d n F o n o m o o n @ i y w A

    n i l E v n o n

    x

    L((x))

    = L(x)

    . @ R F P A

    p o m l ( l d v n n

    L0((x), (x)) = 12

    ( + m22) @ R F Q A

    n d u l n E q o d o n o n

    ( m2) = 0. @ R F R A

    n o J n m m l d n o n l n o n

    0, |0, J = Z[J] = ND expidxL0 + J + i2 2, @ R F S A ( l

    i d d d o m k n l o n F n n k o J

    d n o D F F n m l l o d o d m n n n d

    m o n F s n n o n

    Z[J] =

    D exp

    i

    dx

    L0 + J +

    i

    22

    =

    D exp

    i

    dx

    1

    2

    (

    m2) + i2+ J. @ R F T A s n D u l n E q o d o n o n o m l l m o n l z d o n

    (

    m2

    + i)c = J. @ R F U A o k n n d d m n o n n d d ( n n p n m n o o

    (x y) = 1(2)d

    ddk

    eik(xy)

    k2 + m2 i @ R F V A

    o l o n o n l z d u l n E q o d o n o n o m

    c(x) =

    dy(x y)J(y). @ R F W A

  • 8/14/2019 Zeta Function Regularization

    55/115

    4 D I M E N S I O N A L R E G U L A R I Z A T I O N S Q

    p n m n o o o

    ( m2 + i)(x y) = d(x y). @ R F I H A r n m m l d n n n m o o J

    0, |0, J = Nexp i

    2

    dxdyJ(x)(x y)J(y)

    @ R F I I A

    o

    Z0[J] = Z0[0] exp

    i

    2

    dxdyJ(x)(x y)J(y)

    . @ R F I P A

    n 0, |0, J := Z0[J]F p n m n o o l o o m d n o n l d o Z0[J]

    (x y) = iZ0[0]

    2Z0[J]J(x)J(y)

    J=0

    . @ R F I Q A

    s n o d o l

    Z0[0] @ m o m m l d n n o o A n d o n o d m n m

    x4 = t = ix0 n d o o = 2 + 2 o

    Z0[0] =

    D exp

    1

    2

    dx(

    m2)

    =1

    Det( m2), @ R F I R A

    l d D d m n n o d o n l o o n d n o n d

    o n d o n F m o D v n n o o m l l ( l d k o m

    L0 = m2 ||2 + J + J, @ R F I S A n d o n n l n n n o n l o m

    Z0[J, J] =

    DD exp

    i

    dx(L0 i ||2)

    =

    DD exp

    i

    dx(

    m2 i) + J + J

    ,@ R F I T A

    d ' n n o n o o

    (x y) = iZ0[0, 0]

    2Z0[J, J]

    J(x)J(y)

    J=J=0

    . @ R F I U A

    m l n o n o u l n E q o d o n o n ( m2) = J n d (

    m2) = J

    Z0[J, J] = Z0[0, 0] exp

    i

    dxdyJ(x)(x y)J(y)

    @ R F I V A

    n d n n o k o o n

    Z0[0, 0] =

    DD exp

    i

    dx( m2 i)

    =

    1

    Det( m2). @ R F I W A

  • 8/14/2019 Zeta Function Regularization

    56/115

    4 D I M E N S I O N A L R E G U L A R I Z A T I O N S R

    n o o n l n v n n

    L(, ) = L0(, ) V() @ R F P H A

    o m d o l X o m o o n l l m d m m n d n o m l E

    z o n o o n d o n d o n d l d l F o n l

    l l o o m V() = n! n

    l n m n o n o n n d n > 2 n n F e o D n n n o n l P D R

    Z[J] =

    D exp

    i

    dx

    1

    2(

    m2) V() + J

    =

    D exp

    i

    dxV()

    exp

    i

    dx (L0(, ) + J)

    = expi dxVi J(x)D expidx (L0(, ) + J)

    =k=0

    dx1

    dxk

    (i)kk!

