symmetry and symmetry violation in particle physics 违反对称 lecture 3 march 21, 2008
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Symmetry and Symmetry Violation in Particle Physics 违反对称
Lecture 3 March 21, 2008
Summary Lecture 2
• Antimatter predicted by Dirac & discovered by Chao & Anderson– 1933 Nobel prize Dirac– 1936 Nobel prize Anderson (but not Chao)
• Electron & positron have opposite parity
• Charge “reversal” Charge “conjugation”– Particle Antiparticle (not just charge)
• C=+1 even # of ’s; C=-1 odd # of ’s
• and K mesons = qq with L=0, S=0 & P=-1
Summary Lecture 2 (pg 2)
• + = ++- & +0 puzzle led Lee & Yang to question L-R symmetry of nature
• C.S. Wu discovered P viol. in Co60Ni60 e-– 1957 Nobel Prize to Lee & Yang (but not Wu)
• + and + are the same particle, the K+ meson
• C & P violation differences seen in -/+ decay
– But CP seems okay
• Large matter vs antimatter asymmetry in the
present-day Universe implies CP is violated.• K0K0 transitions possible @ 2nd-order W.I.
C, P & CP for and K mesons
Particle P C CP|+
|0|-
-1
-1
-1
-1
+|- -|-+|0 -|0
+|+ -|+
+|K0
|K+|K0
|K0|K-
-1
-1
-1
+|K+ -|K+
-|K-+|K--|K0 +|K0-|K0
Reminder
My tentative plan for this class is as follows:
Lecture 1. Definition of symmetry, why they are important in physics. Symmetries of the laws of nature. Relation of symmetry and conservation laws. Discrete symmetries C, P & T. Violation of parity (P) in beta-decay
Lecture 2. Antimatter, and matter-antimatter symmetry. Quark content of hadrons & discrete symmetries of hadrons. Violation of parity (P) and charge conjugation (C ) symmetry in beta-decay Particle- antiparticle mixing.
Lecture 3. K0K0 mixing. CP violation in K decay. Difficulties with incorporating CP violation into a physics theory. KM 6-quark model for CP violation. Role of B mesons in the theory
Lecture 4. Studying CP violation in the B meson system. Experimental techniques and results. What is left for the future.
Lecture 5. Exam
Discovery of CP violation in the neutral K meson system
• Neutral K meson decay mechanisms
• K0 – K0 mixing KS and KL mesons
• Discovery of KL+-
• CP violation in KLe-/e+ decays
• “Direct” CP violation in KL decays
outline
K0 +- decays via weak interaction
d
W.I.
u
W+
u
d
s
d
K0
-
+
S=-1
K0 also decays to +-
S W.I.
u
W- u
d
d
d
K0
+
-
S=1
K0 K0 possible as a 2nd orderweak interaction process
S W.I.
u
W- u
d
dd
K0
+
-
W.I.
W+
s
dK0
This is a so-called “long-range” process. It occurs on a size scale determined by the mesons: ~ 10-15m
1 fermi
S|=2
K0 K0 in short-range quark
S W.I.u
W-
c td
u
K0W.I.
W+
s
d
K0
This is a so-called “short-range” process. It occurs on a size scale determined by the t-quark: ~ 10-18 m
W.I.
c tW.I.
10-3 fermi
S|=2
What happens when two identical systems are coupled?
Energy transfersback-and-forthbetween the two oscillators
Steady-state “normal modes”
Shrodinger Equation: H = E
0
0
0
0
0
0
K
KE
K
K
H
00
00
:
:
KK
KK
..
