tensors.ppt
TRANSCRIPT
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Tensors
References:
P. Chadwick, Contiuum Mechanics, Dover Publications, 1976.
M. E. Gurtin, An Introduction to Continuum Mechanics,
Academic Press, 1981.
Acknowledgements:
H. Garmestani, Georgia Tech
A. Rollett, CMU
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Mappings Sets: Collection of Objects.
Elements: Constituents of a Set.
Mapping (or Transformation):
fmaps D in C
Domain of f: Set D
Codomain of f: Set C
Range of f:
Range is a subset of codomain: rangefmaps D onto C: range
One-to-one mapping:
a e
cbaA ,,
CDf :
})({ Dxxff Cf
Cf
2121 )()( xxxfxf
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Tensors
Tensors: mathematical representation ofphysical entities or phenomena (e.g. Stress,
Strain, Elastic Stiffness)
Tensors of different rank are used to
represent different types of physicalquantities
Tensors of a given rank have certain
common properties and follow certain rules(e.g. coordinate transformation laws)
Tensors are not simply setsor matrices
Tensors do not require definition of acoordinate system
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Scalars: Tensors of Rank Zero
Scalars may be specified completely by
a single number (e.g. density,
temperature, energy)
Scalars are not constants, but may
actually be functions of position and/ortime.
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Points: Rank One Tensors
a
b
cd
ef
g
Euclidean Point Space E
Set of all points in three
dimensional space
Labeling of the points does not
require a coordinate frame!
Operations on points are not
meaningful
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Vectors: Rank One Tensors
Defined as difference for a
given ordered pair (a,b): v=
ba
Euclidean Vector Space V
Still no need of a reference
frame!
a
b
cd
ef
g
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Operations on Vectors:
Dot Product
vu u
v
cosvuvu
uuu Magnitude or Norm
V
vuvuuv , ,,,)( Vwvuwvwuwvu
V uuu 0 0uuu if f0No need for a reference frame yet!
0
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Operations on Vectors:
Dot Product
1nUnit Vector:
Orthogonal Vectors: 0 vuSeveral physical quantities possess thecharacteristics described here for Vectors;therefore they are all classified as Rank OneTensors.
e.g. Force, Displacement, Velocity
These quantities require not only an assignmentof magnitude, but also a specification of direction.
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Coordinate Frames
Right-handed, orthogonal, Cartesian Coordinate system.
Set of orthonormal basis vectors
}{},,{ 321 ieeee
Origin oijji
jiif
jiif
0
1 ee
Kronecker delta ij
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Coordinate Frames
v
iiivevComponents of a vector v:
ve iiv
ii
ii vu evuw Adding Vectors (parallelogram law):
uIndicial Notation:
iii vuw
2/1
iiuu
uuu
Einsteins Summation
Convention
iivu vu
w
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Coordinate Transformation
Matrices: 2-D
Or, inverting
The graph above represents a transformation of coordinates when the system is
rotated at an angle CCW
y
x
y
xor
yxy
yxx
cossin
sincos
sincos
sincos
y
x
y
xor
yxy
yxx
cossin
sincos
cossin
sincos
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Coordinate Transformation
Matrices: 3-D
}{},,{ 321 ieeee First Frame:
}{},,{ 321 ieeee Second Frame:
iiii vv eev
jijijiijii vvvv eeee
ijiijij vQvv ee
jiijQvQv ee
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Coordinate Transformation
Matrices: 3-D
ijjkikkljlikljlkikji QQQQQQ eeee
Six
equations Three independent parameters in [Q]
ITQQ TQQ 1
1det Q
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Coordinate Transformations:
Euler Angles
A sequence of three rotations (called Euler
angles) are needed to completely specify a
arbitrary transformation.
e1 e2
e3
e1
e
2
e3
Rotation 1: Angle f1about e3so
that the new orientation of e1is
perpendicular to e3.
Rotation 2: Angle Fabout the newe1so that the new orientation of e3is
parallel to e3.
Rotation 3: Angle f2about e3to
bring the two frames in coincidence.