    V

    i

    J(x1)

    V

    i

    J(xk)

    Z0[J]. @ R F P I A

    q n n o n @ m o n o o d m o d o ( l d

    o o A

    Gn(x1, , xn) := 0|T[(x1) (xn)]|0 = (i)nn

    J(x1) J(xn) Z[J]J=0

    @ R F P P A

    n d n n n o n l

    Z[J]Fr o D n n n o n l d o Z[J] o n d J = 0 n d o m l n o l o n o n o o n n l o n d o n

    Z[J] =k=1

    1

    k!

    n

    i=1

    dxiJ(xi)

    0|T[(x1) (xn)]|0 =

    0

    Texp

    dxJ(x)(x)

    0

    .

    @ R F P Q A

    g o n n d n E o n n o n n d

    Z[J] = exp(W[J]), @ R F P R A

    n d ' o n d ( n d v n d n o m o n o l l o

    [cl] := W[J] ddxiJcl @ R F P S A

    cl := J =W[J]

    J. @ R F P T A

    l l l o [cl] n I E l d l d m @ f l n n d v o I n d m o n d R A F

    s o n n n n o o d o d o n n o m l m n n n d l o

  • 8/14/2019 Zeta Function Regularization

    57/115

    4 D I M E N S I O N A L R E G U L A R I Z A T I O N S S

    n l o o l m n F n n n o n l o o l o n n o n o

    ( l d o v n n L n @ R F S A

    Z[J] =

    D exp

    i

    d4x(L + J)

    , @ R F P U A

    m l o n n d n E T n d T D T (1 i) F p m o o l l o n

    0|T (x1)(x2)|0 = limT(1i)

    D(x1)(x2)exp

    iTT

    d4xL

    D exp

    iTT

    d4xL

    = Z[J]1

    i J(x1)

    i

    J(x2)

    Z[J]

    J=0

    . @ R F P V A

    v d o o m m n l o n o n m l Y n d d n l

    o m l o n o n m m n @ e p Q A o n m n o n

    l d n o o m l l n n d o n o l d l l o o n o o n o n

    o o d l o k o n o m n F m d o n l n ( n m l

    o o n o m n n ( n m l o o d p n m n o o F

    x o D k o o n o m o o d n t ix0 l d i l d n R E o o d

    x2 = t2 |x|2 (x0)2 |x|2 = |xE |2 , @ R F P W A

    n d m l l m n l o n n o n o m l n n q n 9

    n o n o n m ( l d o o d o l o n n o n i n v a r i a n t n d

    o o n l m m o o E d m n o n l i l d n F

    4 . 2 F u n c t i o n a l e n e r g y , a c t i o n a n d p o t e n t i a l a n d t h e c l a s s i c a l e l d

    cl(x)

    v n o l o 4 o F e k n o o n n

    S =

    d4x(L + J) =

    d4x

    1

    2()

    2 12

    m22 4!

    4 + J

    , @ R F Q H A

    n d o m n k o o n

    i

    d4xE(LE J) = i

    d4xE

    1

    2(E)

    2 +1

    2m22

    4!4 J

    , @ R F Q I A

    n n k E o d n n n o n l

    Z[J] =

    D exp

    d4xE(LE J)

    . @ R F Q P A

    n o n l LE[] o n d d o m l o n d n ( l d l m l d o l d n n o n l o m l F o o l d m l LE [] o m o n n n d o n n l o l n d d o l o

    ) o n o F n l D k o d n o n l Z[J] o n n o n d n l m n o m o o m n o m n ) n l

  • 8/14/2019 Zeta Function Regularization

    58/115

    4 D I M E N S I O N A L R E G U L A R I Z A T I O N S T

    ( l d F

    p n l l D l n l o n ( l d o n d l m n

    n n q n 9 n o n o (xE) P

    (xE1)(xE2) =

    d4kE(2)4

    eikE (xE1xE2)

    k2E + m2

    , @ R F Q Q A

    n p n m n o o l d n l k o n n d l l o '

    exp(m|xE1 xE2|) F o o n d n n n m ( l d o n d l m n l n m o n n n d n d n l o l d n F

    l l n n n n o n l o o l o n n o n D d ( n n n n o n l

    E[J]

    Z[J] = exp(iE[J]) =D exp

    i

    d4x(L + J)

