study of h-passivation of a bi 2 te 3 (111) surface

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Study of H-passivation of a Bi 2 Te 3 (111) surface Jesse Maassen Physics department McGill University First principles calculations are utilized to help answer the following questions: Will H bind to a Bi 2 Te 3 surface? If so: How many H atoms per surface atom? With what configuration? What are the properties of the H-terminated surface?

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Study of H-passivation of a Bi 2 Te 3 (111) surface. Jesse Maassen Physics department McGill University. First principles calculations are utilized to help answer the following questions: Will H bind to a Bi 2 Te 3 surface? - PowerPoint PPT Presentation

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Page 1: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Study of H-passivation of a Bi2Te3(111) surface

Study of H-passivation of a Bi2Te3(111) surface

Jesse MaassenPhysics departmentMcGill University

First principles calculations are utilized to help answer the following questions:

Will H bind to a Bi2Te3 surface? If so: How many H atoms per surface atom? With what

configuration? What are the properties of the H-terminated surface?

First principles calculations are utilized to help answer the following questions:

Will H bind to a Bi2Te3 surface? If so: How many H atoms per surface atom? With what

configuration? What are the properties of the H-terminated surface?

Page 2: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Our focus : Since it is too computationally expensive to consider the bonding of H on Bi2Te3 slabs of varying thickness, we focus only on the case of 3 quintuple layers (QL).

The system under considerationThe system under consideration

Te(2)

Bi

Te(1)

1QL

Primitivecell

Te(2)

Bi

Page 3: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Energetics of H-passivationEnergetics of H-passivation

Our plan : Calculate the total energy of the H-bonded Bi2Te3 slab and compare this energy to that of the isolated H / Bi2Te3 system. The configuration which minimizes the total energy will correspond to the most stable case (i.e., most likely to exist). Procedure : We consider the possibility of 1H, 2H and 3H per Te surface atom. The initial positions of the H atoms are chosen such that they replicate the bond directions of the middle Te(1) atom with a bond length of 1.5Å. There are 3 such directions, that we label A, B and C. (next page…)

Page 4: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Energetics of H-passivationEnergetics of H-passivation

Procedure (cont.): Structural relaxations are then performed to ensure each atom has a force < 0.01 eV/Å. The final step is to compute the total energy of the relaxed system.

Simulation technique : The Vienna Ab Initio Simulation Package (VASP) is utilized for all calculations. The energy cutoff for the plane wave basis is set to 400 eV. The core potential is treated within the projector-augmented wave (PAW) method. A k-mesh of 13131, generated using the Monkhorst-Pack scheme, is used.

Page 5: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Outline of studyOutline of study

1. Structural relaxations 3 H atoms / surface Te 2 H atoms / surface Te 1 H atom / surface Te

2. Total energy calculations

3. Properties of H-passivated Bi2Te3

Page 6: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Outline of studyOutline of study

1. Structural relaxations 3 H atoms / surface Te 2 H atoms / surface Te 1 H atom / surface Te

2. Total energy calculations

3. Properties of H-passivated Bi2Te3

Page 7: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Relaxation (case 1) : 3 H atoms / TeRelaxation (case 1) : 3 H atoms / Te

Initial Final

Afterrelaxation

After relaxation, only 1 H atom remains bonded to the surface Te. The other 2 H atoms form an H2 molecule and move away from the surface. There is significant distortion to the slab.

Conclusion: The 3 H atom system converts to the case of a single H.

Page 8: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Relaxation (case 2) : 2 H atoms / TeRelaxation (case 2) : 2 H atoms / Te

Initial Final

Afterrelaxation

After relaxation, the 2 H atoms form an H2 molecule and move away from the surface.

Conclusion: The 2 H atoms desorb from the surface leaving the Bi2Te3 slab bare.

Page 9: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Relaxation (case 3) : 1 H atoms / TeRelaxation (case 3) : 1 H atoms / Te

The single H atom is found to remain bonded to the surface Te. The presence of the H results in the distortion of the Bi2Te3 lattice.

Conclusion: A single H atom bonds to the surface of Bi2Te3.

Initial Final

Afterrelaxation

Note that for the case of 1 H / Te, I tested 9 different initial configurations corresponding to the top & bottom H atoms each at the sites A, B and C.

