sql solved questions

8/10/2019 SQL Solved Questions

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SQL Queries

Reference Text Book:

Fundamentals of DBMS 5e.

Chapter name: The Relational Algebra and

Relational Calculus.

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Company RDBMS

Pno: 6.19, Page no: 214-215

Reference Schema: Fig 5.5

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6.19a. Retrieve the names of all employees in department 5 who work more than 10

hrs per week on the productX project.

select fname,minit,lname

from employee

where dno=5 and ssn in ( select essn

from project JOIN works_on ON

pname = productX and hours > 10);

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6.19.b. List the names of all employees who have a dependent with the same first

name as themselves.

select fname , minit , lname

from employee JOIN dependent ON

where fname = dependent_name;

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6.19.c. Find the names of all employees who are directly supervised by Franklin

Wong

Select e.fname,e.minit,e.lname

from employee e

where e.super_ssn = (select ssn from employee where fname=Franklin and

lname = Wong);

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6.19.d. For each Project list the Project name and the total hour per week ( by all

employees ) spend on that project.

select pname,SUM(hours) as Total_no_of_hours

from project JOIN works_on ON

pnumber = pno

group by pname;

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6.19.e. Retrieve the names ofall

employees who works on every project.

select e.fname,e.minit,e.lname

from employee e

where not exists ( (select pnumber from project ) MINUS

( select pno from works_on where e.ssn = essn));

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6.19.f. Retrieve the names of all employees who do not work on any project.


from employee

where ssn not in ( select essn from works_on );

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6.19.g. For each department, retrieve the department name and the average salary of

all employees working in that department.

select dname,AVERAGE(salary) as Average_sal

from ( select dname,salary from employee JOIN department ON dno = dnumber )

group by dname;

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6.19.h. Retrieve the average salary of all female employees.

select AVERAGE(salary) as Avg_salary

from employee

where sex = F;

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6.19.i. Find the names and address of all employees who work on at least one project

located in houston but whose department has no location in houston.

select fname,address

from employee

where dno in ( (select dnum from project where plocation = Houston ) MINUS

( select dnumber from dept_location where dlocation = Houston ));

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6.19.j. List the names of all department managers who have no dependent.


from employee

where ssn not in ( select essn from dependent ) and

ssn in ( select mgr_ssn from department);

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Airline RDBMS

Pno: 5.16, Page no:215

Reference Schema :Fig 5.16

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6.20.a. For each flight list the flight number, the departure airport for first leg of the

flight and arrival airport for the last leg of the flight.

Create view flight_min_leg as

select * from

flight_leg f1 JOIN (select flight_number,MINIMUM(leg_number)) ON

f1.flight_number = flight_number and f1.leg_number = MINIMUM(leg_number)

Create view flight_max_leg as

select * from

flight_leg f1 JOIN (select flight_number,MAXIMUM(leg_number)) ONf1.flight_number = flight_number and f1.leg_number = MAXIMUM(leg_number)

Select * from

(select flight_no,dname dep from airport a JOIN (select * from flight_min_leg) b

ON a.airport_code = b.departure_airport_code) NATURAL JOIN

( select flight_no,dname arr from airport a1 JOIN (select * from flight_max_leg)

b1 ON a1.airport_code = b1.arrival_airport_code) ;

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6.20.b. List the flight numbers and weekdays of all flight or flight legs that depart from

Houston international airport ( IAH ) and arrive at Los Angeles international airport( LAX )

select flight_number,weekdays

from flight NATURAL JOIN flight_leg

where departure_airport_code = IAH and arrival+airport_code = LAX;

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6.20.c. List the number ,departure airport code, scheduled departure time, arrival airport code,

scheduled arrival time, and weekdays of all flights or flight legs that depart from some airport in

the city of Houston and arrive at some airport in the city of Los Angeles.

select * from

( ( flight_leg NATURAL JOIN

( select departure_airport_code from

airport JOIN ( select departure_airport_code from flight_leg f1 ) ON airport_code

= departure_airport_code

where city = HOUSTON )) NATURAL JOIN select arrival_airport_code from

airport JOIN (select arrival_airport_code from flight_leg f2) ON airport_code =arrival_airport_code

where city = LOS ANGELES);

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6.20.d. List the fare information for flight number CO197.

select fare_code,amount,restrictions

from fare

where flight_number = CO197 ;

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6.20.e. Retrieve the number of available seats for flight number CO197 on

1999-10-09.

select SUM(number_of_available_seats) as Total_no_of_seats

from leg_instance

where flight_number = CO197 and date = 1999-10-09;

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6.21.b. How many copies of the book titled The Last Tribe are owned by each library

branch.

select branch_name,SUM(no_of_copies) as Total_copies

from book_copies NATURAL JOIN library_branch

where book_id = (select book_id from book where title = The last tribe)

group by branch_name;

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6.21.c. Retrieve the names of all borrowers who do not have any book checked out.

select name

from borrower NATURAL JOIN (select card_no from book_loans

where due_date < today );

NOTE: Please Replace today by today`s date.