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Bunge Euler Angles
g {1,f,2}
(0 1 2, 0 f , 02 2)
(1))2()3( elj
ekl
eik
eij RRRR
fff
ffffff
cossincossinsin
cossincoscoscossinsincoscossinsincossinsinsincoscoscossinsincossincoscos
11
221212121
221212121e
ijR
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Invariants
kklkkllkiliklilkikii uuuuuuQQuQuQuu
All tensorial quantities possess certain
measures that are independent of the choice of
the coordinate reference frame. For example,
rank one tensors (or vectors) have one
invariant norm or magnitude of the vector.
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Vector (cross) Product
vuw
u
vsinvuw
V vuuvvu ,
0
w
V wvuwvwuwvu ,,)()()(
V vuvuu ,0)(
V vuvuvvuuvuvu ,)())(()()( 2
w is perpendicular to uand v
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Vector (cross) Product
,,, 213132321 eeeeeeeee
kijkji eee
Permutation symbol ijk
).,.(
),3,2,1(),,(0
1.,.
:)3,2,1(),,(1
)1.,.(
:),3,2,1(),,(1
213321132
312231123
sametheareindicestwoanyifei
ofnpermutatioanotiskjiif
ei
ofnpermutatiooddaniskjiif
ei
ofnpermutatioevenaniskjiif
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Vector (cross) Product
jijijjii
vuvu eeeevu
kijkjivu evu
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Dyadic (Outer) Product
Rank Two Tensor:
jji cba )()( cbacba
ijnjmmnijnmmnijiij WWWW eeeeeeWee
332313
322212
312111
321
3
2
1
bababa
bababa
bababa
bbb
a
a
a
W
)( baW jiij baW
jiijjijijjii Wbaba eeeeeeW
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Rank Two Tensors: Coordinate
Transformations
srijsjrissjrriij
jijisrrsjiij
TQQQQT
QTT
eeee
eeeeeeT
)()(
]][][[][ Tijsjrirs QTQTTQQT
ororder tensn
ororder tensthird
ororder tenssecond
vector
scalar
th
......
nnmnrkrjnimijk
mnrkrjnimijk
mnjnimij
mimi
TQQQT
TQQQT
TQQT
aQa
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Tensor (Inner) Products
3
2
1
333231
232221
131211
3
2
1
a
a
a
TTT
TTT
TTT
b
b
b
bTa
ijijijkkijikjkijkkjiij
aTaTaT
aT
eeeee
eeeTa
ijij baT
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Tensor (Inner) Products
kjkij aSTSaTaTS
STTS
3
2
1
333231
232221
131211
333231
232221
131211
a
a
a
SSS
SSS
SSS
TTT
TTT
TTT
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Rank Two Tensors
Unit (spherical) Tensor or Identity Tensor:
iijiij eeeeI
Isotropic Tensor = iijiij CC eeee
SSSSSSSISS
00A0vAIAvIv
321
0
Transpose of a Tensor:iijjijij
T vSuvuS vSuvSu
SSSTSTTSTS TTTTTTTT
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Rank Two Tensors
Symmetric Tensor:
Tij= Tji T= TT
Skew-symmetric or Antisymmetric:
Wij= -Wji W= -WT
Decomposition of a general tensor: WSL
TT LLWLLS 2
1
2
1
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A linear transformation, from rank one tensor spaceV
into itself defines a rank two tensor
Tensors as Transformations
(Mappings)
cTb
TaaT
TbTab)T(a
)(
RV ,)( ba,TbTabaT
Mapping:
Linear Mapping:
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Tensors
Yestensor?aisthen,3If TaTa
TaaTaaTaaaaT
TbTab)T(abaTbTa
babab)T(a
)(3)3(3)(3)(
33
33)(3
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Tensors
Notensor?aisthen,23If 1 TeaTa
TbTab)T(a
ebeaTbTa
ebaebab)T(a
11
11
2323
2332)(3
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Tensors as MappingsExamples
TQR ][100
0cossin
0sincos
Transform vectors by a right-hand
rotation about the e3axis by an angle .
= 90
33
212
211
cossin
sincos
ab
aab
aab
33
12
21
ab
ab
ab
100
001
010
R
e1
e2
ab
V abRa
e1
e2
ab
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Q: Let Rcorrespond to a 90right-handrigid body rotation about the x3axis.
Find the rotation tensor R.
