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GYAN GANGA INSTITUTE OF TECHNOLOGY AND SCIENCES, JABALPUR

DEPARTMENT OF ELECTRONICS & COMMUNICATION ENGINEERING

NAME:

ENROLLMENT NO.:

BRANCH: Electronics and Communication Engineering

SEMESTER: 5th SEM

SUBJECT: Microprocessor and Microcontroller

1

INDEXS. No Name of the Practical Date Grade Sign

1 WALP to add and subtract two 8 bit and 16 bit nos.

2 WALP to multiply two 8 bit and 16 bit nos.

3 WALP to divide two 8 bit and 16 bit nos.

4 WALP to add a series of five 8-bit nos.

5 WALP to find odd and even number from a given group of nos.

6 WALP to find positive and negative number from a given group of nos.

7 WALP to find largest and smallest number and store the result in

Accumulator

8 WALP for arranging in ascending and descending order of given 5

numbers

9 WALP for interfacing of 8255 Programming Peripheral Interface (PPI)

with 8086

10 WALP to add two 8 bit nos. using 8051 microcontroller

2

Experiment 1

Aim: WALP to add and subtract two 8 bit and 16 bit nos.

Tool Required: Dyna Trainer Kit

Program:

(a) Addition of two 8 bit numbers

Address Opcode Operand CommentDyna_86> A 1000:2000 This specifies the segment and offset (effective address)1000:2000 MOV AL,23 Load the 8 bit no.23 into 8 bit register AL1000:2002 MOV BL,54 Load the 8 bit no.54 into 8 bit register BL1000:2004 ADD AL,BL Add the contents of register AL and BL and store the result in

register AL1000:2006 INT 3 Interrupt the current operation.1000:2007 Press EnterDyna_86> G 1000:2000 and

press EnterBreak at 0FFF: 1007Dyna_86> R

Result:

AX= 0077, BX=0054, CX=0000, DX=0000, SP=06FD, BP=0000, SI=0000, IP=2007, FL=F006

Conclusion:

1. In each instruction, offset address is incremented by 2 bit because 1 address is occupied by instruction and the other

saves the data.

2. If AL is replaced by AH then the output will be


3. If BL is replaced by BH then the output will be


3

(b) Addition of two 16 bit numbers

Address Opcode Operand CommentDyna_86> A 1000:2000 This specifies the segment and offset (effective address)1000:2000 MOV AX,A2C6 Load the 16 bit no.A2C6 into 16 bit register AX1000:2003 MOV BX,3C36 Load the 16 bit no.3C36 into 16 bit register BX1000:2006 ADD AX,BX Add the contents of register AX and BX and store the result in

register AX1000:2008 INT 3 Interrupt the current operation.1000:2009 Press EnterDyna_86> G 1000:2000 and

press EnterBreak at 2009 0FFF: 1009Dyna_86> R

Result:

AX= DEFC, BX=3C36, CX=0000, DX=0000, SP=06FD, BP=0000, SI=0000, IP=2009, FL=F086

Conclusion:

In each instruction, offset address is incremented by 3 bits because 1 address is occupied by instruction and the rest two

saves the data.

(c) Subtraction of two 8 bit numbers

Address Opcode Operand CommentDyna_86> A 1000:2000 This specifies the segment and offset (effective address)1000:2000 MOV AL,44 Load the 8 bit no.44 into 8 bit register AL1000:2002 MOV BL,22 Load the 8 bit no.22 into 8 bit register BL1000:2004 SUB AL,BL Subtract the contents of register AL and BL and store the result in



Result:


Conclusion:

In each instruction, offset address is incremented by 2 bit because 1 address is occupied by instruction and the other saves

the data.

4

(b) Subtraction of two 16 bit numbers

Address Opcode Operand CommentDyna_86> A 1000:2000 This specifies the segment and offset (effective address)1000:2000 MOV AX,4321 Load the 16 bit no.4321 into 16 bit register AX1000:2003 MOV BX,1234 Load the 16 bit no.1234 into 16 bit register BX1000:2006 SUB AX,BX Subtract the contents of register AX and BX and store the result in


press EnterBreak at 2009 0FFF: 1009Dyna_86> R

Result:

AX= 30ED, BX=1234, CX=0000, DX=0000, SP=06FD, BP=0000, SI=0000, IP=2009, FL=F086

Conclusion:


saves the data.

5

Experiment 2

Aim: WALP to multiply two 8 bit and 16 bit nos.


