uva-vu master course: advanced solid state physics master course: advanced solid state physics...

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UvA-VU Master Course: Advanced Solid State Physics Contents in 2005: Diffraction from periodic structures (week 6, AdV) Electronic band structure of solids (week 7, AdV) Motion of electrons and transport phenomena (week 8, AdV) Superconductivity (week 9&10, RW) Magnetism (week 11&12,JB) Anne de Visser Rinke Wijngaarden Jürgen Buschow

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UvA-VU Master Course: Advanced Solid State Physics

Contents in 2005:• Diffraction from periodic structures (week 6, AdV)• Electronic band structure of solids (week 7, AdV)• Motion of electrons and transport phenomena (week 8, AdV)• Superconductivity (week 9&10, RW)• Magnetism (week 11&12,JB)

Anne de Visser Rinke Wijngaarden Jürgen Buschow

Literature, software and homework

The course is based on the book:H. Ibach and H. Lüth: Solid State Physics3rd edition (Springer-Verlag, Berlin, 2003)ISBN 3-540-43870-XSee also:N.W. Ashcroft and N.D. Mermin: Solid State Physics(Saunders College Publ.)ISBN 0-03-083993-9

Computer simulations form an essential part of the course:R.H. Silsbee and J. Dräger: Simulations for Solid State Physics(Cambridge University Press, Cambridge 1997)ISBN 0-521-59911-3Software (freeware): www.physics.cornell.edu/sss/

Homework exercises will be distributed throughout the courseCompleting the course gives 6 ECTS → ~ 6 x 28 hours

Course 1: Diffraction from periodic structures

∑ ⋅−=α

ααrGi

hklhklefS

rr

GkkKrrrr

=−= 0'

Course 1: Diffraction from periodic structures

• Question: how do we learn the structure of a periodic solid?• Diffraction of waves or particles with λ ≈ lattice constant• Coherent scattering events give Bragg peaks

Bragg condition:2dsinθ = λ

scattering vector:K=k-k0

This picture (and some others!) taken from the Solid State Course by Mark Jarrel (Cincinnati University).

Intermezzo periodic structures

Fruit

TEM silicon STM graphite ???

Lattice vectors and unit cells

332211 anananrnrrrr ++=

real or direct lattice

The 14 Bravais lattices

)aa(aaab

321

321 2 rrr

rrr

×⋅×= π

321 blbkbhGrrrr

++=

ijii ab πδ2=⋅ rr

)aa(aaab

132

132 2 rrr

rrr

×⋅×= π

)aa(aaab

213

213 2 rrr

rrr

×⋅×= π

332211 anananrnrrrr ++=

real lattice reciprocal lattice

Inside out: the reciprocal lattice

length reciprocal lattice vector = 2π/(length direct vector)

Probe beams differ in:• wave length λ = h/p• scattering cross section• magnetic moment

For lattice constant a ~10-10 m ~ λ =2πh/pthe relevant energy scale is• electrons: Ee = p2/2me~ 300 eV• neutrons: En = p2/2mn~ 0.6 eV• photons: Eph= pc ~ 12 keV

Typical probes:• electrons (10 eV - 1 keV)• neutrons (10 meV - 1 eV)• x-ray photons (1 keV -100 keV)

Probe beams

The de Broglie wavelength (λ=2π/k) of photons, electrons, neutrons, helium atoms as function of energy

Different probe beams for different research• electrons typically penetrate only ~ 50 Å and are used to

probe the surface (e.g. LEED)

• neutrons scatter at nuclei and carry magnetic momentused for phonon dispersion, resolving magnetic structuresetc.

• x-rays, wide energy range, resolve crystallographicstructures of solids, complex molecules etc.

Clean, not oxidized,surfaces needed!

Used to determine the value of the lattice parameters accurately.

If a monochromatic x-ray beam is directed at a single crystal, then only one or two diffracted beams may result.

If the sample consists of some tens of randomly orientated single crystals, the diffracted beams lie on the surface of several cones.

A sample of some hundreds of crystals (i.e. a powdered sample) show that the diffracted beams form continuous cones. Each cone intersects the film giving diffraction lines. For every set of crystal planes, by chance, one or more crystals will be in the correct orientation to give the correct Bragg angle to satisfy Bragg's equation. Each diffractionline is made up of a large number of small spots, each from a separate crystal.

