study of h-passivation of a bi 2 te 3 (111) surface
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Study of H-passivation of a Bi 2 Te 3 (111) surface. Jesse Maassen Physics department McGill University. First principles calculations are utilized to help answer the following questions: Will H bind to a Bi 2 Te 3 surface? - PowerPoint PPT PresentationTRANSCRIPT
Study of H-passivation of a Bi2Te3(111) surface
Study of H-passivation of a Bi2Te3(111) surface
Jesse MaassenPhysics departmentMcGill University
First principles calculations are utilized to help answer the following questions:
Will H bind to a Bi2Te3 surface? If so: How many H atoms per surface atom? With what
configuration? What are the properties of the H-terminated surface?
First principles calculations are utilized to help answer the following questions:
Will H bind to a Bi2Te3 surface? If so: How many H atoms per surface atom? With what
configuration? What are the properties of the H-terminated surface?
Our focus : Since it is too computationally expensive to consider the bonding of H on Bi2Te3 slabs of varying thickness, we focus only on the case of 3 quintuple layers (QL).
The system under considerationThe system under consideration
Te(2)
Bi
Te(1)
1QL
Primitivecell
Te(2)
Bi
Energetics of H-passivationEnergetics of H-passivation
Our plan : Calculate the total energy of the H-bonded Bi2Te3 slab and compare this energy to that of the isolated H / Bi2Te3 system. The configuration which minimizes the total energy will correspond to the most stable case (i.e., most likely to exist). Procedure : We consider the possibility of 1H, 2H and 3H per Te surface atom. The initial positions of the H atoms are chosen such that they replicate the bond directions of the middle Te(1) atom with a bond length of 1.5Å. There are 3 such directions, that we label A, B and C. (next page…)
Energetics of H-passivationEnergetics of H-passivation
Procedure (cont.): Structural relaxations are then performed to ensure each atom has a force < 0.01 eV/Å. The final step is to compute the total energy of the relaxed system.
Simulation technique : The Vienna Ab Initio Simulation Package (VASP) is utilized for all calculations. The energy cutoff for the plane wave basis is set to 400 eV. The core potential is treated within the projector-augmented wave (PAW) method. A k-mesh of 13131, generated using the Monkhorst-Pack scheme, is used.
Outline of studyOutline of study
1. Structural relaxations 3 H atoms / surface Te 2 H atoms / surface Te 1 H atom / surface Te
2. Total energy calculations
3. Properties of H-passivated Bi2Te3
Outline of studyOutline of study
1. Structural relaxations 3 H atoms / surface Te 2 H atoms / surface Te 1 H atom / surface Te
2. Total energy calculations
3. Properties of H-passivated Bi2Te3
Relaxation (case 1) : 3 H atoms / TeRelaxation (case 1) : 3 H atoms / Te
Initial Final
Afterrelaxation
After relaxation, only 1 H atom remains bonded to the surface Te. The other 2 H atoms form an H2 molecule and move away from the surface. There is significant distortion to the slab.
Conclusion: The 3 H atom system converts to the case of a single H.
Relaxation (case 2) : 2 H atoms / TeRelaxation (case 2) : 2 H atoms / Te
Initial Final
Afterrelaxation
After relaxation, the 2 H atoms form an H2 molecule and move away from the surface.
Conclusion: The 2 H atoms desorb from the surface leaving the Bi2Te3 slab bare.
Relaxation (case 3) : 1 H atoms / TeRelaxation (case 3) : 1 H atoms / Te
The single H atom is found to remain bonded to the surface Te. The presence of the H results in the distortion of the Bi2Te3 lattice.
Conclusion: A single H atom bonds to the surface of Bi2Te3.
Initial Final
Afterrelaxation
Note that for the case of 1 H / Te, I tested 9 different initial configurations corresponding to the top & bottom H atoms each at the sites A, B and C.