Program:

(a) Multiplication of two 8 bit numbers

Address Opcode Operand CommentDyna_86> A 2000:1000 This specifies the segment and offset (effective address)2000:1000 MOV AL,07 Load the 8 bit no.07 into 8 bit register AL2000:1002 MOV BL,08 Load the 8 bit no.08 into 8 bit register BL2000:1004 MUL BL Multiply the contents of register AL and BL and store the result in



Result:

AX= 0038, BX=0008, CX=0000, DX=0000, SP=06FD, BP=0000, SI=0000

Conclusion:


the data.

6

(b) Multiplication of two 16 bit numbers

Address Opcode Operand CommentDyna_86> A 2000:1000 This specifies the segment and offset (effective address)2000:1000 MOV AX,09 Load the 16 bit no.09 into 16 bit register AX2000:1003 MOV BX,05 Load the 16 bit no.05 into 16 bit register BX2000:1006 MUL BX Add the contents of register AX and BX and store the result in



Result:

AX= 002D, BX=0005, CX=0000, DX=0000, SP=06FD, BP=0000, SI=0000

Conclusion:


saves the data.

7

Experiment 3

Aim: WALP to divide two 8 bit and 16 bit nos.


Program:

(a) Division of two 8 bit numbers

Address Opcode Operand CommentDyna_86> A 2000:1000 This specifies the segment and offset (effective address)2000:1000 MOV AL,09 Load the 8 bit no.09 into 8 bit register AL2000:1002 MOV BL,05 Load the 8 bit no.05 into 8 bit register BL2000:1004 DIV BL Dividing the contents of register AL by contents of register BL and

store the result in register AL2000:1006 INT 3 Interrupt the current operation.2000:1007 Press EnterDyna_86> G 2000:1000 and


Result:

AX= 0401, BX=0005, CX=0000, DX=0000, SP=06FD, BP=0000, SI=0000

Conclusion:


the data.

8

(b) Division of two 16 bit numbers

Address Opcode Operand CommentDyna_86> A 2000:1000 This specifies the segment and offset (effective address)2000:1000 MOV AX,0020 Load the 16 bit no.0020 into 16 bit register AX2000:1003 MOV BX,0003 Load the 16 bit no.0003 into 16 bit register BX2000:1006 DIV BX Dividing the contents of register AX by the contents of register BX

and store the result in register AX2000:1008 INT 3 Interrupt the current operation.2000:1009 Press EnterDyna_86> G 2000:1000 and


Result:

AX= 000A, BX=0002, CX=0000, DX=0000, SP=06FD, BP=0000, SI=0000

Conclusion:


saves the data.

9

Experiment 4

Aim: WALP to add a series of five 8-bit nos.


Program:

Address Opcode Operand CommentDyna_86> A 2000:1000 This specifies the segment and offset (effective address)2000:1000 MOV AL,23 Load the 8 bit no.23 into 8 bit register AL2000:1002 MOV [2000], AL Load the value of 8 bit register AL into memory location [2000]2000:1005 MOV AL,12 Load the 8 bit no.12 into 8 bit register AL2000:1007 MOV [2001], AL Load the value of 8 bit register AL into memory location [2001]2000:100A MOV AL,34 Load the 8 bit no.34 into 8 bit register AL2000:100C MOV [2002], AL Load the value of 8 bit register AL into memory location [2002]2000:100F MOV AL,44 Load the 8 bit no.44 into 8 bit register AL2000:1011 MOV [2003], AL Load the value of 8 bit register AL into memory location [2003]2000:1014 MOV AL,68 Load the 8 bit no.68 into 8 bit register AL2000:1016 MOV [2004], AL Load the value of 8 bit register AL into memory location [2004]2000:1019 MOV CL,05 Set a counter CL to value 52000:101B MOV AL,00 Clear any previous value and reset the AL register to 02000:101F MOV SI,2000 Set the register SI to location 20002000:1022 MOV BL,[SI] Load the data saved in SI, i.e., data at the address saved at SI into

8 bit register BL2000:1024 ADD AL,BL Add the contents of register BL and AL and store the data in AL2000:1026 INC SI Increment the value of SI by 12000:1027 DEC CL Decrement the value of counter CL by 12000:1029 JNZ 1022 This will fetch the next instruction from the address 1022 if CL is

not equal to 02000:102B INT 3 Interrupt the current operation.2000:102C Press EnterDyna_86> G 2000:1000 and

press EnterBreak at 1FFF: 102CDyna_86> R

Result:


10

Experiment 5

Aim: WALP to find odd and even number from a given group of nos.


