the sine and cosine rule

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    Powerpoint hosted on www.worldofteaching.comPlease visit for 100s more free powerpoints

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    A

    CB

    c b

    a

    The sine rules enables us to calculate sides and angles

    In the some triangles where there is not a right angle.

    ((

    The Sine Rule is used to solve any problems involvingtriangles when at least either of the following isknown:

    a) two angles and a side

    b) two sides and an angle opposite a given side

    In Triangle ABC, we use the convention that

    a is the side opposite angle A

    b is the side opposite angle B

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    Example 2 (Given two sides and an included angle)

    Solve triangleABCin which A = 55, b = 2.4cm and

    c= 2.9cm

    By cosine rule,

    a2 = 2.42+ 2.92- 2 x 2.9 x 2.4 cos 55

    = 6.1858

    a=

    2.49cm

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    EitherC

    c

    B

    b

    A

    a

    sinsinsin!!

    Or

    c

    C

    b

    B

    a

    A sinsinsin!!

    [1]

    [2]

    Use [1] when finding a side

    Use [2] when finding an angle

    Using this label of a triangle,

    the sine rule can be stated

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    Example:A

    CB

    c

    Given

    Angle ABC =600

    Angle ACB = 500

    Find c.

    7cm

    To find c use the following proportion:

    B

    b

    C

    c

    sinsin!

    0060sin

    7

    50sin!

    c

    0

    0

    60sin

    50sin7 xc !

    c= 6.19 ( 3 S.F)

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    A

    C

    B

    15 cm

    6 cm

    1200

    BFind

    012015

    ,6

    !!

    !(

    AandcmBC

    cmACBACIn

    SOLUTION:

    a

    A

    b

    B sinsin!

    15

    120sin

    6

    sin0

    !B

    15

    60sin6sin

    0x

    B !

    sin B = 0.346

    B= 20.30

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    SOLVE THE FOLLOWING USING THESINE RULE:

    Problem 1 (Given two angles and a side)

    In triangleABC, A = 59, B = 39 and a = 6.73cm.

    Find angle C, sides b and c.

    DRILL:

    Problem 2 (Given two sides and an acute angle)

    In triangleABC, A = 55, b = 16.3cm and

    a = 14.3cm. Find angle B, angle C and side c.

    Problem 3 (Given two sides and an obtuse angle)

    In triangleABC A =100, b = 5cm and a = 7.7cm

    Find the unknown angles and side.

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    C= 180 - (39 + 59)= 82

    Answer Problem 1

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    Bsin

    3.16

    55sin

    3.140!

    3.14

    55sin3.16sin

    0

    !B

    = 0.9337

    00.69!B

    0005569180 !C

    056!

    0056sin69sin

    3.16 c!

    0

    0

    69sin

    56sin3.16!c

    = 14.5 cm (3 SF)

    ANSWER PROBLEM 2

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    Answer Problem 3

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    Sometimes the sine rule is not enough to help us

    solve for a non-right angled triangle.

    For example:C

    B

    A

    a14

    18 300

    In the triangle shown, we do not have enough information

    to use the sine rule. That is, the sine rule only provided the

    Following:

    CBa

    sin18

    sin14

    30sin0

    !!

    Where there are too many unknowns.

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    For this reason we derive another useful result, known as the

    COSINE RULE. The Cosine Rule maybe used when:

    a. Two sides and an included angle are given.

    b. Three sides are given

    B

    C

    A

    a

    b

    c

    C

    B

    A

    a c

    The cosine Rule: To find the length of a sidea2 =b2+ c2 - 2bccosA

    b2 =a2 + c2 - 2accosB

    c2 =a2 + b2 - 2ab cosC

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    THE COSINE RULE:To find an angle when given all three

    sides.

    bc

    acbA

    2cos

    222

    !

    ac

    bca

    B 2cos

    222

    !

    ab

    cba

    C 2cos

    222

    !

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    Example 1 (Given three sides)

    In triangleABC, a = 4cm, b = 5cm andc= 7cm. Find the size of thelargestangle. The largest angle is the onefacing the longest side, which is angleC.

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    DRILL:

    ANSWER

    PAGE203#S 1-10

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