    =

    |eiHT|

    , @ R F Q R A

    o n n o n m l n d o F x o i o n o n n l n o n o @ R F P R A F n o n l

    E[J] D d o D m n n o n o n l o J F v o m n o n l d o

    E[J] o J(x)

    J(x)E[J] = i

    J(x)log Z

    =

    D exp

    i

    d4x(L + J)

    1 D(x)exp

    i

    d4x(L + J)

    @ R F Q S A

    n d

    J(x) E[J] = |(x)|J @ R F Q T A

    m o n l n n o o J F

    x D d ( n

    E l l ( l d

    cl(x) = |(x)|J , @ R F Q U A d o l l o l ) o n D n d d n d n o n o J F

    E ' o n v n d n o m o n o

    E[J] F F n @ R F P S A

    [cl] := E[J]

    d4xJ(x)cl(x). @ R F Q V A

    f o @ R F Q T A o l l o n

    cl(x)[cl] =

    cl(x)E[J]

    d4x

    J(x)

    cl(x)cl(x

    ) J(x)

    =

    d4xJ(x)

    cl(x)

    E[J]

    J(x)

    d4xJ(x)

    cl(x)cl(x

    ) J(x) = J(x) @ R F Q W A

    m n n o o z o D o n

    cl(x)[cl] = 0 @ R F R H A

  • 8/14/2019 Zeta Function Regularization

    59/115

    4 D I M E N S I O N A L R E G U L A R I Z A T I O N S U

    ( d ' o n F o n o l o n l o

    (x)

    n l o o F s l l m d o l m

    n n n d n l o n n d v o n z n o m o n F m l n l

    m l ( o n o @ R F R H A o o l m o o n d n o l o n cl l l n d n d n o x D n d n j o l n n y h i o o n l F

    m o d n m l l D o o o n l o o l m o m o n o n o n l n l k n D n d o D n l n F g o n n l D n

    m o o l m V n d o d T o o n m

    [cl] = (V T)Veff(cl), @ R F R I A Veff ' p o t e n t i a l F s n o d [cl] n m m n d o l l o n o o l d

    clVeff(cl) = 0. @ R F R P A

    i o l o n o @ R F R P A n l o n n n o o D F J = 0F o D ' o n @ R F Q V A E n ( = E) n d o n n l Veff(cl) l d o l o n o @ R F R P A n d n o o o n d n F

    ' o n l d ( n d @ R F R I A n d @ R F R P A l d n o n o m n m z o n

    d ( n m o ( l d o n l d n l l ' o n m o o n F

    l o n o

    Veff(cl) l l o l l o o m n l o m l o n F s n o d o o m l l l o l l o k n n d o d 9 m o d n n o l l o o m

    F t k S n d d k o I W U R F d o o m ' o n d l o m n l d ( n o n n d n o n Veff o n o n o n n l o cl Ff n n o m l z d o n o D v n n

    L =1

    2

    ()2

    1

    2

    m202

    0

    4!

    4@ R F R Q A

    o o l

    L = L1 + L, @ R F R R A

    n l o o o l o v n n n n o m l z d

    4 o d o n n e p D

    j n Q n d f l n n d v o g U F R I D F F l n ( l d = Z1/2r Z d n v d o n o m l

    d4x | T (x)(0)| eipx = iZp2 m2 + (terms regular at p

    2 = m2), @ R F R S A

    m n l m F l n v n n n o

    L =1

    2

    (r)2

    1

    2

    m202r

    0

    4!

    4r +1

    2

    Z(r)2

    1

    2

    m2r

    4!

    4r, @ R F R T A

    o Z = Z 1D m = m20Z m2 n d = 2Z m n d l l m d F l m k n o n o n m n d k

    n o o n n ( n n d n o l n m n d

    l m F

    e l o o d n o n o l o n n o n d

    l l ( l d

    L

    =cl

    + J(x) = 0. @ R F R U A

  • 8/14/2019 Zeta Function Regularization

    60/115

    4 D I M E N S I O N A L R E G U L A R I Z A T I O N S V

    f n o n l Z[J] d n d o n cl o d n d n o n J o o l o o m n o n o cl F l l n o n F x D d ( n J1 o n o n l ( l l ( l d o n o o o d D F F n L = L1