Example diffraction experiment: powder diffraction

Diffraction angle θ is:

Bragg’s law:

Interplanar spacing d, lattice parameter a

Indexing a powder pattern

⎟⎠⎞

⎜⎝⎛ −==

WSor

WS 21 1

22πθπθ

222 lkhadhkl

++=

θλ sin2dn =

( )2222

22

4sin lkh

a++= λθ

λ=1.54 Å, W= 180 mm, cubic structure

Structure factor calculation:face centered cubich,k,l all even or odd

a = 4.02 Å

Diffraction in “kinetic” approximation

- single scattering, emission of spherical waves- coherent scattering, phase relation fixed- source Q, scattering center P, observer B- approximate spherical wave by plane wave at large distance from source- scattering material with scattering density ρ(r) emits spherical waves

tirRkip eAA 00 )(

0ω−+⋅=

rrramplitude at P, time t:

rRertrAA

rRik

pB rrrr

rr

−=

')(),(

'

ρ

∫ ⋅−−∝ rde)r(e)t(A r)kk(itiB

rr rrr00 ρω

amplitude at B, time t:

total scattering amplitude static lattice:

with along identical for all Pkr

rR rr−'

elastic scattering ω=ω0

General theory of diffraction in “kinetic” approximation

with scattering vector

In diffraction experiment intensity is measured

- intensity is absolute square of the Fourier transform of the scattering density ρ(r)

- if one could measure the amplitude(time) (phase), structure could be determined by inverse Fourier transform, this is NOT possible

Procedure: choose possible crystal structure (symmetry)→ calculate diffraction pattern → compare with measured pattern

22 )()( ∫ ⋅−∝∝ rderAKI rKiB

rrr rr

ρ0' kkKrrr

−=

Forward scattering Laueimage of a hexagonal crystal

If material consists of single type of atomsscattering density at position i

Decompose Patterson function in- correlation of atom with itself and- correlation of atom with all other atoms

For disordered systems analysis facilitated by Patterson function:P(r) = the autocorrelation function of the scattering density

∫ ⋅∝ ')'()( ' rderPKI rKi rrr rr

rd)r'r()r()'r(P rrrrr += ∫ ρρ

intensity is Fourier transform ofPatterson function

∑ −=i

iat )rr()r( rrr ρρ

rd)r'r()r(NNf)'r(P 'r,r++= ∫ ρρδ 0

2

∑≠

−=ij

jat )rr()r( rrρρ

f is “atom factor”: measure of the magnitude of the scattering amplitude of an atom

if r′ = lattice vector P(r′) peaks

Pair correlation function for amorphoussilicon and liquid iron (1833 K)

g(r) ∝ Fourier transform of S(K)-1

structure factor S(K) and pair correlation function g(r)

∫ ⋅+=∝ rdergVNKSKI rKi rrr rr

)(1)()(

rdrrrrgfVN r)'()()'(2 += ∫ ρρ

N = numberof atoms

V = volume

amorphoussilicon dioxide

one dimensional example: periodic array of atoms, translational invariance

,...2,1,0)()( ±±=+= nnaxx ρρ∑=

n

xaninex )/2()( πρρ

∑ ⋅=G

rGiGer

r

rr

rr ρρ )(

Fourier series

generalization to three dimensions

321 glgkghG rrrr++=

332211 anananrnrrrr ++=

translational invariance implies mrG n π2=⋅ rr

m integer

ijii ag πδ2=⋅ rrG is reciprocal lattice vector

)(2

321

321 aaa

aag rrr

rrr

×⋅×= π

real lattice

and cyclic permutations

Scattering from periodic structures

2)(

2

20

')( ∫∑ ⋅−∝ rde

RA

KI rKGi

GG

rr rrr

otherwiseandKGifVrde rKGi 0~)(rrrrrr

==∫ ⋅−

Insert Fourier series of periodic array ρ(r) in expression for intensity

Laue scattering condition: constructive interference will occur whenthe change in wave vector is a vector of the reciprocal lattice

22

2

20

')( V

RA

GKI Gr

rrρ∝=

significant contribution only when G=K, thus:

GkkKrrrr

=−= 0'

(since width of intensity distribution ~V-1 total intensity ~V)

with intensity

diffraction peaks observed at

2hklhklI ρ∝

321 glgkghG rrrr++=

Miller indices - distance between planes

Miller indices (h, k, l):integered inversed direct space coordinates

egerintsmallestispZ)l,k,h()'l,'k,'h(p

o/'l,n/'k,m/'haoanamrn

∈====

++=111

321rrrr

Example: (m,n,o) = (0.5,1,1) → (h,k,l) = (2,1,1)

The reciprocal lattice vectoror Ghkl is directed perpendicular to the plane (h,k,l)its length relates to the distance between the planes

hklhkl d/G π2=

321 glgkghG rrrr++=

Laue condition

GkkKrrrr

=−= 0

hklGkkKK =−== 0

rrrhklhkl dGkK /2sin4sin2 0 πθ

λπθ ====

λθ /sin2/1 =hkld

Laue condition is equivalent to Bragg condition

Bragg condition

θλ sin2 hkld=

The Ewald construction to determine if the conditions are correctfor obtaining a Bragg peak• select a point in k space as origin. • draw the incident wave vector k0 to the origin. • from the base of k0 wave vector k in all possible directions to form a sphere (elastic scattering |k|=|k0|).