Relaxation (summary)Relaxation (summary)
Starting with initial configurations including 1H, 2H and 3H atoms per surface Te, the structural relaxations show that only two cases are relevant:
Bi2Te3 slab with 1H per surface Te Bare Bi2Te3 slab
Outline of studyOutline of study
1. Structural relaxations 3 H atoms / surface Te 2 H atoms / surface Te 1 H atom / surface Te
2. Total energy calculations
3. Properties of H-passivated Bi2Te3
Total energyTotal energy
Configuration
Total energy (eV)
AA -63.722 (+2.05)
AB -63.728 (+2.05)
AC -63.736 (+2.04)
BA -63.740 (+2.04)
BB -63.734 (+2.04)
BC -63.724 (+2.05)
CA -63.727 (+2.05)
CB -63.727 (+2.05)
CC -63.743 (+2.03)
Bare + H2 -65.775
Bon
ded
This table shows the total energy of a Bi2Te3 slab + 2 H atoms (bonded vs. unbonded). A, B and C indicate the initial bond direction. The numbers in () corresponds to the difference relative to the bare+H2 case.
First letter: top HSecond letter: bottom H.
A Bi2Te3 slab without H is always energetically favorable by ~ 2 eV.
Total energy (summary)Total energy (summary)
A bare Bi2Te3 is always energetically favorable.
H-passivated Bi2Te3 surfaces are meta-stable states that cost at minimum 2 eV.
The fact that a Bi2Te3 surface does not want to interact with a molecular adsorbate is consistent with previous experiments*.
* Physical Review 119, 567 (1960).
Outline of studyOutline of study
1. Structural relaxations 3 H atoms / surface Te 2 H atoms / surface Te 1 H atom / surface Te
2. Total energy calculations
3. Properties of H-passivated Bi2Te3
Pure Bi2Te3
Properties of Bi2Te3:H (bonding picture; review)
Properties of Bi2Te3:H (bonding picture; review)
*See, for example: J. Phys. Chem. Solids 5, 142 (1958),
Physical Review 119, 567 (1960), Physics Letters A 135, 223 (1989).
Te(2)
Bi
Te(1)
Te(2)
Bi
Bi [5e–] : 3 Te(1) + 3 Te(2) neighborsTe(1) [6e–] : 6 Bi neighborsTe(2) [6e–] : 3 Bi neighbors
It is believed* that Te(2)’s 4 p-type e– bond to the 3 neighboring Bi atoms, and the 2 s-type e– form a lone pair. This results in fully satisfied Te(2) atoms such that the QLs interact via Van der Waals (VdW) forces. The Te(1) and Bi atoms have nearly octahedral coordination, indicating that both s- and p-type e– are used in the bonding.
Pure Bi2Te3
Properties of Bi2Te3:H (charge density)Properties of Bi2Te3:H (charge density)
Small non-zero charge in between QLs, thus not purely VdW interaction.
Te(2) atoms share more charge with Bi than Te(1) with Bi.
Surface Te(2) charge density appears very similar to that of the Te(2) in the middle QL.
Pure Bi2Te3 Bi2Te3 : H
Properties of Bi2Te3:H (bond lengths & angles)Properties of Bi2Te3:H (bond lengths & angles)
With H, the surface Te atom moves such that it breaks a bond with 1 Bi while bonding to H and conserving the 2 other Bi bonds. The bond angles between the 2 Bi atoms and the H atoms are slightly different and roughly 90; similar to the case of no H.
3.09 Å
3.09 Å
3.09 Å
For pure Bi2Te3, the surface Te atom
shares the same bond length with all 3 Bi nearest neighbors. All the bond angles are identical and equal to 92.9. These nearly 90 angles indicate that the bonding is largely p-type.
