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Page 1: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of
Page 2: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

Five-Minute Check (over Lesson 12–5)

Then/Now

Key Concept: Lateral and Surface Area of Cylinders

Example 1: Surface Area of a Cylinder

Example 2: Real-World Example: Compare Surface Areas of Cylinders

Page 3: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

Over Lesson 12–5

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. 197.6 cm2

B. 204.7 cm2

C. 247.6 cm2

D. 274.4 cm2

Find the lateral area of the figure.

Page 4: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

Over Lesson 12–5

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. 96 in2

B. 98 in2

C. 106 in2

D. 108 in2

Find the surface area of the figure.

Page 5: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

Over Lesson 12–5

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. 2.4 m2

B. 2.6 m2

C. 3.6 m2

D. 3.8 m2

Find the lateral area of a cube with a length of 0.8 meter.

Page 6: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

Over Lesson 12–5

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. 512 in2

B. 520 in2

C. 570 in2

D. 594 in2

Amy needs to wrap a box that is 18 inches long, 11 inches wide, and 3 inches high. What is the minimum amount of wrapping paper that she needs?

Page 7: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

Over Lesson 12–5

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. 3,360 in2

B. 5,760 in2

C. 7,630 in2

D. 28,800 in2

How much wood is needed to make a rectangular toy box that measures 40 inches long, 30 inches wide, and 24 inches high?

Page 8: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

You have already found the lateral areas and surface areas of prisms. (Lesson 12–5)

• Find lateral and surface areas of cylinders.

• Compare surface areas of cylinders.

Page 10: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

Surface Area of a Cylinder

A. Find the lateral area and surface area of the cylinder. Round to the nearest tenth.

Lateral Area

L = 2πrh

= 2π(5)(8)

= 80πexact answer

≈ 251.3 in2

approximate answerThe lateral area is about 251.3 square inches.

Page 11: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

Surface Area of a Cylinder

Surface Area

S = L + 2πr2

= 80π + 2π(5)2

= 130π exact answer

≈ 408.4 in2

approximate answer

The surface area is about 408.4 square inches.

Answer: L ≈ 251.3 in2, S ≈ 408.4 in2

Page 12: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

Surface Area of a Cylinder

The lateral area is about 537.2 square feet.

Lateral Area

L = 2πrh

= 2 • π • 9 • 9.5

= 171π

= 537.2 ft2

B. Find the lateral area and surface area of the cylinder.

diameter of 18 feet and height of 9.5 feet

The diameter is 18 feet, so the radius is or 9 feet.

Page 13: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

Surface Area

S = L + 2πr2

= 171π + 2π(9)2

= 171π + 162π

≈ 1046.2 ft2

Surface Area of a Cylinder

The surface area is about 1046.2 square feet.

Answer: L ≈ 537.2 ft2, S ≈ 1046.2 ft2

Page 14: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. lateral area, 1082.0 in2; surface area, 1504.4 in2

B. lateral area, 1082.0 in2; surface area, 3852.9 in2

C. lateral area, 2163.9 in2; surface area, 2586.4 in2

D. lateral area, 4436.1 in2; surface area, 4858.6 in2

A. Find the lateral area and the surface area of the cylinder. Round to the nearest tenth.

Page 15: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. lateral area, 47.1ft2; surface area, 56.5 ft2

B. lateral area, 94.2 ft2; surface area, 150.8 ft2

C. lateral area, 141.4 ft2; surface area, 197.9 ft2

D. lateral area, 188.5 ft2; surface area, 301.6 ft2

B. Find the lateral area and the surface area of the cylinder. Round to the nearest tenth. diameter of 6 feet and height of 5 feet

Page 16: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

Compare Surface Areas of Cylinders

MANUFACTURING A company manufactures dowel rods. Rod A has a diameter of 3 inches and a height of 12 inches. Rod B has a diameter of 1 inch and a height of 36 inches. Which rod has the larger surface area?

The diameter of Rod A is 3 inches, so radius is 1.5 inches. Its height is 12 inches.

The diameter of Rod B is 1 inch, so radius is 0.5 inch. Its height is 36 inches.

Find the surface area of both rods.

Page 17: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

Compare Surface Areas of Cylinders

Rod A

S = L + 2πr 2

= 2πrh + 2πr 2

= 2π(1.5)(12) + π(1.5)2

= 36π + 2.25π

≈ 120.2 in2

Rod B

S = L + 2πr 2

= 2πrh + 2πr 2

= 2π(0.5)(36) + π(0.5)2

= 36π + 0.25π

≈ 113.9 in2

Answer: Rod A has the larger surface area.

Page 18: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. Brand A’s container has the larger surface area.

B. Brand B’s container has the larger surface area.

C. The containers have the same surface area.

D. It is not possible to determine the surface areas of the containers.

A cylindrical Brand A oatmeal container has a radius of 5 inches and a height of 12 inches. Brand B uses a cylinder with a radius of 4 inches and a height of 14 inches. Which statement is true?

Page 19: Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–5) Then/Now Key Concept: Lateral and Surface Area of Cylinders Example 1: Surface Area of