vedic maths 5

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    A small advice which I can give youis keep in touch with vedic maths.

    Practice a few examples shown in

    the previous presentation.

    Attend the speed test in my website

    (www.geocities.com/rudranhari/). Examine

    yourself. If you have done the above things,then its time to continue. Done by

    L Hariharan

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    This presentation deals withStrange Coincidence

    Revision of division

    Right to Left Division

    Advance Division

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    NUMBER SQUARE CUBE

    1 1 1

    2 4 8

    3 9 27

    4 16 64

    5 25 125

    6 36 216

    7 49 343

    8 64 512

    9 81 729

    Coincidence:Square of anynumber will notendin2,3,7,8&

    Cube of2ends in8and vice versa. Also,Cube of3ends in7and vice versa.

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    Have you ever Divided 1 by 7. Have you foundthe answer for 1/7. Press any key to continue.

    Note:This fraction 1/7 can be converted to7/49 and the previous division techniquein past presentations can be used tocalculate the answer

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    FIND:1/29= 0.013142408221725Step 1: 1/30= .03.., therefore we have found .0should comeStep 2: Add 0to numerator start dividing 3(ie. 10/3) Thereforewe get quotient as 3and remainder as 1.Step 3: Combine remainder(1) and quotient(3). That is we get13.Step 4: Divide 13 by 3again and find quotient(Q=4) andremainder(R=1) as shown in figure. Repeat step 3.Note:Quotient is running number Remainder is Subscript orbase.

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    Find:8/49= 0.311613322615033006All steps are same except one. Here you are going to divide8/5and find Q = 1, R = 3.Now continue as previous problem. Combine 3and 1, divide 31by 5 again and find Q = 6, R = 1Try solving the problem using a paper andpen, you will definitely get it.

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    So far we were dividing numbers from Left to Right.

    We can also divide numbers from right to left

    Divide 1/19 from right to left

    1/19= 10051206031115171809140713160804021

    Step1: Start with 1, since the denominator is 19start multiplyingby 2.Step2: 12= 02, similarly 04,08,16Step3: 16= 16Now multiply 62and add 1, therefore 13Step4: Continue until the numbers start repeating again.Note: As 1/7, the fraction 1/19 is also a recurringdecimal. Compare 1/19 with left to right division.

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    So far we have seen in divisionDenominator numbers ending in 9.

    Numerator is other than 1 while dividing by 9

    Dividing from right to left and vice versa.

    What ifDenominators does not end in 9 or cannot be converted to 9.

    The number is complex.

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    47/73is written as3 : 47504000000000

    7

    644

    Step1: After 47put as many zeros you want.Step2: Divide 47by 7, Q = 6& R = 5. Put 6and 5as shownin figure.

    Step3: Do 503*6= 32

    Step4: Divide 32by 7, Q = 4& R = 4. Put as shown infigure.

    Step5: Do 40 3*4=28, divide 28by 7,Q = 4& R = 0

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    3 : 4750407050000007

    6438

    Step6: Continuing we get ve number. Therefore 0ischanged to 7and 4is reduced to 3.Step7: 70 3*3= 61Step8: 61divided by 7, Q = 8, R = 5Step9: The process is repeated to get more digits.

    Step10: With our commonsense we can find that the

    division should be 0 6438

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    So far in all the vedic maths presentations we have dealtwith Multiplication, Squares, Cubes, Square Root, Cube Root,

    Division and other interesting concepts.

    If you have to get full benefit from the presentations you

    must also try to solve on your own. These presentations are just a

    helping hand to you.

    I know you have taken a paper and a pen to start solving

    more problems on your own.

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    Write Your comments to

    [email protected]

    Visit my website

    www.geocities.com/rudranhari/