Program:

Address Opcode Operand CommentDyna_86> A 2000:1000 This specifies the segment and offset (effective address)2000:1000 MOV AL,01 Load the 8 bit no.01 into 8 bit register AL2000:1002 MOV [2000], AL Load the value of 8 bit register AL into memory location [2000]2000:1005 MOV AL,02 Load the 8 bit no.02 into 8 bit register AL2000:1007 MOV [2001], AL Load the value of 8 bit register AL into memory location [2001]2000:100A MOV AL,03 Load the 8 bit no.03 into 8 bit register AL2000:100C MOV [2002], AL Load the value of 8 bit register AL into memory location [2002]2000:100F MOV AL,04 Load the 8 bit no.04 into 8 bit register AL2000:1011 MOV [2003], AL Load the value of 8 bit register AL into memory location [2003]2000:1014 MOV AL,05 Load the 8 bit no.05 into 8 bit register AL2000:1016 MOV [2004], AL Load the value of 8 bit register AL into memory location [2004]2000:1019 MOV CL,05 Set a counter CL to value 52000:101B MOV AL,00 Clear any previous value and reset the AL register to 02000:101D MOV SI,2000 Set the register SI to location 20002000:1020 MOV BL,[SI] Load the data saved in SI, i.e., data at the address saved at SI into

8 bit register BL2000:1022 RCR BL,01 Rotate Carry Right Operation is performed to the value stored in

register BL2000:1024 JC 102A Jump to the location 102A if Carry Equal to Zero2000:1026 INC AL Increment the value of DH by 12000:1028 JMP 102C Jump to memory location 102C2000:102A INC DL Increment the DL value by 12000:102C INC SI Increment the SI value by 12000:102D DEC CL Decrement the Counter value by 12000:102F JNZ 1020 Jump to the memory location 1020 if CL is not equal to zero 2000:1031 INT 3 Interrupt the current operation.2000:1032 Press EnterDyna_86> G 2000:1000 and

press EnterBreak at 1FFF:1032Dyna_86> R

Result:

In this program we are finding even and odd no. from a given group of 5 numbers. The O/P generated is AX= 0002, BX=0002, CX=0000, DX=0003, SP=06FD, BP=0000, SI=2005, IP=1034, FL=F047. AX stores even number and DX stores odd number.

11

Experiment 6

Aim: WALP to find positive and negative number from a given group of nos.


Program:

Address Opcode Operand CommentDyna_86> A 2000:1000 This specifies the segment and offset (effective address)2000:1000 MOV AL,48 Load the 8 bit no.48 into 8 bit register AL2000:1002 MOV [2000], AL Load the value of 8 bit register AL into memory location [2000]2000:1005 MOV AL,57 Load the 8 bit no.57 into 8 bit register AL2000:1007 MOV [2001], AL Load the value of 8 bit register AL into memory location [2001]2000:100A MOV AL,69 Load the 8 bit no.69 into 8 bit register AL2000:100C MOV [2002], AL Load the value of 8 bit register AL into memory location [2002]2000:100F MOV AL,A7 Load the 8 bit no.A7 into 8 bit register AL2000:1011 MOV [2003], AL Load the value of 8 bit register AL into memory location [2003]2000:1014 MOV AL,A6 Load the 8 bit no.A6 into 8 bit register AL2000:1016 MOV [2004], AL Load the value of 8 bit register AL into memory location [2004]2000:1019 MOV CL,05 Set a counter CL to value 52000:101B MOV AL,00 Clear any previous value and reset the AL register to 02000:101D MOV SI,2000 Set the register SI to location 20002000:1020 MOV AL,[SI] Load the data saved in SI, i.e., data at the address saved at SI into

8 bit register AL2000:1022 AND AL,80 AND 80 to the value stored in register AL2000:1024 JNZ 102A Jump to the location 102A if Not Equal to Zero2000:1026 INC DH Increment the value of DH by 12000:1028 JMP 102C Jump to memory location 102C2000:102A INC DL Increment the DL value by 12000:102C INC SI Increment the SI value by 12000:102D DEC CL Decrement the Counter value by 12000:102F JNZ 1020 Jump to the memory location 1020 if CL is not equal to zero 2000:1031 INT 3 Interrupt the current operation.2000:1032 Press EnterDyna_86> G 2000:1000 and


Result:

In this program we are finding positive and negative no. from a given group of 5 numbers. The O/P generated is AX= 0080, BX=0000, CX=0000, DX=0302, SP=06FD, BP=0000, SI=2005. DH stores positive number and DL stores negative number.

