the relationship between concentration and time can be derived from the rate law and calculus...
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• The relationship between concentration and time can be derived from the rate law and calculus
• Integration of the rate laws gives the integrated rate laws
• Integrate laws give concentration as a function of time
• Integrated laws can get very complicated, so only a few simple forms will be considered
• First order reactions– Rate law is: rate = k [A]– The integrate rate law can be expressed as:
• [A]0 is [A] at t (time) = 0
• [A]t is [A] at t = t
• e = base of natural logarithms = 2.71828…
kt
t
eAAktA
A 0t0 ][][or
][
][ln
• Graphical methods can be used to determine the first-order rate constant, note
bmxy
AktA
ktAA
ktAA
ktA
A
t
t
t
t
]ln[]ln[
]ln[]ln[
]ln[]ln[
][
][ln
0
0
0
0
• A plot of ln[A]t versus t gives a straight line with a slope of -k
The decomposition of N2O5. (a) A graph of concentration versus time for the decomposition at 45oC. (b) A straight line is obtained from a logarithm versus time plot. The slope is negative the rate constant.
• The simplest second-order rate law has the form
• The integrated form of this equation is
2][ rate Bk
tBB
BB
ktBB
t
t
at time ofion concentrat the][
ofion concentrat initial the][
][
1
][
1
0
0
• Graphical methods can also be applied to second-order reactions
• A plot of 1/[B]t versus t gives a straight line with a slope of k
Second-order kinetics. A plot of 1/[HI] versus time (using the data in Table 15.1).
• The amount of time required for half of a reactant to disappear is called the half-life, t1/2
– The half-life of a first-order reaction is not affected by the initial concentration
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A
A
AAtt
ktA
A
t
t
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1][ ,at
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First-order radioactive decay of iodine-131. The initial concentration is represented by [I]0.
– The half-life of a second-order reactions does depend on the initial concentration
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t
• One of the simplest models to explain reactions rates is collision theory
• According to collision theory, the rate of reaction is proportional to the effective number of collisions per second among the reacting molecules
• An effective collision is one that actually gives product molecules
• The number of all types of collisions increase with concentration, including effective collisions
• There are a number of reasons why only a small fraction of all the collisions leads to the formation of product:– Only a small fraction of the collisions are
energetic enough to lead to products– Molecular orientation is important because a
collision on the “wrong side” of a reacting species cannot produce any product
• This becomes more important as the complexity of the reactants increases
The key step in the decomposition of NO2Cl to NO2 and Cl2 is the collision of a Cl atom with a NO2Cl molecules. (a) A poorly orientated collision. (b) An effectively orientated collision.
– The minimum energy kinetic energy the colliding particles must have is called the activation energy, Ea
– In a successful collision, the activation energy changes to potential energy as the bonds rearrange to for products
– Activation energies can be large, so only a small fraction of the well-orientated, colliding molecules have it
– Temperature increases increase the average kinetic energy of the reacting particles
Kinetic energy distribution for a reaction at two different temperatures. At the higher temperature, a larger fraction of the collisions have sufficient energy for reaction to occur. The shaded area under the curves represent the reacting fraction of the collisions.
• Transition state theory explains what happens when reactant particles come together
• Potential-energy diagrams are used to help visualize the relationship between the activation energy and the development of total potential energy
• The potential energy is plotted against reaction coordinate or reaction progress
The potential-energy diagram for an exothermic reaction. The extent of reaction is represented as the reaction coordinate.
A successful (a) and unsuccessful (b) collision for an exothermic reaction.
• Activation energies and heats of reactions can be determined from potential-energy diagrams
Potential-energy diagram for an endothermic reaction. The heat of reaction and activation energy are labeled.
• Reactions generally have different activation energies in the forward and reverse direction
Activation energy barrier for the forward and reverse reactions.
• The brief moment during a successful collision that the reactant bonds are partially broken and the product bonds are partially formed is called the transition state
• The potential energy of the transition state is a maximum of the potential-energy diagram
• The unstable chemical species that “exists” momentarily is called the activated complex
Formation of the activated complex in the reaction between NO2Cl and Cl. NO2Cl+ClNO2+Cl2
• The activation energy is related to the rate constant by the Arrhenius equation
k = rate constant
Ea = activation energye = base of the natural logarithmR = gas constant = 8.314 J mol-1 K-1
T = Kelvin temperatureA = frequency factor or pre-exponential factor
RTEaAek /
• The Arrhenius equation can be put in standard slope-intercept form by taking the natural logarithm
• A plot of ln k versus (1/T) gives a straight line with slope = -Ea/RT
xmby
TREAk
RTEAk
a
a
)/1()/(lnln
or /lnln
• The activation energy can be related to the rate constant at two temperatures
• The reaction’s mechanism is the series of simple reactions called elementary processes
• The rate law of an elementary process can be written from its chemical equation
121
2 11ln
TTR
E
k
k a
• The overall rate law determined for the mechanism must agree with the observed rate law
• The exponents in the rate law for an elementary process are equal to the coefficients of the reactants in chemical equation
22
32
]k[NO rate
NONO2NO
:process Elementary
• Multistep reactions are common
• The sum of the element processes must give the overall reaction
• The slow set in a multistep reaction limits how fast the final products can form and is called the rate-determining or rate-limiting step
• Simultaneous collisions between three or more particles is extremely rate
• A reaction that depended a three-body collision would be extremely slow
• Thus, reaction mechanism seldom include elementary process that involve more than two-body or bimolecular collisions
• Consider the reaction
• The mechanism is thought to be
tal)(experimen ][Hk[NO]rate
O2HN2H2NO
22
222
• The second step is the rate-limiting step, which gives
• N2O2 is a reactive intermediate, and can be eliminated from the expression
(fast) OH N H ON
(slow) OH ONHON
(fast) ON 2NO
2222
22222
22
]][HON[ rate 222k
• The first step is a fast equilibrium
• At equilibrium, the rate of the forward and reverse reaction are equal
222
222
22
2
NO][]ON[
or ]ON[NO][
thus]ON[se)rate(rever
NO][rd)rate(forwa
r
f
rf
r
f
k
k
kk
k
k
• Substituting, the rate law becomes
• Which is consistent with the experimental rate law
]H[NO]['rate
or ]H[NO][rate
]H[]ON[rate
22
22
222
k
k
kk
k
r
f
• A catalyst is a substance that changes the rate of a chemical reaction without itself being used up– Positive catalysts speed up reactions– Negative catalysts or inhibitors slow reactions
• (Positive) catalysts speed reactions by allowing the rate-limiting step to proceed with a lower activation energy
• Thus a larger fraction of the collisions are effective
(a) The catalyst provides an alternate, low-energy path from the reactants to the products. (b) A larger fraction of molecules have sufficient energy to react when the catalyzed path is available.
• Catalysts can be divided into two groups– Homogeneous catalysts exist in the same phase
as the reactants– Heterogeneous catalysts exist in a separate
phase
• NO2 is a homogeneous catalyst for the production of sulfuric acid in the lead chamber process
• The mechanism is:
• The second step is slow, but is catalyzed by NO2:
4223
322
12
22
SOHOHSO
SOOSO
SOOS
222
1
322
NOONO
SONOSONO
• Heterogeneous catalysts are typically solids
• Consider the synthesis of ammonia from hydrogen and nitrogen by the Haber process
• The reaction takes place on the surface of an iron catalyst that contains traces of aluminum and potassium oxides
• The hydrogen and nitrogen binds to the catalyst lowering the activation energy
322 2NHN3H
The Haber process. Catalytic formation of ammonia molecules from hydrogen and nitrogen on the surface of a catalyst.