    L1

    =cl

    + J1(x) = 0, @ R F R V A

    n d d ' n n o o J n d J1 l l n @ k n n d o d I I F R A

    J(x) = J1(x) + J(x), @ R F R W A

    J o d m n d D o d o d n o n o o @ R F Q U A D n o n (x)J = cl(x)F m n o @ R F Q R A

    eiE[J] =

    D exp

    i

    d4x(L1[] + J1)

    exp

    i

    d4x(L[] + J )

    , @ R F S H A

    l l o n m n o n d o n n l F v o n n o n (

    o n n l ( F i n d n o n n l o (x) = cl(x) + (x) l d d4x(L1[] + J1) =

    d4x(L1[cl] + J1cl) +

    d4x(x)

    L1

    + J1

    +1

    2!

    d4xd4y(x)(y)

    2L1

    (x)(y)

    +1

    3! d4xd4yd4z(x)(y)(z)

    3L1(x)(y)(z)+ @ R F S I A

    n d n d o o d n o n l d o L1 l d cl F o n d n l o n r n @ R F R V A n d o n l o q n n l D o o n n n d

    m F

    v m o 0 n o @ R F S I A @ F F n o n l d o

    L1 A l l E d ( n d o o F s k o n l m o d o d n n d o n l o o ( n l o @ R F S H A ( n d q n n l

    n l d n m o n o n l d m n n o m d n e n d

    D exp

    i

    d4x(L1[cl] + J1cl

    +1

    2 d4xd4y

    2L1(x)(y)

    = exp

    i

    d4x(L1[cl] + J1cl)

    det

    2L1

    (x)(y)

    1/2, @ R F S P A

    l o E o d n m o o n o ' o n n d m n n F s

    n o o n d o n d n l o @ R F S H A o n o o n m o

    v n n n d n d n d o n o

    (L[cl] + J cl) + (L[cl + ] L[cl] + J ). @ R F S Q A

  • 8/14/2019 Zeta Function Regularization

    61/115

  • 8/14/2019 Zeta Function Regularization

    62/115

    4 D I M E N S I O N A L R E G U L A R I Z A T I O N T H

    4 . 3 D e r i v a t i o n o f 4 p o t e n t i a l a t cl(x)

    s n n ( o n o D o n o n n o m m k n

    d l o m n o m o n l @ i A o m l ( l d F p m o D

    i d m n d m n m o n o ' o n l D

    dV

    dcl= 0. @ R F S V A

    ' o n l n l l o n l V o v n n n o

    n m ' k n n o o n F o n o l l o o l n m

    m D o o l d l n o n E n o o n n o m m

    k n F l n m l o o n o n n o d F

    v E o o n d @ R F P R A o l l o F n n n o n l X o

    o n n d q n n o n n l ( l d o D

    Z[J] = exp(i1X[J]) = ND exp

    i1

    d4x(L + J)

    @ R F S W A

    n o m l z o n o n n N o n o

    Z[0] = 1 X[0] = 0. @ R F T H A

    y n E l E d l q n n o n (n) n d ' o n [cl] o I D P D Q D R

    [cl] =n=1

    in

    n!

    d4x1

    d4xn

    (n)(x1, , xn)cl(x1) cl(xn), @ R F T I A

    n d n o o n

    G(N)(x1, x2, , xN) = 1iN

    J1

    J2

    JNZ[J]

    J=0

    .

    s n @ R F S W A o 1 m l l o l v n n @ n o j n o n A

    o V n n d m l l 1 o n d o I n n l l n l l

    o F i o E n l l n n q n n o n G(E) o o F n o m o n D o l l o

    V+I+E = L+1E , @ R F T P A

    o L = I V + 1 n d n o n E n m o n l l n F p m o D o o LE n n d m n n o n o 1

    XF o n E l E d l

    q n n o n (E) n o o o D n m l l n o o n l L F m n o o n d n m o l o o p s F n n o l o o

    (L = 0) o n l n o n E n n (E)

    (2)(p, p) = p2 2 @ R F T Q A

    n d

    (4)(p1, p2, p3, p4) = , @ R F T R A

  • 8/14/2019 Zeta Function Regularization

    63/115

    4 D I M E N S I O N A L R E G U L A R I Z A T I O N T I

    o m o n o o n l @ f l n n d v o R F R A

    V(cl) = n=1

    inn!