Page 10: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Relaxation (summary)Relaxation (summary)

Starting with initial configurations including 1H, 2H and 3H atoms per surface Te, the structural relaxations show that only two cases are relevant:

Bi2Te3 slab with 1H per surface Te Bare Bi2Te3 slab

Page 11: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Outline of studyOutline of study

1. Structural relaxations 3 H atoms / surface Te 2 H atoms / surface Te 1 H atom / surface Te

2. Total energy calculations

3. Properties of H-passivated Bi2Te3

Page 12: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Total energyTotal energy

Configuration

Total energy (eV)

AA -63.722 (+2.05)

AB -63.728 (+2.05)

AC -63.736 (+2.04)

BA -63.740 (+2.04)

BB -63.734 (+2.04)

BC -63.724 (+2.05)

CA -63.727 (+2.05)

CB -63.727 (+2.05)

CC -63.743 (+2.03)

Bare + H2 -65.775

Bon

ded

This table shows the total energy of a Bi2Te3 slab + 2 H atoms (bonded vs. unbonded). A, B and C indicate the initial bond direction. The numbers in () corresponds to the difference relative to the bare+H2 case.

First letter: top HSecond letter: bottom H.

A Bi2Te3 slab without H is always energetically favorable by ~ 2 eV.

Page 13: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Total energy (summary)Total energy (summary)

A bare Bi2Te3 is always energetically favorable.

H-passivated Bi2Te3 surfaces are meta-stable states that cost at minimum 2 eV.

The fact that a Bi2Te3 surface does not want to interact with a molecular adsorbate is consistent with previous experiments*.

* Physical Review 119, 567 (1960).

Page 14: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Outline of studyOutline of study

1. Structural relaxations 3 H atoms / surface Te 2 H atoms / surface Te 1 H atom / surface Te

2. Total energy calculations

3. Properties of H-passivated Bi2Te3

Page 15: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Pure Bi2Te3

Properties of Bi2Te3:H (bonding picture; review)

Properties of Bi2Te3:H (bonding picture; review)

*See, for example: J. Phys. Chem. Solids 5, 142 (1958),

Physical Review 119, 567 (1960), Physics Letters A 135, 223 (1989).

Te(2)

Bi

Te(1)

Te(2)

Bi

Bi [5e–] : 3 Te(1) + 3 Te(2) neighborsTe(1) [6e–] : 6 Bi neighborsTe(2) [6e–] : 3 Bi neighbors

It is believed* that Te(2)’s 4 p-type e– bond to the 3 neighboring Bi atoms, and the 2 s-type e– form a lone pair. This results in fully satisfied Te(2) atoms such that the QLs interact via Van der Waals (VdW) forces. The Te(1) and Bi atoms have nearly octahedral coordination, indicating that both s- and p-type e– are used in the bonding.

Page 16: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Pure Bi2Te3

Properties of Bi2Te3:H (charge density)Properties of Bi2Te3:H (charge density)

Small non-zero charge in between QLs, thus not purely VdW interaction.

Te(2) atoms share more charge with Bi than Te(1) with Bi.

Surface Te(2) charge density appears very similar to that of the Te(2) in the middle QL.

Page 17: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Pure Bi2Te3 Bi2Te3 : H

Properties of Bi2Te3:H (bond lengths & angles)Properties of Bi2Te3:H (bond lengths & angles)

With H, the surface Te atom moves such that it breaks a bond with 1 Bi while bonding to H and conserving the 2 other Bi bonds. The bond angles between the 2 Bi atoms and the H atoms are slightly different and roughly 90; similar to the case of no H.

3.09 Å

3.09 Å

3.09 Å

For pure Bi2Te3, the surface Te atom

shares the same bond length with all 3 Bi nearest neighbors. All the bond angles are identical and equal to 92.9. These nearly 90 angles indicate that the bonding is largely p-type.

3.86 Å3.12 Å 3.13 Å

1.71 Å

Page 18: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Atom Charge

Te (2) +0.37

Bi -0.66

Te (1) +0.58

Bi -0.64

Te (2) +0.35

Te (2) +0.35

Bi -0.64

Te (1) +0.57

Bi -0.64

Te (2) +0.35

Te (2) +0.35

Bi -0.64

Te (1) +0.58

Bi -0.66

Te (2) +0.37

Atom Charge

H +0.17

Te (2) +0.06

Bi -0.49

Te (1) +0.52

Bi -0.59

Te (2) +0.33

Te (2) +0.35

Bi -0.62

Te (1) +0.56

Bi -0.63

Te (2) +0.35

Te (2) +0.33

Bi -0.59

Te (1) +0.51

Bi -0.49

Te (2) +0.06

H +0.17

Properties of Bi2Te3:H (charge transfer)Properties of Bi2Te3:H (charge transfer)

