the z-transform: introduction why z-transform? 1.many of signals (such as x(n)=u(n), x(n) = (0.5) n...
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![Page 1: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages](https://reader035.vdocuments.mx/reader035/viewer/2022070307/551b339f550346cf5a8b6241/html5/thumbnails/1.jpg)
The z-Transform: Introduction
• Why z-Transform?1. Many of signals (such as x(n)=u(n), x(n) = (0.5)nu(-
n), x(n) = sin(nω) etc. ) do not have a DTFT.2. Advantages like Fourier transform provided:
• Solution process reduces to a simple algebraic procedures• The temporal domain sequence output y(n) = x(n)*h(n) can
be represent as Y(z)= X(z)H(z)• Properties of systems can easily be studied and
characterized in z – domain (such as stability..)
• Topics:– Definition of z –Transform– Properties of z- Transform– Inverse z- Transform
![Page 2: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages](https://reader035.vdocuments.mx/reader035/viewer/2022070307/551b339f550346cf5a8b6241/html5/thumbnails/2.jpg)
Definition of the z-Transform
1. Definition:The z-transform of a discrete-time signal x(n) is defined by
where z = rejw is a complex variable. The values of z for which the sum converges define a region in the z-plane referred to as the region of convergence (ROC).
2. Notationally, if x(n) has a z-transform X(z), we write
3. The z-transform may be viewed as the DTFT or an exponentially weighted sequence. Specifically, note that with z = rejw, X(z) can be looked as the DTFT of the sequence r--nx(n) and ROC is determined by the range of values of r of the following right inequation.
![Page 3: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages](https://reader035.vdocuments.mx/reader035/viewer/2022070307/551b339f550346cf5a8b6241/html5/thumbnails/3.jpg)
ROC & z-plane • Complex z-plane
z = Re(z)+jIm(z) = rejw
• Zeros and poles of X(z)Many signals have z-transforms that are rational function of z:
Factorizing it will give:
The roots of the numerator polynomial, βk,are referred to as the zeros (o) and αk are referred to as poles (x). ROC of X(z) will not contain poles.
![Page 4: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages](https://reader035.vdocuments.mx/reader035/viewer/2022070307/551b339f550346cf5a8b6241/html5/thumbnails/4.jpg)
ROC properties
• ROC is an annulus or disc in the z-plane centred at the origin. i.e.
• A finite-length sequence has a z-transform with a region of convergence that includes the entire z-plane except, possibly, z = 0 and z = . The point z = will be included if x(n) = 0 for n < 0, and the point z = 0 will be included if x(n) = 0 for n > 0.
• A right-sided sequence has a z-transform with a region of convergence that is the exterior of a circle:
ROC: |z|>α• A left-sided sequence has a z-transform with a region of
convergence that is the interior of a circle:ROC: |z|<β
• The Fourier Transform of x(n) converges absolutely if and only if ROC of z-transform includes the unit circle
![Page 5: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages](https://reader035.vdocuments.mx/reader035/viewer/2022070307/551b339f550346cf5a8b6241/html5/thumbnails/5.jpg)
![Page 6: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages](https://reader035.vdocuments.mx/reader035/viewer/2022070307/551b339f550346cf5a8b6241/html5/thumbnails/6.jpg)
![Page 7: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages](https://reader035.vdocuments.mx/reader035/viewer/2022070307/551b339f550346cf5a8b6241/html5/thumbnails/7.jpg)
![Page 8: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages](https://reader035.vdocuments.mx/reader035/viewer/2022070307/551b339f550346cf5a8b6241/html5/thumbnails/8.jpg)
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![Page 10: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages](https://reader035.vdocuments.mx/reader035/viewer/2022070307/551b339f550346cf5a8b6241/html5/thumbnails/10.jpg)
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Properties of Z-Transform • Linearity
If x(n) has a z-transform X(z) with a region of convergence Rx, and if y(n) has a z-transform Y(z) with a region of convergence Ry,
and the ROC of W(z) will include the intersection of Rx and Ry, that is, Rw contains .
• Shifting propertyIf x(n) has a z-transform X(z),
• Time reversalIf x(n) has a z-transform X(z) with a region of convergence Rx that is the annulus , the z-transform of the time-reversed sequence x(-n) is and has a region of convergence , which is denoted by
)()()()()()( zbYzaXzWnbynaxnw Z
yx RR
)()( 00 zXznnx nZ
z
)()( 1 zXnx Z
11 z xR1
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Properties of Z-Transform• Multiplication by an exponential
– If a sequence x(n) is multiplied by a complex exponential αn.
• Convolution theormIf x(n) has a z-transform X(z) with a region of convergence Rx, and if h(n) has a z-transform H(z) with a region of convergence Rh,
The ROC of Y(z) will include the intersection of Rx and Rh, that is, Ry contains Rx ∩ Rh .
With x(n), y(n), and h(n) denoting the input, output, and unit-sample response, respectively, and X(z), Y(x), and H(z) their z-transforms. The z-transform of the unit-sample response is often referred to as the system function.
• ConjugationIf X(z) is the z-transform of x(n), the z-transform of the complex conjugate of x(n) is
)()( 1zXnx Zn
)()()()()()( zHzXzYnhnxny Z
)()( zXnx Z
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Properties of Z-Transform
• Derivative– If X(z) is the z-transform of x(n), the z-
transform of is
• Initial value theoremIf X(z) is the z-transform of x(n) and x(n) is equal to zero for n<0, the initial value, x(0), maybe be found from X(z) as follows:
dz
zdXznnx Z )(
)(
)(lim)0( zXxz
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