* If CP symmetry holds:
Eigenvalues and Eigenstates
0
0
Find the eigenvalues
and eigenvectors for:
001
001
0
KKaK
KKK
E
L
S
Answer
Homework: Please check that these answers are correct
特征值
In standard (textbook) notation
0*
12
120
0*12
120
0
0
2
i
MM
MM
00
00
122
KqKpK
KqKpK
MMMM
L
S
SL
1
2
22
1221
12
*122
1*12
12
qp
M
M
p
q
LS
If CP symmetry is good: 2
1pq
00
21
2
00
21
1
KKKK
KKKK
L
S
CP of K1 and K2
00
00
KKCP
KKCP
Recall:
CP = +1
100
1 12
1KKKKCP
00002
2
1
2
1KKKKKCP
21 KCP = -1
1decays
1 CP= (-1)x(-1) = +1
CP = (-1)x(-1)x(-1) = -1
CP +1
CP= +1 OK
NG 1
2decays
2 CP= (-1)x(-1) = +1
CP = (-1)x(-1)x(-1) = -1
CP -1
CP= -1 NG
OK 2
K1 & K2 lifetimes
1has more phase space
QK1 = MK – 2M 215 MeV
2has little phase space
QK2 = MK – 3M 80 MeV
Easier for K1 to decayK1<<K2
相空间
1956: Search for long-lived K0
Brookhaven-Columbia Expt
Can you see it?
KS & KL mesons
Two neutral K mesons were discovered:
KS +- KS 0.1 nanosecs (10-10s)
KL +-0 KS 50 nanosecs (5x10-8s)
(Are they the CP eigenstates K1 and K2?)
500x bigger
e+ e-510MeV
510MeV
pL = 110 MeV<> = 3.4m
pS = 110 MeV<> = 6mm +
-
+
0
-
= ssM() = 1020 MeV
KL = K-long
KS = K-short
KL & KS mesons in e+e- annihilation
KLOEExperiment
in Italy2m
K L
KS
In this event the KL
only travels ~1m before it decays
Usually, the KL traverses to entire 2m radius of the drift chamber
KKLL “crash”“crash”
= 0.22 (TOF)= 0.22 (TOF)
KKSS ee
2m
KL “crash”
KS
Neutral K mesons “Basis” sets
K0-K0
Flavor States
K1-K2
CP eigenstates
KS-KL
Mass eigenstsate
These are theParticles that exist in Nature
These have awell defined
quark structure
are these the same?
Does KS=K1 & KL=K2?(i.e. is CP conserved?)
00
00
KqKpK
KqKpK
L
S
00
21
2
00
21
1
KKK
KKK
express them in terms of K1 and K2:
These are theparticles thatare observed
in nature
00
21
2
00
21
1
KKK
KKK
212
10
21210
KKK
KKK
invert
222
12KqpKqp
212121 KKqKKpKS
212121 KKqKKpKL
121
12
KKKL
211
12 KKKS
If CV is conserved: =0, KS=K1 & KL=K2
Does KL +- ?
121
12
KKKL
Forbidden(?)
211
12
KKKS
Forbidden(?)
2
2
1
1
K
K
K
K
S
L
if CP is conserved
Remember,+- has CP=+1
Christenson-Cronin-Fitch-Turlay Experiment (1964)
KL
+
-
2
2
4
2
c
pp
c
EEM
M(+-)<M(KL)
M(+-)>M(KL)
M(+-)=M(KL)
KL
-
+
+
cos
+- “invariant mass”
4x10-6
small,but not 0
CP is violated!!
1980 Nobel Prize for Physics No prizes for Christenson or Turlay
James Cronin Val Fitch
Flavor-non specific K0 (K0) decays
00
If you see +-, you don’t know if it was from a K0 or a K0
00
Decays that are equally likely for K0 and K0
Same for +-0, (& & )
特定
Flavor specific K0 (K0) decays
If you see -e+,you know it must befrom a K0, not K0
Decays that can only come from a K0 or K0, but not both
d
W.I.
