what’s the hurry? 1-1-5 the kinematics of freefall
TRANSCRIPT
What’s the hurry?
1-1-5 The Kinematics of Freefall
Falling Down• Things fall because gravity causes objects with mass
to attract one another.– We don’t yet know how or why gravity does this!
• But, we do know:– As objects fall they ACCELERATE (gain speed)
– They do this at a CONSTANT RATE no matter what the mass of the falling object is.
The Constant Rate
• We use “g” as a shorthand for ACCELERATION DUE TO GRAVITY
• On Earth the value for ‘g’ is -9.81 m/s2
• Other examples– Moon: -1.62 m/s2
– Jupiter: -26 m/s2
– Mars: -3.75 m/s2
Falling without air resistance…
Using “g” to find changes in speed• An object falls from rest. What is its velocity at the end of one
second? Two seconds? Three seconds?
t = 0 vi = 0 m/s
t = 1 s v = -9.81 m/s (≈10 m/s)
t = 2 s v = -19.62 m/s (≈20 m/s)
t = 3 s v = -29.43 m/s (≈30 m/s)
atvv if
Uses for “g”• An object falls from rest. How far has it fallen at
the end of one second? Two seconds? Three seconds?
t = 0 d = 0 m
t = 1 s d = -4.905 m (≈5 m)
t = 2 s d = -19.62 m (≈20 m)
t = 3 s d = -44.145 m (≈45 m)
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Longest Freefall in History (until 2013!)
Throwing Downward• An object is thrown downward from the
top of a 175 meter building with an initial speed of 10 m/s.
– What acceleration does it experience?• -9.81 m/s2
– What is the object’s initial velocity?• -10 m/s
vi = -10 m/sa = -9.81 m/s2
“a” and “vi” in SAME DIRECTION
Building Example (cont.)• What is the object’s velocity as it hits the ground?
• vi = -10 m/s• d = -175 m• a = -9.81 m/s2
• vf = ?
• How long does it take the object to hit the ground?• t = ?
vf2 = vi
2 + 2advf
2 = 0 + 2(-9.81 m/s2)(-175 m)vf = -58.6 m/s
vf = vi + at-58.6 m/s = -10 m/s + (-9.81 m/s2) t
t = 4.95 s
Throwing Upward• A cannon fires a shot
directly upward with an initial velocity of 50 m/s.– What acceleration does the
cannonball experience?• -9.81 m/s2
– What is the cannonball’s initial velocity?
• +50 m/s
t = 0 svi = +50 m/s
t = 1 sv = +40.19 m/s
t = 2 sv = +30.38 m/s
“a” and “vi” in OPPOSITE DIRECTION
atvv if
Cannon (cont.)• What is the object’s velocity as it reaches the top of
its flight?
• How long does it take the cannonball to reach the top of its flight?
• What is the maximum height of the cannonball?
0 m/s (All objects momentarily STOP at the top of their flight)
vf = vi + at0 = +50 m/s + (-9.81 m/s2) t
t = 5.1 s
d = vit + ½ at2
d = (+50 m/s)(5.1 s) + ½ (-9.81 m/s2)(5.1 s)2
d = +127.4 m