statistical challenges for studying the evolution of function valued traits patrick a. carter school...
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Statistical Challenges for Studying the Evolution of Function Valued Traits
Patrick A. Carter
School of Biological Sciences
Washington State University
Interesting Problems in Evolutionary Biology
• How do organisms evolve?– What processes are involved (selection, genetic drift);
how do they interact?
• What is the role of genetic variation in evolution?– How does genetic variation shape evolution?– How does evolution alter genetic variation?
• What influences the tempo of evolution?– Constraints
• My lab investigates these questions at the both the genetic and physiological levels.
Basic Quantitative Genetics• Most traits show continuous variation
and are influenced by many genes.• If family relationships are known, the
phenotypic variance can be partitioned:– VP = VG+VE
• VG also can be partitioned:– VG = VA + VD + VI
• VA is additive genetic variance (variance in breeding values)– One trait: simple variance– Multiple traits: G matrix– FV Trait: G function
Trait
Fre
qu
ency
S
Interesting Questions about the Evolution of FV Traits
• Have we estimated the phenotypic function in the most meaningful way biologically?
• Has the phenotypic function evolved in response to selection, and in the way we predicted?
• Has the underlying genetic variance-covariance function evolved in response to selection?
Statistical Challenges
• Register the curves in a biologically meaningfully way.
• Compare mean trajectories from different populations with different evolutionary histories.
• Compare G functions from different populations with different evolutionary histories.
Registration
• How do we align curves that contain variation in multiple points of biological interest?
• Growth curves of larval insects:– Hatch– High Growth– Peak = hormonal shift– Wandering phase = loss of body mass– Pupation = end of larval phase
Mean Phenotype by Half-Sib Family
0
50
100
150
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350
1 6 11 16 21
Days
Mass (
µg
)M
ass
(µg)
Mass Vs. Age By Half-Sib Family (Warped Ages)
0
0.5
1
1.5
2
2.5
3
0 5 10 15 20 25
Age (Days, Warped)
log(
Mas
s, g
)
Population Comparisons
• Evolutionary biologists frequently want to compare characteristics of populations with different evolutionary histories, especially:– Mean population phenotypes (has selection
changed the trait?)– Genetic variances and covariances (has
selection eroded the variances and covariances as alleles become fixed?)
Statistical Challenges
• Formally compare mean phenotypic curves– Most experimental designs are nested, with
replicate lines nested within experimental selection group. Replicates lines can provide information about genetic drift.
• Formally compare G functions (and their eigenfunctions) from different populations.
Control LinesFemales Females
Selected Lines
Acknowledgements
• Students: Ted Morgan, Steph Kane, Greg Ragland, Drew Reinbold, Kristy Bellinger, Kristen Irwin, Anna Heink
• Collaborators: Fun Value Group• Funding: NSF (DEB 0083638, DEB
0105079, EF 0328594), National Institute of Mathematical and Biological Synthesis
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21
Age (days)
0
100
200
300
400
Bod
y M
ass
(mic
rogr
ams)
Overall Mean PhenotypeOverall Mean Phenotype
Mean Phenotype by Half-Sib Family
0
50
100
150
200
250
300
350
1 6 11 16 21
Days
Mass (
µg
)M
ass
(µg)
Additive Genetic Covariance FunctionAdditive Genetic Covariance Function
0 2 4 6 8 10 12 14 16 18 20 22
Age (days)
-1.5
-1.0
-0.5
0.0
0.5
1.0
1.5
2.0
2.5
3.0
3.5
Eig
enfu
nctio
ns
EF1EF2EF3
EigenfunctionsEigenfunctions
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22
Age (days)
0
50
100
150
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300
350
400
Bod
y M
ass
( m
icro
gra
ms)
Predicted Response to SelectionCurrent Mean Function
Response to SelectionResponse to Selection
Statistical Challenges
• Formally compare growth curves in selected vs. non-selected populations.
• Compare selection responses: along axis of major variation vs. axis in “nearly null space”.
• Formally compare G functions from different populations.
0 2 4 6 8 10 12 14 16
Generation
2
4
6
8
10
12
14
16
18
Whe
el R
evol
utio
ns (
kilo
met
ers)
Mean of Days 5 + 6 in Females
GS2 Sept. 19, 2001 1:14:49 PM
ControlSelected
5 15 25 35 45 55 65 75 85
Age (weeks)
18
20
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Bo
dy
Ma
ss
(g
)
Active Control
Active Selection
Sedentary Control
Sedentary Selection
Females
0 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85
Age (weeks)
10
15
20
25
30
35
40
45
50
55
60
65
70
75
80
Wh
ee
l-R
evo
lutio
ns
(km
)Mean Wheel-Running Activity
Females
Control LinesSelected Lines