3.86 Å3.12 Å 3.13 Å
1.71 Å
Atom Charge
Te (2) +0.37
Bi -0.66
Te (1) +0.58
Bi -0.64
Te (2) +0.35
Te (2) +0.35
Bi -0.64
Te (1) +0.57
Bi -0.64
Te (2) +0.35
Te (2) +0.35
Bi -0.64
Te (1) +0.58
Bi -0.66
Te (2) +0.37
Atom Charge
H +0.17
Te (2) +0.06
Bi -0.49
Te (1) +0.52
Bi -0.59
Te (2) +0.33
Te (2) +0.35
Bi -0.62
Te (1) +0.56
Bi -0.63
Te (2) +0.35
Te (2) +0.33
Bi -0.59
Te (1) +0.51
Bi -0.49
Te (2) +0.06
H +0.17
Properties of Bi2Te3:H (charge transfer)Properties of Bi2Te3:H (charge transfer)
Pure Bi2Te3Bi2Te3 : H
Atom Charge
Te (2) +0.37
Bi -0.66
Te (1) +0.58
Bi -0.64
Te (2) +0.35
Te (2) +0.35
Bi -0.64
Te (1) +0.57
Bi -0.64
Te (2) +0.35
Te (2) +0.35
Bi -0.64
Te (1) +0.58
Bi -0.66
Te (2) +0.37
Atom Charge
H +0.17
Te (2) +0.06
Bi -0.49
Te (1) +0.52
Bi -0.59
Te (2) +0.33
Te (2) +0.35
Bi -0.62
Te (1) +0.56
Bi -0.63
Te (2) +0.35
Te (2) +0.33
Bi -0.59
Te (1) +0.51
Bi -0.49
Te (2) +0.06
H +0.17
Properties of Bi2Te3:H (charge transfer)Properties of Bi2Te3:H (charge transfer)
Pure Bi2Te3Bi2Te3 : H
Charge per bond for a surface Te(2) atom = 0.37 e– / 3 Bi nearest neighbors
0.12 e– / bond
Charge transferred from Bi to the surface Te(2) + H= 0.06 e– + 0.17 e–
= 0.23 e–
This value equals the charge of 2 bonds.
The surface Te(2) atom broke 1 of it’s bonds with the 3 Bi to bind with the H.
Atom |M| (B)
H 0.006
Te (2) 0.013
Bi 0.148
Te (1) 0.016
Bi 0.027
Te (2) 0.025
Te (2) 0.016
Bi 0.014
Te (1) 0.004
Bi 0.018
Te (2) 0.012
Te (2) 0.053
Bi 0.028
Te (1) 0.038
Bi 0.169
Te (2) 0.014
H 0.011
Properties of Bi2Te3:H (magnetic moments)Properties of Bi2Te3:H (magnetic moments)
Pure Bi2Te3Bi2Te3 : H
Atom |M| (B)
Te (2) 0.008
Bi 0.006
Te (1) 0.006
Bi 0.019
Te (2) 0.010
Te (2) 0.014
Bi 0.016
Te (1) 0
Bi 0.015
Te (2) 0.014
Te (2) 0.010
Bi 0.018
Te (1) 0.006
Bi 0.006
Te (2) 0.008
Total magnetic moment = 0.00 B
Total magnetic moment = 1.07 B
Large |M| localized to surface Bi, due to dangling bond.
Properties of Bi2Te3:H (bandstructure)Properties of Bi2Te3:H (bandstructure)E -
EF
(eV
)
K M K ME -
EF
(eV
)
Pure Bi2Te3 Bi2Te3 : H
Large change in the bands with H.
States are now spin-split due to the dangling bonds of the surface Bi atoms.
Electronic bands of a 3QL Bi2Te3 slab.
All states are doubly degenerate.
K M
E -
EF
(eV
)
Bi2Te3 : H
The contribution of H to the bands are shown in black.
The H states are located at roughly -4 eV, and hence play no direct role in the bands at EF.
Properties of Bi2Te3:H (bandstructure)Properties of Bi2Te3:H (bandstructure)
ConclusionConclusion
A first principles study was performed to determine whether H atoms will bind to the surface of a 3QL Bi2Te3 slab.
Structural relaxations show that only important cases correspond to 0 H per surface Te or 1 H per surface Te.
Total energy calculations indicate that the H-termined surface is a meta-stable state with ~2 eV higher energy than a bare slab.
With H, the bands are significantly altered (due to large charge transfer) and result in spin non-degenerate states and a net magnetic moment.
An analysis of the charge density, charge transfers and bond lengths and angles, it is confirmed that the surface Te atom breaks 1 of 3 bonds in order to bind to H. This explains the high energetic cost of binding to H, and hence the unlikely occurrence of atomic adsorption.