12

Experiment 7

Aim: WALP to find largest and smallest number and store the result in Accumulator


Program:

(a) ALP to find the largest number

Address Opcode Operand CommentDyna_86> A 2000:1000 This specifies the segment and offset (effective address)2000:1000 MOV AL,40 Load the 8 bit no.40 into 8 bit register AL2000:1002 MOV [2000], AL Load the value of 8 bit register AL into memory location [2000]2000:1005 MOV AL,61 Load the 8 bit no.61 into 8 bit register AL2000:1007 MOV [2001], AL Load the value of 8 bit register AL into memory location [2001]2000:100A MOV AL,75 Load the 8 bit no.75 into 8 bit register AL2000:100C MOV [2002], AL Load the value of 8 bit register AL into memory location [2002]2000:100F MOV AL,C7 Load the 8 bit no.C7 into 8 bit register AL2000:1011 MOV [2003], AL Load the value of 8 bit register AL into memory location [2003]2000:1014 MOV AL,20 Load the 8 bit no.20 into 8 bit register AL2000:1016 MOV [2004], AL Load the value of 8 bit register AL into memory location [2004]2000:1019 MOV CL,04 Set a counter CL to value 42000:101B MOV SI,2000 Set the register SI to location 20002000:101E MOV DI,2001 Set the register DI to location 20012000:1021 MOV AL,[SI] Load the data saved in SI, i.e., data at the address saved at SI into

8 bit register AL2000:1023 MOV BL,[DI] Load the data saved in SI, i.e., data at the address saved at SI into

8 bit register BL2000:1025 CMP AL,BL Compare the contents of Register AL and BL2000:1027 JNC 102F Jump to the memory location 102F if Carry is not generated2000:1029 XCHG AL,BL Exchange the values of AL and BL if carry is generated2000:102B MOV [SI],AL Copy the contents of register AL to the memory location stored

by register SI2000:102D MOV [DI],BL Copy the contents of register BL to the memory location stored

by register DI2000:102F INC DI Increment the register DI value by 12000:1030 DEC CL Decrease the CL value by 12000:1032 JNZ 1021 Jump to the memory location 1021 if CL is not equal to zero 2000:1034 INT 3 Interrupt the current operation.2000:1035 Press EnterDyna_86> G 2000:1000 and


13

(b) ALP to find the smallest number

Address Opcode Operand CommentDyna_86> A 2000:1000 This specifies the segment and offset (effective address)2000:1000 MOV AL,51 Load the 8 bit no.51 into 8 bit register AL2000:1002 MOV [2000], AL Load the value of 8 bit register AL into memory location [2000]2000:1005 MOV AL,A5 Load the 8 bit no.A5 into 8 bit register AL2000:1007 MOV [2001], AL Load the value of 8 bit register AL into memory location [2001]2000:100A MOV AL,75 Load the 8 bit no.75 into 8 bit register AL2000:100C MOV [2002], AL Load the value of 8 bit register AL into memory location [2002]2000:100F MOV AL,C7 Load the 8 bit no.C7 into 8 bit register AL2000:1011 MOV [2003], AL Load the value of 8 bit register AL into memory location [2003]2000:1014 MOV AL,20 Load the 8 bit no.20 into 8 bit register AL2000:1016 MOV [2004], AL Load the value of 8 bit register AL into memory location [2004]2000:1019 MOV CL,04 Set a counter CL to value 42000:101B MOV SI,2000 Set the register SI to location 20002000:101E MOV DI,2001 Set the register DI to location 20012000:1021 MOV AL,[SI] Load the data saved in SI, i.e., data at the address saved at SI into


8 bit register BL2000:1025 CMP AL,BL Compare the contents of Register AL and BL2000:1027 JC 102F Jump to the memory location 102F if Carry is generated2000:1029 XCHG AL,BL Exchange the values of AL and BL if carry is generated2000:102B MOV [SI],AL Copy the contents of register AL to the memory location stored

by register SI2000:102D MOV [DI],BL Copy the contents of register BL to the memory location stored

by register DI2000:102F INC DI Increment the register DI value by 12000:1030 DEC CL Decrease the CL value by 12000:1032 JNZ 1021 Jump to the memory location 1021 if CL is not equal to zero 2000:1034 INT 3 Interrupt the current operation.2000:1035 Press EnterDyna_86> G 2000:1000 and


