this lecture single from single to coupled oscillators

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THIS LECTURE rom single single to oupled oscillators oupled oscillators

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THIS LECTURE

From singlesingle to coupled oscillatorscoupled oscillators

Two thin rods connected by a pivot “Chaotic” motion

Coupled pendulaCoupled pendula

Coupled oscillators

• Normal modesModes of vibration in which each oscillator vibrates with same frequency

• Coupled motion implies energy exchange

Two coupled oscillators

Newton equations

k’k k

x1 x2

)(

)(

12'

22

21'

11

xxkkxxm

xxkkxxm

)cos(2

)cos(2

)cos(2

)cos(2

222

111

2

222

111

1

tA

tA

x

tA

tA

x

mkk

mk

/)'2(

/

2

1

A1, A2, 1 and 2 are constants that depend on initial conditions

Two coupled oscillators

Newton equations

k’k k

x1 x2

)(

)(

12'

22

21'

11

xxkkxxm

xxkkxxm

)cos(2

)cos(2

)cos(2

)cos(2

222

111

2

222

111

1

tA

tA

x

tA

tA

x

mkk

mk

/)'2(

/

2

1

A1, A2, 1 and 2 are constants that depend on initial conditions

Two coupled oscillators

Newton equations

k’k k

x1 x2

)(

)(

12'

22

21'

11

xxkkxxm

xxkkxxm

)cos(2

)cos(2

)cos(2

)cos(2

222

111

2

222

111

1

tA

tA

x

tA

tA

x

mkk

mk

/)'2(

/

2

1

A1, A2, 1 and 2 are constants that depend on initial conditions

NORMAL MODESNORMAL MODESEach mass vibrates with the same frequency

m

k1

NORMAL MODE 1

Masses are in phase and vibratewith frequency

m

kk '22

Masses are in antiphase and vibratewith frequency

NORMAL MODE 2

)cos(2 22

221 t

Axx)cos(

2 111

21 tA

xx

ProblemAt t =0, one mass is moved a distance 2a, but the second mass is held fixed. Find the time-dependence of x1 and x2.

x1

x2

t

t

2

2

121T

2

2

122T

T2

ttax2

cos2

cos2 12121

ttax2

sin2

sin2 12122

T1

Two coupled oscillators: general case

Newton equations

k2k1

k3

x1 x2

Mm

2121111 xaxax

2221212 xaxax

To find the normal modes, we assume that x1 and x2 are harmonic functions with same frequency .

)cos( 111 tAx )cos( 222 tAx

12

1 xx 22

2 xx

Normal modes

Two coupled oscillators: general case

Newton equations

k2k1

k3

x1 x2

Mm

To find the normal modes, we assume that x1 and x2 are harmonic functions with same frequency .

)cos( 111 tAx )cos( 222 tAx

12

1 xx 22

2 xx

Normal modes

Newton equations 12

2121111 xxaxax

22

2221212 xxaxax

Two coupled oscillators: general case

Newton equations

k2k1

k3

x1 x2

Mm

Newton equations 12

2121111 xxaxax

22

2221212 xxaxax

0))(( 21122

222

11222

12

21

211

aaaaa

a

a

a

This system of equations has solution if the determinant of its coefficients vanishes

This is a quadratic equation in the variable . It has two solutions, 1 and 2, corresponding to two normal modes.

1 and 2 corresponding to two normal modes

)cos( 11 tAx

)cos( 12 tBx

)cos( 21 tCx

)cos( 22 tDx

)cos()cos( 211 tCtAx

)cos()cos( 212 tDtBx

NORMAL MODE 1 NORMAL MODE 2

The most general solution is the superposition of the two modes.

Two coupled oscillators: general case

k2k1

k3

x1 x2

Mm

Crystals

Coupled oscillators

N coupled oscillators

z

y

x

Method to describe the motionMethod to describe the motion• Consider separate motion along x, y, z

• Write down Newton equations for the displacement of each mass along a given direction, for example x. Displacements are called x1, x2, x3…xN.

Normal modesDetermine the normal modes for each variable x1, x2…xN to obtain equations that describe harmonic motion NNNNNNN

NN

NN

xaxaxaxx

xaxaxaxx

xaxaxaxx

...

............................................................

...

...

22112

222212122

2

121211112

1