• at each point where this sphere intersects a lattice point in k space,there will be a Bragg peak with G = k - k0.

For instance 8 peaks in the example below.

single crystalaligned with respect to k0

for small changesin k0 no Bragg peaks!

reciprocal latticeorigin

Structure factor and atomic form factor

• position of Bragg peaks ← Laue condition (reciprocal lattice)• intensity of Bragg peaks ← structure factor and atomic form factor

structure factor → interference of wavesscattering from different atoms

atomic form factor →interference of waves scattering from different parts of the atom

Intensity is proportional to Fourier coefficients of scattering density

integrate over basis cell and sum over N cells

2hklhklI ρ∝

∫∑ ∫

∑ ∫∫⋅−+⋅−

⋅−⋅−

==

==

cell

rGi

n,n,n cell

)rr(Gi

cells cell

rGirGihkl

rde)r(VNrde)r(

V

rde)r(V

rde)r(V

hklnhkl

hklhkl

rrrr

rrrr

rrrrr

rrrr

ρρ

ρρρ

321

1

11

mrG n π2=⋅ rr

with N/V=1/Vc with Vc volume of cell

Next: calculate scattering density due to different atoms in cell

332211 anananrnrrrr ++=r→rcell+rn

With different atomic density of different elements in the cell: ρα(r′)

atomic scattering factor

structure factor

for lattices with one atom per unit cell S=f

∑ ∫ ⋅−⋅−=α

αρρ α 'rde)'r(eV

'rGirGi

chkl

hklhklrr rrrr1

∫ ⋅−= 'rde)'r(f 'rGi hklrr rr

αα ρ

hklc

hkl SV1=ρ

schematic representation of 3d and 4f orbitalsdifferent occupation → different atomic scattering factor

r→rα+r′

αα

α feS rGihkl

hkl∑ ⋅−=rr

Evaluate fα using spherical coordinates

θ is polar angle between G and r′, integrating over θ and ϕ

and

with G = K = 2k0sinθ and k0 = 2π/λ

→ atomic scattering function is function f(sinθ/λ)

For θ=0 integral of scattering densityover the atomic volume ∝ Z = number electrons

atom number (for x-rays)

∫∫ −⋅− −== ϕϑρρ ϑααα d)(cosd'dr're)'r('rde)'r(f cos'riG'rGi hklhkl 2rr rr

∫= 'dr'Gr

'Grsin'r)'r(f 24 αα ρπ

∫= 'dr)/(sin'r

)]/(sin'rsin['r)'r(fλθπ

λθπρπ αα 444 2

∫= '')'(4 2 drrrf αα ρπ

)1(2)1()1()1(1

++−++++=

JJLLSSJJgJ

In 3d metals the orbital moment is mostly quenched (L=0)due to the crystalline electric field. The presence of an orbital component can be measured by the atomic form factor.

Example: atomic form factor chromium

)(21)()( 20 kjg

kjkFJ⎟⎟⎠

⎞⎜⎜⎝

⎛−+=

Magnetic form-factor measured at the h0l. Bragg reflections of Cr2O3. The smooth curve is the spin-only free ion form-factor for Cr3+ normalisedto 2.5 µB.

j0 and j2 describe radial distribution spin and current

The structure factor describes the interference from wavesscattered from different atoms in the unit cell

Example for centered lattice

since rα is in the unit cell u,v,w < 1

For body-centered cubic lattice and f1= f2= f

→ systematic extinctions

∑ ⋅−=α

ααrGi

hklhklefS

rr

∑ ++−=α

πα

ααα )lwkvhu(ihkl efS 2

321 awavaur rrrrαααα ++=

evenlkhforfoddlkhfor)e(fS )lkh(i

hkl

++++=+= ++−

201 π

).,.,.(rand),,(r 505050000 21 ==

Example: structure factor cubic lattice

For our example of the powder diffraction pattern:for face centered cubic lattice and f1= f2= f

With help of the structure factor one can unravel complicated crystallographic and magnetic structures like these:

)0,5.0,5.0(),5.0,0,5.0(),5.0,5.0,0(),0,0,0( 4321 ==== rrrr

otherwiseoddorevenlkhforf

eeefS khilhilkihkl

0,,4

)1( )()()(

==

+++= +−+−+− πππ

antiferroquadrupolar state of NpO2 magnetic phase of DyFe4Al8