the gas laws

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Pressure Volume & Temperature

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The Gas Laws. Pressure Volume & Temperature. States of Matter. In liquids and solids, the primary particles (atoms or molecules) are always in contact with each other. In gases, particles move independently. - PowerPoint PPT Presentation

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Page 1: The  Gas  Laws

Pressure Volume & Temperatu

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Page 2: The  Gas  Laws

In liquids and solids, the primary particles

(atoms or molecules) are always

in contact with each other.

In gases, particles move independently.

Because the atoms of gases are far apart

they are very compressible.

Page 3: The  Gas  Laws

When pressure is applied, the volume

occupied by a gas can be decreased.

Gases fill all of the space available to them.

In a contained sample (e.g. balloon) gases expand to fill the total volume of the balloon.

If not contained:

Gases expand indefinitely.

Page 4: The  Gas  Laws

If the cubic meter were divided into 1000 equal smaller parts, each part would be equal

to 1 Liter (slightly larger than a quart)

1 qt = 1.057 L

If each liter were divided into 1000 equal

smaller parts, each part would be equal to

1 milliliter (mL) or 1 cubic centimeter (cc)   1 mL = 1 cc 

Page 5: The  Gas  Laws

Space occupied in 3 dimensions.

Units: liters

One liter is similar in volume to a quart

1 qt = 1.057 L

One liter is equal to 1,000 cubic centimeters

Page 6: The  Gas  Laws

Force per unit of area.

Force / area  =  lbs / sq.in  

Pounds per square inch =  psi 14.7 psi = 1 atm

1 mm Hg = 1 torr 1 atm = 760 mm Hg

Page 7: The  Gas  Laws

Increase the pressure

Volume decreases proportionally  

Pressure x Volume = constant

Product of pressure and volume is fixed.

P x V = constant 

P1 x V1 = P2 x V2

Page 8: The  Gas  Laws

Compressed gas cylinder

Pressure = 135 atm

Volume = 15.0 liters

What volume the gas will occupy at 1.00 atm ?

P1 = 135 atm

V1 = 15.0 L

P2 = 1.00 atm

Page 9: The  Gas  Laws

Determine V2

P1 x V1 = P2 x V2

V2 = ( P1 x V1 ) / P2

V2 = ( 135 atm ) ( 15.0 L ) / 1.00 atm

= 2,030 liters

Page 10: The  Gas  Laws

Increase the temperature

Volume will increase proportionally.

The volume of a sample divided by the

temperature is equal to a constant.

V / T

= constant

V1 / T1 = V2 / T2

Page 11: The  Gas  Laws

Determine the final volume of a

0.35 liter balloon which is heated from

room temperature to 100 degrees C.

V1 / T1 = V2 / T2

Convert all temperatures to Kelvins.

T1 = 25 °C + 273 = 298 K

T2 = 100 °C + 273 = 373 K

Page 12: The  Gas  Laws

V1 / T1 = V2 / T2

V2 = ( V1 x T2 ) / T1

= V1 x ( T2 / T1 )

= ( 0.35 L ) ( 373 K / 298 K)

= ( 0.35 ) ( 1.25)

= 0.44 liters

Page 13: The  Gas  Laws

Pressure is proportional to the temperature

The ratio of the absolute temperature

to the pressure is always constant.

P1 / T1 = P2 / T2  

Page 14: The  Gas  Laws

The pressure inside a compressed gas cylinder is 134 atm @ 25 °C. Calculate the new pressure inside the cylinder if it is heated to 48 °C.

P1 = 134 atm

T1 = 25 + 273 = 298 K

  T2 = 48 + 273 = 321 K

 

Determine P2

Page 15: The  Gas  Laws

P1 / T1 = P2 / T2

 

P2 = ( P1 x T2 ) / T1

P2 = ( 134 atm ) ( 321 K ) / 298 K

= 144 atm

Page 16: The  Gas  Laws

The pressure of CO2 inside a bottle of carbonated soda pop is approximately 1.35 atm @ 25 °C (298 K).

Determine the pressure inside the bottle if it is chilled to 0 °C (273 K) .

 

Page 17: The  Gas  Laws

P1 / T1 = P2 / T2

 

P2 = ( P1 x T2 ) / T1

 P2 = (

1.34 atm ) ( 273 K ) / 298 K

= 1.23 atm

Page 18: The  Gas  Laws

We can combine all of these laws

to get a combined gas law:

P V / T = constant

P1 x V1 / T1 = P2 x V2 / T2

This law holds for a fixed amount of gas (or a fixed number

of moles, n ).

Page 19: The  Gas  Laws

Start with 2.37 liters of gas

@ 25.0 °C ( 298 K ) and 1 atmosphere

Heat it to 297 °C ( 570 K ).

Increase the pressure to 10 atmospheres.

What is the final volume?

*Note: Upon heating, volume will increase.

But on compression, volume will decrease.

Opposing forces

Page 20: The  Gas  Laws

P1 x V1 / T1 = P2 x V2 / T2

Solve for V2 (isolate the variable):  V2

= [ P1 x V1 / T1 ] x ( T2 / P2 )

Express as a product of ratios: V2

= V1 x [ P1 / P2 ] x [ T2 / T1 ]

Page 21: The  Gas  Laws

P1 / P2 = 1 / 10 

T2 / T1 = 570 / 298 

V2 = ( 2.37 ) ( 1 / 10 ) ( 570 / 298)

V2 = ( 2.37 ) ( 0.19 ) = 0.453 L

*Note: Ratio of pressures = 0.10 < 1

Ratio of temps = 1.91 > 1

They offset each other.

Page 22: The  Gas  Laws

P V = n R T

n = # of moles of gas

R = 0.0821 liter * atm / mol * K

PV / nT = constant

( P1 x V1 ) / ( n1 x T1 )

= ( P2 x V2 ) / ( n2 x T2 )

Page 23: The  Gas  Laws

Calculate the volume of 1 mole of Ideal gas

@ Room temp (298 K) and pressure (1 atm).

P V = n R T

V = n R T / PV

= ( 1.0 ) ( 0.0821 ) ( 273 ) / 1.0

= 22.4 L

Page 24: The  Gas  Laws

11.2 L tank of gas is found in the coldest

part of the refrigerator (0 °C = 273 K).  

It contains 4

moles of gas: (1 mole of oxygen and

3 moles of neon).

 What is the pressure in the tank?

P = nRT / V =

= ( 4.0 )( 0.0812 ) ( 273 ) / 11.2

= 7.91 atm