W+
u
d
s
e+
K0
-
S=-1Q=-1
0eIf you see +e-,you know it must befrom a K0, not K0
s W.I.
e-W-
d
ud
K0
+
S=+1Q=+1
0eonlyS=Q
Rule:
特定
K0 & K0 in terms of KS & KL
00
00
KqKpK
KqKpK
L
S
invert
LS
LS
KKK
KKK
0
0
Start with a K0 at t=0
00
00
KqKpK
KqKpK
L
S
using
ttiML
ttiMS
LL
SS eKKeKKKtKK 22 0000 )(
0
1
00
00
KK
KK
and
ttiMttiM LL
SS eeptKK 22)(00
LS KKK 0
KS & KL havedifferent
t-dependence
ttiML
ttiMS
LL
SS eKeKtK 22)(0
ttiMttiM LL
SS eeptKK 22)(00
ttiMttiM LL
SS eeqtKK 22)(00
MteeeptKKIeP ttt LSLS cos2)()( )(2200
021
Similarly:
MteeeqtKKIeP ttt LSLS cos2)()( )(2200
021
)( SL MMM
K0K0 Oscillations
)(
)cos4)(()(
)(2221
tt
ttt
LS
LSLS
ee
MteeeqptA
)()(
)()(
)()(
)()()(
00
00
ePeP
ePeP
KNKN
KNKNtA
K0
K0
t/(“proper time”)
)(tA
Expt NA48 (CERN)
3102)( tA
S>>L (S500xL)
CP is violated in KLe-/e+ decays
)(
)cos4()(
)(21
tt
ttt
LS
LSLS
ee
MteeetA
22
221
qp
qp
Search for direct CPV in KL
121
12
KKKL
Forbidden(?)
CP violation from|S|=2 transition
Mass MatrixIs this true?
Can there be a“direct” CP violation
in |S|=1 K2?
In 2002,after 20 yr searches, NA48 (CERN) & KTeV (Fermilab)
found direct |S|=1 CPV in
K2
= ’ 1.6 x 10-3 x Small, but establishesexistence of “direct” |S|=1 CP violation.
CPV in neutral K meson systemsummary
• Neutral K mesons mix: K0 K0
• CP is violated in the K0-K0 mass-mixing matrix– scale 2x10-3
• CPV is seen in flavor non-specific & flavor specific modes– KL (CPV 4x10-6)
– KL +e- / -e+ (CPV = 2x10-3)
• Direct CP is seen in KL decays– scale = ’ = 1.6 x 10-3
CP is violated in the Weak Interactions
Observation of both Mass-Matrix CPV (|S|=2)
& direct CPV (|S|=1) rule out theorieswhere CPV comes from a previously
unknown “fifth” force characterized by |S|=2
Force C P CPGravity √ √ √Electro-magnetic √ √ √Strong-nuclear √ √ √Weak-Interaction ╳ ╳ OK?
C P and the forces of NatureSlide from last weak
Force C P CPGravity √ √ √Electro-magnetic √ √ √Strong-nuclear √ √ √Weak-Interaction ╳ ╳ ╳
Next:
• How are CP-violating asymmetries generated in QM?
• How does CP violation fit into the Standard Model for particle physics?– Brief review of flavor mixing/GIM-mechanism– Kobayashi 6-quark model
Generating CPV asymmetries in QM
CP: matter
W
gCP( ) =
For CPV: g g* (charge has to be complex)
CP operator:“charge”
antimatter
W†q
g* q’
mirrorsome basic process
QM: processes go as |A|2
• Phases tend to cancel out in rate calculations
qJ
g q’=
2
matter- symmetry is ~“automatic”
even for g* = g (i.e with CPV)
J†
2
q
g* q’
mirror
antimatter
gg* g*g
Phase measurements in QM: need interference
• need a process with 2 competing mechanisms:
• Amplitudes should have similar magnitudes:
A & Bei:
2|A|B|cos
|A|2+|B|2if |A|>>|B|
2|B|
|A|cos
Small numberRelative size of theinterference effect
|A+B|2=|A|2+|B|2+2|A|B|cos
phase
angle
干扰
Even this doesn’t work for CPV!!
