st. projection 2013er

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    X-Ray & TEM Lab

    Stereographic Projection

    Fig 2.25: {100} poles of a cubic crystal

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    X-Ray & TEM Lab

    Stereographic Projection

    Wulff Net

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    X-Ray & TEM Lab

    Stereographic Projection

    Fig 2.26: Angle between two planes

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    Geographic map is equal area concept.

    Crystallography is equiangular concept.

    Plane of projection is placed normal to the

    end of diameter of the sphere.

    Other end of diameter is the source of projection- Imagine that a torch is placed there.

    Plane of projection is normal to the diameter AB.

    Projection is made from point B.

    -If a plane has its pole at P,

    -the stereographic projection of P is at P

    -Obtained by drawing the line BP

    -extend it until it meets the projection plane.

    The stereographic projection of P is the shadow

    cast by P on the projection plane with the light

    source at B.

    NESW is normal to AB and its shadow gives the

    Great circle.

    Fig 2.27: The Stereographic Projection

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    Stereographic Projection of great & small circles

    Fig 2.28: Stereographic Projection of great & small circles

    Great circleANBS projects as the straight line NS.

    Great circleAWBE projects as the straight line WE.

    Inclined great circle NGSH projects as the circle arc

    line NGS.

    Small circles on the sphere also project

    as circles projected center does not coincide

    with their center on the projection.E.g., circleAJEK whose center P lies on

    AEBW projects asAJEK.

    Its center on the projection is at C,

    located at equal distances from

    A and E, but its projected centeris at P located at equal number of

    degrees (45) fromA & E.

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    X-Ray & TEM Lab

    Stereographic Projection

    Fig 2.30: Angle between poles

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    X-Ray & TEM Lab

    Stereographic Projection

    Wulff NetFig 2.31: Angle between poles

    rotation to put on same great circle

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    X-Ray & TEM Lab

    Stereographic Projection

    Fig 2.31: Rotation of poles P1 and P2 to put on same great circle

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    X-Ray & TEM Lab

    Stereographic Projection

    Fig 2.32: Trace of a pole (pole P2)

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    X-Ray & TEM Lab

    Stereographic Projection

    Fig 2.33: Measurement of angle between 2 poles

    P1 and P2 by measurement of the angle of intersection of their traces

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    X-Ray & TEM Lab

    Stereographic Projection

    Fig 2.34: Rotation of poles about NS axis of projection

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    Fig 2.35: Rotation of a pole about an inclined axis

    Rotate A1

    about

    B1 by 40 in a

    clockwise

    direction.

    Initial position

    Rotate projection to bring B1 to the equator.

    Bring B1 to the centre by rotating 48 about the N-S axis.

    At the same time, A1 must also move to A2 along the

    parallel latitude.The rotation axis is now perpendicular to the projection plane.

    Required rotation of 40 brings A2 to A3 along a circular path

    centered on B2.

    The B1 to B2 operation needs to be reversed to bring B2 to its

    original position.

    B2 is brought to B3 and A3 to A4, by a reverse 48 rotationabout the N-S axis.

    Final position

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    Fig 2.35: Rotation of a pole about an inclined axis

    Rotate A1

    about

    B1 by 40 in a

    clockwise

    direction.

    Initial position

    During its rotation about B1, A1 moves along the small circle.

    Centre of this circle is at C on the projection & not at its

    projected centre B1.

    At the same time, A1 must also move to A2 along theparallel latitude.

    To find C, we know that all points on the circle must lie at

    equal angular distances from B1.

    Measurement on a Wulff net shows that A1 and A4 are 76

    from B1.

    We locate any other point D which is 76 from B1.Knowing 3 points on the required circle allows us to locate

    its centre by plane geometry.

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    Table 2-3: Interplanar angles for cubic crystals.

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    X-Ray & TEM Lab

    Stereographic Projection

    Fig 2.25: {100} poles of a cubic crystal

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    Standard Projection

    Let us look at the standard (001) projection.

    The {100} cube poles are obvious.

    The {110} poles are located 45 from the

    {100} poles & are 90 apart.

    (011) Pole is on the great circle joining

    (001) and (010) & at 45 from each.

    Using hu+kv+lw = 0

    We find (111) belongs to both

    and101 011

    Pole of (111) is located at the intersection of zone circle through

    ( ) ( ) ( )010 , 101 , 010 and ( ) ( ) ( )100 , 011 , 100

    Angle between the (111) pole & (010) or (100) must be 54.7

    u = k1l2 k

    2l1

    v = l1h

    2 l

    2h

    1

    w = h1

    k2

    h2

    k1

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    Standard Stereographic Projection

    (001) and (011) standard projections

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    Fig 2.34: Rotation of poles about NS axis of projection