This is a mixed design one part

1) Drug uses the old independent measures method – between conditions with within conditions as error term

The other part is

2) Question (forced choice v free response) is repeated measures – find within subjects then subtract between conditions and interaction to get error (SSsubject x condition)

SubForcedChoice

Free Resp Drug

1 13 8 Ritalin

2 6 8 Ritalin

3 12 12 Ritalin

4 11 13 Ritalin

5 11 8 Adderall

6 6 12 Adderall

7 12 8 Adderall

8 14 15 Adderall

9 8 2 Caffeine

10 9 6 Caffeine

11 13 6 Caffeine

12 10 7 Caffeine

13 10 2 Control

14 3 6 Control

15 14 6 Control

16 8 9 Control

Question

SubForcedChoice

Free Resp Drug

1 13 8 Ritalin

2 6 8 Ritalin

3 12 12 Ritalin

4 11 13 Ritalin

5 11 8 Adderall

6 6 12 Adderall

7 12 8 Adderall

8 14 15 Adderall

9 8 2 Caffeine

10 9 6 Caffeine

11 13 6 Caffeine

12 10 7 Caffeine

13 10 2 Control

14 3 6 Control

15 14 6 Control

16 8 9 Control

Part 1 – Independent measures - Drug

8.5

10

4.5

6

8.5

9.5

7.5

5

14.5

10

9

9.5

12

12

7

10.5

Subj Means

Collapse subject (mean) over Question

Now mean within drug (within Ritalin, etc..)

Then (Subj Mean – Mean (Ritalin) Drug)2

Sum

Multiply times number Levels_Question - 2

Or number of x’s within the Subj Mean (in red)

10.375

MeanRitalin

df = # of subj means (blue) with Ritalin Mean – 1 (3) X number of drug groups (4) = 12

SSwithin_drug

SSwithin_drug

Sub1 Mean

10.5-

10.375

MeanRitalin

SubForcedChoice

Free Resp Drug

1 13 8 Ritalin

2 6 8 Ritalin

3 12 12 Ritalin

4 11 13 Ritalin

5 11 8 Adderall

6 6 12 Adderall

7 12 8 Adderall

8 14 15 Adderall

9 8 2 Caffeine

10 9 6 Caffeine

11 13 6 Caffeine

12 10 7 Caffeine

13 10 2 Control

14 3 6 Control

15 14 6 Control

16 8 9 Control

Part 1 – Independent measures - Drug

8.5

10

4.5

6

8.5

9.5

7.5

5

14.5

10

9

9.5

12

12

7

10.5

Subj Means

1)Collapse subject (mean) over Question

2)Now mean within Drug type (within Ritalin, etc..)

3)Then (Mean (Ritalin) Drug – Grand Mean)2

Then (Mean (Adderall) Drug – Grand Mean)2

4)Sum

5)Multiply times number Levels_Question (2) X number of Subj Means within Mean (Ritalin) Drug (4)=8

Or number of x’s within Subj Mean (in red) times (2) x’s within Mean (Ritalin) Drug (in blue) (4) = 8

10.375

MeanRitalin

df = number of drug groups (4) – 1 = 3

SSbetween_drug

SSbetween_drug

9

Grand Mean_

DRUG SS

df

MS F

between 79.25 3 26.416 2.4244

within/error 130.7 12 10.895

Between is of interest

Within is the error term

Part 2 – Repeated measures - Question

Within_subjectsIs made up of

Between_groups Interaction Error Term

Control9816

Control61415

Control6314

Control21013

Caffeine71012

Caffeine61311

Caffeine6910

Caffeine289

Adderall15148

Adderall8127

Adderall1266

Adderall8115

Ritalin13114

Ritalin12123

Ritalin862

Ritalin8131

DrugFree Resp

ForcedChoiceSub

SSwithin_subjects - Question

10.5

MeanSub 1

2.5

X - meanSub 1

-2.5

X - meanSub 1

1) Mean within Sub

2) Subtract each x from Mean Sub

3) Square each

4) Sum all

6.25

Squared

6.25

Squared

Sum

df = Number of Levels of Question (1) – 1 X Number of Subjects (16) = (16)

Control9816

Control61415

Control6314

Control21013

Caffeine71012

Caffeine61311

Caffeine6910

Caffeine289

Adderall15148

Adderall8127

Adderall1266

Adderall8115

Ritalin13114

Ritalin12123

Ritalin862

Ritalin8131

DrugFree Resp

ForcedChoiceSub

SSbetween_condition Question

10

MeanForcedChoice

1) Mean within Question

2) Subtract each Mean Question from Grand Mean

3) Square each

4) Sum

5) Multiply times number of x’s within each mean (16)

1

Squared

1

Squared

Sum

8

MeanFreeResp

9

GrandMean

1

Mean ForcedChoiceMinusGrandMean

-1

Mean FreeResp

MinusGrandMean

df = two levels of the factor – 1 = 1

Control9816

Control61415

Control6314

Control21013

Caffeine71012

Caffeine61311

Caffeine6910

Caffeine289

Adderall15148

Adderall8127

Adderall1266

Adderall8115

Ritalin13114

Ritalin12123

Ritalin862

Ritalin8131

DrugFree Resp

ForcedChoiceSub

SSdrug x question = SSdrug_question – SSdrug - SSquestion

10.5

Forced Choice Drug TypeMean

10.25

Free Resp Drug Type

Mean

9

GrandMean

1.5

ForcedChoice Drug Type

Mean- GrandMean

1.25

ForcedChoice Drug Type

Mean- GrandMean

1) Take mean of within each Question (Forced Choice) and within each Drug type (Ritalin)

2) Subtract each mean from Grand Mean

3) Square and sum

4) Multiply times the number of x’s into each mean (4)

That equals SSsub_drug

SSdrug_x_question = SSsub_drug – SSdrug – SSquestion

You already have SSdrug from SSbetween_drug, and SSquestion from SSbetween_question

df = Number of Levels of Question (2) – 1 = 1

Need to find SSdrug_question first

Now you need to figure out MSerror, which is

MSerror = SSwithin_sub – SSbetween_question – SSquestion_x_drug

Since you have all these you just subtract them

Since

Within_subjectsIs made up of

Between_groups Interaction Error Term

df of Between_groups, interaction and error term should add up to equal within_subjects

So df_error = df_within – df_between_groups - interaction

DRUG SS

df

MS F

between 79.25 3 26.416 2.4244

within/error 130.7 12 10.895

Between is of interest

Within is the error term

QUESTION

WithinSub 168 16 10.5

BetweenQ 32 1 32 3.65714

DXQ 31 3 10.33 1.1809

Error 105 12 8.75Error for both Between_question and interaction