the gas laws. boyle’s law: pressure and volume if the temperature is constant, as the pressure of...
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![Page 1: The Gas Laws. Boyle’s Law: Pressure and Volume If the temperature is constant, as the pressure of a gas increases, the volume decreases. In turn, as the](https://reader033.vdocuments.mx/reader033/viewer/2022061515/56649c7b5503460f9492ebb4/html5/thumbnails/1.jpg)
The Gas Laws
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Boyle’s Law: Pressure and Volume
• If the temperature is constant, as the pressure of a gas increases, the volume decreases.
• In turn, as the pressure decreases, the volume increases.
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Boyle’s Law: Pressure and Volume
• Boyle’s law states that for a given mass of gas at constant temperature, the volume of the gas varies inversely with pressure.
• P1 x V1 = P2 x V2
• P = pressure• V = volume
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Using Boyle’s Law
• A balloon contains 30L of helium gas at 103 kPa. What is the volume of the helium when the balloon rises to an altitude where the pressure is only 25 kPa?
• Step 1: use Boyle’s law: P1 x V1 = P2 x V2
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Using Boyle’s Law
• Step 2: set up equation to solve for V2
o V2 = (V1 x P1) / P2
• Step 3: plug and chugo V2 = (30L x 103 kPa) / 25 kPao V2 = 124 L
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Using Boyle’s Law Practice
• 1. Nitrous oxide (N2O) is used as an anesthetic. The pressure on 2.5 L of N2O changes from 105 kPa to 40.5 kPa. If the temperature does not change, what will the new volume be?
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Using Boyle’s Law Practice
• 2. A gas with a volume of 4 L at a pressure of 205 kPa is allowed to expand to a volume of 12 L. What is the pressure in the container if the temperature remains constant?
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Charles’s Law: Temperature and Volume
• As the temperature of an enclosed gas increases, the volume increases, if the pressure is constant.
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Charles’s Law: Temperature and Volume
• Charles’s law states that the volume of a fixed mass of gas is directly proportional to its Kelvin temperature if the pressure is kept constant.
• V1/T1 = V2/T2
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Using Charles’s Law
• A balloon inflated in a room at 24 °C has a volume of 4 L. The balloon is then heated to a temperature of 58 °C. What is the new volume if the pressure remains constant?
• Step 1: Turn Celsius into Kelvin K = C + 273o 24 + 273 = 297 K for T1o 58 + 273 = 331 K for T2
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Using Charles’s Law
• Step 2: rearrange Charles’s law to isolate V2o V2 = (V1 x T2) / T1
o Step 3: plug and chugo V2 = (4L x 331K) / 297K = 4.46 L
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Using Charles’s Law Practice
• 3. If a sample of gas occupies 6.8 L at 325°C, what will its volume be at 25°C if the pressure does not change?
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Using Charles’s Law Practice
• 4. Exactly 5L of air at -50 °C is warmed to 100 °C. What is the new volume if the pressure remains constant?
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Gay-Lussac’s Law: Pressure and Temperature
• As the temperature of an enclosed gas increases, the pressure increases, if the volume is constant.
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Gay-Lussac’s Law: Pressure and Temperature
• Gay-Lussac’s law states that the pressure of a gas is directly proportional to the Kelvin temperature if the volume remains constant.
• P1/T1 = P2/T2
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Using Gay-Lussac’s Law
• The gas in a used aerosol can is at a pressure of 103kPac at 25°C. If the can is thrown onto a fire, what will the pressure be when the temperature reaches 928°C?
• Step 1: turn celsius into kelvino 25 + 273 = 298 Ko 928 + 273 = 1201 K
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Using Gay-Lussac’s Law
• Step 2: Use Gay-Lussac’s law and isolate P2o P2 = (P1 x T2) / T1
o Step 3: Plug and chugo P2 = (103 kPa x 1201 K) / 298 K = 415 kPa
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Using Gay-Lussac’s Law Practice
• 5. The pressure in a car tire is 198 kPa at 27°C. After a long drive, the pressure is 225 kPa. What is the temperature of the air in the tire?
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Using Gay-Lussac’s Law Practice
• 6. a sample of nitrogen gas has a pressure of 6.58 kPa at 539 K. If the volume does not change, what will the pressure be at 211 K?
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The Combined Gas Law
• The combined gas law describes the relationship among the pressure, temperature, and volume of an enclosed gas.
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The Combined Gas Law
• The combined gas law allows you to do calculations for situations in which only the amount of gas is constant.
• P1 x (V1/T1) = P2 x (V2/T2)
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Using The Combined Gas Law
• The volume of a gas filled balloon is 30L at 313 K and 153 kPa pressure. What would the volume be at standard temperature and pressure (STP)?
• Step 1: Realize that T2 = 273K and P2 = 101.3 kPa because they are at STP.
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Using The Combined Gas Law
• Step 2: Rearrange the combined gas law to isolate V2:o V2 = (V1 x P1 x T2) / (P2 x T1)
• Step 3: Plug and Chugo V2 = (30L x 153kPa x 273K) / (101.3kPa x 313K)o V2 = 39.5 L
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Combined Gas Law Practice
• 7. A gas at 155 kPa and 25°C has an initial volume of 1L. The pressure of the gas increases to 605 kPa as the temperature is raised to 125°C. What is the new volume?
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Combined Gas Law Practice
• 8. A 5L air sample has a pressure of 107kPa at a temperature of 250°C. If the temperature is raised to 102°C and the volume expands to 7L, what will the new pressure be?