    (n)(0, , 0)ncl V0(cl) = 12 22cl +

    14!

    4cl, @ R F T S A

    l l l d o n m o o n F x o D o D o l o

    n o n l o d o n n o m o n o z n m d D o n l n

    n o n m F f l n n d v o P H I m ' o n [cl]

    [cl] = i log N 18

    dx[iF(0)]

    2 12

    dxcl(x)(

    + 2)cl(x)

    14

    iF(0)

    dx2cl(x)

    1

    24

    dx4cl(x) + O(

    2). @ R F T T A

    m o n n p n m n o o F(0) o m o m d n l o o n l

    n d n d o n o o n n z o o d D o n n l m

    0[cl] = 12

    dxcl(x)(

    + 2)cl(x) 1

    4!

    dx4cl(x) @ R F T U A

    n k n n o o n N = 1 m l n [0] = 0 F ( o d o D l o o n o n D o ' o n l V n d

    ' o n n o m d n

    (x) = 0(x) + (x), @ R F T V A

    0 n z o o d o m o n o cl F r n n n o n l n o n l m o l l o n i y w

    (

    + 2

    )0(x) +

    6 30(x) = J(x).

    @ R F T W A

    n l n n o v n n d n

    L() =1

    2()() 1

    222 1

    4!4 @ R F U H A

    o l l o n n l d4x(L + J) =

    d4x(L(0(x)) + J0)

    +

    d4x

    ()(0) 20 1

    630 + J

    +

    d4

    x

    L2(, 0) 1

    6 3

    0 1

    4 4

    @ R F U I A

    L2 o n n o l l d l o n n o m d D F F

    L2 =1

    2()() 1

    222 1

    420

    2.@ R F U P A

    x o D n

    m n m l l o n n l n m n

    o @ R F U I A d F

    y n o E l n o n l o l l o

    = 1/2 @ R F U Q A

  • 8/14/2019 Zeta Function Regularization

    64/115

  • 8/14/2019 Zeta Function Regularization

    65/115

    4 D I M E N S I O N A L R E G U L A R I Z A T I O N T Q

    m @ R F T U A F d d o n l m n n d d ' o n

    1[cl] = X0[J] 0[cl]

    d4xJcl + X1[J]

    =

    d4x[L(0) + J0]

    d4x[L(cl) + Jcl] +

    i

    2trlog

    A(x, x , 0)

    A(x, x, 0). @ R F V R A

    f 0 o l o n o @ R F T W A d ' n o o n l n @ R F V R A o o d (0 cl)2 = O(2), n d n n n 0 n d cl l l o F o

    1[cl] =i

    2trlog

    A(x, x , cl)

    A(x, x, 0). @ R F V S A

    x D ' o n l V(cl) n d d o m [cl] n cl o n n D n

    [cl] =

    d4xV(cl). @ R F V T A

    h l n o n l l o o d o n l A(x, x , cl) o o l d ( n l o m o @ R F V S A F d o n o l l o

    A(x, x , cl) =

    xx + 2 +

    1

    22cl

    (x x)

    =

    d4k

    (2)4

    xx + 2 +

    1

    22cl

    eik(x

    x)

    =

    d4k

    (2)4 k2 + 2 + 1

    22cl

    eik(xx)

    =

    d4k

    (2)2d4k

    (2)2eix

    k

    k2 + 2 + 12

    2cl

    (k k)eikx @ R F V U A

    r n o m n l o n d o o n

    log A(x, x , cl) =

    d4kd4k

    eixk

    (2)2log

    k2 + 2 + 1

    22cl

    (k k) e

    ixk

    (2)2@ R F V V A

    o

    trlog A =

    d4xd4x(x x)log A(x, x , cl) =

    d4x

    d4k

    (2)4log

    k2 + 2 + 1

    22cl

    .

