thursday january 31, 2013 (mass to mole stoichiometry)
TRANSCRIPT
ThursdayJanuary 31, 2013
(Mass to Mole Stoichiometry)
mol HgO
5.0 mol HgO
HgO æ Hg + O2
Bell RingerThursday, 1-31-13
If 5.0 moles of mercury (II) oxide decompose, how many grams of mercury will be produced?
2 25.0 mol ? grams
X1
=mol Hg
2 g Hg2 1005X
g Hg
mol Hg1201
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Assignment Currently Open
Summative or
Formative?Date
Issued Date Due Date Into GradeSpeed Final Day
QUIZ 16 S1 1/18 1/18 1/24 2/7
WS - Introduction to Stoichiometry and Mole Ratios
F7 1/23 2/1 TOMORROW
WS – Review of Molar Mass F8 1/24 2/1 TOMORROW
Project Share Quiz – Reactions and
BalancingF9 1/25 1/25 TOMORROW
WS – Mole to Mole
StoichiometryF10 1/29 2/1 TOMORROW
WS – Mole to Mass
StoichiometryF11 1/30 2/1 2/8
Types of Stoichiometry Problems
Mass – Mole Conversions : Given is a mass in grams and the
unknown is an amount in moles.When you are given the mass of one substance and asked to calculate the
amount in moles of another substance in the chemical reaction, the general plan is:
Converting Mass to MolesThe following is a solution plan for problems in
which the given quantity is expressed in grams and the unknown quantity is expressed in moles.
Converting Mass to MolesSample Problem
The first step in the industrial manufacture of nitric acid is the catalytic oxidation of ammonia:
NH3 + O2 → NO + H2O (unbalanced)The reaction is run using 824 g of
NH3 and excess oxygen.a. How many moles of NO are formed?
b. How many moles of H2O are formed?
Converting Mass to MolesSample Problem
The first step in the industrial manufacture of nitric acid is the catalytic oxidation of ammonia:
NH3 + O2 → NO + H2O (unbalanced)The reaction is run using 824 g of NH3 and excess oxygen.
a. How many moles of NO are formed?b. How many moles of H2O are formed?
Given: mass of NH3 = 824 gUnknown: a. amt. of NO produced (in mol)
b. amt. of H2O produced (in mol)
Converting Mass to MolesSample Problem
The first step in the industrial manufacture of nitric acid is the catalytic oxidation of ammonia:
NH3 + O2 → NO + H2O (unbalanced)The reaction is run using 824 g of NH3 and excess oxygen.
a. How many moles of NO are formed?b. How many moles of H2O are formed?
Start with a balanced equation:
4NH3 + 5O2 → 4NO + 6H2O
Two conversion factors are needed to solve part (a) - the molar mass of NH3 and the mole ratio of NO to NH3.
Part (b) starts with the same conversion factor as part (a), but then the mole ratio of H2O to NH3 is used to convert
to the amount in moles of H2O. The first conversion factor in each part is the inverted molar mass of NH3.
Converting Mass to Moles
Use the periodic table to compute the molar mass of NH3.
Converting Mass to Moles
Worksheet
Mass to Mole Stoichiometry