Result:

The O/P generated for finding the largest number program is AX= 00C7, BX=0020, CX=0000, DX=0000, SP=06FD, BP=0000, SI=2000, and, for finding the smallest number program is AX= 0020, BX=0020, CX=0000, DX=0000, SP=06FD, BP=0000, SI=2000

14

Experiment 8

Aim: WALP for arranging in ascending and descending order of given 5 numbers


Program:

(a) ALP to arrange in ascending order

Address Opcode Operand CommentDyna_86> A 2000:1000 This specifies the segment and offset (effective address)2000:1000 MOV AL,B1 Load the 8 bit no.B1 into 8 bit register AL2000:1002 MOV [2000], AL Load the value of 8 bit register AL into memory location [2000]2000:1005 MOV AL,95 Load the 8 bit no.95 into 8 bit register AL2000:1007 MOV [2001], AL Load the value of 8 bit register AL into memory location [2001]2000:100A MOV AL,A5 Load the 8 bit no.A5 into 8 bit register AL2000:100C MOV [2002], AL Load the value of 8 bit register AL into memory location [2002]2000:100F MOV AL,61 Load the 8 bit no.61 into 8 bit register AL2000:1011 MOV [2003], AL Load the value of 8 bit register AL into memory location [2003]2000:1014 MOV AL,D7 Load the 8 bit no.D7 into 8 bit register AL2000:1016 MOV [2004], AL Load the value of 8 bit register AL into memory location [2004]2000:1019 MOV CH,04 Set a counter CH to value 42000:101B MOV SI,2000 Set the register SI to location 20002000:101E MOV DX,2001 Set the register DX to location 20012000:1021 MOV DI,DX Move the contents of register DX to DI2000:1023 MOV CL,CH Move the contents of register CH to CL2000:1025 MOV AL,[SI] Load the data saved in SI, i.e., data at the address saved at SI into


8 bit register BL2000:1029 CMP AL,BL Compare the contents of Register AL and BL2000:102B JC 1033 Jump to the memory location 1033 if Carry is generated2000:102D XCHG AL,BL Exchange the values of AL and BL if carry is generated2000:102F MOV [SI],AL Copy the contents of register AL to the memory location stored

by register SI2000:1031 MOV [DI],BL Copy the contents of register BL to the memory location stored

by register DI2000:1033 INC DI Increment the register DI value by 12000:1034 DEC CL Decrease the CL value by 12000:1036 JNZ 1025 Jump to the memory location 1025 if CL is not equal to zero 2000:1038 INC SI Increment the register SI value by 12000:1039 INC DX Increment the register DX value by 12000:103A DEC CH Decrement the register CH value by 12000:103C JNZ 1021 Jump to the memory location 1021 if CL is not equal to zero2000:103E MOV AL,[2000] Move the contents of location [2000] to register AL2000:1041 MOV BL,[2001] Move the contents of location [2001] to register BL2000:1045 MOV CL,[2002] Move the contents of location [2002] to register CL2000:1049 MOV DL,[2003] Move the contents of location [2003] to register DL2000:104D MOV DH,[2004] Move the contents of location [2004] to register DH2000:1051 INT 3 Interrupt the current operation.

15

2000:1052 Press EnterDyna_86> G 2000:1000 and


Result:

AX= 0061, BX=0095, CX=00A5, DX=D7B1, SP=06FD, BP=0000, SI=2004

Conclusion:

The ascending order is: AL=61 BL=95 CL=A5 DL=B1 DH=D7

(b) ALP to arrange in descending order

Address Opcode Operand CommentDyna_86> A 2000:1000 This specifies the segment and offset (effective address)2000:1000 MOV AL,B1 Load the 8 bit no.B1 into 8 bit register AL2000:1002 MOV [2000], AL Load the value of 8 bit register AL into memory location [2000]2000:1005 MOV AL,95 Load the 8 bit no.95 into 8 bit register AL2000:1007 MOV [2001], AL Load the value of 8 bit register AL into memory location [2001]2000:100A MOV AL,A5 Load the 8 bit no.A5 into 8 bit register AL2000:100C MOV [2002], AL Load the value of 8 bit register AL into memory location [2002]2000:100F MOV AL,61 Load the 8 bit no.61 into 8 bit register AL2000:1011 MOV [2003], AL Load the value of 8 bit register AL into memory location [2003]2000:1014 MOV AL,D7 Load the 8 bit no.D7 into 8 bit register AL2000:1016 MOV [2004], AL Load the value of 8 bit register AL into memory location [2004]2000:1019 MOV CH,04 Set a counter CH to value 42000:101B MOV SI,2000 Set the register SI to location 20002000:101E MOV DX,2001 Set the register DX to location 20012000:1021 MOV DI,DX Move the contents of register DX to DI2000:1023 MOV CL,CH Move the contents of register CH to CL2000:1025 MOV AL,[SI] Load the data saved in SI, i.e., data at the address saved at SI into