A
BA+B
A+B
A
B
|A+B| |A+B|=
matterantimattersymmetric
still!
need a “common phase” between A & B
eg A=real: B = |B|eii & B = |B|ei-
i
A
BA+B
A
BA+B
|A+B| |A+B|=
matterantimatterdifference
same sign合用
CP violating asymmetries in QM
• Even if CP is violated, generating matter-antimatter differences is hard– need a CP-violating phase ()– need 2 (or more) interfering
amplitudes
– + a non-zero “common” phase () (often called a “strong” phase)
Common and weak phases“Common” (strong) phase (): same sign for
matter & antimatter CP conserving
Weak phase (): opposite sign for matter& antimatter CP violating
BA+B
A
BA+B
|B|eiiB = |B|ei-i
How does CPV fit into the Standard model?
Clue: CPV is seen in strangeness-changing weak decays.
It must have something to do with flavor-changing Weak Interactions
Flavor mixing&
CP Violation
3 quarks:
d
u
s
q=2/3
q=1/3
4 leptons:
~
e
e
Weak interactions
Brief review of weak int’s in the 3-quark era1964--1974
|S|=1
Problems Problem 1: Different weak interaction “charges” for leptonshadrons:
np
K
0
GF
GdGs
suGs 0.21GF
d
u
s
u
du
Gd 0.98GF
Fermi Constant
Cabibbo’s sol’n: flavor mixing
d = d + s
Weak Int flavor state
Flavor mass eigenstates
Unitarity: |2 + |2 = 1
du
W
GF
Ws
uGF
=cos c; = sin c
+d’
uGF =
c=“Cabibbo angle”
W
=cosc=0.98=sinc=0.21
Missing neutral currents Problem 2: no flavor-changing “neutral currents” seen.
flavor-preserving neutral currents (e.g. NX) are
allowed
flavor-changing neutral currents (e.g. K l+l) are strongly supressed
Discovered
At CERN
GN
d,u d,uK
d
s
GIM sol’n: Introduce 4th quark
2 quark doublets:
s
c
d
u
'' s
c
d
u
charmed quark
Weak eigenstates
Mass eigenstates
d’ & s’ are mixed d & s
Weak eigenstates
Mass eigenstates
s
d
s
d
'
'
4-quarkflavor-mixing
matrix
Mixing matrix must be Unitary
U
UU† = 1
= 1 & =0
10
01**
**
Charged currents (u-quark)
d(s)
u(c)
W
GF
Ws(d)
u(c)
GF
31
31
32
sd
u
GF modified by GF modified by
|S|=1
Charged currents (c-quark)
dc
W
GF
Ws
cGF
31
31
32
sd
c
GF modified by GF modified by
|C|=1|S|=1
|C|=1|S|=0
Flavor preserving Neutral Current
d,(S)GN
=1
OK
dss
sdsddd **
sdd
ssdssddd 2*2
*
=1
=0 =0
22
d,(s)Z
=1
=1
From Unitarity
Flavor changing Neutral Current
From Unitarity
=1
dss
sddsds **
sdd
=0 =0
sdddssds 2*2*
=1
**
FCNC forbidden by Unitarity
s(d)
d(s)
Z
GN
=0
=0
GIM- Mechanism
GIM Mechanism
FCNC forbidden by Unitarityif quarks come in pairs of 2
GIM: Glashow Iliopoulis Maiani
Glashow won 1979Physics Nobel prize
No prize forIliopoulis & Maiani
Next Friday: Incorporating CPV into flavor mixing
Summary Lecture 3
• CP is violated Weak-Interactions – Mass-matrix induced; scale 2x10-3
– Direct CPV; scale = ’ = 1.6 x 10-3 • Observing CPV requires:
– Two interfering amplitudes– One with a CP-violating weak phase – Another “common” or “strong” phase
• In the W.I., the d and s quark mix d’ & s’– d’ =coscd +sin s; s’ =-sincd +coscs– c 120 is the “Cabibbo angle
• If all quarks are in pairs, FCNC = 0 by Unitarity – (GIM Mechanism)