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6.21.d. For each book that is loaned from the Sharpstown branch and whose

due_date is today , Retrieve the booktitle, the borrowers name and borrowers

address.

select b.title,bw.name,bw.address

from (book b CROSS JOIN borrower bw) JOIN (select book_id,cardno

from book_loans bl

where bl.due_date = today and

bl.branch_id = (select branch_id from

library_branch where branchname =

Sharpstown)) ONb.book_id = book_id and bw.cardno = cardno;

NOTE: Replace today by today`s date

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6.21.e. For each library branch retrieve the branch name and the total number of

books loaned from that branch.

select branchname,COUNT(bookid) as Total_no_of_copies

from book_loans NATURAL JOIN library_branch

group by branchname;

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6.21.f. Retrieve the names, address and number of books checked out for all

borrowers who have more than 5 books checked out.

select name,COUNT(bookid) as Books_checked

from book_loans NATURAL JOIN borrower

where today < due_date

having Books_checked > 5;

NOTE: Replace today by today`s date

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Order-Processing RDBMS

Pno: 6.22, Page no: 217

Reference Schema: 5.18

Please Note:# is replaced by _no

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6.22.a. List the order# and ship_date for all orders shipped from warehouse# w2.

select order_no, shipdate

from shipment

where warehouse_no = W2;

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6.22.b. List the warehouse information from which the customer named Jose Lopez

was supplied his orders, produce a listing: order#, warehouse#.

select order_no,warehouse_no

from (customers NATURAL JOIN order) NATURAL JOIN shipment

where cname = Jose Lopez;

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6.22.c. Produce a listing cname, no_of_orders, avg_order_amt where the middle

column is the total number of orders by the customer and the last column is the

average order amount for that customer.

select cname,no_of_orders,avg_order_amt from

(select cust_no,cname,COUNT(order_no) as no_of_orders,AVERAGE(ord_amt) as

avg_order_amtfrom customer NATURAL JOIN order

group by cust_no);

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6.22.d. List the orders that were not shipped within 30 days of ordering.

select order_no

from order NATURAL JOIN shipment

where ship_date odate >=30;

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6.22.e. List the order# for orders that were shipped from allwarehouses that the

company has in New York.

select s.order_no

from shipment s

where not exists ((select warehouse_no from warehouse where city = NewWork)

MINUS (select warehouse_no from shipment where order_no = s.order_no));

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Salesmen Business Trip RDBMS

Pno: 6.23, Page no: 217


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6.23.a. Give the details ( of all attributes ) for trips that exceeds $5000 in expences.

select ssn,from_city,to_city,departure_date,return_date

from trip NATURAL JOIN expence

where amount > 5000;

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6.23.b. Print the ssn and name of the salesman who made trips to SAN FRANSISCO.

select ssn,name

from trip NATURAL JOIN salesperson

where to_city = SAN FRANSISCO;

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6.23.c Print the total trip expenses incurred by the salesman with the name =

Rajaram.

select SUM(amount) as Total_expence

from (salesperson NATURAL JOIN trips) NATURAL JOIN expences

where name = rajaram;

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Student Enrollment RDBMS

Pno: 6.24, Page no: 217


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6.24.a. List the numbers of courses taken up by all students named prakash in winter

2007 ( i.e. quarter = W07 ).

select ssn,COUNT(course_no) as no_of_courses

from enroll NATURAL JOIN student

where name = Prakash

group by ssn;

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6.24.b. Produce a list of textbooks (include course#, book_ISBN , book_title, ) for

courses offered by the IT department that have used more than 3 books.

select course_no,book_ISBN,book_title

from book_adaoption NATURAL JOIN text

where course_no in ( select course_no from

( select c.course_no,COUNT(ba.book_ISBN) from

course c JOIN book_adaoption ba ON c.course_no = ba.course_no

where c.dept=IT

group by c.course_nohaving COUNT(ba.book_ISBN) > 3));

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6.24.c. Mention any department that has all its adapted books published by Addison

Wesley Publishing.

select c.dept

from course c

where not exists ((select book_ISBN from book where publisher = Addison wesleyPublishing) MINUS (select book_ISBN from book_adaoption where course_no =

c.course_no));

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Nested Query Examples.

Pno: 6.35, Page no: 219

Reference Schema:

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6.35.a. List the names of all employees who work in the department that has the

employee with highest salary among all employees.

select e.fname,e.minit,e.lname from employee e

where e.dno in (select e1.dno from employee e1

where e1.salary = (select MAXIMUM(salary) from employee));

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6.35.b List the names of all employees whose supervisors supervisor has 888665555

for ssn.

select e.fname,e.minit,e.lname from employee e

where e.super_ssn in (select ssn from employee where super_ssn = 888665555);

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6.35.c. List the names of employees who make at least $10,000 more than the

employee who is paid the least in the company.

select e.employee,e.minit,e.lname from employee e

where e.salary >= (select 10000+MINIMUM(salary) from employee);

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Book Club RDBMS

Pno: 6.41, Page no: 220-221


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6.41.a. Find the names of members who are the professors older than 45 years.

Select name from members

where age > 45 and designation = professor;

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6.41.b. List the titles of books reserved by professors.

Select btitle

from (members NATURAL JOIN reserves) NATURAL JOIN books

where desidnation = Professor;

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6.41.c. Find IDs of members who have not reserved books that cost more than Rs.500.

Select member_id

from reserves

where member_id in ((select r1.member_id from reserves r1) MINUS (selectr2.member_id from reserves r2 NATURAL JOIN books b

where b.bprice > 500));

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6.41.d. Find the author and titles of books reserved on 27-may-2007.

Select bauthor,titles

from books NATURAL JOIN reserves

where date = 27-may-2007;

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6.41.e. Find the names of members who have reserved allbooks.

Select m.name

from members m

where not exists( (select bid from books) MINUS (select bid from reserves wheremember_id = m.member_id));

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