8 bit register BL2000:1029 CMP AL,BL Compare the contents of Register AL and BL2000:102B JNC 1033 Jump to the memory location 1033 if Carry is not generated2000:102D XCHG AL,BL Exchange the values of AL and BL if carry is generated2000:102F MOV [SI],AL Copy the contents of register AL to the memory location stored

by register SI2000:1031 MOV [DI],BL Copy the contents of register BL to the memory location stored

by register DI2000:1033 INC DI Increment the register DI value by 12000:1034 DEC CL Decrease the CL value by 12000:1036 JNZ 1025 Jump to the memory location 1025 if CL is not equal to zero 2000:1038 INC SI Increment the register SI value by 1

16

2000:1039 INC DX Increment the register DX value by 12000:103A DEC CH Decrement the register CH value by 12000:103C JNZ 1021 Jump to the memory location 1021 if CL is not equal to zero2000:103E MOV AL,[2000] Move the contents of location [2000] to register AL2000:1041 MOV BL,[2001] Move the contents of location [2001] to register BL2000:1045 MOV CL,[2002] Move the contents of location [2002] to register CL2000:1049 MOV DL,[2003] Move the contents of location [2003] to register DL2000:104D MOV DH,[2004] Move the contents of location [2004] to register DH2000:1051 INT 3 Interrupt the current operation.2000:1052 Press EnterDyna_86> G 2000:1000 and


Result:

AX= 00D7, BX=00B1, CX=00A5, DX=6195, SP=06FD, BP=0000, SI=2004

Conclusion:

The descending order is: AL=D7 BL=B1 CL=A5 DL=95 DH=61

17

Experiment 9

Aim: WALP for interfacing of 8255 Programming Peripheral Interface (PPI) with 8086


Features of 8255:

The 8255A is a programmable peripheral interface (PPI) device designed for use in Intel microcomputer systems. Its

function is that of a general purposes I/O component to Interface peripheral equipment to the microcomputer system bush.

The functional configuration of the 8255A is programmed by the systems software so that normally no external logic is

necessary to interface peripheral devices or structures. The important features are:

3 8-bit IO ports PA, PB, PC

PA can be set for Modes 0, 1, 2. PB for 0,1 and PC for mode 0 and for BSR. Modes 1 and 2 are interrupt driven.

PC has 2 4-bit parts: PC upper (PCU) and PC lower (PCL), each can be set independently for I or O. Each PC bit

can be set/reset individually in BSR mode.

PA and PCU are Group A (GA) and PB and PCL are Group B (GB)

Address/data bus must be externally demux'd.

TTL compatible.

Improved dc driving capability

Pin Diagram of 8255

18

Block Diagram of 8255

Program:

Address Opcode Operand CommentDyna_86> A 2000:10002000:1000 MOV AL,90 Load the 8 bit no.90 into 8 bit register AL2000:1002 OUT 33,AL At CWR (address 33) we are putting the data of AL. CWR

1 0 0 1 0 0 0 02000:1004 IN AL,30 Port A (address 30)is acting as input to AL2000:1006 OUT 31,AL Data from AL is sent to PB. So PB is Output Port2000:1008 INT 3 Interrupt the current operation.2000:1009 Press EnterDyna_86> G 2000:1000 and


Result: Data on Port A is PA0-PA7 is 10010000. Data on Port B is PB0-PB7 is 10010000. So equal data is observed.

19

Experiment 10

Aim: WALP to add two 8 bit nos. using 8051 microcontroller


Program:

Address Opcode Operand CommentDyna_51> A 94029402: MOV A,#06 # means immediate data. So no.06 will be copied to A9404: MOV R0,#05 No.05 will be copied to R09406: ADD A,R0 Add the contents of register A and R0 and store the result in

register A9407: JUMP 6000 Instruction to Terminate the program

Press EnterDyna_51> T 9402 It means trace the location 9402 and start the execution of the

program step by step

Result:

A= 0B, PSW=01, SP=4A, DPTR=836B, PC=1770

20

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