the mathematics of the mayan

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THE MATHEMATICS OF THE MAYAN M. Alejandra Sorto & Aaron Wilson SMMG University of Texas Austin March 31, 2012

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The Mathematics of the Mayan. M. Alejandra Sorto & Aaron Wilson SMMG University of Texas Austin March 31, 2012. Mayan Numerical System. Base-10 and Base-20 Counting. Base-10. Base-20. 1s = 0-9 10s = 10 100s = 10x10 1000s = 10x10x10 2012= (2x1000) (0x100) (1x10) (2x1). 1s = 0-19 - PowerPoint PPT Presentation

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Page 1: The Mathematics of the Mayan

THE MATHEMATICS OF THE MAYANM. Alejandra Sorto & Aaron Wilson

SMMG University of Texas

Austin March 31, 2012

Page 2: The Mathematics of the Mayan

MAYAN NUMERICAL SYSTEM

Page 3: The Mathematics of the Mayan

BASE-10 AND BASE-20 COUNTING

Base-10

1s = 0-9 10s = 10 100s = 10x10 1000s = 10x10x10 2012= (2x1000) (0x100) (1x10) (2x1)

Base-20

1s = 0-19 20s = 20 400s = 20x20 8000s = 20x20x20 2012= (0x8000) (5x400) (0x20) (12x1)

Page 4: The Mathematics of the Mayan

THE MAYAN CALENDARS

Page 5: The Mathematics of the Mayan

THE RITUAL CALENDAR OR TZOLKIN

Cycle of 20 days in combination with…

Cycle of 13 months to form…

260 uniquely named days of the year

Page 6: The Mathematics of the Mayan

THE SOLAR CALENDAR OR HAAB

18 “months” each with…

20 days (0 - 19) to form…

A cycle of 360 days, plus 5 (0-4) additional days

Page 7: The Mathematics of the Mayan

1 1

22

3

4

3

45

How many turns of each wheel does it take before you’re back to the starting position- with the same tooth 1 and space 1 meshing together again?

Page 8: The Mathematics of the Mayan

You found that five turns of the 4-gear (five groups of 4) will bring you the same place as four turns of the 5-gear (four groups of 5). So if the gears represent two different calendars, we can say that there is a 20-day cycle in the system using both calendars. Once every 20 days, it will be New Year’s Day on both calendars4 x 5 = 205 x 4 = 20

Page 9: The Mathematics of the Mayan

What about the two Mayan calendars, with 365 and 260 days? Will it take 94,900 days (365 x 260) for the two New Year’s Day to happen together again? That’s only once every 260 astronomical years!

Page 10: The Mathematics of the Mayan

How many turns of each wheel does it take before you’re back to the starting position- with the same tooth 1 and space 1 meshing together again?

1 1

2 3

4

56

2

34

Page 11: The Mathematics of the Mayan

You found that tooth 1 and space 1 line up again after only two turns of the 6-gear and three turns of the 4-gear.

Why is this so?

Page 12: The Mathematics of the Mayan

THIS CORRESPONDS TO THE MATHEMATICAL IDEA OF THE LEAST COMMON MULTIPLE (LCM)

Source: “The Mayan Calendar Round Keeping Time” by Bazin and Tamez.

Page 13: The Mathematics of the Mayan

WHEN WOULD THE TWO MAYAN CALENDAR COINCIDE?

Page 14: The Mathematics of the Mayan

THE CYCLE OF 18,980 DAYS – A CALENDAR ROUND

The combination of both calendars create a major cycle of 18,980 days (the LCM of 260 and 365: 5 x 52 x 73)

They will come together again after 52 astronomical years of 365 days each. The 52-year cycle is called “Calendar Round”

Page 15: The Mathematics of the Mayan

COUNTING FOR A LONG, LONG TIME“LONG COUNT” CALENDAR

Tun: 360-day “year” Katun: A period of 20 tuns (7, 200 days) Baktun: A period of 20 katuns (144, 000

days)

“Great Cycle” of the Long Count: A period of 13 baktuns = 5, 200 years long (in 360-day years).

The Great Cycle will be completed on December 21, 2012