Tensor (Inner) Products
Q: Let Scorrespond to a 90right-
hand rigid body rotation about the x1
axis. Find the rotation tensor S.
Q: Let Wcorrespond to a 90right-
hand rigid body rotation about thex3axis, then a 90right-hand rigid
body rotation about the x1axis. Find
the rotation tensor W
SRW
S
R
010
100001
100
001010
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Tensor (Inner) Products
TS
ijijSS SSSMagnitude or Norm:
STTS WTWSWTS )(
0SS 0SSS if f0
jiji dcba ))(()( dbcadcba
ijijjlikklijljkiklijlkkljiij
TSTSeeeeTS
eeTeeS
TS
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Trace of a Tensor
baba )(tr
)(
)(
)()()(
332211
T
iiijijjiij
jiijjiij
Ttr
TTT
TTT
trTTtrtr
ee
eeeeT
)( TSTS Ttr )(TTI tr
TT
TT
AWAWWW
ASASSS
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Tensors
SRTTR)(SSTR TT
vuSSvu
321det kjiijk SSSS
11 detdetdetdet
detdetdet
SS
SS
TSST
T
1det R
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Inverse of a Tensor
111 STST
Inverse of a tensor T exists if it is non-singular
ISS 1
11 TT SS
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Positive Definite Tensors
0vvSvv ,0 VPositiveDefinite
0vvSvv ,0 VPositiveSemi-definite
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Dual Vector of an Skew Tensor
0
0
0
12
13
23
ww
ww
ww
W
V vvwWv
3
2
1
w
w
w
w Axial vector of W
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Notations
Lin = the set of all rank two tensors
Lin+= subset of Lin with positive determinants
Sym = subset of Lin that are symmetric
Skw = subset of Lin that are skew
Psym = subset of Sym that are positive definite
Orth = set of all orthogonal tensors
Orth += set of all rotations
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Eigenvalues and Eigenvectors
aTa
Second rank tensors provide a linear transformation of
the vector space into itself. However, there would be
special vectors that satisfy the following condition:
are eigen values and {a} are eigen vectors
and {a} are independent of choice of coordinate frame
Multiple solutions are possible
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Eigenvalues and Eigenvectors
0aIT )( aTa
0)det( IT Non-trivial Solutionexists when
0)()()( 32213 TTT iii Characteristicequation
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Eigenvalues and Eigenvectors
0)()()( 322
13 TTT iii
ii
Ttri TT)(1
jiijii TTTtrtri 22222
1)]()[(
2
1)( TTT
3213 det)( kjiijk TTTi TT
)(),(),( 321 TTT iii
List of principal
invariants
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Cayley-Hamilton Theorem
0ITTTTTT )()()( 322
1
3 iii
Roots of Characteristic Equation
0)()()( 322
1
3
TTT iii The characteristic equation can produce
up to three real roots.
Multiple vectors are possible for each .
Rotation Tensors have only one real root!
R t f Ch t i ti E ti
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Roots of Characteristic Equation:
Symmetric Tensors
ii
i
ijiijS eeeeS
3
1
A symmetric tensor Spossesses three eigen values(1,2,3) and at least one orthonormal set of eigen
vectors (e1,e2,e3) associated with (1,2,3) respectively.
bSbaSaSS T 0 ababaSbSabba
ijjjjijiijS eeSee
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Symmetric Tensors
ii
i
i eeS 3
1
)(
)(
)(
3213
1332212
3211
S
S
S
i
i
i
3
2
1
00
00
00
iS
e
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Eigen Values and Eigen Vectors
0,3
1
iii
i
i eeC
A positive definite symmetric tensor Cpossessesthree positive eigen values (1,2,3).
Psymiii
i
UeeCU ,3
1
ii
i
i eeC
3
1
11
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Skew Tensors
V vvwWv
0)(1 WW tri
2222 )]()[(
21)( wWWW trtri
0det)(3 WWi
Whas only one real eigenvalue, which is
equal to zero
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Polar Decomposition
1det,
,,
RIRRRR
VU,FFVFFU
VRRUFF
TT
TT Psym
Lin
3
1
113
1
3
1
3
1
3
1
,,
,
i
iii
i
iii
i
ii
ii
i
iii
i
i
lrFrlFrlR
llVrrU