Pure Bi2Te3Bi2Te3 : H

Page 19: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Atom Charge

Te (2) +0.37

Bi -0.66

Te (1) +0.58

Bi -0.64

Te (2) +0.35

Te (2) +0.35

Bi -0.64

Te (1) +0.57

Bi -0.64

Te (2) +0.35

Te (2) +0.35

Bi -0.64

Te (1) +0.58

Bi -0.66

Te (2) +0.37

Atom Charge

H +0.17

Te (2) +0.06

Bi -0.49

Te (1) +0.52

Bi -0.59

Te (2) +0.33

Te (2) +0.35

Bi -0.62

Te (1) +0.56

Bi -0.63

Te (2) +0.35

Te (2) +0.33

Bi -0.59

Te (1) +0.51

Bi -0.49

Te (2) +0.06

H +0.17

Properties of Bi2Te3:H (charge transfer)Properties of Bi2Te3:H (charge transfer)

Pure Bi2Te3Bi2Te3 : H

Charge per bond for a surface Te(2) atom = 0.37 e– / 3 Bi nearest neighbors

0.12 e– / bond

Charge transferred from Bi to the surface Te(2) + H= 0.06 e– + 0.17 e–

= 0.23 e–

This value equals the charge of 2 bonds.

The surface Te(2) atom broke 1 of it’s bonds with the 3 Bi to bind with the H.

Page 20: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Atom |M| (B)

H 0.006

Te (2) 0.013

Bi 0.148

Te (1) 0.016

Bi 0.027

Te (2) 0.025

Te (2) 0.016

Bi 0.014

Te (1) 0.004

Bi 0.018

Te (2) 0.012

Te (2) 0.053

Bi 0.028

Te (1) 0.038

Bi 0.169

Te (2) 0.014

H 0.011

Properties of Bi2Te3:H (magnetic moments)Properties of Bi2Te3:H (magnetic moments)

Pure Bi2Te3Bi2Te3 : H

Atom |M| (B)

Te (2) 0.008

Bi 0.006

Te (1) 0.006

Bi 0.019

Te (2) 0.010

Te (2) 0.014

Bi 0.016

Te (1) 0

Bi 0.015

Te (2) 0.014

Te (2) 0.010

Bi 0.018

Te (1) 0.006

Bi 0.006

Te (2) 0.008

Total magnetic moment = 0.00 B

Total magnetic moment = 1.07 B

Large |M| localized to surface Bi, due to dangling bond.

Page 21: Study of H-passivation of a   Bi 2 Te 3 (111) surface

Properties of Bi2Te3:H (bandstructure)Properties of Bi2Te3:H (bandstructure)E -

EF

(eV

)

K M K ME -

EF

(eV

)

Pure Bi2Te3 Bi2Te3 : H

Large change in the bands with H.

States are now spin-split due to the dangling bonds of the surface Bi atoms.

Electronic bands of a 3QL Bi2Te3 slab.

All states are doubly degenerate.

Page 22: Study of H-passivation of a   Bi 2 Te 3 (111) surface

K M

E -

EF

(eV

)

Bi2Te3 : H

The contribution of H to the bands are shown in black.

The H states are located at roughly -4 eV, and hence play no direct role in the bands at EF.

Properties of Bi2Te3:H (bandstructure)Properties of Bi2Te3:H (bandstructure)

Page 23: Study of H-passivation of a   Bi 2 Te 3 (111) surface

ConclusionConclusion

A first principles study was performed to determine whether H atoms will bind to the surface of a 3QL Bi2Te3 slab.

Structural relaxations show that only important cases correspond to 0 H per surface Te or 1 H per surface Te.

Total energy calculations indicate that the H-termined surface is a meta-stable state with ~2 eV higher energy than a bare slab.

With H, the bands are significantly altered (due to large charge transfer) and result in spin non-degenerate states and a net magnetic moment.

An analysis of the charge density, charge transfers and bond lengths and angles, it is confirmed that the surface Te atom breaks 1 of 3 bonds in order to bind to H. This explains the high energetic cost of binding to H, and hence the unlikely occurrence of atomic adsorption.