    @ R F V W A

    o m l o d m n n o A n

    Tr log A = log det A. @ R F W H A

    m m z n n n o o l l o n X o n E l o o o d o n o n o '

    o n l

    V1(cl) =i2

    d4k

    (2)4log

    k2 + 2 + 12 2clk2 + 2

    @ R F W I A

  • 8/14/2019 Zeta Function Regularization

    66/115

    4 D I M E N S I O N A L R E G U L A R I Z A T I O N T R

    n d l o d D ' o n l o m d

    V(cl) V0(cl) + V1(cl) = 12

    22cl + 14!4cl i2

    d

    4

    k(2)4

    log

    1 12

    2cl

    k2 2

    , @ R F W P A

    D q k m m D F F o n n n v n n F

    n l m n o n l l o l d n n d d m n o n l E

    l z o n o d l F F @ o n n f l n n d v o D F V H A

    I(, B) =

    d2k

    (2)2(k2 2B + i)1 =

    1

    i

    d2 k(2)2

    (k2 + 2B)1

    =i2B

    162(M2)2

    1

    2 + (1) + 1 log

    2B

    4M2+ O( 2)

    . @ R F W Q A

    f o o l l o n n o m o n o m

    B(x) = Z1/2(x) Z2B = 2 + 2 Z2B = + , @ R F W R A

    n n o m o o n l @ R F W P A o

    V(cl) =1

    222cl +

    1

    4!4cl +

    1

    222cl +

    1

    4!4cl

    i

    2

    d2k

    (2)2log

    1 1

    2

    2clk2 2

    ,

    @ R F W S A

    n q k m n o n n o m l z d m n

    F s m o n o n o D o D m o n n m o d

    MS m F s n m o q n n o n D d l o n l n 2 n d n l z d o n m I

    = M42

    a0(,M/,) +k=1

    ak(,M/)(2 )k

    @ R F W T A

    2 = 2

    b0(,M/,) +

    k=1

    bk(,M/)

    (2 )k

    @ R F W U A

    Z = c0(,M/,) +k=1

    ck(,M/)

    (2 )k @ R F W V A

    a0, b0 n d c0 l 2 n d = M24 F f o n l m l o l D k E n l o n l m l o l 2

    F m n

    k > 1

    ak = bk = 0 F

    o n E o n E d l q n n o n o n o m l z d o

    2(p, p) = p2(1 + Z1) 2 21 +2

    322

    1

    2 + 1 log2

    4M+ O( 2)

    .

    @ R F W W A

    n o n n

    I4(B) =

    d4k

    (2)4(k2 2B + i)1 @ R F I H H A

  • 8/14/2019 Zeta Function Regularization

    67/115

    4 D I M E N S I O N A L R E G U L A R I Z A T I O N T S

    n d @ R F W Q A o n p n m n o o

    F(0) =

    d4k(2)4

    (k2 2B + i)1 = M24 i2162

    12 + 1 log

    24M

    + O( 2)

    .

    @ R F I H I A

    o o D n n D n n q n n o n

    2(p, p) = p2(1 + Z1) +

    2 +1

    2iF(0) +

    21

    + O(2), @ R F I H P A

    n n n p n m n d m o l d n o d F

    o m o n o 4 l n o l l o m l n D n l l D n 4 ( n n n n o m l o n m

    2 o l l o n o l d

    3322 12 2 const, @ R F I H Q A

    =k=2

    k. @ R F I H R A

    ( n o 2 F q o n k o o d o n o @ R F W T A o @ R F W V A n o o l n 2 n l z d n

    a1 =3

    3222, b1 =

    1

    322. @ R F I H S A

    o n k o n o n l o n

    V(cl) =1

    222cl

    1 + b0

    322

    3

    2 + log 4

    +1

    4!4cl

    + a0 3

    2

    322

    3

    2 + log 4

    +1

    642

    2 +

    1

    2cl

    2log

    2 + 12 2cl

    M2 4 log

    2

    M2

    . @ R F I H T A

    s n n o n MS m m o o @ j n o f l n n d v o A

    MS = 3

    322

    12 + log 4

    + O(3) @ R F I H U A

    aMS0 =32

    322[+ log 4] + O(3), aMS1 =

    32

    322+ O(3), @ R F I H V A

    l l d o + log 4 o F r o D n d m n o j o o m o n n o n l E z o n D o l d l o n o m l z V(cl) n n o n o l m n d

  • 8/14/2019 Zeta Function Regularization

    68/11